Bash user input Mysql login - mysql

Question

Will start with what I am trying to accomplish. I wrote up a menu script to add a new database and echo back to screen the results. But can't seem to get it to login with a variable.
Heres the part I am having problems with:
#!/bin/bash
while [[ "$yn" != "Yes" && "$yn" != "Y" && "$yn" != "y" && "$yn" != "yes" ]]; do
echo " Please, type password for root user. #"
read -r mysqlrp
echo " You have entered $mysqlrp as your MySQL password #"
echo " Is this correct? (Yes or No) #"
read yn
done
mysql -u root -p$mysqlrp
have also tried:
mysql -u root -p${mysqlrp}
as well as mysql -u root -p'${mysqlrp}'
I get the following:
ERROR 1045 (28000): Access denied for user 'root'#'localhost' (using password: YES)
even though when I try without the script works fine.
Please help,
Thanks in advance,
Joe

Answer 1

To supply a password directly in the command line string, you should use mysql --password=[password]. See this article.
And to prompt the user for a password, you should probably use something like this.
#!/bin/bash
read -p "Username: " uname
stty -echo
read -p "Password: " passw; echo
stty echo
You must not ever print the password. And it should not be seen while typing it in either.
#!/bin/bash
read -p "Username: " uname
stty -echo
read -p "Password: " passw; echo
stty echo
mysql --user=$uname --password=$passw
That script works for me. If it doesn't for you, please check that your mysql permissions allow you to login from localhost.

Answer 2

In a shellscript, you can do
set -x
to see what the command being executed looks like.
You should prolly do mysql --password="$mysqlrp". '$mysqlrp' -> '$mysqlrp'.
In your real script, I suppose you probably want to do
read -p "Password, plz:" -s mysqlrp
In order to properly answer the question, the actual error you get would be helpful. [UPDATE: answered in comment.]
Also, note that if your query is longrunning, your password will be visible in "ps -ef"