Select last Order state from Orders - mysql

Question

I have tables:
orders:
id_order id_customer
1 1
2 2
3 1
orders_history
id_history id_order id_order_state date_add
1 1 1 2010-01-01 00:00:00
2 1 2 2010-01-02 00:00:00
3 1 3 2010-01-03 00:00:00
4 2 2 2010-05-01 00:00:00
5 2 3 2011-05-02 00:00:00
6 3 1 2011-05-03 00:00:00
7 3 2 2011-06-01 00:00:00
order_state
id_order_state name
1 New
2 Sent
3 Rejected
4 ...
How to get all order_id's where last id_order_state of that order (by last I mean this with MAX(id_history) or MAX(date_add)) is not equal 1 or 3?

Answer 1

select oh.id_history, oh.id_order, oh.id_order_state, oh.date_add
from (
select id_order, max(date_add) as MaxDate
from orders_history
where id_order_state not in (1, 3)
group by id_order
) ohm
inner join orders_history oh on ohm.id_order = oh.id_order
and ohm.MaxDate = oh.date_add

Answer 2

I think what he's after is what orders are complete... ie their final status, not those that are exclusive of the 1 and 3 specifically. The first pre-query should be the max ID regardless of the status code
select
orders.*
from
( select oh.id_order,
max( oh.id_history ) LastID_HistoryPerOrder
from
orders_history oh
group by
oh.id_order ) PreQuery
join orders_history oh2
on PreQuery.ID_Order = oh2.id_order
AND PreQuery.LastID_HistoryPerOrder = oh2.id_history
AND NOT OH2.id_order_state IN (1, 3) <<== THIS ELIMINATES 1's & 3's from result set
join Orders <<= NOW, anything left after above ^ is joined to orders
on PreQuery.ID_Order = Orders.ID_Order
Just to re-show YOUR data... I've marked the last SEQUENCE (ID_History) per ORDER... This is what the PREQUERY is going to return...
id_history id_order id_order_state date_add
1 1 1 2010-01-01 00:00:00
2 1 2 2010-01-02 00:00:00
**3 1 3 2010-01-03 00:00:00
4 2 2 2010-05-01 00:00:00
**5 2 3 2011-05-02 00:00:00
6 3 1 2011-05-03 00:00:00
**7 3 2 2011-06-01 00:00:00
The "PreQuery" will result with the following subset
ID_Order LastID_HistoryPerOrder (ID_History)
1 3 (state=3) THIS ONE WILL BE SKIPPED IN FINAL RESULT
2 5 (state=3) THIS ONE WILL BE SKIPPED IN FINAL RESULT
3 7 (state=2)
Now, the result of this is then re-joined back to order history on just these two elements... yet adds the criteria to EXCLUDE the 1,3 entries for "order state".
In this case,
1 would be rejected as its state = 3 (sequence #3),
2 would be rejected since its last history is state = 3 (sequence #5).
3 would be INCLUDED since its state = 2 (sequence #7)
Finally, all that joined to the orders will result with ONE ID, and nicely match up with the orders table on the Order_ID alone and get the desired results.

Answer 3

Another possible solution:
SELECT DISTINCT
id_order
FROM
Orders_History OH1
LEFT OUTER JOIN Orders_History OH2 ON
OH2.id_order = OH1.id_order AND
OH2.is_order_state IN (1, 3) AND
OH2.date_add >= OH1.date_add
WHERE
OH2.id_order IS NULL

Answer 4

I'm using "answer for my question" because I need to post results of your queries. So.
Unfortunately not all of your answers guys works. Let's prepare test environment:
CREATE TABLE `order_history` (
`id_order_history` int(11) NOT NULL AUTO_INCREMENT,
`id_order` int(11) NOT NULL,
`id_order_state` int(11) NOT NULL,
`date_add` datetime NOT NULL,
PRIMARY KEY (`id_order_history`)
) ENGINE=MyISAM AUTO_INCREMENT=11 DEFAULT CHARSET=latin2;
CREATE TABLE `orders` (
`id_order` int(11) NOT NULL AUTO_INCREMENT,
`id_customer` int(11) DEFAULT NULL,
PRIMARY KEY (`id_order`)
) ENGINE=MyISAM AUTO_INCREMENT=8 DEFAULT CHARSET=latin2;
INSERT INTO `order_history`
(`id_order_history`, `id_order`, `id_order_state`, `date_add`) VALUES
(1,1,1,'2011-01-01 00:00:00'),
(2,1,2,'2011-01-01 00:10:00'),
(3,1,3,'2011-01-01 00:20:00'),
(4,2,1,'2011-02-01 00:00:00'),
(5,2,2,'2011-02-01 00:25:01'),
(6,2,3,'2011-02-01 00:25:59'),
(7,3,1,'2011-03-01 00:00:01'),
(8,3,2,'2011-03-01 00:00:02'),
(9,3,3,'2011-03-01 00:01:00'),
(10,3,2,'2011-03-02 00:00:01');
COMMIT;
INSERT INTO `orders` (`id_order`, `id_customer`) VALUES
(1,1),
(2,2),
(3,3),
(4,4),
(5,5),
(6,6),
(7,7);
COMMIT;
Now, lets select Last/Max State for each Order, so let's run simple query:
select id_order, max(date_add) as MaxDate
from `order_history`
group by id_order
this gives us PROPER results, no rocket science right now:
id_order MaxDate
---------+-------------------
1 2011-01-01 00:20:00 //last order_state=3
2 2011-02-01 00:25:59 //last order_state=3
3 2011-03-02 00:00:01 //last order_state=2
Now for simplicity, lest change our queries to get Orders where Last State is not equal 3.
We're expecting to get one row result with id_order = 3.
So let's test our queries:
QUERY 1 made by RedFilter:
select oh.id_order, oh.id_order_state, oh.date_add
from (
select id_order, max(date_add) as MaxDate
from `order_history`
where id_order_state not in (3)
group by id_order
) ohm
inner join `order_history` oh on ohm.id_order = oh.id_order
and ohm.MaxDate = oh.date_add
Result:
id_order id_order_state date_add
-------------------------------------------------
1 2 2011-01-01 00:10:00
2 2 2011-02-01 00:25:01
3 2 2011-03-02 00:00:01
So it's not true
QUERY 2 made by Tom H.:
SELECT DISTINCT OH1.id_order
FROM order_history OH1
LEFT OUTER JOIN order_history OH2 ON
OH2.id_order = OH1.id_order AND
OH2.id_order_state NOT IN (3) AND
OH2.`id_order_history` >= OH1.`id_order_history`
WHERE
OH2.id_order IS NULL
Result:
id_order
--------
1
2
So it's not true
Any suggestions appreciated.
EDIT
Thanks to Andriy M. comment we have proper solution. It's a modification of Tom H. query all should looks as follow:
SELECT DISTINCT
OH1.id_order
FROM
order_history OH1
LEFT OUTER JOIN order_history OH2 ON
OH2.id_order = OH1.id_order
AND OH2.date_add > OH1.date_add
WHERE OH1.id_order_state NOT IN (3) AND OH2.id_order IS NULL
EDIT 2:
QUERY 3 made by DRapp:
select
distinct orders.`id_order`
from
( select oh.id_order,
max( oh.id_order_history ) LastID_HistoryPerOrder
from
order_history oh
group by
oh.id_order ) PreQuery
join order_history oh2
on PreQuery.id_order = oh2.id_order
AND PreQuery.LastID_HistoryPerOrder = oh2.id_order_history
AND NOT oh2.id_order_state IN (1,3)
join orders
on PreQuery.id_order = orders.id_order
Result:
id_order
--------
3
So it's finally true