I have written the following query:
select
*,
count(pk_id) as row_count
from employee
group by
pk_id
But I am not getting 1 as the row_count value for every column.
How can I get the total number of rows returned as the result of the query?
Can someone please help?
And one more thing is I don't want to write any subquery :(
Have you considered either just counting the rows as you receive them in whatever's consuming this result set, or just using FOUND_ROWS? Is there some reason you need the rowcount to appear as a column in the result set?
Try with:
select
*,
count(*) as row_count
from employee
group by
pk_id
Related
Picture 1 is the table containing the data
Picture 2 is my command
Why is it only returning 1 row and not the same for all the subjectIDs?
How do I make it return a row for each subjectID?
Thanks
p.s Please keep things simple I need to do this with basic sql.
You are running an AVG command. This will aggregate the results, since an average has to be run on multiple rows of data.
If you want to have it grouped in a different way, you can do this with a GROUP BY clause. This will return a row for every distinct values for the column(s) specified in the GROUP BY clause, with the calculated average and so on.
It would look similar to the following:
SELECT subjectid, AVG(result)
FROM Results
GROUP BY subjectid
i have a column full of resort id's say 44 rows, i am using the following query
Query-> SELECT DISTINCT RESORT ID FROM Schema.table Name WHERE Condition='Value' AND ROW NUMBER= 1
the above query returns one value say='15'
when i run it multiple it is returning the same value ='15'!!!
i require a different value each time the query is ran
could any one please help me out.
Thanks,
You will get Random Resort ID by using this
SELECT TOP 1 ResortID FROM TableName
-- WHERE <Condition>
ORDER BY NEWID() ASC
I mistakenly run query
SELECT count(*) table_name
to learn row count. It gives 1 as result. Do you know what is the meaning of this result "1"?
Thanks,
Simple.
The table contains 1 record.
Basically COUNT returns the number of records found on the table.
COUNT
I'm trying to count total number of results on each row of my SELECT query. Something like:
SELECT id, COUNT(*) FROM mytable;
But this returns just a single row with the count. How do I get the total number of returned rows on every row?
I've tried achieve this using: SELECT #i=#i+1 (in a sub query) but it doesn't work. Also, tried grouping by id but that doesn't help either.
Is there some MySql function that returns total number of rows returned so that it could be added into each row of the result (for calculations)?
SELECT id, (SELECT COUNT(*) FROM mytable) FROM mytable;
Maybe you mean something like this?
You are missing GROUP BY id
Use this
SELECT id, COUNT(*) FROM mytable GROUP BY id;
SELECT kullaniciNick,
kullaniciAdi,
kullaniciSoyadi
FROM panelkullanicilari
WHERE id IN
(SELECT user_id
FROM proje_ekip
WHERE proje_id=11)
ORDER BY kullaniciSoyadi
at the query i need the count of rows to check if it is over 6 or less.
When i used the COUNT(*) i got an error message. That said it must used with GROUP BY.
Thank you.
Try this:
SELECT kullaniciNick,
kullaniciAdi,
kullaniciSoyadi,
count(*) -- Added this line
FROM panelkullanicilari
WHERE id IN
(SELECT user_id
FROM proje_ekip
WHERE proje_id=11)
GROUP BY 1,2,3 -- Added this line
ORDER BY kullaniciSoyadi
You can't have a result, and it's size in one query.
Use 2 queries. First one will give you the size of result and second one will be the result. The First query, should be like this:
SELECT count(*)
FROM panelkullanicilari
WHERE id IN
(SELECT user_id
FROM proje_ekip
WHERE proje_id=11)
the second one , is just like the query you wrote above.