How do I combine multiple queries into one?
For example:
//Successful Sales:
SELECT username, count(*) as TotalSales, sum(point) as Points FROM sales where submit_date >= 1301612400 AND submit_date <= 1304204400 AND status = 1 group by username
/Return Sales:
SELECT username, count(*) as Return FROM sales where submit_date >= 1301612400 AND submit_date <= 1304204400 AND status = 2 group by username
//Unsuccessful Sales:
SELECT username, count(*) as UnsuccessfulSales FROM sales where submit_date >= 1301612400 AND submit_date <= 1304204400 AND (status = 3 OR status = 6) group by username
So the report look something like this:
Also How do I add percentage of return?
Note: Fixed SQL queries
I have tried doing this but couldn't get it to work?
SELECT username, TotalSales, Points, Return
FROM (
SELECT username, count(*) as TotalSales, sum(point) as Points FROM sales where submit_date >= 1301612400 AND submit_date <= 1304204400 AND status = 1 group by username
UNION
SELECT count(*) as Return FROM sales where submit_date >= 1301612400 AND submit_date <= 1304204400 AND status = 4 group by username
)
..
// Example Data Structure
CREATE TABLE IF NOT EXISTS `sales2` (
`salesid` int(11) NOT NULL AUTO_INCREMENT,
`username` varchar(50) NOT NULL,
`point` int(11) NOT NULL,
`status` int(11) NOT NULL,
PRIMARY KEY (`salesid`)
) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=6 ;
INSERT INTO `sales2` (`salesid`, `username`, `point`, `status`) VALUES
(1, 'User1', 2, 1),
(2, 'User1', 2, 1),
(3, 'User2', 11, 1),
(4, 'User2', 1, 2),
(5, 'User3', 5, 6);
field status = 1, successful Sales and show point
status 2 - return sales
status 3/6 - unsuccessful sales:
UPDATE:
For your first question, I think this will do what you want (but be warned, this query is dog slow, full of table scans... You should ask for a more experienced stack overflow user to optimize that for you):
SELECT
distinct(outer_sales.username),
(SELECT count(*) as Points FROM sales where status = 1 AND username = outer_sales.username) as TotalSales,
(SELECT sum(point) as Points FROM sales where status = 1 AND username = outer_sales.username) as Points,
(SELECT count(*) FROM sales where status = 2 AND username = outer_sales.username) as Return,
(SELECT count(*) FROM sales where (status = 3 OR status = 6) AND username = outer_sales.username) as UnsuccessfulSales
FROM
sales outer_sales
ORDER BY
outer_sales.username;
And for the second question, if you just want to add a percent sign to the Return column, you can USE the CONCAT function: http://dev.mysql.com/doc/refman/5.0/en/string-functions.html#function_concat.
Try:
SELECT CONCAT(CAST(COUNT(*) AS CHAR), '%') AS Return ...
If the number (and types) of columns match in the queries, you can use UNION to combine the results of the 3 queries.
Related
There are 2 tables ost_ticket and ost_ticket_action_history.
create table ost_ticket(
ticket_id int not null PRIMARY KEY,
created timestamp,
staff bool,
status varchar(50),
city_id int
);
create table ost_ticket_action_history(
ticket_id int not null,
action_id int not null PRIMARY KEY,
action_name varchar(50),
started timestamp,
FOREIGN KEY(ticket_id) REFERENCES ost_ticket(ticket_id)
);
In the ost_ticket_action_history table the data is:
INSERT INTO newdb.ost_ticket_action_history (ticket_id, action_id, action_name, started) VALUES (1, 1, 'Consultation', '2022-01-06 18:30:29');
INSERT INTO newdb.ost_ticket_action_history (ticket_id, action_id, action_name, started) VALUES (2, 2, 'Bank Application', '2022-02-06 18:30:45');
INSERT INTO newdb.ost_ticket_action_history (ticket_id, action_id, action_name, started) VALUES (3, 3, 'Consultation', '2022-05-06 18:42:48');
In the ost_ticket table the data is:
INSERT INTO newdb.ost_ticket (ticket_id, created, staff, status, city_id) VALUES (1, '2022-04-04 18:26:41', 1, 'open', 2);
INSERT INTO newdb.ost_ticket (ticket_id, created, staff, status, city_id) VALUES (2, '2022-05-05 18:30:48', 0, 'open', 3);
INSERT INTO newdb.ost_ticket (ticket_id, created, staff, status, city_id) VALUES (3, '2022-04-06 18:42:53', 1, 'open', 4);
My task is to get the conversion from the “Consultation” stage to the “Bank Application” stage broken down by months (based on the start date of the “Bank Application” stage).Conversion is calculated according to the following formula: (number of applications with the “Bank Application” stage / number of applications with the “Consultation” stage) * 100%.
My request is like this:
select SUM(action_name='Bank Application')/SUM(action_name='Consultation') * 2 as 'Conversion' from ost_ticket_action_history JOIN ost_ticket ot on ot.ticket_id = ost_ticket_action_history.ticket_id where status = 'open' and created > '2020 -01-01 00:00:00' group by action_name,started having action_name = 'Bank Application';
As a result I get:
Another query:
SELECT
SUM(CASE
WHEN b.ticket_id IS NOT NULL THEN 1
ELSE 0
END) / COUNT(*) conversion,
YEAR(a.started) AS 'year',
MONTH(a.started) AS 'month'
FROM
ost_ticket_action_history a
LEFT JOIN
ost_ticket_action_history b ON a.ticket_id = b.ticket_id
AND b.action_name = 'Bank Application'
WHERE
a.action_name = 'Consultation'
AND a.status = 'open'
AND a.created > '2020-01-01 00:00:00'
GROUP BY YEAR(a.started) , MONTH(a.started)
I apologize if I didn't write very clearly. Please explain what to do.
Like I explained in my comment, you exclude rows with your having clause.
I will show you in the next how to debug.
First check what the raw result of the select query is.
As you see, when you remove the GROUP BY and see what you actually get is only 1 row with bank application, because the having clause excludes all other rows
SELECT
*
FROM
ost_ticket_action_history
JOIN
ost_ticket ot ON ot.ticket_id = ost_ticket_action_history.ticket_id
WHERE
status = 'open'
AND created > '2020-01-01 00:00:00'
GROUP BY
action_name, started
HAVING
action_name = 'Bank Application';
Output:
ticket_id
action_id
action_name
started
ticket_id
created
staff
status
city_id
2
2
Bank Application
2022-02-06 18:30:45
2
2022-05-05 18:30:48
0
open
3
Second step, see what the result set is without calculating anything.
As you can see you make a division with 0, what you have learned in school, is forbidden, hat is why you have as result set NULL
SELECT
SUM(action_name = 'Bank Application')
#/
,SUM(action_name = 'Consultation') * 2 AS 'Conversion'
FROM
ost_ticket_action_history
JOIN
ost_ticket ot ON ot.ticket_id = ost_ticket_action_history.ticket_id
WHERE
status = 'open'
AND created > '2020-01-01 00:00:00'
GROUP BY action_name , started
HAVING action_name = 'Bank Application';
SUM(action_name = 'Bank Application') | Conversion
------------------------------------: | ---------:
1 | 0
db<>fiddle here
#Third what you can do exclude a division with 0, here i didn't remove all othe rows as this is only for emphasis
SELECT
SUM(action_name = 'Bank Application')
/
SUM(action_name = 'Consultation') * 2 AS 'Conversion'
FROM
ost_ticket_action_history
JOIN
ost_ticket ot ON ot.ticket_id = ost_ticket_action_history.ticket_id
WHERE
status = 'open'
AND created > '2020-01-01 00:00:00'
GROUP BY action_name , started
HAVING SUM(action_name = 'Consultation') > 0;
| Conversion |
| ---------: |
| 0.0000 |
| 0.0000 |
db<>fiddle here
Final words,
If you get a strange result, simply go back remove everything that doesn't matter and try to get all values, so hat you can check your math
I'm trying to retrieve the best suited price for a product in each quantity depending on the customer and/or his customer group. To do so, I use a weight based system: the matching customer group is more important than the matching customer, so if two rows collide, we should get the row corresponding to the customer group id.
Here's an example:
Customer n°1 is part of Customer group n°2
Product prices:
A - 90€ for customer n°1 (when buying at least 2 of the same product)
B - 80€ for customer group n°2 (when buying at least 2 of the same product)
So the price shown to the customer n°1 should be 80€
He's my query:
SELECT
MAX(IF(t.customer_id = 1, 10, 0) + IF(t.customer_group_id = 1, 100, 0)) as score,
t.*
FROM tierprice t
WHERE t.product_variant_id = 110
AND (t.customer_id = 1 OR t.customer_id IS NULL)
AND (t.customer_group_id = 1 OR t.customer_group_id IS NULL)
GROUP BY t.product_variant_id, t.qty
The problem I'm having is that the correct score is shown in the result row (here: 100), but the row for the given score is not correct. I'm guessing it has something to do with the MAX in the SELECT and the GROUP BY, but I don't know how to assign the score to the row, and then take the highest.
Here's a fiddle :
CREATE TABLE `tierprice` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`product_variant_id` int(11) DEFAULT NULL,
`customer_group_id` int(11) DEFAULT NULL,
`price` int(11) NOT NULL,
`qty` int(11) NOT NULL,
`customer_id` int(11) DEFAULT NULL,
PRIMARY KEY (`id`),
UNIQUE KEY `no_duplicate_prices` (`qty`,`product_variant_id`,`customer_group_id`),
KEY `IDX_BA5254F8A80EF684` (`product_variant_id`),
KEY `IDX_BA5254F8D2919A68` (`customer_group_id`),
KEY `IDX_BA5254F89395C3F3` (`customer_id`)
) ENGINE=InnoDB AUTO_INCREMENT=5 DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci;
INSERT INTO `tierprice` (`id`, `product_variant_id`, `customer_group_id`, `price`, `qty`, `customer_id`)
VALUES
(1, 110, NULL, 8000, 2, 1),
(2, 110, 1, 7000, 2, NULL),
(3, 110, 1, 6000, 5, NULL),
(4, 110, NULL, 5000, 5, 1),
(5, 111, 1, 8000, 2, NULL),
(6, 111, NULL, 6000, 2, 1),
(7, 111, 1, 7000, 6, NULL),
(8, 111, NULL, 5000, 6, 1);
http://sqlfiddle.com/#!9/7bc0d9/2
The price ids that should come out in the result should be ID 2 & ID 3.
Thank you for your help.
Provided query is not a valid query from SQL standard's perspective:
SELECT
MAX(IF(t.customer_id = 1, 10, 0) + IF(t.customer_group_id = 1, 100, 0)) as score,
t.*
FROM tierprice t
WHERE t.product_variant_id = 110
AND (t.customer_id = 1 OR t.customer_id IS NULL)
AND (t.customer_group_id = 1 OR t.customer_group_id IS NULL)
GROUP BY t.product_variant_id, t.qty;
Expression #2 of SELECT list is not in GROUP BY clause and contains nonaggregated column 't.id' which is not functionally dependent on columns in GROUP BY clause; this is incompatible with sql_mode=only_full_group_by
Related: Group by clause in mySQL and postgreSQL, why the error in postgreSQL?
It could be rewritten using windowed functions(MySQL 8.0 and above):
WITH cte AS (
SELECT t.*, ROW_NUMBER() OVER(PARTITION BY product_variant_id, qty
ORDER BY IF(t.customer_id=1,10,0)+IF(t.customer_group_id=1,100,0) DESC) AS rn
FROM tierprice t
WHERE t.product_variant_id = 110
AND (t.customer_id = 1 OR t.customer_id IS NULL)
AND (t.customer_group_id = 1 OR t.customer_group_id IS NULL)
)
SELECT *
FROM cte
WHERE rn = 1;
db<>fiddle demo
The only valid columns that your query can return are product_variant_id, qty, which you use in GROUP BY clause, and the aggregated column score.
Because of t.* you get all the columns of the table but the values chosen are nondeterministic, for the other columns, as it is explained in MySQL Handling of GROUP BY.
What you can do is join your query to the table like this:
SELECT t.*
FROM tierprice t
INNER JOIN (
SELECT product_variant_id, qty,
MAX(IF(customer_id = 1, 10, 0) + IF(customer_group_id = 1, 100, 0)) as score
FROM tierprice
WHERE product_variant_id = 110
AND (customer_id = 1 OR customer_id IS NULL)
AND (customer_group_id = 1 OR customer_group_id IS NULL)
GROUP BY product_variant_id, qty
) g ON g.product_variant_id = t.product_variant_id
AND g.qty = t.qty
AND g.score = IF(t.customer_id = 1, 10, 0) + IF(t.customer_group_id = 1, 100, 0)
WHERE (t.customer_id = 1 OR t.customer_id IS NULL)
AND (t.customer_group_id = 1 OR t.customer_group_id IS NULL)
See the demo.
Results:
> id | product_variant_id | customer_group_id | price | qty | customer_id
> -: | -----------------: | ----------------: | ----: | --: | ----------:
> 2 | 110 | 1 | 7000 | 2 | null
> 3 | 110 | 1 | 6000 | 5 | null
I need some help to do it right in one query (if it possible).
(this is a theoretical example and I assume the presence of events in event_name(like registration/action etc)
I have 3 colums:
-user_id
-event_timestamp
-event_name
From this 3 columns we need to create new table with 4 new columns:
-user year and month registration time
-number of new user registration in this month
-number of users who returned to the second calendar month after registration
-return probability
Result must be looks like this:
2019-1 | 1 | 1 | 100%
2019-2 | 3 | 2 | 67%
2019-3 | 2 | 0 | 0%
What I've done now:
I'm use this toy example of my possible main table:
CREATE TABLE `main` (
`event_timestamp` timestamp,
`user_id` int(10),
`event_name` char(12)
) DEFAULT CHARSET=utf8;
INSERT INTO `main` (`event_timestamp`, `user_id`, `event_name`) VALUES
('2019-01-23 20:02:21.550', '1', 'registration'),
('2019-01-24 20:03:21.550', '2', 'action'),
('2019-02-21 20:04:21.550', '3', 'registration'),
('2019-02-22 20:05:21.550', '4', 'registration'),
('2019-02-23 20:06:21.550', '5', 'registration'),
('2019-02-23 20:06:21.550', '1', 'action'),
('2019-02-24 20:07:21.550', '6', 'action'),
('2019-03-20 20:08:21.550', '3', 'action'),
('2019-03-21 20:09:21.550', '4', 'action'),
('2019-03-22 20:10:21.550', '9', 'action'),
('2019-03-23 20:11:21.550', '10', 'registration'),
('2019-03-22 20:10:21.550', '4', 'action'),
('2019-03-22 20:10:21.550', '5', 'action'),
('2019-03-24 20:11:21.550', '11', 'registration');
I'm trying to test some queries to create 4 new columns:
This is for column #1, we select month and year from timestamp where action is registration (as I guess), but I need to sum it for month (like 2019-11, 2019-12)
SELECT DATE_FORMAT(event_timestamp, '%Y-%m') AS column_1 FROM main
WHERE event_name='registration';
For column #2 we need to sum users with even_name registration in this month for every month, or.. we can trying for searching first time activity by user_id, but I don't know how to do this.
Here is some thinks about it...
SELECT COUNT(DISTINCT user_id) AS user_count
FROM main
GROUP BY MONTH(event_timestamp);
SELECT COUNT(DISTINCT user_id) AS user_count FROM main
WHERE event_name='registration';
For column #3 we need to compare user_id with the event_name registration and last month event with any event of the second month so we get users who returned for the next month.
Any idea how to create this query?
This is how to calc column #4
SELECT *,
ROUND ((column_3/column_2)*100) AS column_4
FROM main;
I hope you will find the following answer helpful.
The first column is the extraction of year and month. The new_users column is the COUNT of the unique user ids when the action is 'registration' since the user can be duplicated from the JOIN as a result of taking multiple actions the following month. The returned_users column is the number of users who have an action in the next month from the registration. The returned_users column needs a DISTINCT clause since a user can have multiple actions during one month. The final column is the probability that you asked from the two previous columns.
The JOIN clause is a self-join to bring the users that had at least one action the next month of their registration.
SELECT CONCAT(YEAR(A.event_timestamp),'-',MONTH(A.event_timestamp)),
COUNT(DISTINCT(CASE WHEN A.event_name LIKE 'registration' THEN A.user_id END)) AS new_users,
COUNT(DISTINCT B.user_id) AS returned_users,
CASE WHEN COUNT(DISTINCT(CASE WHEN A.event_name LIKE 'registration' THEN A.user_id END))=0 THEN 0 ELSE COUNT(DISTINCT B.user_id)/COUNT(DISTINCT(CASE WHEN A.event_name LIKE 'registration' THEN A.user_id END))*100 END AS My_Ratio
FROM main AS A
LEFT JOIN main AS B
ON A.user_id=B.user_id AND MONTH(A.event_timestamp)+1=MONTH(B.event_timestamp)
AND A.event_name='registration' AND B.event_name='action'
GROUP BY CONCAT(YEAR(A.event_timestamp),'-',MONTH(A.event_timestamp))
What we will do is to use window functions and aggregation -- window functions to get the earliest registration date. Then some conditional aggregation.
One challenge is the handling of calendar months. To handle this, we will truncate the dates to the beginning of the month to facilitate the date arithmetic:
select yyyymm_reg, count(*) as regs_in_month,
sum( month_2 > 0 ) as visits_2months,
avg( month_2 > 0 ) as return_rate_2months
from (select m.user_id, m.yyyymm_reg,
max( (timestampdiff(month, m.yyyymm_reg, m.yyyymm) = 1) ) as month_1,
max( (timestampdiff(month, m.yyyymm_reg, m.yyyymm) = 2) ) as month_2,
max( (timestampdiff(month, m.yyyymm_reg, m.yyyymm) = 3) ) as month_3
from (select m.*,
cast(concat(extract(year_month from event_timestamp), '01') as date) as yyyymm,
cast(concat(extract(year_month from min(case when event_name = 'registration' then event_timestamp end) over (partition by user_id)), '01') as date) as yyyymm_reg
from main m
) m
where m.yyyymm_reg is not null
group by m.user_id, m.yyyymm_reg
) u
group by u.yyyymm_reg;
Here is a db<>fiddle.
Here you go, done in T-SQL:
;with cte as(
select a.* from (
select form,user_id,sum(count_regs) as count_regs,sum(count_action) as count_action from (
select FORMAT(event_timestamp,'yyyy-MM') as form,user_id,event_name,
CASE WHEN event_name = 'registration' THEN 1 ELSE 0 END as count_regs,
CASE WHEN event_name = 'action' THEN 1 ELSE 0 END as count_action from main) a
group by form,user_id) a)
select final.form,final.count_regs,final.count_action,((CAST(final.count_action as float)/(CASE WHEN final.count_regs = '0' THEN '1' ELSE final.count_regs END))*100) as probability from (
select a.form,sum(a.count_regs) count_regs,CASE WHEN sum(b.count_action) is null then '0' else sum(b.count_action) end count_action from cte a
left join
cte b
ON a.user_id = b.user_id and
DATEADD(month,1,CONVERT(date,a.form+'-01')) = CONVERT(date,b.form+'-01')
group by a.form ) final where final.count_regs != '0' or final.count_action != '0'
SQL God...I need some help!
I have a data table that has a route_complete_percentage column and a created_at column.
I need two pieces of data:
the time stamp (within created_at column) when the route_complete_percentage is at its minimum but not zero
the time stamp (within created_at column) when the route_complete_percentage is at its maximum, it might be 100% or not, but when its at its highest.
Here is the kicker, there might be multiple time stamps for the highest route completion column. For example,
Example Table
I have multiple values when the route_completion_percentage is at its maximum, but I need the minimum time stamp value.
Here is the query so far...but the two time stamps are the same.
SELECT
A.fc,
A.plan_id,
A.route_id,
mintime.first_scan AS First_Batch_Scan,
min(route_complete_percentage),
maxtime.last_scan AS Last_Batch_Scan,
max(route_complete_percentage)
FROM
(SELECT
fc,
plan_id,
route_id,
route_complete_percentage,
CONCAT(plan_id, '-', route_id) AS JOINKEY
FROM
houdini_ops.BATCHINATOR_SCAN_LOGS_V2
WHERE
fc <> ''
AND order_id <> 'Can\'t find order'
AND source = 'scan'
AND created_at > DATE_ADD(CURDATE(), INTERVAL - 3 DAY)) A
LEFT JOIN
(SELECT
l.fc,
l.route_id,
l.plan_id,
CONCAT(l.plan_id, '-', l.route_id) AS JOINKEY,
CASE
WHEN MIN(route_complete_percentage) THEN CONVERT_TZ(l.created_at, 'UTC', s.time_zone)
END AS first_scan
FROM
houdini_ops.BATCHINATOR_SCAN_LOGS_V2 l
JOIN houdini_ops.O_SERVICE_AREA_ATTRIBUTES s ON l.fc = s.default_station_code
WHERE
l.fc <> ''
AND l.order_id <> 'Can\'t find order'
AND l.source = 'scan'
AND l.created_at > DATE_ADD(CURDATE(), INTERVAL - 3 DAY)
GROUP BY fc , plan_id , route_id) mintime ON A.JOINKEY = mintime.JOINKEY
LEFT JOIN
(SELECT
l.fc,
l.route_id,
l.plan_id,
CONCAT(l.plan_id, '-', l.route_id) AS JOINKEY,
CASE
WHEN MAX(route_complete_percentage) THEN CONVERT_TZ(l.created_at, 'UTC', s.time_zone)
END AS last_scan
FROM
houdini_ops.BATCHINATOR_SCAN_LOGS_V2 l
JOIN houdini_ops.O_SERVICE_AREA_ATTRIBUTES s ON l.fc = s.default_station_code
WHERE
l.fc <> ''
AND l.order_id <> 'Can\'t find order'
AND l.source = 'scan'
AND l.created_at > DATE_ADD(CURDATE(), INTERVAL - 3 DAY)
GROUP BY fc , plan_id , route_id) maxtime ON mintime.JOINKEY = maxtime.JOINKEY
GROUP BY fc , plan_id , route_id
I don't want to meddle with the rest of your query. Here is something that will do what it sounds like you need. There's sample data included. -- I interpreted your blank values as nulls from your sample data.
Basically, what you are looking for is the Minimum created_at value, inside each of the route_complete_percentage groups. So I treated route_complete_percentage as a group identifier. But you only care about two of the groups, so I identify those groups first in the cte, and use them to filter the aggregate query.
if object_id('tempdb.dbo.#Data') is not null drop table #Data
go
create table #Data (
route_complete_percentage int,
created_at datetime
)
insert into #Data (route_complete_percentage, created_at)
values
(0, '20170531 19:58'),
(1, null),
(2, null),
(3, null),
(4, null),
(5, null),
(6, null),
(7, null),
(80, null),
(90, null),
(100, '20170531 20:10'),
(100, '20170531 20:12'),
(100, '20170531 20:15')
;with cteMinMax(min_route_complete_percentage, max_route_complete_percentage) as (
select
min(route_complete_percentage),
max(route_complete_percentage)
from #Data D
-- This ensures the condition that you don't get the timestamp for 0
where D.route_complete_percentage > 0
)
select
route_complete_percentage,
min_created_at = min(created_at)
from #Data D
join cteMinMax MM on D.route_complete_percentage in (MM.min_route_complete_percentage, MM.max_route_complete_percentage)
group by route_complete_percentage
I got in table something like this:
ID | UID | ACTION | URL | TIMESTAMP
Where ...
ID - primary key
UID - user id
ACTION - IN or OUT
URL - action URL
TIMESTAMP - action TIMESTAMP
How to aggregate all data with one query?
I mean... as output I would like table with UID,URL,TOTAL_TIME where TOTAL_TIME would be a sum of all times between IN and OUT of given URL...
I tried some custom functions, but without luck...
Example Input (timestamp simplified to show what I mean):
1|13|IN|http://www.gógle.koń|1
2|13|OUT|http://www.gógle.koń|5
...
13454|13|IN|http://www.gógle.koń|550
...
13465|13|OUT|http://www.gógle.koń|600
...
243252|13|IN|http://www.pr0nstaff.meh|tiny_leg_finger|1200
...
245431|13|OUT|http://www.pr0nstaff.meh/tiny_leg_finger|2200
PLEASE NOTE THAT THERE MAY BE A CASE (AND SURELY WILL BE) WHERE IN - OUT OF ONE URL WOULD BE BROKEN BY IN OR IN - OUT OR OUT OF OTHER
... so we canno't simply count from IN to OUT without checking the site match.
Output for example input (for UUID = 13) should be:
13|www.gógle.koń|14
13|http://www.pr0nstaff.meh/tiny_leg_finger|1000
Try this, but I'm not shure, if there IN/OUT is not always double. So please check..
CREATE TABLE test1 (
id INT NOT NULL,
uid INT NOT NULL,
action VARCHAR(3),
url varchar(100),
timestamp1 TIMESTAMP
);
INSERT INTO test1 VALUES
( 1 , 13 , 'IN', 'www.go.com', '2015-01-07 08:00:00'),
( 2 , 13 , 'OUT', 'www.go.com', '2015-01-07 09:00:00'),
( 3 , 14 , 'IN', 'www.go2.com', '2015-01-07 08:30:00'),
( 4 , 14 , 'OUT', 'www.go2.com', '2015-01-07 09:00:00'),
( 5 , 15 , 'IN', 'www.go3.com', '2015-01-07 09:00:00'),
( 6 , 16 , 'OUT', 'www.go3.com', '2015-01-07 09:00:00');
SELECT i.uid,i.url,SUM(TIMESTAMPDIFF(minute, i.timestamp1, o.timestamp1)) AS diff_hour
FROM (SELECT id,uid,url,timestamp1
FROM test1
WHERE action = 'IN') i
JOIN (SELECT id,uid,url,timestamp1
FROM test1
WHERE action = 'OUT') o
ON i.uid = o.uid
AND i.url = o.url
AND i.id < o.id
GROUP BY i.uid,i.url
ORDER BY i.uid,i.url;
Try this:
SELECT UID, URL, TIMESTAMPDIFF(HOUR, InTime, OutTime) AS TOTAL_TIME
FROM (SELECT UID, URL,
MAX(CASE WHEN ACTION = 'IN' THEN TIMESTAMP ELSE NULL END) InTime,
MAX(CASE WHEN ACTION = 'OUT' THEN TIMESTAMP ELSE NULL END) OutTime
FROM tableA
GROUP BY UID, URL
) AS A;