SELECT id, count(*) as Number
FROM (SELECT id FROM t1
UNION ALL
SELECT id FROM t2
UNION ALL
SELECT id FROM t3
) t
GROUP BY id
ORDER BY Number DESC
This is the query giving me the correct result. But When I want to add where call it is throwing error.
SELECT id, count(*) as Number
FROM (SELECT id from t1
UNION ALL
select id from t2
UNION ALL
select id from t3
) t
WHERE Number > 10
GROUP BY id
ORDER BY Number DESC
You want to test conditions on an aggregate function with a HAVING clause rather than a WHERE.
select id, count(*) as Number
from (select id
from t1
UNION ALL
select id
from t2
UNION ALL
select id
from t3) t
group by id
having Number > 10
order by Number desc;
select
id,
count(*) as Number
from
(
select
id
from
t1
UNION ALL
select
id
from
t2
UNION ALL
select
id
from
t3
)t
group by
id
HAVING
Number > 10
order by
Number desc;
Try that - I think its easier to debug if you make your query easy to read...
Related
Sorry for the poor formatting but as part of a larger problem, I have created a query that produces this table:
id id2
4 7
4 6
1 3
1 2
1 1
How would I extract the rows that don't have the highest id2 for each id1.
What I want:
id id2
4 6
1 2
1 1
I can only seem to figure out how to get rid of the max id2 overall but not for each distinct id1. Any help on actually differentiating the max id2 for each id1 would be appreciated.
You can try below way -
select a.id, a.id2
from tablename a
where a.id2 <> (select max(a1.id2) from tablename a1 where a.id=a1.id)
If you are using MySQL 8+, then RANK() provides one option:
WITH cte AS (
SELECT id, id2, RANK() OVER (PARTITION BY id ORDER BY id2 DESC) rnk
FROM yourTable
)
SELECT id, id2
FROM cte
WHERE rnk > 1
ORDER BY id DESC, id2 DESC;
Demo
instead of a correlated subquery in the where, you can LEFT JOIN and apply not in...
select id, id2
from yourTable YT
LEFT JOIN
( select id, max( id2 ) highestID2
from YourTable
group by id ) TopPerID
on YT.ID = TopPerID.ID
AND YT.ID2 != TopPerID.highestID2
where TopPerID.id IS NULL
Since you can have id values with only one id2 value, you need to check for that situation as well, which you can do by comparing the MAX(id2) value with the MIN(id2) value in a JOIN:
SELECT t1.*
FROM Table1 t1
JOIN (SELECT id, MAX(id2) AS max_id2, MIN(id2) AS min_id2
FROM Table1
GROUP BY id) t2 ON t2.id = t1.id
AND (t1.id2 < t2.max_id2 OR t2.min_id2 = t2.max_id2)
If we add a row 2, 5 to your sample data this correctly gives the result as
id id2
4 6
1 2
1 1
2 5
Demo on SQLFiddle
I have a table:
ID CLUSTERID
1 56
1 24
1 24
1 35
2 13
2 24
Now, i want to get the following:
I want to count per id, which cluster id repeats most of the time.
For example, in ID=1, CLUSTERID=24 repeats most of the time
In ID=2 i have 2 CLUSTER IDs that repeats the same.
So in the output i will have:
ID CLUSTERID
1 24
2 13
2 24
The answer that i wrote (and works)
TT is my original table that have 2 columns: ID and CLUSTER ID
SELECT t3.ID,t3.ClusterID,t3.ListingAmount
FROM
(SELECT ID, ClusterID, COUNT() AS ListingAmount
FROM tt
GROUP BY ID, ClusterID) AS t3 LEFT JOIN
(SELECT ID, MAX(ListingAmount) AS amount
FROM
(SELECT ID, ClusterID, COUNT() AS ListingAmount
FROM tt
GROUP BY ID, ClusterID) AS t2
GROUP BY ID) AS BB ON BB.id=t3.id
WHERE BB.amount=t3.ListingAmount
Can't think of a more elegant solution right now (I'm sure there is), but it seems to do the job:
select t1.id,
t1.clusterid,
t1.cnt
from (
select id,
clusterid,
count(*) as cnt
from foo
group by id, clusterid
) t1
join (select id,
max(cnt) as max_count
from (
select id,
clusterid,
count(*) as cnt
from foo
group by id, clusterid
) tm
group by id
) t2 on t1.id = t2.id
and t1.cnt = t2.max_count
order by t1.id, t1.cnt;
SQLFiddle example: http://sqlfiddle.com/#!2/2cacc/3
I have the following table:
ID Date FirstName Dept
1 1/2/12 James Act
1 2/5/12 Mike IT
2 5/6/12 Joe HR
2 7/6/12 Keith IT
What I need to do that for each ID, I need to get the max date.
I need to show ID, Date, FirstName, Dept for the record for each ID that has the Max Date.
So in this case for ID of 1, I would show 1 2/5/12 Mike IT
How do I do this in SQL Server T-SQL?
I know I need to do group by.
The table name is TblAct
You will use the MAX() function with a GROUP BY
select t1.id, t1.date, t1.fname, t1.dept
from tblAct t1
inner join
(
SELECT Max(Date) maxdate, ID
from TblAct
GROUP BY id
) t2
on t1.id = t2.id
and t1.date = t2.maxdate
See SQL Fiddle with Demo
You can do this with windows/ranking functions:
select ID, Date, FirstName, Dept
from (select t.*,
row_number() over (partition by id order by date desc) as seqnum
from t
) t
where seqnum = 1
This is ordering all the rows for each id by date, in reverse order. It then selects the first of them.
dont use group by :
select * from tblAct t1
where date=(select max(date) from tblAct where t1.id = id)
just enjoy.
I have a table with a list of names spread across five different columns. I'm trying to get the 6 most frequent distinct names. Each name will only appear in each record once. The five columns are name_1, name_2...name_5. And just for names sake call the table 'mytable'.
Any help would be much appreciated.
Here's one approach:
SELECT name, COUNT(1)
FROM ( SELECT name_1 AS name FROM mytable
UNION ALL SELECT name_2 AS name FROM mytable
UNION ALL SELECT name_3 AS name FROM mytable
UNION ALL SELECT name_4 AS name FROM mytable
UNION ALL SELECT name_5 AS name FROM mytable
) AS myunion
GROUP BY name
ORDER BY COUNT(1) DESC LIMIT 6
;
How many rows are there in the table?
try this:
SELECT iTable.iName, Count(iTable.iName) as TotalCount
FROM
(
SELECT DISTINCT name_1 as iName FROM myTable
UNION
SELECT DISTINCT name_2 as iName FROM myTable
UNION
SELECT DISTINCT name_3 as iName FROM myTable
UNION
SELECT DISTINCT name_4 as iName FROM myTable
UNION
SELECT DISTINCT name_5 as iName FROM myTable
) as iTable
GROUP BY iTable.iName
ORDER BY TotalCount DESC
LIMIT 6
You should be able to select all the names from each table and union the results together. Then you can count the number of times each name occurs.
select *
from
(
select name, count(*)
from (
select name from table1
union all
select name from table2
union all
select name from table3
union all
select name from table4
union all
select name from table5
)
group by name
order by count(*) desc
)
where rownum <= 6
UNION + subselect should work for you in this case.
SELECT name_1, COUNT(*) FROM (
SELECT name_1 FROM mytable
UNION ALL SELECT name_2 FROM mytable
UNION ALL SELECT name_3 FROM mytable
UNION ALL SELECT name_4 FROM mytable
UNION ALL SELECT name_5 FROM mytable
) AS names GROUP BY name_1 ORDER BY 2 DESC LIMIT 6;
Hi I have a query like that
SELECT column1,MAX(column2) AS MAX FROM
table1 GROUP BY column1 ORDER BY MAX
DESC;
and i have a second table which name table2 and has same column2 but different column1 name,
I want to apply this query to union of these table,when i try this
SELECT column1,MAX(column2) AS MAX FROM
((SELECT * FROM table1) union (SELECT
* FROM table2)) GROUP BY column1 ORDER BY MAX DESC;
I got this error "ERROR 1248 (42000): Every derived table must have its own alias"
how can i do that? thanks for help...
The alias comes after the derived table definition,
SELECT column1,MAX(column2) AS MAX FROM
(SELECT * FROM table1 union SELECT * FROM table2) t3
GROUP BY column1 ORDER BY MAX DESC;
The alias is t3