What am I doing wrong? It shows up as a blank page. I don't know a whole lot of xslt so I'm just testing it right now. If I can't get this to show up though then I can't really test how it works.
My XML
<?xml version="1.0"?>
<?xml-stylesheet type="text/xsl" href="q3.xsl"?>
<expenseReport>
<companyInfo>
<name>John Doe</name>
<email>JDoe#company.com</email>
<empNum>1</empNum>
<companyCode>10010011</companyCode>
</companyInfo>
</expenseReport>
xslt
<?xml version="1.0" encoding="ISO-8859-1"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/">
<html>
<body>
<h1>Test</h1>
<xsl:value-of select="expenseReport/companyInfo/name"/>
</body>
</html>
</xsl:template>
</xsl:stylesheet>
I can't even get that <h1> to show up, what's going on?
Please use --allow-file-access-from-files if you are trying to view local files from Chrome. They are very strict with local file access so do not rely on this option when you deploy your site. Only use it for development! I just checked it with version 14.0.385.202 and it worked.
Other than this your .xslt is just fine!
Related
I want to embbed a XSLT transformation into an <iframe>. Here are my 2 files:
simple.html:
<!DOCTYPE html>
<html>
<body>
<iframe>
<?xml version="1.0" encoding="UTF-8"?>
<?xml-stylesheet type="text/xsl" href="simple.xsl"?>
<text>
Hello World
</text>
</iframe>
</body>
</html>
simple.xsl:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/">
<html>
<body>
Content: <xsl:value-of select="." />
</body>
</html>
</xsl:template>
</xsl:stylesheet>
Obviously, it doesn't work.
If I put the XML code of the <iframe> into a file named simple.xml and reference it like that <iframe src="simple.xml">, it works well but I don't want to have a separate XML file.
The reason is because the XML code will be provided by the user and I don't want to store it temporarily on my server just so I can reference it in the <iframe>, I want to do all client-side.
Is it possible to do that? If so, how can I do?
Thank you for your help.
I'm working with a bowling website and a software program written for management of our bowling league scores. The software also allows us to write an article on the last bowling league day. Now I'm copying the article into HTML module on the website but since it's also implemented in the same XML output file as the scores I'd like to take it out as well with XSLT. I only don't know what are the commands for this... So I have no XSLT file I'm working with. If I look it up here or on google , there seem to be tons of ways to do it but every time there's a bunch of other code as well and I'm still a beginner...
Can anybody help me?
<Infos>
<Info>
<Title><![CDATA[THIS IS THE TITLE OF THE ARTICLE]]></Title>
<Text><![CDATA[THIS THE ARTICLE]]></Text>
</Info>
</Infos>
The CDATA piece contains text, I want it to display after applying
XSLT and determine the text outcome (bold, Italic and underlined) with
XSLT
The following stylesheet:
XSLT 1.0
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="html" encoding="UTF-8" indent="yes"/>
<xsl:template match="/Infos">
<html>
<body>
<xsl:apply-templates select="Info"/>
</body>
</html>
</xsl:template>
<xsl:template match="Info">
<h2><xsl:value-of select="Title" /></h2>
<i><xsl:value-of select="Text" /></i>
</xsl:template>
</xsl:stylesheet>
when applied to your example input, will produce the following result:
<html>
<body>
<h2>THIS IS THE TITLE OF THE ARTICLE</h2>
<i>THIS THE ARTICLE</i>
</body>
</html>
rendered as:
Is it possible for XSLT preserve anchors and other embedded HTML tags within XML?
Background: I am trying to convert an HTML document into XML with an XSL stylesheet using XSLT. The original HTML document had content interspersed with anchor tags (e.g. Some hyperlinks here and there). I've copied that content into my XML, but the XSLT output lacks anchor tags.
Example XML:
<?xml version="1.0" ?>
<observations>
<observation>Hyperlinks disappear.</observation>
</observations>
Example XSL:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet
version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns="http://www.w3.org/1999/html">
<xsl:output method="html" indent="yes" encoding="UTF-8"/>
<xsl:template match="/observations">
<html>
<body>
<xsl:value-of select="observation"/>
</body>
</html>
</xsl:template>
</xsl:stylesheet>
Output:
<html xmlns="http://www.w3.org/1999/html">
<body>Hyperlinks disappear.</body>
</html>
I've read a few similar articles on stackoverflow and checked out the Identity transform page on wikipedia; I started to get some interesting results using xsl:copy-of, but I don't understand enough about XSLT to get all of the words and tags embedded within each XML element to appear in the resulting HTML. Any help would be appreciated.
Write a separate template to match a elements, copy their attributes and content.
What is wrong with your approach? In your code,
<xsl:value-of select="observation"/>
simply sends to the output the string value of the observation element. Its string value is the concatenation of all text nodes it contains. But you need not only the text nodes in it, but also the a elements themselves.
The default behaviour of an XSLT processor is to "skip" element nodes, because of a built-in template. So, if you do not mention a in a template match, it is simply ignored and only its text content is output.
Stylesheet
Note: This stylesheet still relies on the default behaviour of the XSLT processor to some extent. The order of events will resemble the following:
The template where match="/observations" is matched. It adds html
and body to the output. Then, a template rule must be found for the
content of observations. A built-in template matches observation,
does nothing with it, and looks for a template to process its content.
For the a element, the corresponding template is matched, with
copies the element and attributes. Finally, a built-in template copies
the text nodes inside observation and a.
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="html" indent="yes" encoding="UTF-8"/>
<xsl:strip-space elements="*"/>
<xsl:template match="/observations">
<html>
<body>
<xsl:apply-templates/>
</body>
</html>
</xsl:template>
<xsl:template match="a">
<xsl:copy>
<xsl:copy-of select="#*"/>
<xsl:apply-templates/>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
XML Output
<html>
<body>Hyperlinks disappear.
</body>
</html>
I don't know too much about XSL but have managed to format XML coming from 3rd party web services using XSL without too much trouble. But the other day, a site that used to work stopped working. I discovered that they made a tiny change to the XML returned by the web service. This is what used to work (greatly simplified):
Update: I see the problem now, but I don't have a solution. The problem is with xsl:if test="#xsi:type='r0:CreditTx'". Change every "r0" to "s0" in the XSL, and it does not work.
I have replaced my original code with a working example:
XML:
<?xml version="1.0" encoding="unicode"?>
<MyResp xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:xsd="http://www.w3.org/2001/XMLSchema"
xmlns:r0="http://www.foo.com/2.1/schema"
xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/">
<r0:creditVendReceipt receiptNo="1234567890">
<r0:transactions>
<r0:tx xsi:type="r0:CreditTx">
<r0:amt value="100" />
</r0:tx>
</r0:transactions>
</r0:creditVendReceipt>
</MyResp>
XSL:
<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:r0="http://www.foo.com/2.1/schema"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<xsl:template match="/">
<html>
<head>
</head>
<body >
<xsl:for-each select="MyResp/r0:creditVendReceipt/r0:transactions/r0:tx">
<xsl:if test="#xsi:type='r0:CreditTx'">
<xsl:value-of select="r0:amt/#value"/>
</xsl:if>
</xsl:for-each>
</body>
</html>
</xsl:template>
</xsl:stylesheet>
Desired HTML:
<html xmlns:r0="http://www.foo.com/2.1/schema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<head>
<META http-equiv="Content-Type" content="text/html; charset=utf-8">
</head>
<body>
100
</body>
</html>
The problem came when the web service changed the xmlns' short name "a" to "a0" (it now sends xmlns:a0="http://mysite.com/webservice/1.0/schema"); the namespace and everything else is the same. I have to change "a" to "a0" in the XSL for it to work (i.e. "GetInfoResp/a0:userName"). The problem is that the short name sent by the service changes from time to time. (In the real app there are a lot of name spaces, and the short names are even changing between the various requests.)
I thought the short name was just to make the XML shorter and easier to read, and that the actual name isn't significant (betwen the XML and the XSL; within the XSL obviously it has to match).
Can I get the XSL to ignore the short name in the XML, and just use its own short name?
Sorry if this was answered before; I looked thru the other questions and didn't see this specific issue.
The "short name" is called a namespace prefix -- and you don't have to change the namespace prefix in the transformation -- in fact it may be completely different from any prefix that could be used in the XML document.
This transformation:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:xYz="http://mysite.com/webservice/1.0/schema"
exclude-result-prefixes="xYz">
<xsl:template match="/">
<html>
<body >
<xsl:value-of select="GetInfoResp/xYz:userName"/>
</body>
</html>
</xsl:template>
</xsl:stylesheet>
produces exactly the same result as this transformation:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:a0="http://mysite.com/webservice/1.0/schema"
exclude-result-prefixes="a0">
<xsl:template match="/">
<html>
<body >
<xsl:value-of select="GetInfoResp/a0:userName"/>
</body>
</html>
</xsl:template>
</xsl:stylesheet>
Both transformations, when applied on this XML document (what is provided in the question is severely malformed and had to be corrected):
<GetInfoResp xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:a0="http://mysite.com/webservice/1.0/schema">
<a0:userName>Joe</a0:userName>
</GetInfoResp>
produce the same result:
<html>
<body>Joe</body>
</html>
Lesson to learn:
What matters is the namespace, not the prefix used to shorthand it.
I am trying to do a simple transform of XML using XSLT to generate HTML, but I'm having difficulties and I can't seem to figure out what the problem is. Here is a sample of the XML I am working with:
<?xml version="1.0" encoding="UTF-8"?>
<?xml-stylesheet type="text/xsl" href="C:\Users\cgubata\Documents\Digital Measures\jcamp_fac_ex_xslt.xsl"?>
<Data xmlns="http://www.digitalmeasures.com/schema/data" xmlns:dmd="http://www.digitalmeasures.com/schema/data-metadata" dmd:date="2012-02-27">
<Record userId="310106" username="jcamp" termId="453" dmd:surveyId="1154523">
<dmd:IndexEntry indexKey="COLLEGE" entryKey="School of Business" text="School of Business"/>
<dmd:IndexEntry indexKey="DEPARTMENT" entryKey="Accountancy" text="Accountancy"/>
<dmd:IndexEntry indexKey="DEPARTMENT" entryKey="MBA" text="MBA"/>
<PCI id="11454808064" dmd:lastModified="2012-02-08T13:17:39">
<PREFIX>Dr.</PREFIX>
<FNAME>Julia</FNAME>
<PFNAME/>
<MNAME>M.</MNAME>
<LNAME>Camp</LNAME>
<SUFFIX/>
<ALT_NAME>Julia M. Brennan</ALT_NAME>
<ENDPOS/>
All I want to do is have the value for some of the nodes to be displayed in HTML. So for example, I might want the PREFIC, FNAME, LNAME nodes to display as "Dr. Julia Camp" (no quotes - I'll do styling later). Here's the XSL that I am using:
<?xml version="1.0" encoding="utf-8"?><!-- DWXMLSource="jcamp_fac_ex.xml" -->
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:dmd="http://www.digitalmeasures.com/schema/data-metadata">
<xsl:output method="html" encoding="utf-8"/>
<xsl:template match="/">
<xsl:value-of select="/Data/Record/PCI/PREFIX"/>
</xsl:template>
</xsl:stylesheet>
From what I been researching, that should show the value of that PREFIX field. But instead, it is outputting all of the values from all of the nodes (so if there are 4000 nodes with a text value, I am getting 4000 values returned in HTML). My goal will be to pull out the values from certain nodes, and I will probably arrange them in a table.
How do I pull out the values from a specific node? Thanks in advance.
Well, I can't reproduce your symptoms. When I test what you've posted it doesn't produce any output at all. Which looks correct because your xpath is testing the wrong namespace. You need to add in your xslt a namespace-prefix mapping for the http://www.digitalmeasures.com/schema/data namespace, and then use it in the value-of xpath. Like this:
<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:dmd="http://www.digitalmeasures.com/schema/data-metadata"
xmlns:dm="http://www.digitalmeasures.com/schema/data">
<xsl:output method="html" encoding="utf-8"/>
<xsl:template match="/">
<xsl:value-of select="/dm:Data/dm:Record/dm:PCI/dm:PREFIX"/>
</xsl:template>
</xsl:stylesheet>
I'm afraid you've fallen into the number one XSLT trap for beginners: we see this question at least once a day on this forum. Your elements are in a namespace and your stylesheet is trying to match nodes in no namespace.