Query with sql datepart - sql-server-2008

I have a table with two column as :
serial_number
1
2
3
dateOfAppoinement
2011-06-30 00:39:04.130
2011-06-30 00:40:01.130
2011-06-30 00:49:04.130
I want to get the highest serial_number of a day. I have to avoid the time part. I'm just using the date part.
Can anyone tell me how can I do this?

I updated my answer to use Convert like snkmchnb suggested. However in SQL Server 2008 there is a DATE datatype that is just the date portion of the year so you don't have to specify the 120 code. I tested this and it works perfectly and the SQL is pretty straight forward.
SELECT
MAX(serial_number),
CONVERT(DATE, dateOfAppointment) as [Day]
FROM
#TempSerialsByDate
GROUP BY
CONVERT(DATE, dateOfAppointment)

I think this select solves your problem, can't figure if it is the best way:
select dateadd(dd,0, datediff(dd,0, dateOfAppoinement ))
from your_table where serial_number = (select max(serial_number) form your_table)
How truncate date in sql server can be found here:
How can I truncate a datetime in SQL Server?

Related

Get data from past 7 days DB2

I have no experience working with DB2 before and I'm kind of stuck in something. I'm working on a project in SSIS reading from DB2 where I write into a flat file. I need to run the process weekly and get data from past 7 days.
My query works this way:
Select * From Table
Where ServiceDate >= 2200624 - 7
The above query brings data from the past 7 days, but this query don't work for me since I need to execute this process weekly. I need something like this:
Select * From Table
Where ServiceDate >= DATE(CURRENT_DATE - 7 DAY)
The second query throws an error, is there any other way to achieve this? I'm using ODBC source and I was thinking to use a dynamic query in SSIS but I'm not sure how this works in ODBC source, any suggestions or help will be appreciated.
EDIT:
This tables were created a long time ago, so I don't have any information about the data type of these tables.
The actual date 2200624 correspond to 20200624. This is the way that my date shows in the table.
Thanks in advance
For ServiceDate as YYYYMMDD INT:
Select * From Table
Where ServiceDate >= INT(TO_CHAR(CURRENT_DATE - 7 DAY, 'YYYYMMDD'));
If ServiceDate is CHAR(7) or equivalent, and if value 2200624 corresponds to YYYYMMDD date 20200624 as per your edited question, then the following examples might help.
It assumes ServiceDate values beginning with first character 1 are in the 20th century (19xx years), and dates with first character 2 are in the 21st century.
SELECT ... FROM ... WHERE ( TO_DATE(CASE SUBSTR(ServiceDate,1,1) WHEN '1' THEN '19'||SUBSTR(ServiceDate,2,6) WHEN '2' THEN '20'||SUBSTR(ServiceDate,2,6) END,'YYYYMMDD')) >= CURRENT DATE - 7 DAYS
This will perform badly, so don't use that!
An alternative that will perform better is to convert CURRENT DATE - 7 DAYS into a number that matches your storage-format like this:
...WHERE ServiceDate >= '2'||substr(TO_CHAR(CURRENT_DATE - 7 DAY, 'YYYYMMDD'),2,6)
and if ServiceDate is INTEGER column datatype then:
...WHERE ServiceDate >= int('2'||substr(TO_CHAR(CURRENT_DATE - 7 DAY, 'YYYYMMDD'),2,6))
Always state your Db2-server platform (Z/OS, i-series, Linux/Unix/Windows) when asking for help with Db2, because the answer may be different depending on the platform + version of your Db2-server.

how to calculate expiry date using mysql query?

Calculate expiry date using mysql query.
calculate make_date and expiry_date difference against tblt_name in mysql query.
You can use this below query..
select tblt_name,
(CASE
WHEN datediff(expiry_date,CURDATE()) > 0 then datediff(expiry_date,CURDATE())
ELSE 'Expired'
END) as Remaining_days_expired from tablets;
SQL fiddle
Is this along the lines of what you want:
SELECT tblt_id, tblt_name, make_date, expiry_date, expiry_date - make_date AS shelf_life
FROM medicine
You can use use DATEDIFF() function to do so
SELECT tblt_id , tblt_name , DATEDIFF(s,expiry_date,make_date) FROM TABLE.
First para just put the different date type you wan to compare
s is just display the different in Seconds format.

Mysql Select with Dates and maybe Case when

im having a problem where i cant think of a solution, maybe im having a bad table-structure or i just dont know enough about mysql select commands to think of a good solution. Maybe you can help me out:
So i got a table that has a Column with the Date-format (yyyy-mm-dd) i wanted to select all upcoming dates so i did:
SELECT * WHERE date >= now.
This worked kinda well but i also got "dates" where only the year is entered (2014-00-00) i also wanted to select these but "now" is already bigger so i made another column with the year only and if the month, date or both arent known i will use 0000-00-00 and the Column "year" now i could select like this:
SELECT * WHERE date >= now AND year >=now(year)
Now all entrys with 0000-00-00 wont be selected. If i use OR the entrys from last year will be shown.
So thats my problem, is there any way i can change my table so i can have entries with only the year or only year and month and of course all together? I already considered get rid of the date-format and use simple INT with seperated columns for year, month and date. But i think i will have the same problem.
Sometimes i just want to do a capsuled select like
SELECT *
WHERE (date >= now AND year >= now(year))
OR date == "0000-00-00" (i know that this doesnt work)
If I understood your problem correctly, you could use this request:
WHERE (date >= now OR year > now(year))
There is probably a simpler way though, that would preserve your design, like initializing at January 1st (01-01) instead of 00-00
I think you can use this code:
$_SESSION['month'] = //set here your selected month
$_SESSION['year'] = //set here your selected year
SELECT * FROM table WHERE DATEPART(m,date) >= '".$_SESSION['month']."' AND DATEPART(yyyy,year) >= '".$_SESSION['year']."' AND date <> '0000-00-00'
Change your table structure format. Actually just allow for that field to have null value when not entered. By default it will be null then. You shouldn't be storing 0000-00-00 as a value for Date type field. I would rather leave it as null , or as suggested in some of previous answers, initialize it with some other date. It would be much easier to manipulate with database then.
the problem is that half of you write is not MySQL and your database schema is terrible...
You have the following problems:
column data date does not have the date data type.
To fix it, you need to add a cast to the select statement eg. cast(datecolumn as date)
select * from table where cast(datecolumn as date) >= '2014-01-10';
the way to use now date is using the now function.
select now(), date(now());
result> 2014-01-10 11:11:36, 2014-01-10
select * from table where cast(datecolumn as date) >= date(now());
Because your datecolumn is not a date (2014-00-00 is not a valid date), you need to use string manipulation to extract the year.
select substring('2014-01-01', 1,4)
result> 2014
select * from table where substring(datecolumn, 1,4) = year(now());
The comparassion operator is = and not ==
the select statement syntax looks like this (pay attention because you are missing the table in your statement)
select * from [Table] where [column] = condition ...
You probably need or instead of ands, therefore your query should look like this:
select * from FooTable where
cast(datecolumn as date) >= date(now())
or substring(datecolumn, 1,4) >= year(now())
or datecolumn = '0000-00-00'
You should use something like phpmyAdmin or mySQL workbench to test your sql queries before try to use them on php, java or whatever is your programing language.

how to get the data using from date and to date in sql server?

i need to retreive data from database with the condition from date to to date using between query,
my query is,
select * from Master where Date between '01-08-2013' and '30-08-2013'
but it retreive all data from the table...
i need only data with in that date..
i tried another one like,
select * from PatientMaster where EntryDate >= '01-08-2013' and EntryDate<= '30-08-2013'
how its posible..
whats wrong with my query...
sorry im very bad in english...
thank you in advance...
A date string has the syntax YYYY-MM-DD and not DD-MM-YYYY
select * from Master
where `Date` between '2013-08-01' and '2013-08-30'
for that you can use
select * from Master where Date >='01-08-2013' and dateadd(dd,1,'30-08-2013')
You have to convert your strings to dates. This page shows you how to do it in mysql, which is what you have tagged. For sql server, which is in your subject line, use this page.
Then you do a slight modification of your 2nd attempt. Instead of
and EntryDate <= the end date
you want
and EntryDate < the day after the end date
That takes care of any time components. It might not matter in your case, but it's a good habit to get into.
You'll be looking for an query that works with your format? (dd-mm-yy)
CAST to the desired format!
http://www.w3schools.com/sql/func_convert.asp
105 = dd-mm-yy
SELECT * FROM Master
WHERE CONVERT(date, Date, 105) BETWEEN '01-08-13' and '30-08-13'
Be conscious with regards of the choice of data type for date Columns,
with or without time, day or year first etc. and please do not use varchar
for dates...
know that it CAN be confusing to call a date column for only Date...
be consistent with high/lower case.

How can I group data by month, day and hour in mysql?

I have a mysql database that looks like this:
id | userid | timestamp | activity
Timestamp is a datetime data type, I need to get the data grouped by month, day and hour. I am using mysql and php for my scripts.
I am able to do it by month and day with the following query:
$query = "SELECT COUNT(id) as totals FROM security_transactions WHERE YEAR(timestamp) = 2012 GROUP BY MONTH(timestamp), DAY(timestamp)";
I need to do it by month day and hours.
Please help.
Thanks.
You can add , HOUR(TIME(timestamp)) to your group by query providing your column is of DATETIME format
http://dev.mysql.com/doc/refman/5.1/en/date-and-time-functions.html#function_hour
Also, from the error messages put in the comments below, it looks like #Aprentice is not using mysql, but I've improved this answer for others looking for mysql.
I have never used mssql, so I can't test this but the following might work to group by nearest hour:
GROUP BY dateadd(hour, datediff(hour, 0, timestamp, 0)
Just take it one step further and use HOUR() as well. You will first need to extract the time portion of the timestamp. But guess what, there is a function for that as well ;)