In my CakePHP I have ModelA which hasMany ModelB. ModelB has an int value Q.
Can I query ModelA and use containable to ensure that only those ModelB records with the maximum value for Q?
I've tried this:
$this->ModelA->contain(array(
'ModelB.Q =(SELECT MAX(ModelB.Q) FROM modelb ModelB WHERE ModelA_id = ' . $id . ')'
));
But it throws a MySQL error because CakePHP interprets the right hand side of that equality operator as a field (at least I think that's why) and so dots it.
... WHERE `Draw`.`round` =.(SELECT MAX.(`Draw`.`round`) ...
Is there a way to do this? I'd prefer not to have to drop down into $query() mode, if at all possible.
EDIT OK, after trying to follow the advice on the page that api55 suggested, I have this code:
$dbo = $this->Tournament->getDataSource();
$conditionsSubQuery['"Draw"."tournament_id"'] = $id;
$maxRounds = $dbo->buildStatement(array(
'fields' => array('MAX(Draw.round) AS prevRound'),
'table' => $dbo->fullTableName($this->Tournament->Draw),
'alias' => 'Draw',
'limit' => null,
'offset' => null,
'joins' => array(),
'conditions' => $conditionsSubQuery,
'order' => null,
'group' => null
),
$this->Tournament
);
$maxSubQuery = ' "Draw"."round" = (' . $maxRounds . ') ';
$maxSubQueryExpression = $dbo->expression($maxSubQuery);
$this->Tournament->contain(array(
'Entrant.selected = 1',
$maxSubQueryExpression
));
$tournament = $this->Tournament->read(null, $id);
But when it runs, it gives me 7 notice/warnings. The first 6 are to do with an object being passed instead of a string:
preg_match() expects parameter 2 to be string, object given
And 6 variations on this:
Object of class stdClass to string conversion
The last is less clear:
Model "Tournament" is not associated with model ""
I suspect I'm being colossally stupid, but there we go.
The contain uses conditions as a normal find, a subquery can be generated and put in conditions. So you should be able to do this as well. Try the subquery part in here and tell me how did it go ;)
This way of generating subqueries for conditions shouldn't fail :D since is the cakephp way.
If you got an error or something comment the answer to see if i can help.
Related
I have a table I need to pull records from if the row is between certain times. But some of the times are UFN(until further notice). How can I get cakephp to ignore the 'end' time if the end time is a string and not a time? Would it be easier if I force the user to keep the 'end time' blank if they want to display UFN?
Thanks in advance
EDIT:
The project I'm working on is sensitive so I can't post any of the actual code, but here's an example.
$this->Event->find('all', array(
'conditions' => array(
'Event.active_start <' => date('Y-m-d H:i:s', strtotime($date . " +31 minutes")),
'Event.active_stop >' => $date,
'Event.id >' => $id,
),
'order' => 'Event.active_start',
'group' => 'Event.id'
)
);
Event.active_start is always a datetime, but Event.active_stop can be a datetime or a string, usually 'UFN'.
This query is not pulling any rows that are strings.
Make 'Event.active_stop' as DATETIME field, allow to be empty.
Before save check if datetime format, if not unset($string)
After find (callback) if active_stop is empty field, return string 'UFN'
I'm trying to get a subset of results as a virtualField for use in my view. I may even be way off on how I'm approaching this, but here's what I've done so far:
I started with this question here: CakePHP virtualField find all not null which lead to this little beauty.
Now I have an issue where the find statement passing (Array) into the MySQL.
My code looks like:
class Transaction extends AppModel {
public function __construct($id = false, $table = null, $ds = null) {
parent::__construct($id, $table, $ds);
$this->virtualFields['Accounts'] = $this->find("all", array("conditions" => array("account !=" => null)));
}
And I'm seeing:
Error: SQLSTATE[42S22]: Column not found: 1054 Unknown column 'Array' in 'field list'
SQL Query: SELECT `Transaction`.`id`, `Transaction`.`name`,
`Transaction`.`person_id`, `Transaction`.`account`, (Array)
AS `Transaction__Accounts` FROM `my_database`.`transactions`
AS `Transaction` WHERE `Transaction`.`person_id` = (2)
I've also tried $this->Transaction->find and "Transaction.account !=", to no avail. I've found some other issues with the (Array) but none that help my situation. Any pointers in the right direction would be great.
Problem: your query results are an array, and you're telling SQL to assign a field name to each query result containing that array - virtual fields are only made to contain single level variables like strings.
Solution: use a join structure onto itself with those conditions which will return a nested result set along with each of your results. Use CakePHP's model relationships to do this:
<?php
class Transaction extends AppModel {
var $hasMany = array(
'Accounts' => array(
'className' => 'Transaction',
'foreignKey' => false,
'conditions' => array('Accounts.account IS NOT NULL')
)
);
}
?>
Example output:
Array(
'Transaction' => array( // transaction data),
'Accounts' => array( // associated transaction data with account set to null
)
Now, as you can probably gather from that result, if you return 1000 rows from Transaction, you'll get all results from Accounts nested into each Transaction result. This is far from ideal. From here, you can either make the join conditions more specific to target relevant Accounts records, or this is not the right approach for you.
Other approaches could be:
Accounts model, uses Transaction database table, implicit find conditions are that account is null
Manual query to retrieve these results in the afterFind() method of your Transaction model, which will retrieve these results once, and you'll then return array_merge($accounts, $transactions)
I'm trying to create an AJAX form whereby the content of a select field populates based on the choice of a preceding select field (you see this a lot with 'country' populating 'state/province'). In my case, I want users to be able to choose their province only if active accounts exist in it.
The Javascript I can write no problem. Fetching the data is where I'm... not so much stuck as doing too much work. CakePHP likes to build select fields with options in an array of the form
$options = array(select_option_value => display_text)
My strategy, though functional, must be more convoluted than cake intended (this a is segment of a controller method).
$provinceData = $this->Account->find('all',array('recursive' => 0,
'joins' => array(
array(
'table' => 'provinces',
'type' => 'LEFT',
'conditions' => array('Account.province_id = provinces.id')
)),
'fields'=>array('provinces.id', 'provinces.name', 'provinces.abbrev'),
'conditions' => array('registration > 2')));
$provinces = array();
foreach($provinceData as $pd) {
/*note: lowercase, plural below b/c can't get 'alias' => 'Province'
to work in joins array above : ( */
$id = $pd['provinces']['id'];
$name = $pd['provinces']['name'];
$provinces[$id] = $name;
}
$this->set(compact('provinces'));
Can anyone point out a more appropriate way to do this? I assume there must be a MySQL query that can do this, but I'm pretty bad at writing elaborate MySQL queries in the first place, let alone via Cake's convention (and, for you MySQL gurus out there, I'm happy to do this from a Model->query(//MySQL code) call instead!
Any and all help truly appreciated.
Assuming the relationship Account belongsTo Province you can try this code:
$accounts = $this->Account->find(
'all',
array(
'fields' => array('Account.province_id', 'Province.name'),
'conditions' => array('Account.registration > 2'),
'group' => 'Account.province_id'
)
);
$provinces = Hash::combine($accounts, '{n}.Account.province_id', '{n}.Province.name');
$this->set(compact('provinces'));
edit: missed bracket and a period instead of an underscore . Now should work
I'm trying to use the "HAVING" clause in a SQL query using the CakePHP paginate() method.
After some searching around it looks like this can't be achieved through Cake's paginate()/find() methods.
The code I have looks something like this:
$this->paginate = array(
'fields' => $fields,
'conditions' => $conditions,
'recursive' => 1,
'limit' => 10,
'order' => $order,
'group' => 'Venue.id');
One of the $fields is an alias "distance". I want to add a query for when distance < 25 (e.g. HAVING distance < 25).
I have seen two workarounds so far, unfortunately neither suit my needs. The two I've seen are:
1) Adding the HAVING clause in the "group" option. e.g. 'group' => 'Venue.id HAVING distance < 25'. This doesn't seem to work when used in conjunction with pagination as it messes up the initial count query that is performed. (ie tries to SELECT distinct(Venue.id HAVING distance < 25) which is obviously invalid syntax.
2) Adding the HAVING clause after the WHERE condition (e.g. WHERE 1 = 1 HAVING field > 25) This doesn't work as it seems the HAVING clause must come after the group statement which Cake is placing after the WHERE condition in the query it generates.
Does anyone know of a way to do this with CakePHP's find() method? I don't want to use query() as that would involve a lot of rework and also mean I'd need to implement my own pagination logic!
Thanks in advance
You have to put it with the group conditions. like this
$this->find('all', array(
'conditions' => array(
'Post.length >=' => 100
),
'fields' => array(
'Author.id', 'COUNT(*) as Total'
),
'group' => array(
'Total HAVING Total > 10'
)
));
Hope it helps you
I used the following trick to add my own HAVING clause at the end of my WHERE clause. The "dbo->expression()" method is mentioned in the cake sub-query documentation.
function addHaving(array $existingConditions, $havingClause) {
$model = 'User';
$db = $this->$model->getDataSource();
// Two fun things at play here,
// 1 - mysql doesn't allow you to use aliases in WHERE clause
// 2 - Cake doesn't allow a HAVING clause separate from a GROUP BY
// This expression should go last in the WHERE clause (following the last AND)
$taut = count($existingConditions) > 0 ? '1 = 1' : '';
$having = $db->expression("$taut HAVING $havingClause");
$existingConditions[] = $having;
return $existingConditions;
}
As per the manual, CakePHP/2 supports having at last. It was added as find array parameter on version 2.10.0, released on 22nd July 2017.
From the 2.10 Migration Guide:
Model::find() now supports having and lock options that enable you to
add HAVING and FOR UPDATE locking clauses to your find operations.
Just had the same problem. I know, one is not supposed to modify the internal code but if you open the PaginatorComponent and you modify line 188:
$count = $object->find('count', array_merge($parameters, $extra));
to this:
$count = $object->find(
'count',
array_merge(array("fields" => $fields),$parameters, $extra)
);
Everything will be fixed. You will be able to add your HAVING clause to the 'group' and the COUNT(*) won't be a problem.
Or, make line:
$count = $object->paginateCount($conditions, $recursive, $extra);
to include the $fields:
$count = $object->paginateCount($fields,$conditions, $recursive, $extra);
After that, you can "override" the method on the Model and make sure to include the $fields in the find() and that's it!, =P
Here is another idea that doesn't solve the pagination issue, but it is clean since it just overrides the find command in AppModel. Just add a group and having element to your query and this will convert to a HAVING clause.
public function find($type = 'first', $query = array()) {
if (!empty($query['having']) && is_array($query['having']) && !empty($query['group'])) {
if ($type == 'all') {
if (!is_array($query['group'])) {
$query['group'] = array($query['group']);
}
$ds = $this->getDataSource();
$having = $ds->conditions($query['having'], true, false);
$query['group'][count($query['group']) - 1] .= " HAVING $having";
CakeLog::write('debug', 'Model->find: out query=' . print_r($query, true));
} else {
unset($query['having']);
}
}
return parent::find($type, $query);
}
Found it here
https://groups.google.com/forum/?fromgroups=#!topic/tickets-cakephp/EYFxihwb55I
Using 'having' in find did not work for me. Instead I put into one string with the group
" group => product_id, color_id having sum(quantity) > 2000 " and works like a charm.
Using CakePHP 2.9
I have the following two ActiveRecord queries in an application_helper.rb file:
#left_menu = Page.select('id, menu_name').where(:published => true, :left_menu => true).order("sort")
Also can be written as:
#left_menu = Page.select('id, menu_name').where(:published => true, :left_menu => true).order("'sort' ASC")
and:
#left_menu = Page.find(:all, :conditions => {:published => true, :left_menu => true}, :order => :sort)
Why does the first one fail to sort on the 'sort' column, while the second one does not? Both work in SQLite, but only the second one works in MySQL.
Any ideas?
it's the quote in ther order params .
the query generated will be (similar to)
"SELECT id, title FROM `pages` WHERE (`pages`.`pub` = 1) ORDER BY 'sort' ASC"
its the char ' quote . It's wrong sql syntax , it's going to order by costant value not column value . sqlite allow it , mysql not.
try to simple use
Page.select('id, menu_name').where(:published => true, :left_menu => true).order("sort ASC")
without single quote in the order chain method parameters.
sorry for my english.
have a nice day