hopefully this is an easy one.
I have a query that I want to produce results for todays date only based on a column (record_date) that uses CURRENT_TIMESTAMP.
so my query goes...
Select columns FROM fields WHERE table.record_date = DATE_SUB(NOW());
This is throwing up an error... :(
Thanks for you help....So i tried....
SELECT * FROM daily_record WHERE record_date = CURDATE()
but it yielded no result.
Here is a sample of the data in the column i am searching...
2011-03-31 11:28:37,
2011-03-31 11:28:37,
2011-03-31 11:28:37,
.....
Does it matter that the time is also saved?
Is that what you want ?
Select columns FROM fields WHERE table.record_date > CURDATE();
DATE_SUB() is for subtracting an interval from a date in MySQL. You've got DATE_SUB(now()), but don't specify an interval
It should be something like
... DATE_SUB(now(), INTERVAL 5 DAY);
so MySQL's complaining about the unexpected ), because of the missing interval.
If you want to convert 'now' into a date, you can simply use CURDATE(), or DATE(now())
Related
I have a table called barcode_log, and these are all the datas from the table.
And now if I run this query
SELECT * FROM `barcode_log` WHERE barcode_log.assign_time BETWEEN DATE_SUB(CURRENT_DATE, INTERVAL 30 DAY) AND CURRENT_DATE;
I get this result
But it should return all the rows as all the data is within this month only. And assign_time field is stored as datetime. Any idea what i am doing wrong??
You are ignoring the time part (hh:mm:ss).
If the end day is set to the end timestamp of the current date then you can get the data of current day's too.
BETWEEN is inclusive
SELECT
*
FROM
`barcode_log`
WHERE
barcode_log.assign_time BETWEEN DATE_SUB(
CURRENT_DATE,
INTERVAL 30 DAY
)
AND TIMESTAMP(CONCAT(CURDATE(),' ','23:59:59'));
While the accepted answer works, there is a simpler solution. Just take the date part of the datetime column:
SELECT
*
FROM
`barcode_log`
WHERE
DATE(barcode_log.assign_time)
BETWEEN DATE_SUB(CURRENT_DATE, INTERVAL 30 DAY) AND CURRENT_DATE;
There is another way around: CAST() on barcode_log.assign_time field.
SELECT *
FROM `barcode_log`
WHERE CAST(barcode_log.assign_time AS DATE)
BETWEEN DATE_SUB(CURRENT_DATE, INTERVAL 30 DAY) AND CURRENT_DATE;
This excludes time from comparison and works fine for your purpose.
The title might be a bit misleading, but what I want is:
SELECT * FROM table ORDER BY pid ASC
And in one of the columns I have a DATE(). I want to compare the current date (not time) and return how many days are left till that date. Let's say the date is 2013-04-20 and today's date is 2013-04-16 I don't want to get any data if it's < current date. If it is I want it returned in days.
I've been looking around here and I've found no way to do it, and I can't for the love of me figure it out.
If you're looking for the difference between two date you can use the GETDATE function in MS SQL
SELECT DATEDIFF(DD, DateOne, DateTwo) FROM TABLE
This will return the difference in number of days between the two dates.
If you only want rows where the date field is less than or equal to today's date you can use:
SELECT DATEDIFF(DD, DateField, GETDATE())
FROM TableName
WHERE DateField <= GETDATE()
If you're using MySQL you can use DATEDIFF()
SELECT
DATEDIFF(NOW(), date_column) AS days_diff
FROM
tablename
Get the difference between two dates (ANSI SQL)
select the_date_column - current_date as days_left
from the_table
where the_date_column - current_date <= 4;
SQLFiddle: http://sqlfiddle.com/#!12/3148d/1
I store a date in my database as a string like this:
03/08/2013 --> 8th of march
I'm trying to select only the rows that are the same day as the current day:
SELECT * FROM wp_aerezona_booking WHERE DATE_SUB(CURDATE(),INTERVAL 1
DAY) <= STR_TO_DATE(date, '%m/%d/%Y')
The above is what I tried, but it is returning a lot of results and should only return 1.
This should work already:
SELECT * FROM wp_aerezona_booking
WHERE STR_TO_DATE('03/08/2013', '%m/%d/%Y') = CURDATE();
By using the DATE_SUB you are subtracting1 day from the current day. You're not looking at today but yesterday. Also the <= makes you look at yesterday and all days before that.
Then you don't want <=, but you want =. The former will get all results if date is less than or equal to yesterday's date. I'm not sure that you even want the DATE_SUB either.
If you want the same date as today's date then you have to use "=" operator with.
SELECT *
FROM wp_aerezona_booking
WHERE STR_TO_DATE(date, '%m/%d/%Y')= CURDATE()
I need help with mysql and date_sub(). I have a table call Activity
Activity(id,deadline,alert)
Activity(1,'2011-04-18','1 DAY');
Activity(2,'2011-04-13','1 MONTH');
Every row in A have an 'alert', this field indicate how time before the deadline an activity have to reported.
For example
On 2011-04-17 I have to report the activity with 'id' 1
On 2011-03-14 I have to report the activity with 'id' 2
I trying to use date_sub() functions, but I can't use a field as params of this function. Any idea how to fix this?
SELECT *
FROM `activities`
WHERE date_sub(`deadline`, INTERVAL alert) >= CURDATE();
Split the alert into 2 fields
Alert_count: integer
Alert_period: enum('hour','day','month','week')
And change the query like so:
SELECT *
FROM `activities`
WHERE CASE alert_period
WHEN 'hour' THEN date_sub(`deadline`, INTERVAL alert_count HOUR) >= CURDATE();
WHEN 'day' THEN date_sub(`deadline`, INTERVAL alert_count DAY) >= CURDATE();
...
END CASE
If the number of alerts is small, you could write out a case:
WHERE case
when alert = '1 DAY' then date_sub(`deadline`, INTERVAL 1 DAY)
when alert = '1 MONTH' then date_sub(`deadline`, INTERVAL 1 MONTH)
... etc ...
end >= CURDATE();
Although this solution will work it's not the most efficient way of storing this data because each time you query for this data MySQL must look at the interval value in every row, compute it against deadline date and then return you the answer.
If you were to compute this information just before you insert the data and store alert_date as a DATE column then (assuming you index it too) it'd be very fast for MySQL to find the rows with a query like:
SELECT id FROM activity WHERE alert=CURRENT_DATE();
even more efficient (it'd allow it to be query cached):
SELECT id FROM activity WHERE alert="2011-04-23";
Strings are not allowed after INTERVAL, you can convert your all alert limit to day on one column.
Activity(id,deadline,alert)
Activity(1,'2011-04-18','1');
Activity(2,'2011-04-13','30');
and use as:
SELECT *
FROM `activities`
WHERE date_sub(`deadline`, INTERVAL alert DAY) >= CURDATE();
How to select data from mysql table past date to current date? For example, Select data from 1 january 2009 until current date ??
My column "datetime" is in datetime date type. Please help, thanks
Edit:
If let say i want to get day per day data from 1 january 2009, how to write the query? Use count and between function?
select * from *table_name* where *datetime_column* between '01/01/2009' and curdate()
or using >= and <= :
select * from *table_name* where *datetime_column* >= '01/01/2009' and *datetime_column* <= curdate()
All the above works, and here is another way if you just want to number of days/time back rather a entering date
select * from *table_name* where *datetime_column* BETWEEN DATE_SUB(NOW(), INTERVAL 30 DAY) AND NOW()
You can use now() like:
Select data from tablename where datetime >= "01-01-2009 00:00:00" and datetime <= now();
Late answer, but the accepted answer didn't work for me.
If you set both start and end dates manually (not using curdate()), make sure to specify the hours, minutes and seconds (2019-12-02 23:59:59) on the end date or you won't get any results from that day, i.e.:
This WILL include records from 2019-12-02:
SELECT *SOMEFIELDS* FROM *YOURTABLE* where *YOURDATEFIELD* between '2019-12-01' and '2019-12-02 23:59:59'
This WON'T include records from 2019-12-02:
SELECT *SOMEFIELDS* FROM *YOURTABLE* where *YOURDATEFIELD* between '2019-12-01' and '2019-12-02'