Unable to Create Prepared Statements in MySQL - mysql

I'm trying to create a prepared statement in MySQL that takes in a single parameter. When I try this on the command line I get a syntax error. However, when there are no variables in my prepared statement, I am able to create them fine. Below is a copy and paste of what I am seeing at the MySQL command prompt:
mysql> PREPARE state_name FROM "select * from ? limit 1";
ERROR 1064 (42000): You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '? limit 1' at line 1
mysql> PREPARE state_name FROM "select * from documents limit 1";
Query OK, 0 rows affected (0.00 sec)
Statement prepared
The version of MySQL I'm using is 5.0.77-log.
Is there a syntax error I'm not seeing? And are there any config parameters I have to set in order to get prepared statements to work?

You can't pass in table names as prepared statement parameters, I'm afraid, neither can you pass columns to group or sort by. The only thing you can parametrize are fields in where clauses or for updates:
PREPARE state_name FROM "select * from documents where id = ?";
PREPARE state_name FROM "update documents set field = ? where id = ?";

If you want to create a single prepare statement and use it for more than one table, you cand actually create a variable for every table, and then create the statement using this variable, as the MySQL manual explain it :
mysql> USE test;
mysql> CREATE TABLE t1 (a INT NOT NULL);
mysql> INSERT INTO t1 VALUES (4), (8), (11), (32), (80);
mysql> SET #table = 't1';
mysql> SET #s = CONCAT('SELECT * FROM ', #table);
mysql> PREPARE stmt3 FROM #s;
mysql> EXECUTE stmt3;
+----+
| a |
+----+
| 4 |
| 8 |
| 11 |
| 32 |
| 80 |
+----+
mysql> DEALLOCATE PREPARE stmt3;

Related

Delete the dupliacte using TOP in MYSQL query throws Error Code

I just used TOP syntax to delete the duplicate value from table. But it returns error code.
Query:
DELETE top(SELECT COUNT(*)-1 FROM tests WHERE test_name='WALLET_01' AND product_id=25)FROM tests WHERE test_name='WALLET_01' And product_id=25;
Error Code:
Error Code: 1064 You have an error in your SQL syntax;
Executed alone below query return int value as 1:
SELECT COUNT(*)-1 FROM tests WHERE test_name='WALLET_01' AND product_id=25;
Anybody can help me Why I'm getting syntax error?
You could not use a subquery in Top
Top syntax
[
TOP (expression) [PERCENT]
[ WITH TIES ]
]
expression
Is the numeric expression that specifies the number of rows to be returned. expression is implicitly converted to a float value if PERCENT is specified; otherwise, it is converted to bigint.
We can see it didn't support subquery in TOP only expression
EDIT
I saw you change your use dbms.
Mysql didn't support TOP but you can use LIMIT get the limit row.
If there isn't PK in your table, you can try to use dynamic SQL get to decide how many rows you want to delete in the runtime.
Schema (MySQL v5.6)
CREATE TABLE tests(
test_name VARCHAR(50),
product_id int
);
INSERT INTO tests VALUES('WALLET_01',25);
INSERT INTO tests VALUES('WALLET_01',25);
SET #sql = NULL;
SET #Rn = NULL;
SELECT
(COUNT(*)-1)
INTO #Rn
FROM tests
WHERE test_name='WALLET_01' AND product_id=25;
SET #sql = CONCAT('DELETE FROM tests WHERE test_name=''WALLET_01'' AND product_id=25 limit ',#Rn);
PREPARE stmt FROM #sql;
EXECUTE stmt;
DEALLOCATE PREPARE stmt;
Query #1
SELECT * FROM tests;
| test_name | product_id |
| --------- | ---------- |
| WALLET_01 | 25 |
View on DB Fiddle

MySQL Stored Procedure Variable as Table Name concatenated

I have the following query I want to execute in my stored procedure WITHOUT PREPARING the query, since this gives me problems with OUT to pass back parameters.
DELIMITER //
CREATE PROCEDURE Test (
IN CID BIGINT(20),
IN IDs LONGTEXT
)
BEGIN
#EXECUTE UNDERNEATH QUERY
SELECT * FROM CONCAT('Part1_OfTableName', CID); #CID IS CustomerID
END //
DELIMITER ;
However, this fails and I don't know how to fix the problem.
(Note that in the example I have no spaces in my table name, however in my situation I might have a space in my table name though)
PREPARE should have no bearing on your ability to successfully set OUT parameters of your procedure
SET DELIMITER //
CREATE PROCEDURE test(IN cid INT, IN ids TEXT, OUT out_int INT)
BEGIN
SET #sql = CONCAT('SELECT * FROM `table_', cid, '`', CASE WHEN ids IS NULL THEN '' ELSE CONCAT(' WHERE id IN( ', ids, ')') END);
PREPARE stmt FROM #sql;
EXECUTE stmt;
DEALLOCATE PREPARE stmt;
SET out_int = 1;
END//
SET DELIMITER ;
Sample usage:
mysql> CALL test(1, '2,3', #out_int);
+------+
| id |
+------+
| 2 |
| 3 |
+------+
2 rows in set (0.00 sec)
Query OK, 0 rows affected (0.00 sec)
mysql> SELECT #out_int;
+----------+
| #out_int |
+----------+
| 1 |
+----------+
1 row in set (0.00 sec)
If you need to return results from a stored procedure using sql statement that must be prepared, you can use an intermediate temp table.
BEGIN
CREATE TEMPORARY TABLE `myresults` blah blah....;
//construct and prepare select you would've used, but start it with an insert like so...
// INSERT INTO `myresults` SELECT ....
// Execute the prepared query
SELECT * FROM `myresults`;
DROP TEMPORARY TABLE `myresults`;
END
...at least I am pretty sure this technique used to work; I've been working more in MSSQL the last couple years.
Something to note:
Temporary tables are connection/session specific, so while safe from a global perspective using a generic name like myresults can be problematic if queries executed earlier on the connection/session (or by a procedure calling this one) use the same name; in practice/paranoia, I tended to use a different guid (in each procedure using this technique) as a prefix for any temporary tables generated within it.

Why does this SQL injection succeed even though the SQL statement produces a syntax error?

In this question and some of the comments, this input:
$input = '; DELETE FROM table_name ; #';
was suggested as an example of an SQL injection into this PHP statement:
$input = $_POST['input'];
'SELECT '.$input.' FROM table_name'
I cut into the chase and used an example in MySQL directly, although I used * in place of #. The result is the same.
CREATE TABLE a_table (
id INT NOT NULL);
INSERT INTO a_table (id) VALUES (1), (2), (3), (4), (5);
SELECT * FROM a_table;
SELECT ; DELETE FROM a_table; * FROM a_table;
SELECT COUNT(*) FROM a_table;
This outputs:
mysql> SELECT * FROM a_table;
+----+
| id |
+----+
| 1 |
| 2 |
| 3 |
| 4 |
| 5 |
+----+
5 rows in set (0.00 sec)
mysql> SELECT ; DELETE FROM a_table; * FROM a_table;
ERROR 1064 (42000): You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '' at line 1
Query OK, 5 rows affected (0.03 sec)
mysql> SELECT * FROM a_table;
Empty set (0.00 sec)
Why does this SQL injection succeed despite the syntax error? Is this because MySQL parses and runs the DELETE query before the surrounding SELECT query? I don't plan to rely on such weak PHP code or MySQL syntax errors to guard against SQL injection, of course; this example just intrigued me.
The queries are still run because mysql uses ; to delimit each query and it will continue running the queries even when there is a syntax error if you allow it to do so. Running the queries in SequelPro I get a message about the syntax error and it prompts me if I want to continue running all queries or stop. However, running them straight in MySQL commandline the queries continue running and MySQL just gives an error message and continues to the next query as expected (same thing that happens with the PHP code).

Why is mysql caching the column names of a temporay table that is deleted?

I've reduced my issue down to this simple SP. The column names are getting cached in the SELECT * at the end. I have no idea why or how to stop it. I tried adding SQL_NO_CACHE but that makes no difference.
DROP TABLE IF EXISTS foo;
CREATE TABLE foo(
col1 int,
col2 int);
INSERT INTO foo VALUES(1,2),(3,4),(5,6);
DROP PROCEDURE IF EXISTS mysp;
DELIMITER ;;
CREATE DEFINER=root#localhost PROCEDURE mysp(c INT)
BEGIN
DROP TABLE IF EXISTS mydata;
SET #mycol='col1';
IF c > 0 THEN SET #mycol:='col2';
END IF;
SET #s=CONCAT('CREATE TEMPORARY TABLE mydata AS SELECT ', #mycol, ' FROM foo');
PREPARE stmt FROM #s;
EXECUTE stmt;
DEALLOCATE PREPARE stmt;
-- The following select call fails on 2nd and subsequent executions of the SP
SELECT SQL_NO_CACHE * FROM mydata;
SELECT "Please see new temp table mydata" as Result;
END ;;
DELIMITER ;
Version
mysql> SELECT VERSION();
+------------+
| VERSION() |
+------------+
| 5.5.15-log |
+------------+
1 row in set (0.00 sec)
First run works fine as expected
mysql> CALL mysp(0);
+------+
| col1 |
+------+
| 1 |
| 3 |
| 5 |
+------+
3 rows in set (0.17 sec)
+----------------------------------+
| Result |
+----------------------------------+
| Please see new temp table mydata |
+----------------------------------+
1 row in set (0.17 sec)
Query OK, 0 rows affected (0.17 sec)
Now if I try and run it again using the other column
mysql> CALL mysp(1);
ERROR 1054 (42S22): Unknown column 'qlgqp1.mydata.col1' in 'field list'
mysql> SELECT #mycol;
+--------+
| #mycol |
+--------+
| col2 |
+--------+
1 row in set (0.00 sec)
If I recreate the storedprocedure again its works
mysql> CALL mysp(1);
+------+
| col2 |
+------+
| 2 |
| 4 |
| 6 |
+------+
3 rows in set (0.18 sec)
+----------------------------------+
| Result |
+----------------------------------+
| Please see new temp table mydata |
+----------------------------------+
1 row in set (0.18 sec)
Query OK, 0 rows affected (0.18 sec)
But if I try switching back to the first column - even if I try dropping the temp table first - it still doesn't work
mysql> CALL mysp(0);
ERROR 1054 (42S22): Unknown column 'qlgqp1.mydata.col2' in 'field list'
mysql> DROP TABLE mydata;
Query OK, 0 rows affected (0.03 sec)
mysql> CALL mysp(0);
ERROR 1054 (42S22): Unknown column 'qlgqp1.mydata.col2' in 'field list'
mysql>
*Additional info asked for by eggyal. Also I tried this on another mysql version with same result. *
mysql> CALL mysp(1);
+------+
| col2 |
+------+
| 2 |
| 4 |
| 6 |
+------+
3 rows in set (0.20 sec)
+----------------------------------+
| Result |
+----------------------------------+
| Please see new temp table mydata |
+----------------------------------+
1 row in set (0.20 sec)
Query OK, 0 rows affected (0.20 sec)
mysql> describe mydata;
+-------+---------+------+-----+---------+-------+
| Field | Type | Null | Key | Default | Extra |
+-------+---------+------+-----+---------+-------+
| col2 | int(11) | YES | | NULL | |
+-------+---------+------+-----+---------+-------+
1 row in set (0.00 sec)
mysql> CALL mysp(0);
ERROR 1054 (42S22): Unknown column 'test.mydata.col2' in 'field list'
mysql> describe mydata;
+-------+---------+------+-----+---------+-------+
| Field | Type | Null | Key | Default | Extra |
+-------+---------+------+-----+---------+-------+
| col1 | int(11) | YES | | NULL | |
+-------+---------+------+-----+---------+-------+
1 row in set (0.00 sec)
Interesting development of a fix - changing the last few lines to a prepared statement works - but using exactly the same query as before.
-- The following select call fails on 2nd and subsequent executions of the SP
PREPARE stmt FROM 'SELECT SQL_NO_CACHE * FROM mydata';
EXECUTE stmt;
DEALLOCATE PREPARE stmt;
SELECT "Please see new temp table mydata" as Result;
MySQL is reusing the statement that was prepared on the previous execution. It's not really "caching" column names; what it's "caching" (if you will) is the prepared statement.
The easy workaround is to use dynamic SQL statement to gain control over the behavior, and avoid the reuse of the previously prepared statement:
SET #s=CONCAT('SELECT ',#mycol,' FROM mydata');
PREPARE stmt FROM #s;
EXECUTE stmt;
DEALLOCATE PREPARE stmt;
It's not matter of the column names being "cached", or the results of the query being cached. It's a performance optimization; it's a matter of that statement already being prepared, within your session.
By using dynamic SQL, you can control when the statement is prepared (i.e. parsing the SQL text for syntax (statement formation, keywords, etc.), checked for semantics (object names exist, column names exist, user has required privileges, etc.), and preparing an execution plan.
With the static SQL, all of that happens on the first execution, and then MySQL hangs on to the prepared statement.
For performance reasons, we wouldn't want the overhead of a "hard parse" every time a static statement is executed. This is especially true on a function that gets called multiple times, from a SQL statement.
(NOTE: Oracle does the same thing, BUT, Oracle does a good job of marking prepared statements as INVALID whenever a referenced object is altered or dropped.)
MySQL opted not to do that, probably because of the overhead of tracking all the dependencies. And, in the vast majority of cases, that overhead is not required.
I think the lesson here is if you are going to use dynamic SQL to create a table that is going to have DIFFERENT columns in it, you are going to have to use dynamic SQL to query that table.
My recommendation is that you avoid using SELECT *, unless your statement is in complete control of the columns being returned, for example, from an inline view. Otherwise, SQL statements that use SELECT * are fundamentally broken... they may work now, but a change to a table (adding a column for example) will break an application.
Q: Please explain how it is not a bug.
It is not a bug because the SELECT statement in your stored procedure is really just shorthand for what is actually happening.
On the first execution of your procedure, MySQL is doing the parse of your query text, and preparing and executing a statement. Basically, equivalent to:
PREPARE s1 FROM 'SELECT * FROM mydata';
EXECUTE s1;
On the second execution of the procedure, MySQL is simply executing the statement that has been previously prepared. Basically, equivalent to:
EXECUTE s1;
On that second execution, you seem to be expecting MySQL to run the equivalent of:
DEALLOCATE PREPARE s1;
PREPARE s1 FROM 'SELECT * FROM mydata';
EXECUTE s1;
You can make a case that this is what MySQL should be doing on the second execution. You could argue that statements prepared during a previous execution of a procedure should be discarded, and re-parsed and re-prepared on subsequent executions.
It would not be wrong for a DBMS to do this. But there would be, as always, the consideration about the impact on performance.
You could also make a case that MySQL should track all the database objects that a particular prepared statement is dependent on. You could argue that whenever one of those database objects is dropped or altered, MySQL should invalidate all the prepared statements (and all other objects) that depend on the altered or dropped object. Again, it would not be wrong for a DBMS to do this. Some DBMSs (such as Oracle) do this quite well. But again, the developers of the DBMS also take performance into consideration when making these design and implementation decisions.
The bottom line is that MySQL does provide you with a way to make happen what you want to happen. It's just that the syntax in your procedure, what you are expecting to make it happen, doesn't actually make it happen.
first of all it is a temp table so really should not be expected to be there, 2nd - it is dropped
I think you are reading something different into the "TEMPORARY" keyword than is defined in the specification. A TEMPORARY table is really just like a regular table, except that it is visible only to the session that created it, and it will be automatically dropped when the MySQL session ends. (We also note that a TEMPORARY table is not displayed by a SHOW TABLES command, and does not appear in the information_schema views.)
As to which tables (TEMPORARY or otherwise) MySQL should expect "to be there", I don't believe the documentation really addresses that, except noting that when a SQL statement is executed, and that statement references an object that does not exist, MySQL will throw an exception.
The same behavior you observe with a TEMPORARY table, you will also observe with a non-TEMPORARY table. The issue is not related to whether the table is defined as TEMPORARY or not.
where does SELECT * compare to PREPARE s1 FROM SELECT *
Those two forms effectively follow the same code path. The first execution of a static SELECT * is effectively equivalent to:
PREPARE s1 FROM 'SELECT *';
EXECUTE s1;
(Note the absence of a DEALLOCATE statement following the exeuction.) On a subsequent execution, the statement is already prepared, so it's effectively equivalent to:
EXECUTE s1;
This is similar to what would happen if you were coding in PHP mysqli
$s1 = $mysqli->prepare("SELECT * FROM mydata");
$mysqli->execute($s1);
/* rename the columns in the mydata table */
$mysqli->execute($s1);
I understand this is relatively old (+6 months) but I encountered this problem in prepared statements, and the only way I got around it was to concatenate the field names and use a prepared statement that effectively calls "select *" but uses the actual field names. I'm using prepared statements to create a temporary table, and the only standard field is the first one, while the rest causes the caching problem on "Select *".
Select fields we want to use into a temp table
Iterate through table rows of field names, and on each iteration:
set sql01 = concat(sql01,',',sFieldName,''); (just fields) and: set sql02 = concat(sql02,',',sFieldName,' varchar(50) '); (fields + field type only, for create table statement)
create the output table:
set #sql = concat('CREATE TEMPORARY TABLE tOutput(FirstField varchar(50), ',sql02,');'); PREPARE STMT FROM #sql; EXECUTE STMT; DEALLOCATE PREPARE STMT;
At the end:
set #sql = concat('SELECT FirstField,',sql01,' FROM tOutput;'); PREPARE STMT FROM #sql; EXECUTE STMT; DEALLOCATE PREPARE STMT;

Dynamically choosing a column in MySQL

I know how to pipe one MySQL query into another:
SELECT user_name FROM users WHERE user_id=( SELECT user_id FROM entries WHERE header="foo" );
Out of pure intellectual curiosity, how I dynamically choose a column or a table?
Ex:
SELECT (
SELECT column_name FROM column_names WHERE id = 1
) FROM (
SELECT table_name FROM table_names WHERE id = 1
);
Use a prepared statement:
mysql> SET #sql = CONCAT("SELECT ", (SELECT "NOW()"));
Query OK, 0 rows affected (0.00 sec)
mysql> SELECT #sql;
+--------------+
| #sql |
+--------------+
| SELECT NOW() |
+--------------+
1 row in set (0.00 sec)
mysql> PREPARE stmt FROM #sql;
Query OK, 0 rows affected (0.00 sec)
Statement prepared
mysql> EXECUTE stmt;
+---------------------+
| NOW() |
+---------------------+
| 2009-04-06 23:08:31 |
+---------------------+
1 row in set (0.00 sec)
I'm pretty sure this is impossible with a regular query or view.
In answer to your first question, you should learn about how to do JOIN in SQL. A join is a fundamental operation in the SQL language. It's as important is understanding how to do a loop in other languages.
SELECT DISTINCT users.user_name
FROM users JOIN entries USING (user_id)
WHERE entries.header = 'foo';
Regarding your second question, no, you can't make table names or column names dynamic within a single statement.
However, you can write code in your application to build a SQL statement as a string, based on looking up column names and table names. Then execute the resulting string as a new SQL query.
You can do it by querying the information_schema.columns table.
Do this and check the results. I'm not sure what you're trying to do but that table contains anything related to your columns:
SELECT * FROM information_schema.`COLUMNS` C;
BTW, I don't know any way of doing this in a single query. You should get the columns information and then create a new query in your coding language, whatever that is.