I've been using the Regular Expression Explorer but I still can't come up with the right pattern.
Here's my URL:
http://pie.crust.com:18000/TEST/TEST.html
Here's my RegExp:
/[^http:\/\/][\w-\W]+[\/]/
And the output is:
ie.crust.com:18000/TEST/
All I want is the domain (basically everything inbetween // and /):
pie.crust.com:18000
What am I missing? I just can't figure it out. Any ideas?
Thank you in advance.
Try this one: http:\/\/([^\/]+)
The part [^http:\/\/] is the same as [^htp:\/] and just enumerates all the characters which shouldn't be in the start part of the resulting string. So for http://pie.crust.com:18000/TEST/TEST.html http://p matches this enumeration. I suggest you the following expression:
/http:\/\/([^\/]+)\/.*/
You can use String.replace() the following way:
var myUrl:String = "http://pie.crust.com:18000/TEST/TEST.html";
var refinedUrl:String = myUrl.replace(/http:\/\/([^\/]+)\/.*/, "$1");
Try this:
#http://+(.*?)/#
(Your regexp doesn't have to start and end with / - it's easier to use something else that isn't in your search string.
(?<=http:\/\/)[a-zA-Z.:0-9-]+
The p of "pie" is being matched as part of the http rule, and so is not included. Using a positive look-behind fixed this.
http://regexr.com?2uhjf
try this...
//http:\/\/([^\/]+)\/.***/
Related
My objective is to put all the URLs between "" so I'm trying to select them without the comma , then I will use the regular expression to do a large search/replace.
My current REGEX: "BigImage":\s(\[(.*)\])
I tried this but it doesn't work: "BigImage":\s(\[([^,]+)\])
"BigImage": [http://example.com/1.jpg,http://example.com/2.jpg,http://example.com/3.jpg]
Example: https://regex101.com/r/nE5eV3/30
You can make a regex for your urls, i don know, if it allways looks the same. For your links the regex would lookls like this:
(https?://(www)?[a-zA-Z0-9]*\.[a-zA-Z]{2,4}/[^\.]*\.(jpg|jpeg|png|gif))
This regex will match all of your urls (you posted in your question).
Full Blocks:
("BigImage": \[([^,\]]*,?)*\])
If you want to filter the string you posted above, you can use the regex above.
Tested with this site!
If you post a more complete example of your data, we can help you more.
I have a string in golang as follows.
discount = "("+discount+"% off)"
when passed to html via angularjs it is displayed as follows
(10 %o(MISSING)ff)
Any idea why it is happening?
Thanks in advance.
Something in your HTML rendering process is passing the string through go's fmt.Sprintf or similar. Try escaping the % by doubling it:
discount = "("+discount+"%% off)"
See http://play.golang.org/p/S_GEJXSfnD for a live example.
Looks like you need to escape the string. Try to use this module: http://golang.org/pkg/html/
I know this has been asked at least a thousand times but I can't find a proper regex that will match a name in this string here:
<td><div id="topbarUserName">Donald</div></td>
I want to get the name 'Donald' and the regex that's the closest is >[a-zA-Z0-9]+ but the result is >Donald.
I'm coding in PureBasic (It's syntax is similar to that of Basic) and it uses the PCRE library for regular expressions.
Can anyone help?
Josh's pattern will work if you only make use of the numbered group, not the whole match. If you have to use the whole match, use something like (?<=>)(\w+?)(?=<)
Either way, regex is widely known to not be good for parsing HTML.
Explanation:
(?<=) is used to check if something appears before the current item.
\w+? will match any "word"-character, one or more times, but stop whenever the rest of the pattern matches something, for this situation the ? could have been left out.
(?=) is used to check if something appears after the current item.
Try this
It should capture anything that is a letter / number
>([\w]+)<
Also I'm not exactly sure what your project limitations are, but it would be much easier to do something like this
$('#topbarUserName').text();
in jQuery instead of using a regex.
>([a-zA-Z]+) should do the Trick. Remember to get the grouping right.
Why not doing it with plain old basic string-functions?
a.w = FindString(HTMLstring.s, "topbarUserName") + 16 ; 2 for "> and topbar...
If a > 0
b.w = FindString(HTMLstring, "<", a)
If b > 0
c.w = b - a
Donald.s = Mid(HTMLstring,a, c)
EndIf
EndIf
Debug Donald
With Selenium IDE, how can I test if an element's inner text contains a specific string? For example:
<p id="fred">abcde</p>
'id=fred' contains "bcd" = true)
The Selenium-IDE documentation is helpful in this situation.
The command you are looking for is assertText, the locator would be id=fred and the text for example *bcd*.
It can be done with a simple wildcard:
verifyText
id="fred"
*bcd*
See selenium IDE Doc
You can also use:
assertElementPresent
css=p#fred:contains('bcd')
A solution with XPath:
Command: verify element present
Target: xpath=//div[#id='fred' and contains(.,'bcd')]
Are you able to use jQuery if so try something like
$("p#fred:contains('bcd')").css("text-decoration", "underline");
It seems regular expressions might work:
"The simplest character set is a character. The regular expression "the" contains three
character sets: "t," "h" and "e". It will match any line with the string "the" inside it.
This would also match the word "other". "
(From site: http://www.grymoire.com/Unix/Regular.html)
If you are using visual studio there is functionality for evaluating strings with regular expressions of ALL kinds (not just contains):
using System.Text.RegularExpressions;
Regex.IsMatch("YourInnerText", #"^[a-zA-Z]+$");
The expression I posted will check if the string contains ONLY letters.
Your regular expression would then according to my link be "bcd" or some string you construct at runtime. Or:
Regex.IsMatch("YourInnerText", #"bcd");
(Something like that anyway)
Hope it helped.
You can use the command assertTextPresent or verifyText
I have a big html file (87000+ lines) and want to delete all occurrences of onclick from all elements. Two examples of what I want to catch are:
1. onclick="fnSelectNode('name2',2, true);"
2. onclick="fnExpandNode('img3','node3','/include/format_DB.asp?Index2=3');"
The problem is that both function names and parameters passed to them are not the same. So I need a Regular expression that matches onclick= + anything + );"
And I need one that works in Notepad++
Thanks for helping ;-)
Not familiar with notepad++, but what I use in vim is:
onclick="[^"]+"
Of course this depends on there being double quotes around the onclick in every case...
This regular expression will fail if you have a " or ' character included within quotes escaped by a \. Other than that, this should do it.
(onclick="[^"]+")|(onclick='[^"]+')
onclick="[^"]+" works for me, for that 2 strings.
If you want to go with a regex:
/onclick=".*?"/
You could also use something which is DOM-aware, such as a HTML/XML parser, or even just load up jQuery:
$("[onclick]").removeAttr("onclick");
... and then copy the body HTML into a new file.
Could
onclick=\".+;\"
Work?
onclick=\".*\);\"
This regex should do the trick.
(\s+onclick=(?:"[^"]+")|(?:'[^']+'))
Open your file on dreamweaver, choose edit from the toolbar, select find and replace,
put onclick="[^"]+" in find field and keep replace blank
this will do the whole thing.
Enjoy