I have a table with itemid|fieldid|value and i'm trying to setup a query that will combine some data and return a mathc percentage along with the result. for example, some data could be
itemid fieldid value
19 193 1
45 193 1
37 201 6
25 201 1
45 201 6
19 201 6
19 201 5
Now i want for example, to get all the rows with fieldid = 193 AND value = 1 as well as the rows with fieldid = 201 AND value = 6. The ideal result would be something like :
itemid, percentage getting 100% for all itemids which match both conditions and 50% for all that match one. I have this query working for doing the above over multiple columns but it will not work here
select id,user_class,admin, (
if (admin = 1,1,0)+
if (user_class = 'SA',1,0)
)/2*100 as the_percent
from users
WHERE
admin = 1 OR user_class = 'P'
GROUP BY id
order by the_percent DESC
Also i got the following for absolute matching
SELECT users.id FROM users WHERE
users.id IN
(
SELECT DISTINCT itemid FROM extra_field_values
INNER JOIN (SELECT DISTINCT itemid FROM extra_field_values WHERE fieldid = 201 AND value = 6 ) a1 USING (itemid)
INNER JOIN (SELECT DISTINCT itemid FROM extra_field_values WHERE fieldid = 193 AND value = 1 ) a2 USING (itemid)
)
but combining the two seems to be a bit of a puzzle to me
I think you might be able to make use of a UNION and selecting from a table subquery to make this happen. Perhaps something along the lines of:
SELECT itemid, count(*)/2*100 AS percent FROM
( SELECT itemid FROM extra_field_values WHERE fieldid = 201 AND value = 6
UNION ALL
SELECT itemid FROM extra_field_values WHERE fieldid = 193 AND value = 1 ) AS t
GROUP BY itemid;
It's been a while since I've done anything complex in mysql, and I threw this together in notepad so my syntax could be off :) But basically we create a view of the matching ids, then from that table create our statistics. (You'll also want to do some performance evaluation as well to see how it stacks up compared to doing multiple queries as well).
Related
I have a query which combines a user's balance at a number of locations and uses a nested subquery to combine data from the customer_balance table and the merchant_groups table. There is a second piece of data required from the customer_balance table that is unique to each merchant.
I'd like to optimise my query to return a sum and a unique value i.e. the order of results is important.
For instance, there may be three merchants in a merchant_group:
id | group_id | group_member_id
1 12 36
2 12 70
3 12 106
The user may have a balance at 2 locations but not all in the customer_balance table:
id | group_member_id | user_id | balance | personal_note
1 36 420 1.00 "Likes chocolate"
2 70 420 20.00 null
Notice there isn't a 3rd row in the balance table.
What I'd like to end up with is the ability to pull the sum of the balance as well as the most appropriate personal_note.
So far I have this working in all situations with the following query:
SELECT sum(c.cash_balance) as cash_balance,n.customer_note FROM customer_balance AS c
LEFT JOIN (SELECT customer_note, user_id FROM customer_balance
WHERE user_id = 420 AND group_member_id = 36) AS n on c.user_id = n.user_id
WHERE c.user_id = 420 AND c.group_id IN (SELECT group_member_id FROM merchant_group WHERE group_id = 12)
I can change out the group_member_id appropriately and I will always get the combined balance as expected and the appropriate note. i.e. what I'm looking for is:
balance: 21.00
customer_note: "Likes Chocolate" OR null (depending on the group_member_id)
Is it possible to optimise this query without using resource heavy nested queries e.g. using a JOIN? (or some other method).
I have tried a number of options, but cannot get it working in all situations. The following is the closest I have gotten, except this doesn't return the correct note:
SELECT sum(cb.balance), cb.personal_note FROM customer_balance AS cb
LEFT JOIN merchant_group AS mg on mg.group_member_id = cb.group_member_id
WHERE cb.user_id = 420 && mg.group_id = 12
ORDER BY (mg.group_member_id = 106)
I also tried another option (but since lost the query) that works, but not when the group_member_id = 106 - because there was no record in one table (but this is a valid use case that I'd like to cater for).
Thanks!
This should be equivalent but without subselect
SELECT
sum(c.cash_balance) as cash_balance
, n.customer_note
FROM customer_balance AS c
LEFT JOIN customer_balance as n on ( c.user_id = n.user_id AND n.group_member_id = 36 AND n.user_id = 420 )
INNER JOIN merchant_group as mg on ( c.group_id = mg.group_member_id AND mg.group_id = 12)
WHERE c.user_id = 420
I am trying to apply a conditional condition inside ON clause of a LEFT JOIN. What I am trying to achieve is somewhat like this:
Pseudo Code
SELECT * FROM item AS i
LEFT JOIN sales AS s ON i.sku = s.item_no
AND (some condition)
AND (
IF (s.type = 0 AND s.code = 'me')
ELSEIF (s.type = 1 AND s.code = 'my-group')
ELSEIF (s.type = 2)
)
I want the query to return the row, if it matches any one of the conditions (Edit: and if it matches one, should omit the rest for the same item).
Sample Data
Sales
item_no | type | code | price
1 0 me 10
1 1 my-group 12
1 2 14
2 1 my-group 20
2 2 22
3 2 30
4 0 not-me 40
I want the query to return
item_no | type | code | price
1 0 me 10
2 1 my-group 20
3 2 30
Edit: The sales is table is used to apply special prices for individual users, user groups, and/or all users.
if type = 0, code contains username. (for a single user)
if type = 1, code contains user-group. (for users in a group)
if type = 2, code contains empty-string (for all users).
Use the following SQL (assumed, the the table sales has a unique id field as usual in yii):
SELECT * FROM item AS i
LEFT JOIN sales AS s ON i.sku = s.item_no
AND id = (
SELECT id FROM sales
WHERE item_no = i.sku
AND (type = 0 AND code = 'me' OR
type = 1 AND code = 'my-group' OR
type = 2)
ORDER BY type
LIMIT 1
)
Try following -
SELECT *,SUBSTRING_INDEX(GROUP_CONCAT(s.type ORDER BY s.type),','1) AS `type`, SUBSTRING_INDEX(GROUP_CONCAT(s.code ORDER BY s.type),','1) AS `code`,SUBSTRING_INDEX(GROUP_CONCAT(s.price ORDER BY s.type),','1) AS `price`
FROM item AS i
LEFT JOIN sales AS s
ON i.sku = s.item_no AND (SOME CONDITION)
GROUP BY i.sku
I have a table like this:
userid | trackid | path
123 70000 ad
123 NULL abc.com
123 NULL Apply
345 70001 Apply
345 70001 Apply
345 NULL Direct
345 NULL abc.com
345 NULL cdf.com
And I want a query like this. When path='abc.com', num_website +1; when path='Apply', num_apply +1
userid | num_website | num_Apply | num_website/num_Apply
123 1 1 1
345 1 2 0.5
My syntax looks like this:
select * from
(select userid,count(path) as is_CWS
from TABLE
where path='abc.com'
group by userid
having count(path)>1) a1
JOIN
(select userid,count(userid) as Apply_num from
where trackid is not NULL
group by userid) a2
on a1.userid=a2.userid
My question is
1. how to have the field num_website/num_apply in term of my syntax above?
2. is there any other easier way to get the result I want?
Any spots shared will appreciate.
The simplest way to do it would be to change the select line:
SELECT a1.userid, a1.is_CWS, a2.Apply_num, a1.is_CWS/a2.Apply_num FROM
(select userid,count(path) as is_CWS
from TABLE
where path='abc.com'
group by userid
having count(path)>1) a1
JOIN
(select userid,count(userid) as Apply_num
from TABLE
where trackid is not NULL
group by userid) a2
on a1.userid=a2.userid
and then continue with the rest of your query as you have it. The star means "select everything." If you wanted to select only a few things, you would just list those things in place of the star, and if you wanted to select some other values based on those things, you would put those in the stars as well. In this case a1.is_CWS/a2.Apply_num is an expression, and MySql knows how to evaluate it based on the values of a1.is_CWS and a2.Apply_num.
In the same vein, you can do a lot of what those subqueries are doing in a single expression instead of a subquery. objectNotFound has the right idea. Instead of doing a subquery to retrieve the number of rows with a certain attribute, you can select SUM(path="abc.com") as Apply_num and you don't have to join anymore. Making that change gives us:
SELECT a1.userid,
SUM(path="abc.com") as is_CWS,
a2.Apply_num,
is_CWS/a2.Apply_num FROM
TABLE
JOIN
(select userid,count(userid) as Apply_num
FROM TABLE
where trackid is not NULL
group by userid) a2
on a1.userid=a2.userid
GROUP BY userid
Notice I moved the GROUP BY to the end of the query. Also notice instead of referencing a1.is_CWS I now reference just is_CWS (it's no longer inside the a1 subtable so we can just reference it)
You can do the same thing to the other subquery then they can share the GROUP BY clause and you won't need the join anymore.
to get you started ... you can build on top of this :
select
userid,
SUM(CASE WHEN path='abc.com'then 1 else 0 end ) as num_website,
SUM(CASE WHEN path='Apply' and trackid is not NULL then 1 else 0 end ) as Apply_Num
from TABLE
WHERE path='abc.com' or path='Apply' -- may not need this ... play with it
group by userid
I have an assigns table with the following columns:
id - int
id_lead - int
id_source - int
date_assigned - int (this represents a unix timestamp)
Now, lets say I have the following data in this table:
id id_lead id_source date_assigned
1 20 5 1462544612
2 20 6 1462544624
3 22 6 1462544615
4 22 5 1462544626
5 22 7 1462544632
6 25 6 1462544614
7 25 8 1462544621
Now, lets say I want to get a count of the rows whose id_source is 6, and is the first entry for each lead (sorted by date_assigned asc).
So in this case, the count would = 2, because there are 2 leads (id_lead 22 and 25) whose first id_source is 6.
How would I write this query so that it is fast and would work fine as a subquery select? I was thinking something like this which doesn't work:
select count(*) from `assigns` where `id_source`=6 order by `date_assigned` asc limit 1
I have no idea how to write this query in an optimal way. Any help would be appreciated.
Pseudocode:
select rows
with a.id_source = 6
but only if
there do not exist any row
with same id_lead
and smaller date_assigned
Translate it to SQL
select * -- select rows
from assigns a
where a.id_source = 6 -- with a.id_source = 6
and not exists ( -- but only if there do not exist any row
select 1
from assigns a1
where a1.id_lead = a.id_lead -- with same id_lead
and a1.date_assigned < a.date_assigned -- and smaller date_assigned
)
Now replace select * with select count(*) and you'll get your result.
http://sqlfiddle.com/#!9/3dc0f5/7
Update:
The NOT-EXIST query can be rewritten to an excluding LEFT JOIN query:
select count(*)
from assigns a
left join assigns a1
on a1.id_lead = a.id_lead
and a1.date_assigned < a.date_assigned
where a.id_source = 6
and a1.id_lead is null
If you want to get the count for all values of id_source, the folowing query might be the fastest:
select a.id_source, count(1)
from (
select a1.id_lead, min(a1.date_assigned) date_assigned
from assigns a1
group by a1.id_lead
) a1
join assigns a
on a.id_lead = a1.id_lead
and a.date_assigned = a1.date_assigned
group by a.id_source
You still can replace group by a.id_source with where a.id_source = 6.
The queries need indexes on assigns(id_source) and assigns(id_lead, date_assigned).
Simple query for that would be
check here http://sqlfiddle.com/#!9/8666e0/7
select count(*) from
(select * from assigns group by id_lead )t
where t.id_source=6
I currently have the following SQL query wich retrieves a record from a table and also it's parents and grandparent. The only issue I have is that it's returned as a single record. I would like it return as multiple rows, as it's stored in the database.
Current structure:
comment_id | parent_comment_id
1 3
2 7
3 5
7 11
SQL:
SELECT p3.comment_id as `Grandparent`, p2.comment_id as `Parent`, p1.comment_id as `Child`
FROM comments p1
LEFT JOIN comments p2 on p1.comment_id = p2.parent_comment_id
LEFT JOIN comments p3 on p2.parent_comment_id = p3.comment_id
WHERE p1.comment_id = 1
Current Output (single row):
Grandparent | Parent | Child
5 3 1
Desired Output (separate rows):
comment_id
5
3
1
I am editing some existing mysql code, I do not have the option to convert everything to mysqli or pdo at the moment.
try this:
select comment_id from cm where comment_id = 1
union
select parent_comment_id from cm where comment_id =1
union
select g.parent_comment_id from cm g
join cm p
on p.parent_comment_id = g.comment_id
where p.comment_id = 1;
please verify the logic and make sure it gives you the correct result.
Demo: SQLFiddle