Entity Framework 4.1 two FKs pointing to same table - entity-framework-4.1

Question

I ran into an issue when adding two navigation properties of the same type in a model, giving me this error :
System.Data.SqlClient.SqlException:
Invalid column name : 'Createur_IdUtilisateur'.
Invalid column name : 'Proprietaire_IdUtilisateur'.
This is the code (broken) that I have :
public class Billet
{
[Key]
public int IdBillet { get; set; }
public int IdMandat { get; set; }
public string Titre { get; set; }
[AllowHtml]
public string Description { get; set; }
public int IdUtilisateurCreateur { get; set; }
public int IdUtilisateurProprietaire { get; set; }
public DateTime DateCreation { get; set; }
public DateTime? DateFermeture { get; set; }
public int EstimationTemps { get; set; }
public int Priorite { get; set; }
public bool FermetureParCreateur { get; set; }
public virtual ICollection<Intervention> Interventions { get; set; }
public virtual Mandat Mandat { get; set; }
public virtual Utilisateur Createur { get; set; }
public virtual Utilisateur Proprietaire { get; set; }
}
public class Utilisateur
{
[Key]
public int IdUtilisateur { get; set; }
public int IdUtilisateurRole { get; set; }
public string Courriel { get; set; }
public string Nom { get; set; }
public string Password { get; set; }
public bool Actif { get; set; }
public virtual UtilisateurRole Role { get; set; }
}
And this is what the relationships look like in the database.
I've read about [InverseProperty], but I'm not sure how I would go about implementing that in my situation. Do I need to add reverse navigation properties in my Utilisateur class to make this work?

Answer 1

Shortly after asking I realized my mistake, this is how I fixed it :
public class Entities : DbContext
{
...
protected override void OnModelCreating(DbModelBuilder modelBuilder)
{
...
modelBuilder.Entity<Billet>()
.HasRequired(b => b.Createur)
.WithMany()
.HasForeignKey(b => b.IdUtilisateurCreateur);
modelBuilder.Entity<Billet>()
.HasRequired(b => b.Proprietaire)
.WithMany()
.HasForeignKey(b => b.IdUtilisateurProprietaire);
}
}