SELECT u.username, count(t.tid) as total
FROM tbl2 t
JOIN users u ON t.userid = u.userid
GROUP BY t.userid
The above query works fine and all, it returns the number of total task for each user that has atleast one task in the tbl2 table.
But what i want to do is return all users, Even if the user doesn't have any records associated to him in the second tbl2 table. I want the total to show as 0 for those users who doesn't have any records, how can i accomplish this?
The problem with the other answers given is that you want to select all users that have no associated records; using a LEFT JOIN, the users table is on the wrong (nullable) side of the join. You could replace that LEFT JOIN with a RIGHT JOIN, but that syntax always feels unintuitive to me.
The standard answer is to reverse the order of the tables while using a LEFT JOIN:
SELECT u.username, count(t.tid) as total
FROM users u
LEFT JOIN tbl2 t ON t.userid = u.userid
GROUP BY u.username
Note that it's better practice (and, in some DBMSes, required) to group on the non-aggregated columns in the SELECT list, rather than grouping on userid and selecting username.
You should use a LEFT JOIN insteed of an INNER JOIN (default type of join), something like this:
SELECT u.username, count(t.tid) as total
FROM tbl2 t
LEFT JOIN users u ON t.userid = u.userid
GROUP BY t.userid
You'd want to use a LEFT JOIN then instead
SELECT u.username, count(t.tid) as total
FROM tbl2 t
LEFT JOIN users u ON t.userid = u.userid
GROUP BY t.userid
LEFT JOIN will join the table and show null column results for tbl2 if an associated entry doesn't exist.
Related
I have the following SQL query which returns 2 results which are the same only different by a where clause.
I would like to have them combined and group them under the user names. At the moment the two results are displayed but the results are not fully combined and the users are shown twice because of the two select statements.
How can I combine the two to create a single result.
The SQL query is as follows
SELECT
COUNT (asings.user_id),
post_status.status_id as status_id,
users.name,
users.id as user_id
from asigns
LEFT JOIN
post_status on asigns.post_id = post_status.post_id
RIGHT JOIN
users on asigns.user_id = users.id
WHERE
post_status.status_id = 2
GROUP BY users.id
UNION
SELECT
COUNT(asigns.user_id),
post_status.status_id as status_id,
users.name,
users.id from asigns
LEFT JOIN
post_status on asigns.post_id = post_status.post_id
RIGHT JOIN
users on asigns.user_id = users.id
WHERE
post_status.status_id = 3
GROUP BY users.id
See in this photo the usernames are appearing twice, what I want is to join the two username, and move count as two different columns depending on the status_id
How can I solve this. Thanks
You should use a single query with conditional aggregation:
SELECT
SUM(ps.status_id = 2) AS cnt_2,
SUM(ps.status_id = 3) AS cnt_3,
u.name,
u.id as user_id
FROM users u
LEFT JOIN assigns a ON a.user_id = u.id
LEFT JOIN post_status ps ON a.post_id = ps.post_id
GROUP BY u.id;
Use SELECT distinct for the union:
SELECT distinct * FROM ([FIRST SELECT] UNION [SECOND SELECT])
Or GROUP BY username
SELECT * FROM ([FIRST SELECT] UNION [SECOND SELECT]) GROUP BY username
BUT I suggest to review your both selects, if it differs just in the where clause so use where clause with the operator OR and you handle it just by one SELECT
Although your are using a LEFT and a RIGHT join and implicitly an INNER join between users and asigns, the WHERE clause transforms all the joins to INNER joins, because you are picking only the matching rows from post_status.
So, you only need INNER joins and conditional aggregation:
SELECT COALESCE(SUM(ps.status_id = 2), 0) counter_2,
COALESCE(SUM(ps.status_id = 3), 0) counter_3,
u.name,
u.id AS user_id
FROM users u
INNER JOIN asigns a ON a.user_id = u.id
INNER JOIN post_status ps ON ps.post_id = a.post_id
WHERE ps.status_id IN (2, 3)
GROUP BY u.id;
I am stuck with some SQL query.
I have four tables. Which are connected:
user =>user_account=>acount_profile_entries=>profile_entries
From left to right they are one to many.
user_account has a user_id field as FK.
account_profile_field has user_account_id and profile_entry_id.
Profile_entries has a text field that I need to show for each user (account).
I need to write a query that will show me, all accounts for every user, and its profile entries.
I am sorry if this is confusing, I tried to make it simple
This is what I have done so far. I can show all accounts for every user and this is the point I am stuck with. Last two commented out Joins are not working properly. I believe I am close somewhat, I just need a push :)
SELECT
u.email AS Email,
u.id AS UserId,
ua.id AS UserAccountId,
ua.app_id AS Application
FROM users AS u
INNER JOIN user_accounts ua ON ua.user_id = u.id
-- INNER JOIN account_profile_entries ape ON ape.user_account_id = ua.id
-- INNER JOIN profile_entries as pe ON pe.id = ape.profile_entry_id
limit 10
Try this SQL Query with using LEFT JOIN
Description :- The MySQL LEFT JOIN joins two tables and fetches rows based on a condition, which is matching in both the tables and the unmatched rows will also be available from the table written before the JOIN clause.
SYNTAX
SELECT column_name(s)
FROM table1
LEFT JOIN table2 ON table1.column_name = table2.column_name;
SELECT u.*,
u.id AS UserId,
ua.id AS UserAccountId,
ua.app_id AS Application,pe.* FROM `users` u
LEFT JOIN user_accounts ua ON ua.user_id = u.id
LEFT JOIN account_profile_entries ape ON ape.user_account_id = ua.id
LEFT JOIN profile_entries as pe ON pe.id = ape.profile_entry_id LIMIT 10
I'm trying to select results from two different unrelated tables, showcase and questions to appear in a feed. They should be ordered by the common column hotness which is a float value.
SELECT s.id,s.date,s.title,s.views,s.image,s.hidpi,s.width,s.description,u.display_name,u.avatar
FROM showcase AS s
INNER JOIN users AS u ON s.user_id = u.id
UNION
SELECT q.id,q.date,q.title,q.views,q.text,u.display_name,u.avatar,0,0,0
FROM questions AS q
INNER JOIN users AS u ON q.user_id = u.id
ORDER BY hotness DESC
LIMIT 10
I've tried UNION, but I have no idea how I should be using it here and get this error unknown column hotness
You need to select the value in order for the ORDER BY to recognize it:
SELECT s.id,s.date,s.title,s.views,s.image,s.hidpi,s.width,s.description,u.display_name,u.avatar, s.hotness
FROM showcase AS s
INNER JOIN users AS u ON s.user_id = u.id
UNION ALL
SELECT q.id,q.date,q.title,q.views,q.text,u.display_name,u.avatar,0,0,0, q.hotness
FROM questions AS q
INNER JOIN users AS u ON q.user_id = u.id
ORDER BY hotness DESC;
Note that I also changed the UNION to UNION ALL. Unless you intend to remove duplicates, there is no reason to incur the extra processing for doing that.
You can try this query:
SELECT r.* FROM (
SELECT s.id,s.date,s.title,s.views,s.image,s.hidpi,s.width,s.description,u.display_name,u.avatar, s.hotness
FROM showcase AS s
INNER JOIN users AS u ON s.user_id = u.id
UNION
SELECT q.id,q.date,q.title,q.views,q.text,u.display_name,u.avatar,0,0,0, q.hotness
FROM questions AS q
INNER JOIN users AS u ON q.user_id = u.id
) as r
ORDER BY r.hotness DESC
LIMIT 10
You need to merge Union result in subquery to apply Order by on the result. I also added hotness in select clause, please check I take field from good table.
There are three tables. user, like, comment. Table like and comment has rows associated to user. I need all users with their associated row count from table like and comment. It's easy to do when there is only one table associated. However, here is my query.
SELECT u.id as id, u.display_name as displayName,
COUNT(x.user_id) as likeCount,
COUNT(y.user_id) as commentCount
FROM `user` u
LEFT JOIN
`like` x ON x.user_id = u.id
LEFT JOIN
`comment` y ON y.user_id = u.id
GROUP BY u.id
Table relationships:
One user has many likes
One user has many comments
commentCount is giving correct rows count, but likeCount giving wrong rows count. Please don't post answer which uses sub queries. I want it with only ONE SELECT clause. I am using MySQL. TIA
You can get the user count per individual table, like this:
SELECT user, COUNT(*) AS t1Count
FROM table1
GROUP BY user;
SELECT user, COUNT(*) AS t2Count
FROM table2
GROUP BY user;
Then you can join those two to the Users table to get the count of each. You should use COALESCE() to return null values with 0:
SELECT u.id, COALESCE(t1.t1Count, 0), COALESCE(t2.t2Count, 0)
FROM users u
LEFT JOIN(
SELECT user, COUNT(*) AS t1Count
FROM table1
GROUP BY user) t1 ON u.id = t1.user
LEFT JOIN(
SELECT user, COUNT(*) AS t2Count
FROM table2
GROUP BY user) t2 ON u.id = t2.user;
Here is an SQL Fiddle example.
I have a table of ratings for comments, when I fetch comments, I also fetch the ratings and I also want to be able to display which comments the logged user has already voted on. This is what I am doing now
SELECT
c.id,
c.text,
c.datetime,
c.author,
u.email AS author_name,
SUM(cr.vote) AS rating,
cr2.vote AS voted
FROM comments c
LEFT JOIN users u ON u.id = c.author
LEFT JOIN comments_ratings cr ON c.id = cr.comment
LEFT JOIN comments_ratings cr2 ON c.id = cr2.comment AND cr2.user = :logged_user_id
GROUP BY c.id ORDER BY c.id DESC
But I don't like how I'm performing a second join on the same table. I know it is perfectly valid but if I could get the information I want from the first join, which is there anyway, why perform a second one?
Is it possible to figure out if a row with column user equal to :logged_user_id exists on table comments_ratings cr before executing the aggregate function(s)?
P.S.: If someone could come up with a better title, people can find in future, I'd also appreciate that.
You can do what you want with conditional aggregation:
SELECT c.id, c.text, c.datetime, c.author, u.email AS author_name,
SUM(cr.vote) AS rating,
MAX(cr.user = :logged_user_id) as voted
FROM comments c LEFT JOIN
users u
ON u.id = c.author LEFT JOIN
comments_ratings cr
ON c.id = cr.comment
GROUP BY c.id
ORDER BY c.id DESC;