I have the following table:
---------------------------
| id | capital_id | value |
---------------------------
| 1 | 1 | a |
---------------------------
| 2 | 2 | b |
---------------------------
| 3 | 2 | c |
---------------------------
| 4 | 2 | d |
---------------------------
| 5 | 3 | b |
---------------------------
| 6 | 3 | e |
---------------------------
| 7 | 4 | f |
---------------------------
I need to select only distinct capital_id's, but different from one that has a value given.
To be more clear, I'll provide an example: If I have the record with id=5, I need to fetch all distinct capital_id's, different than 3 and with the value different from 'b' (so capital_id's to be fetched are: 1 and 4).
I managed to write the query like SELECT id FROM table WHERE capital_id != $capital_id AND value != $value, but duplicate capital_id's are fetched this way. I tried to add a GROUP BY capital_id, but then capital_id=2 is also fetched, although one of its values is 'b'.
How can I solve this problem?
SELECT capital_id
FROM tableName
WHERE capital_id <> $capital_id
GROUP BY 1
HAVING SUM(value = $value) = 0
Try this.
SELECT DISTINCT id FROM table WHERE capital_id != $capital_id AND value != $value
SELECT capital_id
FROM tableName t
WHERE capital_id != $capital_id
AND NOT EXISTS(SELECT *
FROM tableName
WHERE capital_id = t.capital_id
AND value = $value)
GROUP BY capital_id
Related
I have a table data:
+-------+-----------+------+-------+-------------+
| id | client_id | type | name | status |
+-------+-----------+------+-------+-------------+
| 523 | 2 | one | a | verified |
| 526 | 1 | one | a | verified |
| 527 | 1 | one | b | verified |
| 527 | 1 | two | b | verified |
+-------+-----------+------+---------------+-----+
I need to get the client_id's for those that where type='one' and name='a' and status='verified'' AND DON'T have a record where type=one and name=b
In my table above, the result would include client_id = 2.
How do I write a query like this?
You could use a correlated suqbuery with a NOT EXISTS condition to filter out the unwanted records (ie those for which another record exists with the same client_id, with type = 'one' and name = 'b')
SELECT *
FROM data d
WHERE
type = 'one'
AND name = 'a'
AND status = 'verified'
AND NOT EXISTS (
SELECT 1
FROM data d1
WHERE d1.client_id = d.client_id AND d1.type = 'one' and d1.name = 'b'
)
I have a table that has an autoincremented numeric primary. I'm trying to get a count of rows that match a condition grouped by increments of their primary key. Given the data:
| id | value |
|----|-------|
| 1 | a |
| 2 | b |
| 3 | a |
| 4 | a |
| 5 | b |
| 6 | a |
| 7 | b |
| 8 | a |
| 9 | b |
| 10 | b |
| 11 | a |
| 12 | b |
If I wanted to know how many rows matched value = 'a' for every five rows, the result should be:
| count(0) |
|----------|
| 3 |
| 2 |
| 1 |
I can nest a series of subqueries in the SELECT statement, like such:
SELECT (SELECT count(0)
FROM table
WHERE value = 'a'
AND id > 0
AND id <= 5) AS `1-5`,
(SELECT count(0)
FROM table
WHERE value = 'a'
AND id > 5
AND id <=10) AS `6-10`,
...
But is there a way to do this with a GROUP BY statement or something similar where I don't have to manually write out the increments? If not, is there a more time efficient method than a series of subqueries in the SELECT statement as in the above example?
You could divide the ID by 5 and then ceil the result:
SELECT CONCAT((CEIL(id / 5.0) - 1) * 5, '-', CEIL(id / 5.0) * 5), COUNT(*)
FROM mytable
WHERE value = 'a'
GROUP BY CEIL(id / 5.0)
The following aggregated query should do the trick :
SELECT CEIL(id/5), COUNT(*)
FROM table
WHERE value = 'a'
GROUP BY CEIL(id/5)
I am trying to fetch a table on certain conditions with join. My table is:
tab_registrations
--------------------------------------------
reg_id |familyid| familyname | parent_id |
| | | |
-------|--------|-------------|-----------|
1 | 2 | null | null |
-------|--------|-------------|-----------|
2 | others | abc | 3 |
-------|--------|-------------|-----------|
3 | 3 | null | null |
-------|--------|-------------|-----------|
4 | others | def | 2 |
-------|--------|-------------|-----------|
tab_family
-------------------------------------
family_id | family_name | parent_id |
| | |
-------------------------------------
1 | tyu | 0 |
-------------------------------------
2 | xyz | 1 |
-------------------------------------
3 | mno | 2 |
-------------------------------------
I want to join these tables on:
if tab_registrations.family not equal to null, then select corresponding parent_id from tab_family
SELECT tab_registration.*,tab_family.family_id,tab_family.parent_id
FROM `tab_registration`
join tab_family on tab_registration.family_id = tab_family.family_id
WHERE reg_id = 1
if tab_registrations.family is equal to 'others', then select tab_registrations.familyname and tab_registrations.parent_id
When I try the above query if tab_registrations.family = 'others', no rows fetched
How can I achieve this? Can anyone help me?
Change to LEFT JOIN with the condition that tab_registration.familyid is not equal to others. Also, you can use conditional CASE..WHEN statements to get the familyname and parent_id values.
SELECT tr.*,
CASE WHEN tr.familyid = 'others' THEN tr.familyname
ELSE tf.family_name
END AS familyname,
CASE WHEN tr.familyid = 'others' THEN tr.parent_id
ELSE tf.parent_id
END AS parent_id
FROM tab_registration tr
LEFT JOIN tab_family tf
ON tr.family_id = tf.family_id AND
tr.familyid <> 'others'
WHERE tr.reg_id = 1
For multi-table queries, it if preferable to use Aliasing for code clarity and readability.
may be useful this query
SELECT tr.*,tf.family_id,tf.parent_id,
IF(tr.familyid='others',tr.familyname,tf.family_name) as fname
IF(tr.familyid='others',tr.parent_id,tf.parent_id) as parentId
FROM `tab_registration` tr
left join tab_family tf on tr.family_id = tf.family_id
I have a table like this
|num|id|name|prj|
| 1 | 1|abc | 1 |
| 2 | 1|efg | 1 |
| 3 | 1|cde | 1 |
| 4 | 2|zzz | 1 |
I want to run a query like this:
SELECT * FROM table WHERE prj=1 ORDER BY name
but printing out repeated values only once. I want to keep all the rows and I would like to do this at database level and not on the presentation layer (I know how to do it in php).
Desired result is
|num|id|name|prj|
| 1 | 1|abc | 1 |
| 3 | |cde | 1 |
| 2 | |efg | 1 |
| 4 | 2|zzz | 1 |
any hint on where to start from to build that query?
Use a session variable to test if the previous ID is the same as the current ID:
SELECT num, IF(#lastid = id, '', #lastid := id) AS id, name, prj
FROM table
CROSS JOIN (SELECT #lastid := null) x
ORDER BY table.id, name
DEMO
Note that you need to qualify table.id, because ORDER BY defaults to using the alias from the SELECT list if it's the same as a table column, and that would order the empty fields first.
Hello there I have a following table
------------------------------------------
| id | language | parentid | no_daughter |
------------------------------------------
| 1 | 1 | 0 | 2 |
------------------------------------------
| 1 | 1 | 0 | 2 |
------------------------------------------
| 2 | 1 | 1 | 1 |
------------------------------------------
| 2 | 2 | 1 | 1 |
------------------------------------------
| 3 | 1 | 1 | 0 |
------------------------------------------
| 3 | 2 | 1 | 0 |
------------------------------------------
| 4 | 1 | 2 | 0 |
------------------------------------------
| 4 | 2 | 2 | 0 |
------------------------------------------
| 5 | 1 | 2 | 0 |
------------------------------------------
| 5 | 2 | 2 | 1 |
-----------------------------------------
| 5 | 1 | 4 | 1 |
------------------------------------------
| 5 | 2 | 4 | 1 |
------------------------------------------
Scenario
Every record has more than one rows in table with different language ids. parentid tells who is the parent of this record. no_daughter columns tells against each record that how many child one record has. Means in Ideal scenario If no_daughter has value 2 of id = 1 , it means 1 should be parentid of 2 records in same table. But If a record has more than one exitance with respect to language, it will be considered as one record.
My Problem
I need to find out those records where no_daughter value is not correct. It means if no_daughter is 2, there must be two records whoes parentid has that id. In above case record with id = 1 is valid. But record having id = 2 is not valid because the no_daughter = 1 but actual daughter of this record is 2. Same is the case with id=4
Can any body tell me how can I find these faulty records?
Updated after answers
Ken Clark has and shola has given answer which return same result for example shola query is
SELECT DISTINCT
id
FROM
tbl_info t
INNER JOIN
(SELECT
parentid,
COUNT(DISTINCT id) AS childs
FROM
tbl_info
GROUP BY parentid) AS parentchildrelation
ON t.id = parentchildrelation.parentid
AND t.no_daughters != parentchildrelation.childs
This query is returning those ids who have been used as parentid somewhere in table but having wrong no_daughter values. But not returning ids that has value in no_daugter columns but have not been used as parentid any where in table. For exampl id = 5 has no_daughter = 1 but it is not used as parentid in table. So it is also a faulty record. But above query is not capturing such records.
Any help will be much appreciated.
Try this:
SELECT DISTINCT
id
FROM
tbl_info t
Left JOIN
(SELECT
parentid,
COUNT(DISTINCT id) AS childs
FROM
tbl_info
GROUP BY parentid) AS parentchildrelation
ON t.id = parentchildrelation.parentid
Where t.no_daughters != parentchildrelation.childs
Try this:
SELECT id FROM tinfo t inner join
(SELECT parentid, COUNT(distinct language ) as childs FROM tinfo group by parentid) as summary
on t.id=summary.parentid and t.no_daughters!= summary.childs
try this
Select Distinct * From tablename t
Left Join
(
Select COUNT(t1.Id) Doughter,t1.parentid,t1.language From tablename t1 Group By t1.parentid,t1.language
)tbl
On t.id=tbl.parentid And tbl.language=t.language And t.no_daughter<>tbl.Doughter