SELECT id, absolute_tag, tag FROM c7_storage_tags
WHERE users_id = 1
AND LOWER(absolute_tag) LIKE LOWER('##Pictures#zee\'s fav%')
This is not giving me the correct result, even thou i do have a row in my database with the correct string.
The better solution for me would be to figure out a way so that "##Pictures#zee\'s fav" string of mine, could be treated as just a string. And I can perform like on it.
How can I fix it.
Thanks in advance.
Zeeshan
IF you string has a backslash in it, you should escape it twice :
// value absolute_tag == "##Pictures#zee\'s fav"
select * from test where `absolute_tag` like '##Pictures#zee\\\\\'%'
From http://dev.mysql.com/doc/refman/5.0/en/string-comparison-functions.html#operator_like
Your query should look like
SELECT id, absolute_tag, tag FROM c7_storage_tags
WHERE users_id = 1
AND LOWER(absolute_tag) LIKE LOWER('##Pictures#zee\\\\\'s fav%')
Your original query was looking for a record with absoulte_tags begins with "##Pictures#zee's fav"
Related
I am using PHP to access a mysql database field that contains up to 2500 characters per record.
I want to build queries that will return only the records that include a single word, like 'taco'.
Sometimes, however, the user will need to search for a word like 'jalapeno'. Except that jalapeno may exist in the database as 'jalapeno' or as 'jalapeño'. The query should return both instances.
As a further complication, the user may also need to search for a word like 'creme', which may appear as 'creme' or 'créme', but never as 'crémé'.
It seems like I should be able to construct something that uses a replace, and then a Regular Expression, so that the letter 'n' is always replaced with '[n|ñ]', and then search for a string with an embedded Regular Expression like this: 'jalape[n|ñ]o'. Except that does not work. MySQL treats the RegEx syntax as literals.
None of the following return the results that I am looking for:
SELECT id, record FROM table WHERE record like '%jalapeno%';
SELECT id, record FROM table WHERE record REGEXP 'jalapeno';
SELECT id, record FROM table WHERE record REGEXP 'jalape[n|ñ]o';
SELECT id, record FROM table WHERE REGEXP_LIKE(record, 'jalape[n|ñ]o', 'im');
Additionally, I can use PHP to do a replacement of the potential characters, but I end up with stuff like this:
SELECT id, record FROM table WHERE (record like '%creme%' || record like '%crémé%');
I would be Ok with a search like this, but it seems overly complicated to construct programmatically:
SELECT id, record FROM table WHERE (record like '%creme%' || record like '%crémé%' || record like '%cremé%' || record like '%cremé%' );
Is there a MySQL method that provides a REGEX 'OR' to be embedded within a String?
Maybe something like this:
SELECT id, record FROM table WHERE record like '%cr[e|é]m[e|é]%' ;
Or is there another solution that would not require the construction of an excessively convoluted SQL Statement?
Thanks for anyone who spent time trying to figure this out.
As I commented above, REGEXP_LIKE() does not appear to be a valid MySQL function for the current release.
Here is my solution; Note that this works for MySQL 5.7.x.
SELECT id, record FROM table WHERE record RLIKE 'jalape(n|ñ)o';
I have a table where the field "company_name" has weird characters, like "à","ö","¬","©","¬","†", etc. I want to return all "company_name"s that contain these characters anywhere within the string. My current query looks like this:
SELECT * FROM table WHERE
MATCH (company_name) AGAINST ('"Ä","à","ö","¬","©","¬","†"' in natural language mode);
But I keep getting no data from the query. I know this can't be the case, as there are definitely examples of them I can find manually. To be clear, the query itself isn't throwing any errors, just not returning any data.
The minimun word length is 3 pr 4 .
you can change it see manial
https://dev.mysql.com/doc/refman/8.0/en/fulltext-fine-tuning.html
or use regular expressiions
SELECT * FROM table WHERE
ompany_name REGEXP '[Äàö¬©¬†]+';
SELECT *
FROM table
WHERE company_name LIKE '%[^0-9a-zA-Z !"#$%&''()*+,\-./:;<=>?#\[\^_`{|}~\]\\]%' ESCAPE '\'
This will find any wacky stuff, including wide characters or 'euro-ASCII' or emoji.
What is the best way to search a database for a phrase such as "Almond Anise Cookie" and return the result?
If I
SELECT *
FROM recipes
WHERE name LIKE '%".$query."%'
and use the phrase "Almond Cookie", nothing is returned as expected. But if I search for "Anise Cookie" the result above is returned.
I've also tried
SELECT *
FROM recipes
WHERE name LIKE '%".$query."%'
OR name LIKE '".$query."%'
OR name LIKE '%".$query."'
with the same failed result.
Using MATCH AGAINST returns everything that contains "Almond" and everything that contains "Cookie" also not a good result. Is there a happy middle in returned results?
You can try using REPLACE. Something like this should work:
SELECT *
FROM recipes
WHERE NAME LIKE REPLACE(' ".$query." ',' ','%');
Note that I purposely add spaces between .$query. to ensure that the replace operation will make your term filled with the wildcard symbol. In the example above:
If $query='almond cookies' then REPLACE(' ".$query." ',' ','%') will become %almond%cookies%.
You can test the fiddle here : https://www.db-fiddle.com/f/kMzp99S8ENbTkYcW5FVdYN/0
I have a form where users can search all the entries in a table and i'm having problems with a specific entry.
I'll give an example for a better understanding:
The user can check 5 boxes: 1, 2, 3, 4, 5 and he checks all the boxes.
If the specific row has the value '1|2|3', my search query won't find it.
Beforehand i get the post variable in php (which is an array) and add '%' before and after every value. In this case: '%1%2%3%4%5%'
My search query:
SELECT id FROM table WHERE string LIKE '%1%2%3%4%5%'
In this case, it won't find the row with the value '1|2|3'.
I guess it's normal this way and it works great the other way around but I want to perform a query that matches parts of the original string. In my case '%1%2%3%4%5%' to match '1|2|3'.
How can i do this?
Thanks in advance for taking the time.
EDIT: Can i do this without multiple AND, OR operators?
just change it to this:
string LIKE '%1%'
OR
string LIKE '%2%'
OR
string LIKE '%3%'
...
this would solve your problem - but you should really think about normalizing your database (in this case, store 5 different flags as 1/0 for the five different settings instead of putting them all together in one field).
Before you find something sexier and more efficient, you can use:
SELECT id FROM table WHERE string LIKE '%1%' OR string LIKE '%2%' OR string LIKE '%3%' OR string LIKE '%4%' OR string LIKE '%5%'
I would say - dont use like, use substring or some similar function.
I'm trying to get around pulling all the data from a table, and cycling through it with php. Here's my current Query:
SELECT
*
FROM
ExampleTable
WHERE
StringContains LIKE "%lkjlkjsomeuser#example.comjkjhkjhkjhkjhk,mniu,mk,mkjh%"
ExampleTable.StringContains has values that look like 'someuser#example.com', 'someuser2#example.com', etc.
This doesn't match because LIKE only finds sub strings of the column value, not the other way around. Any ideas on commands to find rows where the table value is a substring of the passed string?
SELECT
*
FROM
ExampleTable
WHERE
'lkjlkjsomeuser#example.comjkjhkjhkjhkjhk,mniu,mk,mkjh' LIKE
CONCAT('%', StringContains, '%')
Try this:
SELECT *
FROM ExampleTable
WHERE "lkjlkjsomeuser#example.comjkjhkjhkjhkjhk,mniu,mk,mkjh" LIKE
CONCAT("%",StringContains,"%")
The key is to recognize that the column variable just represents a string, and the LIKE statement is always comparing two strings in the form
"stringA" LIKE '%stringB%'
Usually people use it to search for a "part" of a string contained in the "whole" database field string, but you can easily switch them. The only extra tool you need is the CONCAT statement, since you want the database field to be the part instead of the whole. The CONCAT statement builds a string with the %'s around the database field string, and the string form of the argument is now equivalent to
"stringB" LIKE "%stringA%"
Just make the LIKE in the opposit order. Since you have to add those % you'll have to concatenate the field first:
SELECT *
FROM ExampleTable
WHERE "lkjlkjsomeuser#example.comjkjhkjhkjhkjhk,mniu,mk,mkjh" LIKE CONCAT('%', StringContains, '%');