I need to add a "0" before a integer field in a MYSQL table. How do I update those fields so they have a ) added to them? Thanks.
You can't unless you change the column type to string. However you can add the zero when reading the field:
SELECT CONCAT( '0', int_col ) FROM ....
If you want to format the output of all integer values in one column to a fixed column size, say 5, with leading zeroes for small numbers, use an ALTER TABLE statement like:
ALTER TABLE table MODIFY `col` INT(5) ZEROFILL;
Refer to MySQL 5.1 Reference Manual.
Related
I have a column of decimals, but MySQL is reading them as TEXT. I tried this to alter the column by:
ALTER TABLE `engine_type_project`.`weo_data_eu_test`
CHANGE COLUMN `Mean_GDP_all_time` `Mean_GDP_all_time` DECIMAL(6,2) NULL DEFAULT NULL;
An original value is: 3,282.772
But my code returns it as: 3.00
Prior to this, I attempted:
SELECT CAST('Mean_GDP_all_time' AS DECIMAL(6,2))
FROM weo_data_eu_test;
But the entire column returned as 0.00
In casting non-numeric values to numeric, mysql does not expect commas. So it gives up looking for additional parts of the number after the "3".
Before changing the type, remove the commas with:
update weo_data_eu_test set Mean_GDP_all_time=replace(Mean_GDP_all_time,',','')
fiddle
I have a database with a column named "price" - within this column there are prices rounded to 5 decimal places, e.g 62.083333 - I would like to run a command to change every value within "price" column to just 2 decimal places, e.g 62.08
Is there a simple command to run on this column? We have over 36,000,000 values so would prefer not to have to update them all manually! :)
Would this command be the one?
SELECT CONVERT(DECIMAL(20,2),price)
Here's a similar question: mass update mysql table decimal value and change column field type
You can use
ALTER TABLE '<name>' CHANGE COLUMN '<name>' DECIMAL(20,2)
Simply alter table and modify data type
ALTER TABLE [TableName] MODIFY COLUMN [ColumnNameHere] decimal(20,2)
Try ,
UPDATE table_name SET price = round(price,2) where your
conditions;
I have a table with more than 1 million records, in 2 columns with datatype varchar(50) I have values like 23.23.
I need to convert the data/values to int.
For Example, 23.23 to 23 by remove the floating points.
I don't have primary key on this table.
ALTER TABLE t1 CHANGE <column_name> <column_name> <type>
note: you have to write column name twice
OR
ALTER TABLE t1 MODIFY <column_name> <type> ;
Reference
You can use FLOOR:
SELECT FLOOR(columnName)
FROM TableName
Floor returns the largest integer value not greater than X.
Read more here.
To convert the datatype of the field:
ALTER TABLE TableName CHANGE columnName newColumnName targetFieldType;
Try this:
SELECT ROUND(5.693893);
SELECT FLOOR(7.55);
You can try casting this field to a Decimal.
SELECT CAST(field AS DECIMAL(10,0)) FROM table;
I had the same issue. My table has a field that is of type 'float' which I needed to be of type 'int'.
Thanks to Neels!
So, I had to first convert the field to be of type DECIMAL with 10,0 (no value after decimal) and then convert the field to be INT with length 11 for example.
ALTER TABLE track CHANGE type type DECIMAL(10,0);
ALTER TABLE track CHANGE type type INT(11);
ALTER TABLE tablename CHANGE columnname columnname INT
I'm trying to insert rows from one table to the other. In the first table, the datatype of one column is char(5), but the same column has tinyint(4) datatype in the second table. When i run the insert query, it says
Incorrect integer value: '' for column 'x' at row 258
I cannot alter or modify the datatype now as it violates some constraints. Is there a way to use cast or convert char to tinyint?
Thanks.
You probably want something like this:
INSERT INTO newtable
SELECT CASE WHEN x = '' THEN 0 ELSE x END
FROM oldtable
I'm assuming that you want blanks to turn into zeros? If not, then provide the integer value you want blanks to have.
If there are other exceptions, use more alternatives in the CASE expression.
I am using MySQL database.
I have one table having column with datatype binary(16).
I need help with the insert statement for this table.
Example:
CREATE TABLE `assignedresource` (
`distid` binary(16) NOT NULL
)
insert into assignedresource values ('9fad5e9e-efdf-b449');
Error : Lookup Error - MySQL Database Error: Data too long for column 'distid' at row 1
How to resolve this issue?
You should remove the hyphens to make the value match the length of the field...
Example:
CREATE TABLE `assignedresource` (
`distid` binary(16) NOT NULL
)
insert into assignedresource values ('9fad5e9eefdfb449');
Also, MySQL standard is to use this notation to denote the string as binary... X'9fad5e9eefdfb449', i.e.
insert into assignedresource values (X'9fad5e9eefdfb449');
Well, assuming that you want to strictly insert a hexadecimal string, first you need to remove the dashes and then "unhex" your string before inserting it into a binary(16) data type column, the code would go like this:
INSERT INTO `assignedresource` VALUES(UNHEX(REPLACE('9fad5e9e-efdf-b449','-','')));
Also... the "usable" data you are inserting is actually 8 bytes after undashing it, so binary(8) would do fine if you plan on not storing the dashes.
You can strip the hyphens and perpend 0x to the value unquoted, like this:
insert into assignedresource values (0x9fad5e9eefdfb449);
As well as, as this (mentioned in other answers):
insert into assignedresource values (X'9fad5e9eefdfb449');
Both are valid notation for a hexadecimal literal.
Your string is 18 char long, change the database
CREATE TABLE `assignedresource` (
`distid` binary(18) NOT NULL
)