Hi there i have some sql tables and i want to convert these in a "Drupal Node Format" but i don't know how to do it. Does someone knows at least which tables i have to write in order to have a full node with all the keys etc. ?
I will give an example :
I have theses Objects :
Anime
field animeID
field animeName
Producer
field producerID
field producerName
AnimeProducers
field animeID
field producerID
I have used the CCK module and i had created in my drupal a new Content Type Anime and a new Data Type Producer that exist in an Anime object.
How can i insert all the data from my simple mysql db into drupal ?
Sorry for the long post , i would like to give you the chance to understand my problem
Thx in advance for your time to read my post
You can use either the Feeds module to import flat CSV files, or there is a module called Migrate that seems promising (albiet pretty intense). Both work on Drupal 6 or 7.
mmmmm.... i think you can export CVS from your sql database and then use
http://drupal.org/project/node_import
to import this cvs data to nodes.....mmmm i don know if there is another non-programmatically way
The main tables for node property data are node and node_revision, have a look at the columns in those and it should be fairly obvious what needs to go in those.
As far as fields go, their storage is predictable so you would be able automate an import (although I don't envy you having to write that!). If your field is called 'field_anime' it's data will live in two tables: field_data_field_anime and field_revision_field_anime which are keyed by the entity ID (in this case node ID), entity type (in the case 'node' itself) and bundle (in this case the name of your node type). You should keep both tables up to date to ensure the revision system functions correctly.
The simplest way to do it though is with PHP and the node API functions:
/* This is for a single node, obviously you'd want to loop through your custom SQL data here */
$node = new stdClass;
$node->type = 'my_type';
$node->title = 'Title';
node_object_prepare($node);
// Fields
$node->field_anime[LANGUAGE_NONE] = array(0 => array('value' => $value_for_field));
$node->field_producer[LANGUAGE_NONE] = array(0 => array('value' => $value_for_field));
// And so on...
// Finally save the node
node_save($node);
If you use this method Drupal will handle a lot of the messy stuff for you (for example updating the taxonomy_index table automatically when adding a taxonomy term field to a node)
Related
Setup:
I'm using Ruby on Rails with ActiveRecord and MySQL.
I have a Coupon model.
It has an attribute called query, it is a string which could be run with a where.
For example:
#coupon.query
=> "'http://localhost:3003/hats' = :url OR 'http://localhost:3003/shoes' = :url"`
If I were to run this query it would either pass or fail based on the :url value I pass in.
# passes
Coupon.where(#coupon.query, url: 'http://localhost:3003/hats')
Coupon.where(#coupon.query, url: 'http://localhost:3003/shoes')
# fails
Coupon.where(#coupon.query, url: 'http://localhost:3003/some_other_url')
This query varies between Coupon models, but it will always be compared to the current url.
I need a way to say: Given an ActiveRecord collection #coupons only keep coupons with queries that pass.
The structure of the where is always the same, but the query changes.
Is there any way to do this without a loop? I could potentially have a lot of coupons and I am hoping to do this an ActiveRecord scope. Something like this?
#coupons.where(self.query, url: #url)
Perhaps I need to write a user defined function in my database?
Using multiple variables in a query is easy, but where the thing you are comparing your variable to is also a variable - that has me stumped. Any suggestions very appreciated.
I would agree with Les Nightingill's comment that this looks like something that should probably be solved at a more architectural level. I'd imagine an easy refactoring to extract a new CouponQuery model that's a 1:n table containing multiple entries for a coupon_id for each query url that should pass. Then you could use a simple join like
Coupon.joins(:coupon_query).where(coupon_queries: { url: my_url })
If adding a new table is not an option, and if you're running on a newer MySQL version (>= 5.7), you could consider transforming the query column (or adding a new json_query column) into a MySQL JSON field and using the new JSON_CONTAINS query.
If from the user-side they should be able to manage the queries as a plain text field, you could use a before_save hook on your model to translate this into the separate table structure or JSON format respectively.
But if neither is an option for you and you really need to stick with the query column that stores a plain string, then you could use a LIKE query to match the sub-string 'your-url' = :url:
Coupon.where('url LIKE "%? = :url%"', my_url)
which, if you e.g. pass 'http://localhost:3003/hats' as my_url would return something like this SQL query:
SELECT `coupons`.* FROM `coupons`
WHERE (url LIKE "%'http://localhost:3003/hats' = :url%")
I have a model with a UUID as primary key.
class Books(models.Model):
id = models.UUIDField(primary_key=True, default=uuid.uuid4, editable=False)
title = .....
And I have a simple query:
results = Books.objects.all()
All is working fine in terms of saving and retrieving data, but part of the record editing process requires storing records in the session variables which means I get the 'UUID('…') is not JSON serializable' error.
It seems to me, that the simplest answer is to convert the UUID objects to strings immediately after making the initial query, thus preventing multiple changes elsewhere. Does that sound logical? If so, I assume I could do it with some sort of list comprehension. Could someone help with the syntax please? Or direct me on the approach if preferred!
Many thanks.
#you have to use
import json
results = Books.objects.all().values('id')
json_str = json.dumps(results)
I'm trying to convert the output of a Model->find query into SQL to be input into a database completely separate from the current MySQL database being used by the cakePHP system. My problem is that I have several virtual fields in the models which are inevitably returned when performing a Model->find on the data. Clearly, I need to find and remove these virtual fields from the find if I am to convert the data into SQL, which will be used as input to an identical database as the original MySQL one. Is there a simple way to omit virtual fields? any way that this can be done in a version higher than 1.3 would also be very helpful.
Many thanks.
You can either only define your virtual fiels at runtime. This is what I usually do.
$this->virtualFields['x'] = 'y';
// find query
But you can also limit the find fields
'fields' => array('all fields without the virtual fields')
This will also skip your virtual fields.
Usually you don't want to verbosely define all fields, though.
You can also unset all the virtual fields for the find() call:
$tmp = $this->virtualFields;
$this->virtualFields = array();
// find query
$this->virtualFields = $tmp;
I am trying to grab two columns of data out of a database, using Ruby on Rails ActiveRecord calls and put them into a 2D JSON array for passing to the client.
I have it working for one column. Now I need to get it working for 2 columns.
This is what I have so far for the database call:
select("TOTAL").map{|x| x.TOTAL.ceil}
This is what I have for the controller:
#results = JSON.dump({ :totals => PerformanceResults.find_totals })
This gives me something like this:
{"totals" [145,132,863,693,372,74,838,91,18,172,84,90,373,161,160,173,1910,210,513,14,79,21,84,41,2630,0,93,150,2971]}
To get two columns, this is how I'm starting out, but it's not going well:
Database call:
select("TOTAL, time_stamp ").map{|x| x.attributes.slice(:x.TOTAL.ceil, x.time_stamp)}
Its telling me "undefined method `TOTAL' for :x:Symbol", which I understand, but since I'm new to Ruby on Rails and also JSON, I thought I'd ask for some help in doing this...
My goal is to get this passed to the client: {"totals" [['timestamp', data], ['timestamp', data], etc.... ]}
I have solved this on my own using the following for anyone looking for this solution in the future.
select("TOTAL, time_stamp ").map{|x| [x.TOTAL.ceil, x.time_stamp]}
In rails console, to fetch multiple columns, you could also use the following method. Suppose you have a User table and you wish to print the id's and email's of the users, You have to do it as shown below:
User.all.map{|user| "#{user.id},#{user.email}"}
This is an alternative to what was already explained above.
I want to use Jasypt with Hibernate in servlets. I refered Jasypt here. It says how to configure Hibernate. But, still it is not clear that how I can handle session to save & retrieve results. I did configurations of Hibernate as mentioned in above link(and I m not going to past them here again). Let me know how to save & retrieve data with Session.
For a simple example,lets say, I have a table called 'login' consisting 2 columns 'name','password'. column 'name' data type is varchar and 'password' is varbinary. The pojo class has variables String name and byte[] password. How can I save and retrieve data from table 'login'.At least any useful link which explain with sample codes ll be appreciated.
Edit
When I configured hibernate .hbm file & try to save as usual, an exception is also thrown.