I am trying to learn some new things in MYSQL with PHPMyAdmin and I am wondering if the following thing is possible and how to get that to work. I'll try to explain it plain.
I have two tables
Table 1 = users & has
userID
username
etc.
Table 2 = users_permission & has
id
userID
is_admin
Now my idea was when I create record in table 1 by using an relation to table 2. It will automatically insert userID in Table 2 and create record based on default values. Is there someone who can help to get on track?
you need to make insertion for both tables seperately.
You first need to insert user into users table after that you need to insert into user permissions.
insert into users (userId, username) values( 1, 'JohnDoe');
insert into user_permission (id, userId, isAdmin) values (10, 1, 1);
For auto incremented ID column
insert into users (username) values('JohnDoe');
insert into user_permission (userId, isAdmin) values (LAST_INSERT_ID(), 1);
I am new to MySQL so bear with me please. I have set up a member table and a session table. When insert a new record in member table, session table will grab the assigned new record ID from member table and automatically insert into session table. Is this possible?
so the order will be something like:
insert new record(member table) -> fetch id(member table) -> insert new record(session table)
-I have already set up a foreign key in session table, but I don't know what to do
-Im using php, if this matter..
easily you can use LAST_INSERT_ID();
your query can be like this:
INSERT INTO members (id, name)
VALUES('', 'test');
INSERT INTO sessions (member_id, description)
VALUES(LAST_INSERT_ID(),'some description');
in this case id is set auto increment.
at the moment you insert your data into member table by using (LAST_INSERT_ID) the last inserted id will store in session table.
I have a table named invisible with 3 fields (user_id , username, password), and another table named user_info with fields (user_id , first_name and last_name). user_id from user_info has foreign key constraint on user_id from invisible and this id is auto generated by MySQL using auto increment. I want to insert data about user into these two tables. As of now what i had in mind was to insert a random unique username using INSERT
$username=bin2hex(openssl_random_pseudo_bytes(10));
$password=bin2hex(openssl_random_pseudo_bytes(10));
$query="INSERT INTO invisible SET username='$username', password='$password'";
mysqli_query($query);
And then do
mysqli_query("INSERT INTO user_info SET user_id=(SELECT user_id FROM invisible WHERE username=$username AND password=$password) , first_name=$first_name, last_name=$lastname");
This ,however, i think is a bad way of doing it, since the username and password need not be unique.
So my question is, is there a way to select the user_id from last insert without having to deal with username and password, or better yet, some way to do the whole thing in a better way, like maybe in a single step?
use mysqli::$insert_id:
$username=bin2hex(openssl_random_pseudo_bytes(10));
$password=bin2hex(openssl_random_pseudo_bytes(10));
$query="INSERT INTO invisible SET username='$username', password='$password'";
mysqli_query($query);
$inserted_user_id = mysqli::$insert_id;
mysqli_query("INSERT INTO user_info SET user_id=$inserted_user_id, first_name=$first_name, last_name=$lastname");
Just use LAST_INSERT_ID(), it contains the last auto generated key in the session (ie from your previous insert)
INSERT INTO invisible SET username='$username', password='$password';
INSERT INTO user_info SET user_id=LAST_INSERT_ID();
A simple SQLfiddle.
This question already has answers here:
Insert into multiple tables in one query
(6 answers)
Closed 1 year ago.
I tried searching a way to insert information in multiple tables in the same query, but found out it's impossible?
So I want to insert it by simply using multiple queries i.e;
INSERT INTO users (username, password) VALUES('test', 'test')
INSERT INTO profiles (userid, bio, homepage) VALUES('[id of the user here?]','Hello world!', 'http://www.stackoverflow.com')
But how can I give the auto-increment id from the users to the "manual" userid for the profile table?
No, you can't insert into multiple tables in one MySQL command. You can however use transactions.
BEGIN;
INSERT INTO users (username, password)
VALUES('test', 'test');
INSERT INTO profiles (userid, bio, homepage)
VALUES(LAST_INSERT_ID(),'Hello world!', 'http://www.stackoverflow.com');
COMMIT;
Have a look at LAST_INSERT_ID() to reuse autoincrement values.
You said "After all this time trying to figure it out, it still doesn't work. Can't I simply put the just generated ID in a $var and put that $var in all the MySQL commands?"
Let me elaborate: there are 3 possible ways here:
In the code you see above. This
does it all in MySQL, and the
LAST_INSERT_ID() in the second
statement will automatically be the
value of the autoincrement-column
that was inserted in the first
statement.
Unfortunately, when the second statement itself inserts rows in a table with an auto-increment column, the LAST_INSERT_ID() will be updated to that of table 2, and not table 1. If you still need that of table 1 afterwards, we will have to store it in a variable. This leads us to ways 2 and 3:
Will stock the LAST_INSERT_ID() in
a MySQL variable:
INSERT ...
SELECT LAST_INSERT_ID() INTO #mysql_variable_here;
INSERT INTO table2 (#mysql_variable_here, ...);
INSERT INTO table3 (#mysql_variable_here, ...);
Will stock the LAST_INSERT_ID() in a
php variable (or any language that
can connect to a database, of your
choice):
INSERT ...
Use your language to retrieve the LAST_INSERT_ID(), either by executing that literal statement in MySQL, or using for example php's mysql_insert_id() which does that for you
INSERT [use your php variable here]
WARNING
Whatever way of solving this you choose, you must decide what should happen should the execution be interrupted between queries (for example, your database-server crashes). If you can live with "some have finished, others not", don't read on.
If however, you decide "either all queries finish, or none finish - I do not want rows in some tables but no matching rows in others, I always want my database tables to be consistent", you need to wrap all statements in a transaction. That's why I used the BEGIN and COMMIT here.
fairly simple if you use stored procedures:
call insert_user_and_profile('f00','http://www.f00.com');
full script:
drop table if exists users;
create table users
(
user_id int unsigned not null auto_increment primary key,
username varchar(32) unique not null
)
engine=innodb;
drop table if exists user_profile;
create table user_profile
(
profile_id int unsigned not null auto_increment primary key,
user_id int unsigned not null,
homepage varchar(255) not null,
key (user_id)
)
engine=innodb;
drop procedure if exists insert_user_and_profile;
delimiter #
create procedure insert_user_and_profile
(
in p_username varchar(32),
in p_homepage varchar(255)
)
begin
declare v_user_id int unsigned default 0;
insert into users (username) values (p_username);
set v_user_id = last_insert_id(); -- save the newly created user_id
insert into user_profile (user_id, homepage) values (v_user_id, p_homepage);
end#
delimiter ;
call insert_user_and_profile('f00','http://www.f00.com');
select * from users;
select * from user_profile;
What would happen, if you want to create many such records ones (to register 10 users, not just one)?
I find the following solution (just 5 queryes):
Step I: Create temporary table to store new data.
CREATE TEMPORARY TABLE tmp (id bigint(20) NOT NULL, ...)...;
Next, fill this table with values.
INSERT INTO tmp (username, password, bio, homepage) VALUES $ALL_VAL
Here, instead of $ALL_VAL you place list of values: ('test1','test1','bio1','home1'),...,('testn','testn','bion','homen')
Step II: Send data to 'user' table.
INSERT IGNORE INTO users (username, password)
SELECT username, password FROM tmp;
Here, "IGNORE" can be used, if you allow some users already to be inside. Optionaly you can use UPDATE similar to step III, before this step, to find whom users are already inside (and mark them in tmp table). Here we suppouse, that username is declared as PRIMARY in users table.
Step III: Apply update to read all users id from users to tmp table. THIS IS ESSENTIAL STEP.
UPDATE tmp JOIN users ON tmp.username=users.username SET tmp.id=users.id
Step IV: Create another table, useing read id for users
INSERT INTO profiles (userid, bio, homepage)
SELECT id, bio, homepage FROM tmp
have a look at mysql_insert_id()
here the documentation: http://in.php.net/manual/en/function.mysql-insert-id.php
try this
$sql= " INSERT INTO users (username, password) VALUES('test', 'test') ";
mysql_query($sql);
$user_id= mysql_insert_id();
if(!empty($user_id) {
$sql=INSERT INTO profiles (userid, bio, homepage) VALUES($user_id,'Hello world!', 'http://www.stackoverflow.com');
/* or
$sql=INSERT INTO profiles (userid, bio, homepage) VALUES(LAST_INSERT_ID(),'Hello world!', 'http://www.stackoverflow.com'); */
mysql_query($sql);
};
References
PHP
MYSQL
Just a remark about your saying
Hi, I tried searching a way to insert information in multiple tables in the same query
Do you eat all your lunch dishes mixed with drinks in the same bowl?
I suppose - no.
Same here.
There are things we do separately.
2 insert queries are 2 insert queries. It's all right. Nothing wrong with it. No need to mash it in one.
Same for select. A query must be sensible and do its job. That's the only reasons. Number of queries is not.
There is no point in looking for a way to stuff different queries in one call. Different calls is how the database API is meant to work.
For PDO You may do this
$dbh->beginTransaction();
$stmt1 = "INSERT INTO users (username, password) VALUES('test', 'test')";
$stmt2 = "INSERT INTO profiles (userid, bio, homepage) VALUES('LAST_INSERT_ID(),'Hello world!', 'http://www.stackoverflow.com')";
$sth1 = $dbh->prepare($stmt1);
$sth2 = $dbh->prepare($stmt2);
$sth1->execute (array ('test','test'));
$sth2->execute (array ('Hello world!','http://www.stackoverflow.com'));
$dbh->commit();
I am trying to implement a rating system where I keep the following two fields in my db table:
rating (the current rating)
num_rates (the number of ratings submitted so far)
UPDATE `mytable`
SET rating=((rating*num_rates)+$theRating)/num_rates, num_rates=num_rates+1
WHERE uniqueCol='$uniqueCol'
the variables are from my PHP code.
So, basically sometimes the row with the uniqueCol does not exist in the DB, so how can I do the above statement if the exists and if it doesn't then do something like this:
INSERT INTO `mytable`
SET rating=$theRating, num_rates=1, uniqueCol=$uniqueCol
Have a look at INSERT ... ON DUPLICATE KEY UPDATE.
It should look something like that:
INSERT INTO mytable (rating, num_rates, uniqueCol)
VALUES ($theRating, 1, $uniqueCol)
ON DUPLICATE KEY UPDATE
rating=((rating*num_rates)+$theRating)/num_rates,
num_rates=num_rates+1;
Make sure to have a UNIQUE index or PRIMARY KEY on your uniqueCol.