I need to get the average rating and the total number of ratings for a particular user and then select all single ratings (rating_value, rating_text, creator) as well:
$rating_query = mysql_query("SELECT COUNT(1) as rating_count
,AVG(rating_value), rating_value, rating_text, creator
FROM user_rating WHERE rated_user = $user_id");
This query would return the COUNT(1) result and the AVG(rating_value) for every row, but I only need those values once.
Is there any way to do this without making 2 separate queries?
There may be a trick I'm not aware of, but I don't think that's possible to do in a single query. You could try using a GROUP BY clause if that would make sense for you, but I'm guessing it probably doesn't from the column names you're using. Any relation requires a single atomic value at any given row and column, even if that value is null. What you are requesting is that columns 1 and 2 in every row but the first have no value, and again I don't think this is possible.
Related
My database is called: (training_session)
I try to print out some information from my data, but I do not want to have any duplicates. I do get it somehow, may someone tell me what I do wrong?
SELECT DISTINCT athlete_id AND duration FROM training_session
SELECT DISTINCT athlete_id, duration FROM training_session
It works perfectly if i use only one column, but when I add another. it does not work.
I think you misunderstood the use of DISTINCT.
There is big difference between using DISTINCT and GROUP BY.
Both have some sort of goal, but they have different purpose.
You use DISTINCT if you want to show a series of columns and never repeat. That means you dont care about calculations or group function aggregates. DISTINCT will show different RESULTS if you keep adding more columns in your SELECT (if the table has many columns)
You use GROUP BY if you want to show "distinctively" on a certain selected columns and you use group function to calculate the data related to it. Therefore you use GROUP BY if you want to use group functions.
Please check group functions you can use in this link.
https://dev.mysql.com/doc/refman/8.0/en/group-by-functions.html
EDIT 1:
It seems like you are trying to get the "latest" of a certain athlete, I'll assume the current scenario if there is no ID.
Here is my alternate solution:
SELECT a.athlete_id ,
( SELECT b.duration
FROM training_session as b
WHERE b.athlete_id = a.athlete_id -- connect
ORDER BY [latest column to sort] DESC
LIMIT 1
) last_duration
FROM training_session as a
GROUP BY a.athlete_id
ORDER BY a.athlete_id
This syntax is called IN-SELECT subquery. With the help of LIMIT 1, it shows the topmost record. In-select subquery must have 1 record to return or else it shows error.
MySQL's DISTINCT clause is used to filter out duplicate recordsets.
If your query was SELECT DISTINCT athlete_id FROM training_session then your output would be:
athlete_id
----------
1
2
3
4
5
6
As soon as you add another column to your query (in your example, the column called duration) then each record resulting from your query are unique, hence the results you're getting. In other words the query is working correctly.
I've been trying to learn MySQL, and I'm having some trouble creating a join query to not select duplicates.
Basically, here's where I'm at :
SELECT atable.phonenumber, btable.date
FROM btable
LEFT JOIN atable ON btable.id = atable.id
WHERE btable.country_id = 4
However, in my database, there is the possibility of having duplicate rows in column atable.phonenumber.
For example (added asterisks for clarity)
phonenumber | date
-------------|-----------
*555-681-2105 | 2015-08-12
555-425-5161 | 2015-08-15
331-484-7784 | 2015-08-17
*555-681-2105 | 2015-08-25
.. and so on.
I tried using SELECT DISTINCT but that doesn't work. I also was looking through other solutions which recommended GROUP BY, but that threw an error, most likely because of my WHERE clause and condition. Not really sure how I can easily accomplish this.
DISTINCT applies to the whole row being returned, essentially saying "I want only unique rows" - any row value may participate in making the row unique
You are getting phone numbers duplicated because you're only looking at the column in isolation. The database is looking at phone number and also date. The rows you posted have different dates, and these hence cause the rows to be different
I suggest you do as the commenter recommended and decide what you want to do with the dates. If you want the latest date for a phone number, do this:
SELECT atable.phonenumber, max(btable.date)
FROM battle
LEFT JOIN atable ON btable.id = atable.id
WHERE btable.country_id = 4
GROUP BY atable.phonenumber
When you write a query that uses grouping, you will get a set of rows where there is only one set of value combinations for anything that is in the group by list. In this case, only unique phone numbers. But, because you want other values as well (I.e. Date) you MUST use what's called an aggregate function, to specify what you want to do with all the various values that aren't part of the unique set. Sometimes it will be MAX or MIN, sometimes it will be SUM, COUNT, AVG and so on.
if you're familiar with hash tables or dictionaries from elsewhere in programming, this is what a group by is: it maps a set of values (a key) to a list of rows that have those key values, and then the aggregating function is applied to any of the values in the list associated with the key
The simple rule when using group by (and one that MySQL will do implicitly for you) is to write queries thus:
SELECT
List,
of,
columns,
you,
want,
in,
unique,
combination,
FN(List),
FN(of),
FN(columns),
FN(you),
FN(want),
FN(aggregating)
FROM table
GROUP BY
List,
of,
columns,
you,
want,
in,
unique,
combination
i.e. You can copy paste from your select list to your group list. MySQL does this implicitly for you if you don't do it (i.e. If you use one or more aggregate functions like max in your select list, but forget or omit the group by clause- it will take everything that isn't in an agggregate function and run the grouping as if you'd written it). Whether group by is hence largely redundant is often debated, but there do exist other things you can do with a group by, such as rollup, cube and grouping sets. Also you can group on a column, if that column is used in a deterministic function, without having to group on the result of he deterministic function. Whether there is any point to doing so is a debate for another time :)
You should add GROUP BY, and an aggregate to the date field, something like this:
SELECT atable.phonenumber, MAX(btable.date)
FROM btable
LEFT JOIN atable ON btable.id = atable.id
WHERE btable.country_id = 4
GROUP BY atable.phonenumber
This will return the maximum date, hat is the latest date...
I am working on a query that needs to output 'total engagements' by users in columns like 1 -eng column will display users who have one engagements, second column 2-eng which will display users who have done 2 engagements. Likewise 3eng, and so on. Note that the display should be like this. I have a engagement table which has userID. So I get distinct users like this
select count(distinct userID) from engagements
and I get engagements as
select count(*) from engagements
Engagements here refers to users who have either liked,replied,or shared the content
Please help. Thanks! I have used CASE and IF but unable to display in the below form
1eng 2eng 3eng
100 200 100
Consider returning the results in rows and pivoting them afterwards in your application.
To return the desired results in rows, you could use the following query:
SELECT
engagementCount,
COUNT(*) AS userCount
FROM (
SELECT
userID,
COUNT(*) AS engagementCount
FROM engagements
GROUP BY userID
) AS s
GROUP BY engagementCount
;
Basically, you first group the engagements rows by userID and get the row counts per userID. Afterwards, you use the counts as the grouping criterion and count how many users were found with that count.
If you insist on returning the columnar view in SQL, you'll need to resort to dynamic SQL because of the indefinite number of columns in the final result set. You'd probably need to store the results of the inner SELECT temporarily, scan it to build the list of count expressions for every engagementCount value and ultimately construct a query of this kind:
SELECT
COUNT(engagementCount = 1 OR NULL) AS `1eng`,
COUNT(engagementCount = 2 OR NULL) AS `2eng`,
COUNT(engagementCount = 3 OR NULL) AS `3eng`,
...
FROM temporary_storage
;
Or SUM(engagementCount = value) instead COUNT(engagementCount = value OR NULL). (For me, the latter expresses the intention more explicitly, hence why I've suggested it first, but, in case you happen to prefer the SUM technique, there should be no discernible difference in performance between the two. The OR NULL trick is explained here.)
I have a table of transactions that records the person that made the purchase. I want the number of people that have had more than one transaction. The part I became stuck at is how do I specify that Member must match at least twice (e.g. two or more transactions)?
I figured it'd be something along the lines of
SELECT COUNT(*) FROM `table` WHERE COUNT(`Member`)>2
but I realize that isn't a proper usage of the second count.
To further clarify: I want the result to be a single row that contains the number of users that this condition matches. So I don't want it to return how many times it matches per user or anything like that.
you need to use GROUP BY and HAVING.
SELECT COUNT(*) totalMember
FROM
(
SELECT Member
FROM `table`
GROUP BY Member
HAVING COUNT(Member) > 2
) a
I want to get the distinct value of a particular column however duplicity is not properly managed if more than 3 columns are selected.
The query is:
SELECT DISTINCT
ShoppingSessionId, userid
FROM
dbo.tbl_ShoppingCart
GROUP BY
ShoppingSessionId, userid
HAVING
userid = 7
This query produces correct result, but if we add another column then result is wrong.
Please help me as I want to use the ShoppingSessionId as a distinct, except when I want to use all the columns from the table, including with the where clause .
How can I do that?
The DISTINCT keyword applies to the entire row, never to a column.
Presently DISTINCT is not needed at all, because your script already makes sure that ShoppingSession is distinct: by specifying the column in GROUP BY and filtering on the other grouping column (userid).
When you add a third column to GROUP BY and it results in duplicated ShoppingSession, it means that some ShoppingSession values are associated with many different values of the added column.
If you want ShoppingSession to remain distinct after including that third column, you should decide which values of the the added column should be left in the output and which should be discarded. This is called aggregating. You could apply the MAX() function to that column, or MIN() or any other suitable aggregate function. Note that the column should not be included in GROUP BY in this case.
Here's an illustration of what I'm talking about:
SELECT
ShoppingSessionId,
userid,
MAX(YourThirdColumn) AS YourThirdColumn
FROM dbo.tbl_ShoppingCart
GROUP BY
ShoppingSessionId,
userid
HAVING userid = 7
There's one more note on your query. The HAVING clause is typically used for filtering on aggregated columns. If your filter does not involve aggregated columns, you'll be better off using the WHERE clause instead:
SELECT
ShoppingSessionId,
userid,
MAX(YourThirdColumn) AS YourThirdColumn
FROM dbo.tbl_ShoppingCart
WHERE userid = 7
GROUP BY
ShoppingSessionId,
userid
Although both queries would produce identical results, their efficiency would be different, because the first query would have to pull all rows, group/aggregate them, then discard all rows except userid = 7, but the second one would discard rows first and only then group/aggregate the remaining, which is much more efficient.
You could go even further and exclude the userid column from GROUP BY and pull its value with an aggregate function:
SELECT
ShoppingSessionId,
MAX(userid) AS userid,
MAX(YourThirdColumn) AS YourThirdColumn
FROM dbo.tbl_ShoppingCart
WHERE userid = 7
GROUP BY
ShoppingSessionId
Since all userid values in your output are supposed to contain 7 (because that's in your filter), you can just pick a maximum value per every ShoppingSession, knowing that it'll always be 7.