I'm using TextMate to edit a project that I'm doing(HTML files) and I have some <div> tags assigned with the class=navigation property, but I need to change this <div>'s for a new design that I'm planning, but they are much(about 47 results if I search for class=navigation).
So I need a regular expression to match the entire line that this property is found, but which is it?
I'm not a regex expert, but I would think that ^.*class=navigation.*$ would work.
Related
I have a bunch of records in a QuickBase table that contain a rich text field. In other words, they each contain some paragraphs of text intermingled with HTML tags like <p>, <strong>, etc.
I need to migrate the records to a new table where the corresponding field is a plain text field. For this, I would like to strip out all HTML tags and leave only the text in the field values.
For example, from the below input, I would expect to extract just a small example link to a webpage:
<p>just a small <a href="#">
example</a> link</p><p>to a webpage</p>
As I am trying to get this done quickly and without coding or using an external tool, I am constrained to using Quickbase Pipelines' Text channel tool. The way it works is that I define a regex pattern and it outputs only the bits that match the pattern.
So far I've been able to come up with this regular expression (Python-flavored as QB's backend is written in Python) that correctly does the exact opposite of what I need. I.e. it matches only the HTML tags:
/(<[^>]*>)/
In a sense, I need the negative image of this expression but have not be able to build it myself.
Your help in "negating" the above expression is most appreciated.
Assuming there are no < or > elsewhere or entity-encoded, an idea using a lookbehind.
(?:(?<=>)|^)[^<]+
See this demo at regex101
(?:(?<=>)|^) is an alternation between either ^ start of the string or looking behind for any >. From there [^<]+ matches one or more characters that are not < (negated character class).
I want to edit this HTML lexer rule and I need help with the Regular Expression
the TAG_NAME refers to any HTML attribute for ex: (required, class, id, etc...).
I want to edit it to make it does not accept this exact syntax: 'az-'.
I think this needs regular expression modification, I looked it up but I couldn't integrate what I found online with the way these rules are written.
I tried to remove the '-' in the Tag_NameChar as a first try but that made the HTML doesnt recognize attributes like 'data-target'.
This snippet is for the rule:
and this one shows how the attributes are recognized.
ANTLR does not support lookahead syntax like some regex engines do, so there's no easy way to exclude certain matches from within the regex. It's always possible to rewrite a regular expression to exclude a given string (regular expressions are closed under negation and intersection), but it usually ends up quite painful. In your case, you'd end up with something following the logic of "a tag name can either have less than 3 characters, more than 3 characters, or it could have three characters where the first isn't an 'a', the second isn't a 'z' or the last isn't a '-'".
The less painful, but also less cross-language solution is to use a predicate that returns false if the text of the tag name equals az-. So something like {getText().equals("az-")}? depending on the language.
If you're okay with introducing an additional lexer rule, you may also introduce a rule INVALID_TAG_NAME (or whatever you want to call it) that matches exactly az- and that's defined before TAG_NAME. That way any tag that's named exactly az- will produce an INVALID_TAG_NAME token instead of a TAG_NAME token.
Depending on your requirements, you could also leave the grammar unchanged altogether and simply produce an error when you see a tag named az- when you traverse the tree in a listener or visitor.
Using regular expressions, I need to extract a multiline content of a tag, which has specific id value. How can I do this?
This is what I currently have:
<div(.|\n)*?id="${value}"(.|\n)*?>(.|\n)*?<\/div>
The problem with this is this sample:
<div id="1">test</div><div id="2">test</div>
If I want to replace id="2" using this regexp (with ${value} = 2), the whole string would get matched. This is because from the tag opening to closing I match everything until id is found, which is wrong.
How can I do this?
A fairly simple way is to use
Raw: <div(?=\s)[^>]*?\sid="2"[^>]*?>([\S\s]*?)</div>
Delimited: /<div(?=\s)[^>]*?\sid="2"[^>]*?>([\S\s]*?)<\/div>/
Use the variable in place of 2.
The content will be in group 1.
Change (.|\n) to [^>] so it won't match the > that ends the tag. Then it can't match across different divs.
<div\b[^>]*\bid="${value}"[^>]*>.*?<\/div>
Also, instead of using (.|\n)* to match across multiple lines, use the s modifier to the regexp. This makes . match any character, including newlines.
However, using regular expressions to parse HTML is not very robust. You should use a DOM parser.
I would like to replace opening and closing tag, leaving the content of tags and its attribute intact.
Here is what I have:
<div class="QText">Text to be kept</div>
to be replaced with
<span class="QText">Text to be kept</span>
I tried this expression which finds all expressions I want but there seems to be no way to replace found expressions.
<div class="QText">(.*?)</div>
Thanks in advance.
I think #AmitJoki's answer will work well enough in certain circumstances, but if you only want to replace div elements when they have an attribute or a specific set of attributes, then you would want to use a regex replacement with backreferences - how you specify and refer to a backreference, unfortunately, depends upon your chosen editor. Visual Studio has the most unique and annoying "flavor" of regex I know of, while Dreamweaver has a fairly typical implementation (both as well as I imagine whatever editor you're using do regex replacement - you just have to know the menu item or keystroke to bring up the dialog).
If memory serves, Dreamweaver has replacement options when you hit Ctrl+F, while you have to hit Ctrl+H, so try those.
Once you get a "Find" and "Replace" box, you would put something like what you have in your last example above: <div class="QText">(.*?)</div> or perhaps <div class="(QText|RText|SText)">(.*?)</div> into your "Find" box, then put something like <span class="QText">\1</span> or <span class="\1">\2</span> in the "Replacement" box. A few utilities might use $1 to refer to a backreference rather than \1, but you'll have to lookup help or experiment to be sure.
If you are using a language to run this expression, you need to tell us which language.
If you are using a specific editor to run this expression, you need to tell us which editor.
...and never forget the prevailing wisdom on regex and HTML
Just replace div.
var s="<div class='QText'>Text to be kept</div>";
alert(s.replace(/div/g,"span"));
Demo: http://jsfiddle.net/9sgvP/
Mark it as answer if it helps ;)
Posted as requested
If its going to be literal like that, capture what's to be kept, then replace the rest,
Find: <div( class="QText">.*?</)div>
Replace: <span$1span>
I want to replace <whatever>Some Title</whatever> with <something>Some Title</something> using the Find and Replace tool inside of Dreamweaver. How do I perform?
Not a Dreamweaver user, but this simple approach works in my editor (Emacs):
Replace:
<whatever>\(.*\)</whatever>
With:
<something>\1</something>
This is a pretty straightforward approach but it may fall short of your needs. Do some or all of your <whatever> element pairs occupy more than one line of text? Or do you have more than one <whatever> pair on a single line?
i guess what you want is to change all your <whatever> tag with an <something> tag whitout changing your text, right?
If it is so, you want to use find and replace with regular expression. Find (in source code) <whatever>(.*)</whatever> and replace it with <something>$1</something>. The $1 is used as a variable for anything fits the (.*) part DW finds for each instance.
For example, you you want to comment all instances of an
document.NAMEOFANYFORMONTHEPAGE.WHATEVERNAME.focus();
in a JavaScript file, you would use find:
document\.(.*)\.focus\(\);
and replace it with:
// document.$1.focus();
Don't forget to escape special characters and, please, try a few instances before using Replace All