I have tried this multiple distinct from MySQL and I cant seem to get anything to work... I have a table that is a history table. The appartments can be found many times from the same building with different status. I need to find the newest one for each appartment (the one with the highest id ORDER BY id)
id building appartment_id status
208 1 2 2
209 1 3 2
210 1 4 2
211 1 5 2
212 1 6 2
213 1 7 2
214 1 2 1
215 1 2 3
But how do I do that?! :S
I have tried this:
SELECT *, GROUP_CONCAT(appartment_id, building)
FROM `ib30_history`
group by appartment_id, building
order by id DESC
It seems to work but im not sure that is the right way of doing it and the code that uses the output seems to make funny things running through the data so im not sure it really works!
SELECT yourtable.id, yourtable.building, yourtable.appartment_id, yourtable.status
FROM yourtable
INNER JOIN (
SELECT MAX(id) AS id
FROM yourtable
GROUP BY building, appartment_id
) AS child ON yourtable.id = child.id
Get rid of distinct and use something like:
GROUP BY building , appartment_id
What you're looking for is called GROUP BY, and MySQL's documentation knows a lot about how it's to be used. At the timeI type this, the OP doesn't contain a query so I cannot give you an example...
SELECT a.*
FROM table_name a
INNER JOIN
(SELECT MAX(id) as max_id
FROM table_name
GROUP BY appartment_id) b
ON (b.max_id = a.id)
Related
I'm trying to get the unique call counts (no dupe calls) by state. For example...
MO 249
OK 220
CA 216
TX 190
KS 158
The following works (no errors), but it's not removing the dupes.
SELECT DISTINCT CallFrom, FromState, count(*) AS cnt
FROM `calls`
WHERE DateCreated >= CURDATE() - INTERVAL 2 YEAR AND
(CallTo = '+15555555555' OR CallTo = '+15555555556' )
GROUP BY FromState
ORDER BY cnt DESC
Any ideas? Thanks in advance.
UPDATE: The following 'calls' table example was requested...
Index CallTo CallFrom FromState
1 +15555555555 18166283100 MO
2 +15555555556 13307059600 OH
3 +15555555555 17722631600 FL
4 +15555555556 16173024800 MA
5 +15555555556 16173024800 MA
6 +15555555556 16175025500 MA
Just realized I forgot to include the DateCreated column, but like I said, everything is working except for deduplicating. The output for this example would be...
MA 2
MO 1
OH 1
FL 1
Your wording is not very clear, but I think you're saying you want to count how many unique CallFrom numbers occurred in each state. There may be better ways to do this, but this will work. First it builds a list of unique CallFrom/State combinations, and then it groups and counts on that list, instead of on the raw data:
SELECT FromState, COUNT(*)
FROM
(SELECT DISTINCT CallFrom, FromState
FROM `calls`
WHERE
(CallTo = '+15555555555' OR CallTo = '+15555555556' )
) c
GROUP BY FromState
Demo:
https://dbfiddle.uk/?rdbms=mysql_8.0&fiddle=d057e3482ec9d5ad4519e58056232e58
I have a table, it similar with this table
ID Name Age Status
1 John 32 Life
2 Andre 99 Life
3 Anton 89 Dead
4 Maria 99 Life
5 Mario 13 Life
6 Santi 89 Dead
7 Anggy 56 Dead
8 Amir 99 Life
I want to do something like this
1. Group rows by status (Life)
2. Get the max Age from that group (99) (only the max number need)
4. Make new group by age and sort it by ID.
The result will be
8 Amir 99 Life
4 Maria 99 Life
2 Andre 99 Life
Any way to use only 1 line query for that job? with some (php) data procesing its not to hard to get the result i want, but i want to make code as clean as posible, so maybe i can do that 3 step in just a single query?
I think the right logic is:
select t.id, t.name, t.age, t.status
from table t join
(select max(t2.age) from table t2 where t2.status = 'life') m
on t.age = m.age
where t.status = 'life'
order by id desc;
select id, name, age, status
from thetable
where age =
(select max(age)
from thetable
where status="Life"
)
where status="Life"
order by id desc
Use the below mentioned query :
SELECT
*
FROM
t4
CROSS JOIN
(SELECT
MAX(`age`) AS 'age'
FROM
t4
WHERE
`status` = 'Life') AS t5
WHERE
`status` = 'Life' AND t4.`age` = t5.age
ORDER BY `id` DESC;
Check SQLFiddle
I need a little help with a MySQL query.
I have two tables one table is a list of backlinks with a is_homepage (bool) flag. The second table is a list of the domains for all of the backlinks, a was link_found (bool) flag, and a url_count column which is the number of rows in the backlinks table that are associated with each domain.
Note that the domain_id column is the foreign key to the domain table id column. Heres some sample data.
backlinks
id domain_id is_homepage page_href
1 1 1 http://ablog.wordpress.com/
2 1 0 http://ablog.wordpress.com/contact/
3 1 0 http://ablog.wordpress.com/archives/
4 2 1 http://www.somewhere.org/
5 2 0 http://www.somewhere.org/page=3
6 3 1 http://www.great-fun-site.com/
7 3 0 http://www.great-fun-site.com/index.html
8 4 0 http://red.blgspot.com/page=7
9 4 0 http://blue.blgspot.com/page=9
domains
id url_count link_found domain_name
1 3 1 wordpress.com
2 2 0 somewhere.org
3 2 1 great-fun-site.com
4 2 1 blgspot.com
The results Im looking to get from the above data would be: count = 2, total = 5.
Im trying to get the count of rows from the domains table (count) and then the sum of the url_count (total) from the domains table WHERE link_found is 1 and where one of the links in the backlink table is_homepage is 1.
Here's the query I'm trying to work with.
SELECT SUM(1) AS count, SUM(`url_count`) total
FROM `domains` AS domain
LEFT JOIN `backlinks` AS link ON link.domain_id = domain.id
WHERE domain.id IN (
SELECT DISTINCT(bl.domain_id)
FROM `backlinks` AS bl
WHERE bl.tablekey_id = 11
AND bl.is_homepage = 1
)
AND domain.link_found = 1
AND link.is_homepage = 1
GROUP BY `domain`.`id`
The problem with this query is that it returns a row for each entry in the domains table. I think I might need one more sub query to add up the returned results but I'm not sure if that's correct. Does anyone see what I'm doing wrong? Thank you!
EDIT:
The problem I'm having is that if there are more than one homepage in the back-links table then its counted multiple times. I need to only count each domain once.
Well, you shouldn't have to do a group by as you are not selecting anything other than aggregated fields. I'm no mysql expert, but this should work:
SELECT count(d.id) as count, sum(d.url_count) as total from domains as d
inner join backlinks as b
on b.domain_id = d.id
Where d.Link_found = 1 and b. is_homepage = 1
The reason you're getting a row for each entry in the domains table is that you're grouping by domain.id. If you want grand totals only, just leave off the GROUP BY piece.
I think a fairly simple query will do the trick:
SELECT COUNT(*), SUM(domains.URL_Count)
FROM domains
WHERE domains.link_found = 1 AND domains.id IN (
SELECT domain_id FROM backlinks WHERE is_homepage = 1)
There's a working SQLFiddle here.
Thanks for the help. Sorry it was so hard to explain I need a MySQL fiddle :)
If anyones interested heres what I ened up with:
SELECT SUM(1) AS count, SUM(total) AS total
FROM
(
SELECT SUM(`url_count`) total
FROM `domains` AS domain
LEFT JOIN `backlinks` AS link ON link.domain_id = domain.id
WHERE domain.id IN (
SELECT DISTINCT(bl.domain_id)
FROM `backlinks` AS bl
WHERE bl.tablekey_id = 11
AND bl.is_homepage = 1
)
AND domain.link_found = 1
AND link.is_homepage = 1
GROUP BY `domain`.`id`
) AS result
I have the following query:
SELECT a.feeder_id, b.feeder_pr
FROM authors_article_feeders a
LEFT JOIN feeders b ON b.id = a.feeder_id
WHERE website_id =1
LIMIT 0 , 30
which results in:
feeder_id feeder_pr
18 2
18 2
18 2
18 2
32 6
What I need is to modify the above query so that it will manipulate this data so that the result would end up with a count of each feeder_pr, so in this case the result would be:
feeder_pr count
2 4
6 1
Any assistance is appreciated. If you have time please describe your solution so that I can learn from it while I'm at it.
Everything I've tried has ended in inaccurate results, usually with just one row instead of the expected 2.
You just need to add a GROUP BY And, you would not even need the joins
SELECT b.feeder_pr, COUNT(b.feeder_pr)
FROM feeders b
GROUP BY b.feeder_pr
SELECT b.feeder_pr, count(a.feeder_id) as count
FROM authors_article_feeders a
LEFT JOIN feeders b ON b.id = a.feeder_id
WHERE website_id =1
GROUP BY 1
I have a table by the following structure and records, All i want to do is to just extract orderid of those records whose status id is either 1 or 2 , i want to exclude all orderid with statusid=3 , , problem is that orderid 106 has both status 1 and 3 ...
I have written a sub-query which serves the purpose..
select *
from orders_status_history
where orders_id NOT IN
(select orders_id
from orders_status_history
where orders_status_id = 3)
is there any other way of doing this without using sub-queries as i have heard it hampers performance. As my query can return thousands of rows as well.
id order-id status-id
1 1 1
2 2 1
3 105 1
4 106 1
5 106 3
6 108 1
7 109 1
8 109 2
Any help or suggestion will be highly appreciated ..Thanks in advance..
You may do that:
SELECT osh.*
FROM orders_status_history osh
LEFT JOIN
orders_status_history oshd
ON oshd.orders_id = osh_orders_id
AND oshd.orders_status_id = 3
WHERE oshd.orders_id IS NULL
However, if you have an index on order_status_history (orders_id, orders_status_id), then the NOT IN query is just as fine.
You may want to read this:
NOT IN vs. NOT EXISTS vs. LEFT JOIN / IS NULL: MySQL
I wonder why you use sub query while you can use the following query
select orders_id from orders_status_history where orders_status_id <> 3
Please try this , and I hope it helps