Without the third join D.cid = C.id, this query gives me the count of C. With the third join it corrupts the count and gets unwanted tuples into the count of C's join. So how can I get the count of C and D without having the C count effected? Is there a form of parenthesis I can use to make sure I get the correct count?
SELECT A.*, B.*, COUNT(C.aid) AS cCount
FROM tableA A
LEFT JOIN tableC AS C ON A.id = C.aid
INNER JOIN tableB AS B ON A.id = B.aid
LEFT JOIN tableD AS D ON D.cid = C.id
GROUP BY A.id
I would have the counts from the other tables pre-aggregated unto themselves and joined... something like...
SELECT
A.*,
B.*,
COALESCE( PreAggC.CCount, 0 ) as CCount,
COALESCE( PreAggC.WithDCount, 0 ) as WithDCount
FROM
tableA A
JOIN tableB B
on A.ID = B.aID
LEFT JOIN ( select aID,
count( distinct id ) CCount,
count(*) as WithDCount
from tableC
left join tableD D
on c.ID = D.cID
group by aID ) PreAggC
on A.id = PreAggC.aID
Now, do you really want how many entries actually have "D" records? so I included both counts... distinct "C" entries, and the overall count with correlation with "D"
Related
I think it's impossible, but I'm asking if there's a good way.
There are A table / B table / C table.
The table was joined LEFT JOIN based on table A with FK called id of each table.
At this time, I would like to output the count(*) as B table rows and C table rows based on b.id(B_CNT) c.id(C_CNT)
SELECT
*
FROM
A
LEFT JOIN B ON A.ID = B.ID
LEFT JOIN C ON A.ID = C.ID (base query)
how could I count group by b.id and c.id?
You could try:
SELECT
COUNT(DISTINCT B.ID), COUNT(DISTINCT C.ID)
FROM A
LEFT JOIN B
ON A.ID = B.ID
LEFT JOIN C
ON A.ID = C.ID
(I couldn't quite understand from your question, but I'm making an assumption that you want the distinct count of "ID" from each table)
You can use a couple of scalar subqueries. For example:
select id,
(select count(*) from b where b.id = a.id) as b,
(select count(*) from c where c.id = a.id) as c
from a
How could I count an inner join output, thanks a lot
-- Quantity A = 981
SELECT COUNT(DISTINCT ID) FROM A;
-- Quantity B = 673
SELECT COUNT(DISTINCT ID) FROM B;
How can i count an inner join
SELECT * FROM A
INNER JOIN B
ON A.ID = B.ID;
Combine your two attempts into one since you're performing an INNER JOIN, it does not matter if you use A.ID or B.ID in the DISTINCT COUNT:
SELECT COUNT(DISTINCT A.ID) AS AB_Count FROM A INNER JOIN B ON A.ID = B.ID;
Fiddle for reference.
I have this query:
select a.*, b.*, (select c.* from tableC c where c.id_tableA = a.id) from tableA a inner join tableB b on a.id = b.id_tableA where b.id_user = 50;
The subquery (which is tableC) is returning me more than 1 row as expected. How can I return only 1 row from tableC so it could match with the rest of the query?
So far I have tried this:
(select c.* from tableC c where c.id_tableA = a.id limit 1)
It didn't work as mysql said:
"Operand should contain 1 column(s)"
You are mixing two things. Scalar subquery in SELECT list should return only one value (both row and column). Using LIMIT 1 will get you one row, but still many columns.
So you could specify column name:
select a.*, b.*,
(select c.col_name from tableC c where c.id_tableA = a.id order by .. limit 1)
from tableA a
inner join tableB b on a.id = b.id_tableA
where b.id_user = 50;
or use normal JOIN:
select a.*, b.*, c.*
from tableA a
inner join tableB b
on a.id = b.id_tableA
left join tableC c
on c.id_tableA = a.id
where b.id_user = 50;
if column id from table C is a primary key then it should have no problem
but if no, try to add another condition that will filter your subquery results like ,
for example here is the start_date:
SELECT a.column_1, b.column_2,
(SELECT column_3 FROM tableC
WHERE (id = a.id
AND (start_date = (SELECT MAX(b.start_date)
from tableC as c
where a.id = c.id ))) AS column_3
FROM tableA as a INNER JOIN
tableB as b ON b.id = a.id
WHERE b.id_user = 50;
I have 2 tables in my SQL database. Let's call them Table A and Table B.
I have joined both the tables using left join on ID = AID. Table A has a field by name ID and Table B has field AID and Price.
The problem is Table B can have multiple prices for the ID present in Table A.
The requirement is - If only one price is present in Table B corresponding to ID in table A then it should return that price.
If more than one price is present in table B for an ID in table A then I should get the price as Zero/null.
Query -
SELECT DISTINCT A.ID,B.Price
from A
left join B
on A.ID = B.AID
where "some condition"
Use Count() with Over() window function to find the count of records for each ID then based on count return the price
Try this way
SELECT DISTINCT A.ID,
case when count(1) over(partition by A.ID) > 1 then NULL else B.Price end
from A
left join B
on A.ID = B.AID
For Mysql
SELECT DISTINCT a.id,
CASE
WHEN c.aid IS NULL THEN NULL
ELSE b.price
END
FROM a
LEFT JOIN b
ON a.id = b.aid
LEFT JOIN (SELECT aid
FROM b
GROUP BY aid
HAVING Count(1) = 1) c
ON a.id = c.aid
For SQL Server (should work for MySQL too). One sub-query (you can put in CTE) that shows only AIDs that have only one price:
SELECT A.ID,
B.Price
FROM A
LEFT JOIN (
SELECT AID
FROM B
GROUP BY AID
HAVING COUNT(Price) = 1
) as C
ON C.AID = A.ID
LEFT JOIN B
ON C.AID = B.AID
Use below query. It should work.
SELECT A.ID, o.Price
FROM A
OUTER APPLY
(
SELECT IIF(COUNT(B.Price)>1,NULL,MAX(B.Price)) AS Price
FROM B
WHERE B.AID = A.ID
) AS o;
ok so my problem is that I have a set of results:
ID CODE
1 A
1 B
3 C
I also have another table of:
CODE
A
B
C
What I want to get using SQL is a query of CODES that each result from table 1 is missing. So basically:
ID CODE
1 C
3 A
3 B
Any help would be great.
You can use:
SELECT a.id, b.code
FROM (SELECT DISTINCT id FROM idcodes) a
CROSS JOIN codes b
LEFT JOIN idcodes c ON a.id = c.id AND b.code = c.code
WHERE c.id IS NULL
ORDER BY a.id, b.code
If you have another table that stores unique entries for id, it would be better to just use that table instead rather than a DISTINCT subselect:
SELECT a.id, b.code
FROM ids a
CROSS JOIN codes b
LEFT JOIN idcodes c ON a.id = c.id AND b.code = c.code
WHERE c.id IS NULL
ORDER BY a.id, b.code
SQLFiddle Demo
You can use exists. Construct the full list of possible variations with a Cartesian join and then ensure what you have isn't in this list.
select id, code
from idcode_table x
where not exists ( select 1
from idcode_table a
cross join code_table b
where b.code = x.code
and a.id = x.id )
This can also be re-written with a not in.
select id, code
from idcode_table
where (id, code) not in ( select distinct a.id, b.code
from idcode_table a
cross join code_table b )
The distinct is optional. It will make it slower to construct the list of possibles but quicker to determine if you have one of them already. I'd test it to see which is quicker.