Is it possible to group results and then filter by how many rows are in the group?
Something like this:
SELECT * FROM mytable WHERE COUNT(*) > 1 GROUP BY name
You want to use HAVING to filter on the aggregate function.
SELECT name, COUNT(*)
FROM mytable
GROUP BY name
HAVING COUNT(*) > 1
You need to use HAVING
SELECT * FROM mytable GROUP BY name HAVING COUNT(*) > 1
Although, SELECT * doesn't make much sense when you're grouping. I assume it's just for an example
You want a HAVING clause.
SELECT *
FROM mytable
GROUP BY name
HAVING COUNT(*) > 1
Use having in your query:
SELECT * FROM mytable GROUP BY name having COUNT(*) > 1
Related
Is it possible to group results and then filter by how many rows are in the group?
Something like this:
SELECT * FROM mytable WHERE COUNT(*) > 1 GROUP BY name
You want to use HAVING to filter on the aggregate function.
SELECT name, COUNT(*)
FROM mytable
GROUP BY name
HAVING COUNT(*) > 1
You need to use HAVING
SELECT * FROM mytable GROUP BY name HAVING COUNT(*) > 1
Although, SELECT * doesn't make much sense when you're grouping. I assume it's just for an example
You want a HAVING clause.
SELECT *
FROM mytable
GROUP BY name
HAVING COUNT(*) > 1
Use having in your query:
SELECT * FROM mytable GROUP BY name having COUNT(*) > 1
i have a sample data like this:
Now i want to get lastest data used to have user_id = 41 and highest price, output like this:
How can i do it with SQL command line ?
Thank for read
Try this query
select User_id,auction_id,price from tablename where price in(select price from tablename where id in(select max(id) from tablename group by user_id))
As per your output that you wish try this:
select user_id,auction_id,price
from table_name
where user_id=41
order by id desc;
If you have updated output incorrectly then try it as per your provided conditions-
select user_id,auction_id,price
from mytable
where user_id=41
order by auction_id;
But if as per your output you want 1 latest row of user_id=41 and then all rows of highest price then you can try it-
SELECT user_id,auction_id,price
FROM mytable
WHERE user_id=41
ORDER BY id DESC LIMIT 1
UNION
SELECT b.user_id,b.auction_id,price
FROM mytable b
JOIN (
SELECT MAX(price) AS price
FROM mytable
) a ON a.price=b.price;
m new in mysql
here is my table
now i want to count "count_id" where count of 'questionID' greater than 2
Try this :
SELECT COUNT(count_id) FROM myTable WHERE questionID > 2
select count(Count_ID),QuestionID,SurveyId from table
where QuestionID>2
group by QuestionID,SurveyID
select count(count_id) from yourtable where questionID > 2
If you want to count unique ID:
select count(DISTINCT count_id) from table_name where questionID > 2
SELECT COUNT(count_id) FROM table_name WHERE questionID > 2
Group by Count_ID and count their distinct questions. Stay with those that have more than two. Then count how many IDs you got.
select count(*)
from
(
select count_id
from mytable
group by count_id
having count(distinct questionid) > 2
) x;
EDIT: If count_id + questionid happen to be unique for the table, you can replace count(distinct questionid) with count(*).
You can also try the statement below:
select count(count_id) CountOfID,count_id from mytable
where questionID > 2 group by count_id;
Hi I want to GROUP BY file_serial but only when file_serial > 1 that mean no duplicate file_serial with value bigger than 1
so it should look like
Any idea how, would be great.
Thanks.
One way would be
select * from table
where file_serial > 1
group by file_title
having count(*) > 1
UNION
select * from table
UPDATE
The above will work only if all the selecting columns with the same value. In this case you may need to change as since file_id is different for the same title.
select * from table
where file_serial > 1
group by file_title
having count(*) > 0
UNION
select * from table
file_serial <= 1
DEMO
Try below query, where no need of extra having clause-
SELECT
file_id,file_title,file_serial
FROM mytable
WHERE file_serial<=1
UNION ALL
SELECT
file_id,file_title,file_serial
FROM mytable
WHERE file_serial>1
GROUP BY file_serial;
is it possible in an SQL query to add UNION after order by 1
SELECT * FROM table1 WHERE etc='1' ORDER BY 11;
can we add a union select query beside 11 to be like this ?
SELECT * FROM table1 WHERE etc='1' ORDER BY 11 UNION select etc etc etc ...;
In MySQL, you can enclose the order by clause within a subquery and union the results of multiple subqueries; something like this:
SELECT * FROM (SELECT * FROM table1 WHERE etc='1' ORDER BY 11) sq1
UNION ALL
SELECT * FROM (SELECT * FROM table2 WHERE etc='2' ORDER BY 12) sq2
...
Maybe something like this:
SELECT
*,
11 AS orderby
FROM
table1
WHERE
etc='1'
UNION
select
*,
10 AS orderby
FROM
table2
ORDER BY
orderby
You can use like this:
SELECT * FROM table1 WHERE etc='1'
union
SELECT * FROM table1 WHERE etc='1'
ORDER BY any_column
You can only use ORDER BY at the end of the query after the last union. Basically all SELECTs are done first, then the entire result set is ordered.