how to return string exclude query string it self.
column string = AAA/BBB/CCC
result string = BBB/CCC where column like AAA
column string = AAA/BBB/CCC
result string = CCC where column like AAA/BBB
"SELECT DISTINCT `column` FROM `table` WHERE `column` like '???'";
Thank you.
select distinct replace(column, 'AAA/BBB/', '') as column
from table
where column like 'AAA/BBB/%';
Related
I will escape the parameter at first and then concat the sql string when querying.
So when I concat query strings using like:
const name = mysql.escape(req.info.name)
const sqlString = `select...name like '%${name}%'`
It will lead to select ... where name like '%'hello'%',
but what I want is select ... where name like '%hello%'
How can I select from database by given string and mysql to return the row on same string with diacritics?
select * from myTable where nume = "Stefan"
and the row from database that should be returned:
id = 1
name = "Ștefan"
You can search like:
SELECT * from myTable
where
CONVERT(nume USING utf8) LIKE '%Stefan%'
But this is a bit unclear, as MySql already know how to search for strings with diactritics.
I would like the query to select only if there is a column named firstName. If the column is firstname then the query should not return anything.
SELECT firstName as currentName from tableNew WHERE id = $Id
I tried the code below but does not work
SELECT binary firstName as currentName from tableNew WHERE id = $Id
Can you please help?
On Unix, table names are case sensitive. On Windows, they are not.
Column, index, and stored routine names are not case sensitive on any
platform, nor are column aliases.
If you have access to INFORMATION_SCHEMA do this:
SELECT firstName as currentName from tableNew WHERE id = $Id AND (SELECT COUNT(TABLE_NAME)
FROM information_schema.COLUMNS
WHERE
TABLE_SCHEMA = 'mydbname'
AND TABLE_NAME = 'tableNew'
AND BINARY COLUMN_NAME = 'firstName') > 0;
How to select rows from a table where its condition can match any value from an array.
something like this:
Select * from Table Where Name = Array_of_Names;
Array_of_Names is a java array.
You can pass it using IN keyword in query with multiple items separated by comma in brackets like :
String query = "Select * from Table Where Name IN (";
for(int i =0 ;i<arrayName.length();i++){
query = query + "'" +arrayName(i) + "'" + ",";
}
query = query.substring(0, query.length()-1);
query = query + ")";
// execute your query here
This ll pass your query like :
Select * from Table Where Name IN ('arrayvalue1','arrayvalue2','arrayvalue3');
as per length of array.
You'll need to craft the SQL statement and use WHERE ... IN ...
SELECT column_name(s)
FROM table_name
WHERE column_name IN (value1,value2,...);
here you are:
Select * from Table Where Name in ("Tom", "Dick", "Harry");
I have a function which takes an argument that is used in where clause
function(string x)-->Now this will create a sql query which gives
select colname from tablename where columnname=x;
Now I want this function to give all rows i.e. query equivalent to
select colname from tablename;
when I pass x="All".
I want to create a generic query that when I pass "All" then it should return me all the rows else filter my result.
Just leave the where condition out.
If you really want it that complicated use
where columnname LIKE '%'
which will only filter nulls.
select colname from tablename
where columnname=(case when #x ="All" then columnname
else #x end)
Try this
select colname from tablename where 1=1
hope the above will work
where 1=1 worked for me, Although where clause was being used all records were selected.
You can also try
[any_column_name]=[column_name_in_LHL]
(LHL=left hand side.)
refer my answer for more details
I had the same issue some time ago and this solution worked for me
select colname from tablename where columnname=x or x = 'ALL'
SELECT * FROM table_name WHERE 1;
SELECT * FROM table_name WHERE 2;
SELECT * FROM table_name WHERE 1 = 1;
SELECT * FROM table_name WHERE true;
Any of the above query will return all records from table.
In Node.js where I had to pass conditions as parameter I used it like this.
const queryoptions = req.query.id!=null?{id : req.query.id } : true;
let query = 'SELECT * FROM table_name WHERE ?';
db.query(query,queryoptions,(err,result)=>{
res.send(result);
}
It's unclear what language you're using for your function, but you have to somehow parse the 'All' prior to getting to sql:
public void query(String param) {
String value = "":
switch (param) {
case 'All':
value = "*";
break;
default:
value = param;
}
String sql = "select colname from tablename where colname="+value;
//make the query
}
If you have to allow 'ALL' to be passed through as the parameter value to your function, then you will need to put some manipulation code in your function to construct your SELECT statement accordingly. I.e. You can detect if the parameter has 'ALL' in it and then omit the WHERE clause from your SQL statement. If a value other than 'ALL' comes through, then you can include the WHERE clause along with the relevant filter value from the parameter.
An example of a piece of code to do this would be;
IF x = 'ALL'
THEN
SELECT COLNAME FROM TABLENAME;
ELSE
SELECT COLNAME FROM TABLENAME WHERE COLUMNNAME = X;
END IF;
Give a conditional check in your code(assuming Java) to append the WHERE clause only when x != 'All'
mySqlQuery = "SELECT colname FROM tablename" +
(x.equals("All") ? "" : "WHERE columnname = "+x);