How do $_REQUEST two fields and post them together on another page? - mysql

Question

I have a form that inserts data into mySQL. It works fine.
After the submission, I have a success page that displays 'part_no'. I need to also show 'add_qty', as well.
How do i alter my post script to show two field data's on the success page?
Here is part of my code (that already works):
$part_no = $_REQUEST['part_no'] ;
header("location: inv_fc_add_success.php?part_no=" . urlencode($part_no));
}
else {
header("location: inv_fc_add_fail.php");
}
?>

Answer 1

Just append it as another $_GET variable i.e part_no="part"&quantity=1
header("location: inv_fc_add_success.php?part_no=" . urlencode($part_no)."&qty=".$quantity );

Answer 2

You need 3 things.
First, you'll need:
$add_qty = $_REQUEST['add_qty'];
Alternatively you can simply use $_REQUEST['add_qty'] directly instead of assigning it to a new variable ($add_qty).
Then instead of:
header("location: inv_fc_add_success.php?part_no=" . urlencode($part_no));
you need:
header("location: inv_fc_add_success.php?part_no=" . urlencode($part_no) . "&add_qty=" . urlencode($add_qty));
Then, on the page inv_fc_add_success.php (which you will need to edit), you display the variable the same way that you display $part_no. As always, you can either assign it to a variable, like you already do at the top, or you can just use $_REQUEST['add_qty'] directory.