This particular query is supposed to enter the user into the database.
This query does not always insert the values of the firstname and the lastname fields along with others. firstname and lastname are empty for a few insertions and for the others its working as expected.
INSERT INTO `users` (mobile, passwordHash, firstname, lastname, ent_id, email )
VALUES ('913800341127', '678a1491514b7f1006d605e9161946b1', 'nat', 'sam', '108', NULL)
ON DUPLICATE KEY UPDATE `firstname` = VALUES(firstname),`lastname` = VALUES(lastname)
Related Info:
CREATE TABLE `users` (
`id` int(11) NOT NULL auto_increment,
`tag` varchar(5) NOT NULL default 'ind',
`username` varchar(50) default NULL,
`firstname` varchar(100) default NULL,
`lastname` varchar(100) default NULL,
`passwordhash` varchar(255) NOT NULL,
`secretq` varchar(255) default NULL,
`secreta` varchar(100) default NULL,
`email` varchar(50) default NULL,
`mobile` varchar(13) default NULL,
`last_login` datetime default NULL,
`ent_id` bigint(20) NOT NULL default '1',
`is_inactive` tinyint(1) NOT NULL COMMENT 'Whether the user is active or not',
PRIMARY KEY (`id`),
UNIQUE KEY `mobile_2` (`mobile`,`ent_id`),
UNIQUE KEY `email_2` (`email`,`ent_id`),
KEY `username` (`username`),
KEY `ent_id` (`ent_id`,`tag`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1
syntax error it should be :
ON DUPLICATE KEY UPDATE firstname = 'nat',lastname = 'sam'
Related
I have 2 tables 'open_invoices' and 'paid_invoices' with the below structures:
CREATE TABLE `open_invoices` (
`id` int(11) UNSIGNED NOT NULL AUTO_INCREMENT,
`unique_identifier` varchar(255) NOT NULL,
`insert_date` datetime NOT NULL DEFAULT CURRENT_TIMESTAMP,
`cust_nbr` int(11) NOT NULL,
`location` varchar(10) NOT NULL,
`company` varchar(10) NOT NULL,
`invoice_nbr` int(11) NOT NULL,
`future_letter` varchar(1) NOT NULL,
`invoice_total` decimal(8,2) NOT NULL,
`invoice_payments` decimal(8,2) NOT NULL,
`record_type` int(11) NOT NULL,
`terms_desc` varchar(255) NOT NULL,
`due_date` varchar(8) NOT NULL,
`discount_date` varchar(8) NOT NULL,
`orig_disc_avail` decimal(8,2) NOT NULL,
`cust_po` varchar(10) NOT NULL,
`invoice_date` varchar(8) NOT NULL,
`status` int(11) NOT NULL,
`check_no` varchar(10) NOT NULL,
`last_pay_date` varchar(8) NOT NULL,
`as_of_date` varchar(8) NOT NULL,
`as_of_time` varchar(11) NOT NULL,
`remaining` varchar(1) NOT NULL,
PRIMARY KEY (`id`),
UNIQUE KEY `unique_identifier` (`unique_identifier`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8;
CREATE TABLE `paid_invoices` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`date_change` datetime NOT NULL DEFAULT CURRENT_TIMESTAMP,
`invoice_date` varchar(8) NOT NULL,
`unique_identifier` varchar(255) NOT NULL,
`amount_paid` decimal(8,2) NOT NULL,
`amount_left` decimal(8,2) NOT NULL,
`payment_type` varchar(2) NOT NULL,
`last4` varchar(255) NOT NULL,
`transac_id` varchar(255) NOT NULL,
`customer_id` varchar(255) NOT NULL,
`payment_P_F` varchar(1) NOT NULL,
PRIMARY KEY (`id`),
FOREIGN KEY (unique_identifier)
REFERENCES open_invoices (unique_identifier)
ON DELETE CASCADE
ON UPDATE CASCADE
) ENGINE=InnoDB DEFAULT CHARSET=utf8;
I'm trying to insert a row in 'paid_invoices' like below:
INSERT INTO `paid_invoices` (`invoice_date`, `unique_identifier`, `amount_paid`, `amount_left`, `payment_type`, `last4`, `transac_id`, `customer_id`, `payment_P_F`) VALUES ('07/19/18', '126_89948_2576', 0, '37.45', '', '', '', '13776', 'P')
I get the below error:
Error Number: 1452
Cannot add or update a child row: a foreign key constraint fails (`accounts_receivables`.`paid_invoices`, CONSTRAINT `paid_invoices_ibfk_1` FOREIGN KEY (`unique_identifier`) REFERENCES `open_invoices` (`unique_identifier`))
INSERT INTO `paid_invoices` (`invoice_date`, `unique_identifier`, `amount_paid`, `amount_left`, `payment_type`, `last4`, `transac_id`, `customer_id`, `payment_P_F`) VALUES ('07/19/18', '126_89948_2576', 0, '37.45', '', '', '', '13776', 'P')
If I search on google, it says that the foreign key 126_89948_2576 was not found in the table 'open_invoices'.
When I do SELECT * FROM open_invoices WHERE id = 2576 I see the row with the foreign key 126_89948_2576 as shown in the picture below :
[![query 1][1]][1]
but when I do this query SELECT * FROM open_invoices WHERE unique_identifier = '126_89948_2576' I get no result see capture below:
[![query 2][2]][2]
I'm sure there is no extra blank space in the value saved for foreign key 126_89948_2576.
What is going on please? Is there a bug in the version of MySQL I'm using?
Server: Localhost via UNIX socket
Server type: MySQL
Server version: 5.6.40 - MySQL Community Server (GPL)
Protocol version: 10
Thanks.
[1]: https://i.stack.imgur.com/L2QDX.png
[2]: https://i.stack.imgur.com/T9Fz5.png
It seems you are using wrong divider symbols, "_" instead of "-" in your query. Try unique_identifier = '126-89948-2576'
Because the underscore _ is a wildcard like the percent %, except that it only looks for one character.
SQL pattern matching enables you to use "_" to match any single character and "%" to match an arbitrary number of characters (including zero characters).
you can use
SELECT * FROM open_invoices WHERE unique_identifier like '%126\_89948\_2576%'
Good day,
I have an issue using the phpmyadmin for my database, I'm in new in this and this is the mysql structure from previewmysql:
CREATE TABLE `mydb`.`attendant`
(
`id` INT NOT NULL auto_increment,
`first_name` VARCHAR(20) NOT NULL,
`names` VARCHAR(50) NOT NULL,
`gender` ENUM(0) NOT NULL,
`email` VARCHAR(20) NOT NULL,
`phone` INT(15) NULL,
`marital_status` ENUM(0) NOT NULL,
`added_date` DATETIME NOT NULL DEFAULT CURRENT_TIMESTAMP,
`membership` ENUM(0) NOT NULL,
`address` VARCHAR(20) NOT NULL,
`suburb` ENUM(0) NOT NULL,
`partner_name` VARCHAR(25) NULL,
PRIMARY KEY (`id`),
UNIQUE `email_address` (`email`)
)
engine = innodb;
The error is:
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '0) NOT NULL , `email` VARCHAR(20) NOT NULL , `phone` INT(15) NULL , `marital_sta' at line 1
And also attached is my phpmyadmin table structure.
Will appreciate any help.
Try it.Hope errors goes boom.I just fixed your errors. But your table structure is not good enough. give time, then day by day you will also be expert on it.
CREATE TABLE `mydb`.`attendant`
(
`id` INT NOT NULL auto_increment,
`first_name` VARCHAR(20) NOT NULL,
`names` VARCHAR(50) NOT NULL,
`gender` ENUM('0','1') NOT NULL,
`email` VARCHAR(20) NOT NULL,
`phone` INT(15),
`marital_status` ENUM('0','1') NOT NULL,
`added_date` DATETIME NOT NULL DEFAULT CURRENT_TIMESTAMP,
`membership` ENUM('0','1') NOT NULL,
`address` VARCHAR(20) NOT NULL,
`suburb` ENUM('0','1') NOT NULL,
`partner_name` VARCHAR(25) NULL,
PRIMARY KEY (`id`),
UNIQUE `email_address` (`email`)
)
engine = innodb;
Modify ENUM declaration as ENUM ('male', 'female') for gender column and others also as shown in your table. It will not accept ENUM(0).
ENUM(0) is wrong format , if you want that for gender roles then you can use :-
ENUM('Male', 'Female') i.e you can run this query :-
CREATE TABLE `mydb`.`attendant`
(
`id` INT NOT NULL auto_increment,
`first_name` VARCHAR(20) NOT NULL,
`names` VARCHAR(50) NOT NULL,
`gender` ENUM('Male', 'Female') NOT NULL,
`email` VARCHAR(20) NOT NULL,
`phone` INT(15) NULL,
`marital_status` ENUM('Single','Married','divorced') NOT NULL,
`added_date` DATETIME NOT NULL DEFAULT CURRENT_TIMESTAMP,
`membership` ENUM('no','yes') NOT NULL,
`address` VARCHAR(20) NOT NULL,
`suburb` ENUM('Cape Town','Woodstock') NOT NULL,
`partner_name` VARCHAR(25) NULL,
PRIMARY KEY (`id`),
UNIQUE `email_address` (`email`)
)
engine = innodb;
You have used ENUM data type in your table. And provided 0 as argument but
An enumeration value must be a quoted string literal
You can refer the mySql documentation for more information
http://dev.mysql.com/doc/refman/5.7/en/enum.html
I stumbled upon weird behavior in MySQL.
Lets say that I have only one record in table
| id | oib |
|----|-----|
| 1 | 5 |
Field oib is unique.
INSERT INTO `test` (`id`, `oib`) VALUES (NULL, '6')
I get following exception
Duplicate entry '5' for key 'oib_UNIQUE'
And this keeps going on no matter what value I try to save.
Anyone have idea what could cause this. I've never seen it.
UPDATE:
Here is CREATE TABLE statement:
CREATE TABLE IF NOT EXISTS `user` (
`id` int(25) NOT NULL AUTO_INCREMENT,
`email` varchar(45) DEFAULT NULL,
`password` varchar(255) DEFAULT NULL,
`first_name` varchar(45) DEFAULT NULL,
`last_name` varchar(45) DEFAULT NULL,
`dob` int(25) DEFAULT NULL,
`address` varchar(255) DEFAULT NULL,
`zip` int(6) DEFAULT NULL,
`oib` int(11) DEFAULT NULL,
`position` tinyint(4) DEFAULT NULL,
`role` varchar(45) DEFAULT NULL,
`status` tinyint(4) DEFAULT NULL,
`note` mediumtext,
PRIMARY KEY (`id`),
UNIQUE KEY `email_UNIQUE` (`email`),
UNIQUE KEY `oib_UNIQUE` (`oib`)
)
You cannot insert null value in id primary key
Are you sure your table have one record for oib = '5' ?
You cannot insert null into primary key.
I have an Users Table with a staff column and a remove column.
I don't want to show Users that have the remove column with the value of 1
SELECT *
FROM Users
WHERE
Users.staff = 1
AND Users.remove != 1
I don't get an error but my code doesn't work.
this is the schema
CREATE TABLE `Users` (
`userId` int(11) unsigned NOT NULL AUTO_INCREMENT,
`fullName` varchar(50) DEFAULT NULL,
`firstName` varchar(25) NOT NULL DEFAULT '',
`lastName` varchar(25) NOT NULL DEFAULT '',
`address` varchar(50) NOT NULL DEFAULT '',
`city` varchar(25) DEFAULT NULL,
`state` char(2) DEFAULT NULL,
`zipCode` varchar(25) DEFAULT NULL,
`email` varchar(50) NOT NULL DEFAULT '',
`cellPhone` varchar(15) DEFAULT NULL,
`birthDate` date NOT NULL,
`creditCard` varchar(250) NOT NULL DEFAULT '',
`subscriptionStarted` date NOT NULL,
`subscriptionEnded` date NOT NULL,
`basicPlan` tinyint(1) DEFAULT NULL,
`standardPlan` tinyint(1) DEFAULT NULL,
`premiumPlan` tinyint(1) DEFAULT NULL,
`remove` tinyint(1) DEFAULT NULL,
`staff` tinyint(1) DEFAULT NULL,
`admin` tinyint(1) DEFAULT NULL,
`systemAdmin` tinyint(1) DEFAULT NULL,
`edited` datetime DEFAULT NULL,
`created` datetime NOT NULL,
PRIMARY KEY (`userId`)
) ENGINE=InnoDB AUTO_INCREMENT=20 DEFAULT CHARSET=latin1;
both work for me Boss.
create table users
( staff int not null,
remove int not null
);
insert users (staff,remove) values (1,0);
insert users (staff,remove) values (1,1);
insert users (staff,remove) values (2,0);
insert users (staff,remove) values (2,1);
SELECT *
FROM Users
WHERE
Users.staff = 1
AND Users.remove != 1
SELECT *
FROM Users
WHERE
Users.staff = 1
AND Users.remove <> 1
Edit due to nullability:
SELECT * FROM Users
WHERE staff=1
and remove <> 1 or remove is null
SELECT * FROM Users
WHERE staff=1
and remove is not null
I have this MySQL query that I want to optimize:
SELECT r.WarehouseLocation,sum(sir.qty)
FROM repairableissue as r
INNER JOIN SIR ON r.sirno=sir.sirno
AND r.region=sir.region
AND r.ItemName=sir.Itemdesc
AND r.SerialNo=sir.Serialno
WHERE r.status='Pending'
GROUP BY r.warehouseLocation
How do I optimize this query? I read about optimization and found out that indexes might help but still could not achieve the desired performance.
Which index should be used and which should be removed?
Below is the explain of query:
Repairableissue
CREATE TABLE `repairableissue` (
`Vendor` varchar(40) NOT NULL,
`ItemName` varchar(200) NOT NULL,
`SerialNo` varchar(50) NOT NULL,
`person` varchar(200) NOT NULL,
`siteid` varchar(10) NOT NULL,
`invuser` varchar(50) NOT NULL,
`region` varchar(50) NOT NULL,
`id` int(11) NOT NULL AUTO_INCREMENT,
`Dated` date NOT NULL,
`Sirno` varchar(50) NOT NULL,
`status` varchar(30) NOT NULL DEFAULT 'Pending',
`trackthrough` varchar(30) NOT NULL,
`reason` varchar(100) NOT NULL,
`ckh` timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP ON UPDATE CURRENT_TIMESTAMP,
`WarehouseType` varchar(20) NOT NULL,
`WarehouseLocation` varchar(20) NOT NULL,
PRIMARY KEY (`id`),
UNIQUE KEY `id` (`id`),
KEY `I1` (`status`),
KEY `ind2` (`ItemName`),
KEY `ind3` (`region`),
KEY `ind5` (`SerialNo`),
KEY `ind4` (`Sirno`)
) ENGINE=MyISAM AUTO_INCREMENT=63029 DEFAULT CHARSET=latin1
sir
CREATE TABLE `sir` (
`SirNo` varchar(50) NOT NULL,
`SiteId` varchar(80) NOT NULL,
`Vendor` varchar(70) NOT NULL,
`Type` varchar(15) NOT NULL,
`ItemDesc` varchar(200) NOT NULL,
`ItemCode` varchar(25) NOT NULL,
`SerialNo` varchar(50) NOT NULL,
`Unit` varchar(15) NOT NULL,
`AssetCode` varchar(50) NOT NULL,
`Qty` decimal(11,0) NOT NULL,
`Region` varchar(15) NOT NULL,
`Status` varchar(20) NOT NULL DEFAULT 'Installed',
`FaultInfo` varchar(100) NOT NULL DEFAULT 'date()',
`chk` timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP ON UPDATE CURRENT_TIMESTAMP,
`Phase` varchar(15) NOT NULL,
`Category` varchar(200) NOT NULL,
`Issue_Vendor` varchar(30) NOT NULL,
`AssetName` varchar(150) NOT NULL,
`Ownership` varchar(20) NOT NULL,
`Dated` date NOT NULL,
`PersonName` varchar(150) NOT NULL,
`Remarks` varchar(300) NOT NULL,
`po` varchar(100) NOT NULL,
`invuser` varchar(50) NOT NULL,
`id` int(11) NOT NULL AUTO_INCREMENT,
`grnno` varchar(30) NOT NULL,
`WarehouseType` varchar(20) NOT NULL,
`WarehouseLocation` varchar(20) NOT NULL,
`mainpartserial` varchar(200) NOT NULL,
PRIMARY KEY (`Vendor`,`Type`,`ItemCode`,`ItemDesc`,`SerialNo`,`Ownership`,`SirNo`,`Region`,`WarehouseType`,`WarehouseLocation`,`po`,`Qty`,`id`),
KEY `id` (`id`),
KEY `ind4` (`ItemDesc`),
KEY `ind6` (`SerialNo`),
KEY `ind7` (`SerialNo`)
) ENGINE=MyISAM AUTO_INCREMENT=228007 DEFAULT CHARSET=latin1
One multi-column index on r.status + r.warehouseLocation, in that order.
One multi-column index on sir.sirno + sir.region + sir.Itemdesc + sir.Serialno, in order of most cardinality to least cardinality, with sir.qty tacked on the end.
This assumes the fields are small enough to fit (combined) into an index.
Still, join seeks are unavoidable. The number of records that match r.status='Pending' is going to dictate the speed of this query.