I don't think this is a duplicate posting because I've looked around and this seems a bit more specific than whats already been asked (but I could be wrong).
I have 4 tables and one of them is just a lookup table
SELECT exercises.id as exid, name, sets, reps, type, movement, categories.id
FROM exercises
INNER JOIN exercisecategory ON exercises.id = exerciseid
INNER JOIN categories ON categoryid = categories.id
INNER JOIN workoutcategory ON workoutid = workoutcategory.id
WHERE (workoutcategory.id = '$workouttypeid')
AND rand_id > UNIX_TIMESTAMP()
ORDER BY rand_id ASC LIMIT 6;
exercises table contains a list of exercise names, sets, reps, and an id
categories table contains an id, musclegroup, and type of movement
workoutcategory table contains an id, and a more specific motion (ie: upper body push, or upper body pull)
exercisecategory table is the lookup table that contains (and matches the id's) for exerciseid, categoryid, and workoutid
I've also added a column to the exercises table that generates a random number upon entering the row in the database. This number is then updated only for the specified category when it is called, and then sorted and displays the ascending order of the top 6 listings. This generates a nice random entry for me. (Found that solution elsewhere here on SO).
This works fine for generating 6 random exercises from a specific top level category. But I'd like to drill down further. Here's an example...
select all rows inside categoryid 4
then still within the category 4 results, find all that have movementid 2, and then find one entry with a typeid 1, then another for typeid 2, etc
TLDR; Basically there's a few levels of categories and I'm looking to select a few from here and a few from there and they're all within this top level. I'm thinking this could all be executed within more than one query but im not sure how... in the end I'm looking to end with one array of the randomized entries.
Sorry for the long read, its the best explanation I've got.
Just realized I never came back to this posting...
I ended up using several mysql queries within a switch based on what is needed during the request. Worked out perfectly.
Related
I'm working on a mysql database select and cannot find a solution for this tricky problem.
There's one table "words" with id and names of objects (in this case possible objects in a picture).
words
ID object
house
tree
car
…
In the other table "pictures" all the information to a picture is saved. Besides to information to resolution, etc. there are especially informations on the objects in the picture. They are saved in the column objects by the ids from the table words like 1,5,122,345, etc.
Also the table pictures has a column "location", where the id of the place is written, where I took the picture.
pictures
location objectsinpicture ...
1 - 1,2,3,4
2 - 1,5,122,34
1 - 50,122,345
1 - 91,35,122,345
2 - 1,14,32
1 - 1,5,122,345
To tag new pictures of a particular place I want to become suggestions of already saved information. So I can create buttons in php to update the database instead of using a dropdown with multiple select.
What I have tried so far is the following:
SELECT words.id, words.object
FROM words, pictures
WHERE location = 2 AND FIND_IN_SET(words.id, pictures.objectsinpicture)
GROUP BY words.id
ORDER BY words.id
This nearly shows the expected values. But some information is missing. It doesn't show all the possible objects and I cannot find any reason for this.
What I want is for example all ids fo location 2 joined to the table words and to group double entries of objectsinpicture:
1,5,122,34
1,14,32
1,5,14,32,34,122
house
...
...
...
...
...
Maybe I need to use group_concat with comma separator. But this doesn't work, either. The problem seems to be where condition with the location.
I hope that anyone has an idea of solving this request.
Thanks in advance for any support!!!
This is a classic problem of denormalization causing problems.
What you need to do is store each object/picture association separately, in another table:
create table objectsinpicture (
picture_id int,
object_id int,
primary key (picture_id, object_id)
);
Instead of storing a comma-separated list, you would store one association per row in this table. It will grow to a large number of rows of course, but each row is just a pair of id's so the total size won't be too great.
Then you can query:
SELECT w.id, w.object
FROM pictures AS p
JOIN objectsinpicture AS o ON o.picture_id = p.id
JOIN words AS w ON o.object_id = w.id
WHERE p.location = 2;
I have following problem:
I am currently working with 3 tables , bw, mkz and wcn.
bw is the main table I work with and mkz is some kind of link between the ids of bw and the categories in wcn ( web categorie names ). In wb one item can contain many categories and also none.
My problem is that I simply dont understand how to select all categories for one id in bw. The problem is that I would need, in the best case, to get 30 lines of web items and each web item containing all its categories
bw contains the web ids and other information
mkz contains web ids and category ids and links them
wcn contains category ids and names that need to be represented
My guess is that I somehow need to select in a select and count but I cant seem to find a possible solution to concat the category strings...
Fundamentally, you want group_concat(). Here is one method for retrieving all columns from bw along with the categories:
select bw.*,
(select group_concat(wcn.name)
from mkz join
wcn
on mkz.category_id = wcn.category_id
where mkz.web_id = bw.web_id
) as categories
from bw;
I have a 1 to many relationship between people and notes about them. There can be 0 or more notes per person.
I need to bring all the notes together into a single field and since there are not going to be many people with notes and I plan to only bring in the first 3 notes per person I thought I could do this using at most 3 queries to gather all my information.
My problem is in geting the mySQL query together to get the first, second, etc note per person.
I have a query that lets me know how many notes each person has and I have that in my table. I tried something like
SELECT
f_note, f_person_id
FROM
t_person_table,
t_note_table
WHERE
t_person_table.f_number_of_notes > 0
AND t_person_table.f_person_id = t_note_table.f_person_id
GROUP BY
t_person_table.f_person_id
LIMIT 1 OFFSET 0
I had hoped to run this up to 3 times changing the OFFSET to 1 and then 2 but all I get is just one note coming back, not one note per person.
I hope this is clear, if not read on for an example:
I have 3 people in the table. One person (A) has 0 notes, one (B) with 1 and one (C) with 2.
First I would get the first note for person B and C and insert those into my person table note field.
Then I would get the second note for person C and add that to the note field in the person table.
In the end I would have notes for persons B and C where the note field for person C would be a concatination of their 2 notes.
Welcome to SO. The thing you're trying to do, selecting the three most recent items from a table for each person mentioned, is not easy in MySQL. But it is possible. See this question.
Select number of rows for each group where two column values makes one group
and, see my answer to it.
Select number of rows for each group where two column values makes one group
Once you have a query giving you the three rows, you can use GROUP_CONCAT() ... GROUP BY to aggregate the note fields.
You can get one note per person using a nested query like this:
SELECT
f_person_id,
(SELECT f_note
FROM t_note_table
WHERE t_person_table.f_person_id = t_note_table.f_person_id
LIMIT 1) AS note
FROM
t_person_table
WHERE
t_person_table.f_number_of_notes > 0
Note that tables in SQL are basically without a defined inherent order, so you should use some form or ORDER BY in the subquery. Otherwise, your results might be random, and repeated runs asking for different notes might unexpectedly return the same data.
If you only aim for a concatenation of notes in any case, then you can use the GROUP_CONCAT function to combine all notes into a single column.
What's the best way to store "ordered lists" in a database, so that updating them (adding, removing and changing the order of entries) is easily done?
Consider a database where you have a table for users and movies. Each user has a list of favorite movies.
Since many users can like the same movie, I made users and movies separate tables and uses a third table to connect them, usermovies.
usermovies contains an id of a user and a movie and an "order number". The order number is used to order the list of movies for users.
For example, user Josh might have the following list:
Prometheus
Men in Black 3
The Dictator
and user Jack might have a list like:
The Dictator
Prometheus
Battleship
Snow White and the Huntsman
So, they share some favorites, but not necessarily in the same order.
I can get the list of movie IDs for each user using a query:
SELECT movie_id FROM usermovies WHERE user_id =? ORDER BY order_number
Then, with the ordered movie_ids, I can get the list of movies using another query
SELECT name FROM movies WHERE id in (?,?,?) ORDER BY FIELD (id, ?,?,?)
So queries work, but updating the lists seems really complex now - are there better ways to store this information so that it would be easy to get the list of movies for user x, add movies, remove them and change the order of the list?
If you are not looking for a "move up / move down" kinda solution, and then defaulting to adding at the bottom of the list, here are a few more pointers:
Inserting new rows into a specific position can be done like this: (inserting at position 3)
UPDATE usermovies SET order_number = ordernumber + 1
WHERE ordernumber > 3 and user_id = ?;
INSERT INTO usermovies VALUES (?, 3, ?);
And you can delete in a similar fashion: (deleting position 6)
DELETE usermovies WHERE order_numer = 6 and user_id=?;
UPDATE usermovies SET order_number = ordernumber - 1
WHERE ordernumber > 6 and user_id = ?;
A junction/link table with additional columns for the attributes of the association between movies and users is the standard way of realizing a many-many association with an association class - so what you have done seems correct.
Regarding the ease of insert/update/delete, you'll have to manage the entire association (all rows for the user-movie FKs) every time you perform an insert/update/delete.
There probably isn't a magical/simpler way to do this.
Having said this, you'll also need to run these operations in a transaction and more importantly have a 'version' column on this junction table if your application is multi-user capable.
To retrieve user favourites movies you could use a single query:
SELECT um.order_number, m.name FROM movies m
INNER JOIN usermovies um ON m.id = um.movie_id
WHERE um.user_id = ?
ORDER BY um.order_number
To add/remove a favourite movie simply add/remove related record in usermovies table.
To alter a movie order simply change all order_number field in user_movies table related to user.
In addition to what others have said, reordering existing favorites can be done in a single UPDATE statement, as explained here.
The linked answer explains reordering of two items, but can be easily generalized to any number of items.
This is for a homework assignment. I haven't copy-pasted the question below, I made an simpler version of it that focuses on the specific area where I'm stuck.
Let's say I have a table of two values: a person's name, and the place he had lunch yesterday. Assume everyone has lunch in pairs. How can I query the database to return all the pairs of people that had lunch together yesterday? Each pair must be only listed once.
I'm actually not even sure what the professor means by return them as pairs. I've sent him an email, but no reply yet. It seems like he wants me to write a query that returns a table with column 1 as person 1 and column 2 as person 2.
Any suggestions on how to go about this? Does it seem right to assume he wants them as separate columns?
So far, I basically have:
SELECT name, restaurant FROM lunches GROUP BY restaurant, name
which essentially just reorganizes the table so that the people who had lunch together are one after the other.
We have to assume there can be only one pair eating lunch in a given restaurant.
You can get a list of pairs either using self-join:
SELECT l1.name, l2.name FROM lunches l1
JOIN lunches l2
ON l1.restaurant = l2.restaurant AND l1.name < l2.name
or using GROUP BY:
SELECT GROUP_CONCAT(name) FROM lunches
GROUP BY restaurant
The first query will return pairs in two different columns, while the second in one column, using comma as separator (default for GROUP_CONCAT, you can change it to whatever you wish).
Also note that for the first query names in pairs will come in alphabetical order as we use < instead of <> to avoid listing each pair twice.