Very simple
I have a column of string like that :
abc1
abc2
abc3
abc4
abc5
I need to remove 'abc' from this column and keep only the number on the right, so column would have only the number like :
1
2
3
4
5
I thought about smth like that but it doesn't work
update table2
-> set col1 = case when 'abc1' then 1
-> else end;
I know how to concat text, I don't know how to undo it... Help please ^^;
#McArthey already hinted at it, but this is easy to do when the "abc" is consistently "abc" (i.e. the length doesn't change.)
Amongst the various string functions is one in particular: RIGHT(). This allows you to select a fixed number of characters from a string. e.g.
SELECT RIGHT('abc3',1) -- Results in "3"
SELECT RIGHT('abc3',2) -- Results in "c3"
Coupled with the LENGTH() function, you can conclude the numbers are anything past the 3rd character. i.e.
SELECT RIGHT('abc3',LENGTH('abc3')-3) -- Results in "3"
Obviously I'm using hard strings ('abc3'), but these can easily be replaced with column names.
The caveat here is that these all are based on fixed length letter prefixes. The more variable (changing) the "abc" in your example is, the harder picking the numeric value out of the column becomes.
If these are single digit values you could use
select right(column,1) ...
You may also find the REGEXP docs useful if it is more complex.
If you are trying to modify the column you will have to take the values separately and then concatenate them back together. It's difficult to give a precise answer since I don't know what you're trying to accomplish but you could do something with SUBSTR to grab the separate values.
Get 'abc': SUBSTR(column, 1,3)
Get digits: SUBSTR(column, 4)
Related
I have a use case as below:
I have thousands of records in the database and let's say I am having one column named myValue.
Now the myValue's actual value can be an alphanumeric string where the first two characters are alphabets, the next 6 characters are numbers and the last character is a fixed alphabet let say 'x', which may be or may not be present in the value. (For Example 'AB123456','AB123456x')
So I know the format of the value for myValue field but not know all the actual values as there are lots of records.
Now I want to retrieve all such values for which the value without last character x (For Example, 'AB123456') and the same value with last character x (For Example, 'AB123456x') exists.
So is there any way I can retrieve such data?
I am right now doing trial and error on existing data but have not found success and there are thousands of such rows, so any help on this would be appreciated a lot.
You can do so like this:
SELECT myvalue
FROM t
WHERE myvalue LIKE '________'
AND EXISTS (
SELECT 1
FROM t AS x
WHERE x.myvalue = CONCAT(t.myvalue, 'x')
)
A (most likely) faster alternate is:
SELECT TRIM(TRAILING 'x' FROM myvalue) AS myvalue2
FROM t
GROUP BY myvalue2
HAVING COUNT(DISTINCT myvalue) > 1
I have this column in a table which is comma delimited to separate the values.
Here's the sample data:
2003,2004
2003,2005
2003,2006
2003,2004,2005
2003,2007
I want to get all data that contains only 1 comma.
I've been playing around with the '%' and '_' wildcards, but I can't seem to get the results I need.
SELECT column FROM table WHERE column like '%_,%'
Replace the , with '' empty set then take the original length less the replaced length. if 1 then only 1 comma if > 1 then more than 1 comma.
The length difference would represent the number of commas.
Length(column) - length(Replace(column,',','')) as NumOfCommas
or
where Length(column) - length(Replace(column,',','')) =1
While this may solve the problem, I agree with what others have indicated. Storing multiple values in a single column in a RDBMS is asking for more trouble. Better to normalize the data and get it to at least 3rd Normal form!
You can also use find_in_set() method which searches a value in comma separated list, by picking the last value of column using substring_index we can then check result of find_in_set should be 2 so that its the second and last value from list
select *
from demo
where find_in_set(substring_index(data,',',-1),data) = 2
Demo
Maybe another solution is to use regular expression in your case it can look like this ^[0-9]{4},[0-9]{4}$ :
SELECT * FROM MyTable WHERE ColName REGEXP '^[0-9]{4},[0-9]{4}$'
Or if you want all non comma one or more time :
SELECT * FROM MyTable WHERE ColName REGEXP '^[^,]*,[^,]*$'
one of my table contains column path stores the URL example:\xyz\attachments, \abc\attachments, etc total i have 16 combinations to replace
i found rows by using rlike in where clause 'abc|xyz|'
have to update xyz with xxx or abc with yyyy
i am not sure how to update these part of the values of column. Is it possible using single query or i have to write 16 queries to do that? please advise here
This is not reliable, but is doable. Basically nested replace() calls:
UPDATE ...
SET yourfield = REPLACE(REPLACE(yourfield, '\\xyz', 'newtext'), '\\abc', 'othertext')
Note that if xyz or abc can appear in multiple places in either string, you may end up replacing something that shouldn't have been.
I have a quite big table in mysql and I need to change all the records related to this column.
records are like this :
/name/nm0000209/?ref_=ttfc_fc_cl_t1,
/name/nm0000151/?ref_=ttfc_fc_cl_t2,
...,
/name/nm0104594/?ref_=ttfc_fc_cl_t10
what I want is to keep only the string in the middle which is nm0000209, nm0000151,.... I know how to delete specific characters from the right or left of the words by REPLACE or Trim , .., but my problem is that in this case the number of characters in the third part of string are not equal (as you see when it reaches to 10, I have to delete 21 characters from the end instead of 20 characters and since this table contains lots of records I dont know how to do it.
I reaaly appreciate if someone could helop me,
thanks
I want is to keep only the string in the middle which is nm0000209, nm0000151...
You can use 'SUBSTRING_INDEX' on the column to crop part of the column value.
Following example assumes that the said column will have 'name/' as starting pattern.
Example:
update table_name
set column_name = substring_index(
substring_index( column_name, 'name/', -1 )
, '/', 1 );
The same can be used for updating with the same value.
Demo # MySQL Fiddle
One approach would be to use MYSQL's SUBSTRING_INDEX function. It would let you get whatever's after the last slash. Or after the second to last.
For your particular case
select
SUBSTRING_INDEX(SUBSTRING_INDEX(thefield,'/',-2 ),'/', 1)
from supertext
would yield the desired result
EDIT: for update purposes
UPDATE thetable
SET thefield=SUBSTRING_INDEX(SUBSTRING_INDEX(thefield,'/',-2 ),'/', 1)
I have this table under user_name='high'
function_description :
akram is in a date
test
akram is studying
test4
kheith is male
test3
I want a query that returns results of field that have at least an 'akram'
SELECT *
FROM functions
WHERE 'isEnabled'=1
AND 'isPrivate'=1
AND user_name='high'
AND function_description LIKE '%akram%'
and this returns absolutely nothing!
Why?
You are listing the column names as if they are strings. This is why it returns nothing.
Try this:
SELECT *
FROM functions
WHERE user_name='high'
AND function_description LIKE '%akram%'
edit: After trying to re-read your question... are isEnabled and isPrivate columns in this table?
edit2: updated.. remove those unknown columns.
You are comparing strings 'isEnabled' with integer 1, which likely leads to the integer being converted to a string, and the comparison then fails. (The alternative is that the string is converted to an integer 0 and the comparison still fails.)
In MySQL, you use back-quotes, not single quotes, to quote column and table names:
SELECT *
FROM `functions`
WHERE `isEnabled` = 1
AND `isPrivate` = 1
AND `user_name` = 'high'
AND `function_description` LIKE '%akram%'
In standard SQL, you use double quotes to create a 'delimited identifier'; in Microsoft SQL Server, you use square brackets around the names.
Please show the schema more carefully (column names, sample values, types if need be) next time.