I have three tables persons, jobs, jobs_persons
One person can have multiple jobs.
Person 1 is Technical Support AND Manager
Person 2 is Technical Support
Person 3 Is Manager
Job 1 Technical Support
Job 2 Manager
I need to find a query give me the result for the person who currently is Technical Support AND Manager
The answer would be only Person 1
SELECT persons.*
FROM persons INNER JOIN jobs_persons ON persons.id = jobs_persons.person_id
INNER JOIN jobs ON jobs.id = jobs_persons.job_id
WHERE job.id IN (1,2)
Returns 3 rows
SELECT persons.*
FROM persons INNER JOIN jobs_persons ON persons.id = jobs_persons.person_id
INNER JOIN jobs ON jobs.id = jobs_persons.job_id
WHERE job.id = 1 AND job.id = 2
Returns 0 rows.
I'm currently working on Ruby on Rails.
Somebody can help?
You want to use an OR operator. Using job.id = 1 AND job.id = 2 will only return elements where id equals 1 and at the same time 2. No element can do that. You want elemets where th id is 1 or where the id is 2.
to make it more obvious:
SELECT * FROM table WHERE lastname = 'Smith' AND firstname = 'James';
when executing this you obviously don't want everybody who is called Smith or James. ;-)
EDIT:
Misread the question. what you need is a second join to join the jobs table two times in and join them with the different jobs. It is a bit hard as you didn't show the schema, but this might work:
SELECT persons.*
FROM persons
INNER JOIN jobs_persons jp1 ON persons.id = jp1.person_id
INNER JOIN jobs_persons jp2 ON persons.id = jp2.person_id
INNER JOIN jobs j1 ON j1.id = jp1.job_id
INNER JOIN jobs j2 ON j2.id = jp2.job_id
WHERE j1.id = 1 AND j2.id = 2
Try this to get all the person who has got a job of 1 AND 2 in your associative entity table. No need to hit the job table.
SELECT p.*
FROM persons p
WHERE id in (
SELECT person_id FROM jobs_persons
WHERE job_id IN (1,2)
GROUP BY person_id
HAVING COUNT(*) = 2
);
With your recent comments, it seems you're having performance problems. That's really outside of the scope of this question and answer.
You need to make sure your indexes are in place on the appropriate columns:
jobs_person.job_id
persons.id
Related
This question already has answers here:
Left Outer Join doesn't return all rows from my left table?
(3 answers)
Closed 6 months ago.
studentTable:
id
studentName
1
Name1
2
Name2
3
Name3
studentCourseTable:
id
studentId
courseId
1
1
1
2
1
2
3
3
1
4
3
3
5
2
2
I want to (let's say) list students who have taken courseId 1 AND 3 (together) BUT have NOT taken 2. Or any dynamic combination such as that, like courseId 1,2,3 should be taken; 1,2 not taken but 3 is taken etc etc.
I have tried some JOIN clause to filter but have not been able to apply more than 1 condition:
SELECT student.*
FROM studentTable AS s
LEFT JOIN studentCourseTable AS sc
ON sc.studentId = s.id
WHERE sc.studentId IN (1,3)
AND sc.studentId NOT IN (2)
or:
SELECT student.*
FROM studentTable AS s
LEFT JOIN studentCourseTable AS sc
ON sc.studentId = s.id
AND sc.courseId IN (1, 3)
AND sc.courseId IN (2)
The important thing is that I want to find students that take specified courses TOGETHER, AND not take any other specified course. The student may take more courses than specified (as long as it is not in NOT taken list).
**Edit for some clarifications: ** For example if I say the student should take (2,4) but NOT (3), returning a student that takes (2,4,5) is ok. But (2,3) or (2,4,5) are NOT ok.
There are some other tables that I'm joining the student table with, not sure if it matters but this is the gist of it.
Can anyone assist me with this?
** Edit: ** #lemon has cracked it. Here's the demo he made, which lists any user that attended 1 OR 3 AND have not attended 2. Here's my updated demo which lists students that attended 1 AND 3 AND have not attended 2.
Thanks to all who helped me, this was superb.
You can select all information from your students and use two kind of JOIN operations:
an INNER JOIN for each due attended course
a LEFT JOIN for non-attended courses, to be filtered out in the WHERE clause
SELECT s.*
FROM students s
INNER JOIN (SELECT DISTINCT studentId FROM courses WHERE courseId = 1) c1
ON s.id = c1.studentId
INNER JOIN (SELECT DISTINCT studentId FROM courses WHERE courseId = 3) c3
ON s.id = c3.studentId
LEFT JOIN (SELECT DISTINCT studentId FROM courses WHERE courseId IN (2)) not_c
ON s.id = not_c.studentId
WHERE not_c.studentId IS NULL
Check the demo here.
Another option is to count
positively your needed courses
negatively your unneeded courses
Eventually sum up the values, and filter out those students whom don't have sum equal to the amount of needed courses.
SELECT s.*
FROM courses c
INNER JOIN students s
ON s.id = c.studentId
GROUP BY s.id,
s.studentName
HAVING SUM(CASE WHEN c.courseId IN (1,3) THEN 1
WHEN c.courseId IN (2) THEN -1 END) = 2
Check the demo here.
To get only students that are in groups 1 and 3
SELECT s.studentName
from studenttable AS s
INNER JOIN studentCourseTable AS sc ON sc.studentId = s.id
where sc.courseId in (1,3)
group by s.id
having count(*) = 2;
We first should group by student name or id, then we get only those that are in the 2 courses by adding "having count(*) = 2"
So i have this relational model for hospital (not made by me).
Patient (has an adress and an id), hospital (has id and address), and also there's a table for relationship representing placement in the hospital (hospital.id, patient.id) (also there's other tables, but they don't matter in this query);
The purpose of the query is to find hospitals where is no placed patients from from other cities than hospital's one (on condition that address only contains city).
The problem that i have is theoretical, i don't really know if to use full outer join with a or b null, or something else in the query that finds hospitals containing "foreign" patients, (like join hospital with its placement and then full outer join with a or b table record null, but that leads to a question will i get results in the query? Because i need cities that don't match but all the explanations of that join are about .
Thanks to all who embraced my utterly imperfect english and understood it.
Upd.
Patient:
id=1, city =A;
id=2, city =B;
id=3, city =B;
id=4, city =A;
id=5, city =C;
Hospital:
Id =1, city=A
id =2, city=B;
Placement:
h.id p.id
1 1
1 4
2 2
2 3
2 5
Expected results is "1", id of the first hospital (where's no patients from other city) and others with that "feature"
my query is like
select id from hospital where id not in
(select id,address from hospital inner join placement on h.id=placement.h.id as b inner join patient on placement.p.id=p.id where hospital.address<>patient.address )
Sorry for the delay
Is shawn's query correct?
Can i use h.id instead 1? Idk if our teacher would accept that, because he's never showed us something like that and in 10 years he hasn't managed to create an example of that database for students to test queries on.
select * from hospitals h
where not exists (
select 1 -- dummy value, use h.id if you prefer
from patients p inner join placement pl on pl.pid = p.id
where pl.hid = h.id and p.city <> h.city
)
or
select h.id
from hospitals h
left outer join
placement pl inner join patients p on p.id = pl.pid
on pl.hid = h.id
group by h.id
-- this won't count nulls resulting from zero placements for that hospital
-- as long as standard sql null comparisons are active
having count(case when h.city <> p.city then 1 end) = 0
Looks like it works to me: http://rextester.com/BTJB59061
SELECT p.id, p.first
FROM people p
LEFT JOIN job j ON ( p.job_id = j.id )
LEFT JOIN favourites f ON ( p.company_id = f.company_id )
WHERE p.company_id = 1
I have 3 tables.
Job Favourites People
Each have company_id inside them. When I try the above it outputs p.id,p.first twice. If I remove one of the JOINs then the output is as expected but without the table which was removed.
As I said in the comments what you have here is just an one-to-many relationship which gives you exactly what you are saying.
Like you have a registry on people and you have two favourites to this people on table favourite. To clarify consider the following situation:
Table people:
id name job_id first
1 John 1 1
2 Campos 2 2
Table job
id job
1 Programmer
2 Developer
Table favourites
company_id desc
1 Blah
2 Bleh
1 Blih
On the above model a people have two favourites registries.
For your model it seems that one people can have only one job, but since you did not specify what the table favourites looks like it is probably the the situation i've shown is generating your problem. So to quickly solve it you can use a DISTINCT command like:
SELECT DISTINCT p.id, p.first
FROM people p
LEFT JOIN job j
ON ( p.job_id = j.id )
LEFT JOIN favourites f
ON ( p.company_id = f.company_id )
WHERE p.company_id = 1
I have three tables, I'll just list the important columns
db_players
id | name
players
id | teamid | careerid
db_teams
The db_teams id links to the players teamid.
I need to run a query where I select rows from db_players as long as db_teams.id isn't in a row in players as teamid where the careerid = 1.
I've never attempted this type of query with mysql before, I know I could do two queries and involve php but I'm intrigued as to whether it's possible with a pure db query.
Thanks.
EDIT - simpler now.
SELECT dp.first_name
FROM tbl_foot_career_db_players dp
INNER JOIN tbl_foot_career_players p
ON p.playerid != dp.id
WHERE p.careerid = 1
The idea is that I want to return all rows from tbl_foot_career_db_players WHERE the id from that table isn't present in a row in tbl_foot_career_players in the column playerid. And the tbl_foot_career_players.careerid must also equal 1.
List all db_players that are not in players with career = 1
SELECT d.*
FROM db_players d
LEFT JOIN players p
ON p.player_id = d.id
AND p.career = 1
WHERE p.id IS NULL
Try to JOIN them with db_players id is not in players teamid.
SELECT db_players.* FROM db_players
LEFT JOIN players ON players.id != db_players.id
LEFT JOIN db_teams ON players.teamid = db_teams.id
WHERE careerid = 1
I'm working on a mysql query in a Drupal database that pulls together users and two different cck content types. I know people ask for help with groupwise maximum queries all the time... I've done my best but I need help.
This is what I have so far:
# the artists
SELECT
users.uid,
users.name AS username,
n1.title AS artist_name
FROM users
LEFT JOIN users_roles ur
ON users.uid=ur.uid
INNER JOIN role r
ON ur.rid=r.rid
AND r.name='artist'
LEFT JOIN node n1
ON n1.uid = users.uid
AND n1.type = 'submission'
WHERE users.status = 1
ORDER BY users.name;
This gives me data that looks like:
uid username artist_name
1 foo Joe the Plumber
2 bar Jane Doe
3 baz The Tooth Fairy
Also, I've got this query:
# artwork
SELECT
n.nid,
n.uid,
a.field_order_value
FROM node n
LEFT JOIN content_type_artwork a
ON n.nid = a.nid
WHERE n.type = 'artwork'
ORDER BY n.uid, a.field_order_value;
Which gives me data like this:
nid uid field_order_value
1 1 1
2 1 3
3 1 2
4 2 NULL
5 3 1
6 3 1
Additional relevant info:
nid is the primary key for an Artwork
every Artist has one or more Artworks
valid data for field_order_value is NULL, 1, 2, 3, or 4
field_order_value is not necessarily unique per Artist - an Artist could have 4 Artworks all with field_order_value = 1.
What I want is the row with the minimum field_order_value from my second query joined with the artist information from the first query. In cases where the field_order_value is not valuable information (either because the Artist has used duplicate values among their Artworks or left that field NULL), I would like the row with the minimum nid from the second query.
The Solution
Using divide and conquer as a strategy and mysql views as a technique, and referencing this article about groupwise maximum queries, I solved my problem.
Create the View
# artists and artworks all in one table
CREATE VIEW artists_artwork AS
SELECT
users.uid,
users.name AS artist,
COALESCE(n1.title, 'Not Yet Entered') AS artist_name,
n2.nid,
a.field_image_fid,
COALESCE(a.field_order_value, 1) AS field_order_value
FROM users
LEFT JOIN users_roles ur
ON users.uid=ur.uid
INNER JOIN role r
ON ur.rid=r.rid
AND r.name='artist'
LEFT JOIN node n1
ON n1.uid = users.uid
AND n1.type = 'submission'
LEFT JOIN node n2
ON n2.uid = users.uid
AND n2.type = 'artwork'
LEFT JOIN content_type_artwork a ON n2.nid = a.nid
WHERE users.status = 1;
Query the View
SELECT
a2.uid,
a2.artist,
a2.artist_name,
a2.nid,
a2.field_image_fid,
a2.field_order_value
FROM (
SELECT
uid,
MIN(field_order_value) AS field_order_value
FROM artists_artwork
GROUP BY uid
) a1
JOIN artists_artwork a2
ON a2.nid = (
SELECT
nid
FROM artists_artwork a
WHERE a.uid = a1.uid
AND a.field_order_value = a1.field_order_value
ORDER BY
uid ASC, field_order_value ASC, nid ASC
LIMIT 1
)
ORDER BY artist;
A simple solution to this can be to create views in your database that can then be joined together. This is especially useful if you often want to see the intermediate data in the same way in some other place. While it is possible to mash together the one huge query, I just take the divide and conquer approach sometimes.