I have three relevant tables:
Evaluations:
EvalID
WorktypeID
PointsPossible
Items:
EvalID
ItemID
Value
QuestionID
Question_Worktype:
WorkTypeID
QuestionID
Points
There are multiple Items for each Evaluation, and each item has a QuestionID/WorkTypeID pair that relates to an entry in Question_Worktype, where the score lies.
Items.Value is whether an Item was correct or not.
I would like a query that returns the total Points of all Items for an Evaluation, Points only are awarded if the Value of the Item is 1.
My goal would be to get:
Eval_ID, Total Points (calculated), Points Possible
I can't seem to wrap my brain around it.
Edit: I forgot an important part:
I have an additional table:
qa_edits:
EditID
ItemID
NewValue
Date
If someone edits the value, it's stored here, and I really need it to calculate based on the newest edit for the item if there is one, or the item value if there isn't.
Start with your edit table, to get the latest edit for each item:
SELECT
M.ItemId,
COALESCE(Q.Value, I.Value) as Value,
I.QuestionId
FROM (
SELECT
I.ItemId,
MAX(Date) as LastEditDate
FROM Items as I
LEFT OUTER JOIN QA_Edits as E ON
I.ItemId = E.ItemId
GROUP BY
I.ItemId
) as M
LEFT OUTER JOIN QA_Edits as Q ON
M.ItemId = Q.ItemId
AND M.LastEditDate = Q.Date
LEFT OUTER JOIN Items as I ON
M.ItemId = Q.ItemId
AND M.LastEditDate IS NULL
I'd suggest a view for that - let's call it LatestItems.
Then, back to Blorgbeard's:
select
e.Eval_ID,
sum(qw.Points) as TotalPoints,
e.PointsPossible
from Evaluations e
join LatestItems i on
e.Eval_ID = i.Eval_ID
and i.Value = 1
join Questions_WorkType qw on
qw.QuestionID = i.QuestionID
group by
e.Eval_ID, e.PointsPossible
I think this should work:
select e.Eval_ID, sum(qw.Points) as TotalPoints, e.PointsPossible
from Evaluations e
left join Items i on e.Eval_ID = i.Eval_ID and i.Value = 1
join Questions_WorkType qw on qw.QuestionID = i.QuestionID
group by e.Eval_ID, e.PointsPossible
Related
My query does return the lowest price from the two columns (price_base, price_special) but it is not returning the correct store_id that corresponds to the lowest price found.
My Query:
SELECT grocery_item.id, grocery_item.category,
grocery_category.name AS cat, grocery_item.name AS itemName,
MIN( if( grocery_price.price_special>0,
grocery_price.price_base)) AS price,
grocery_price.store_id,
grocery_store.name AS storeName
FROM grocery_item
LEFT JOIN grocery_category ON
grocery_category.id=grocery_item.category
LEFT JOIN grocery_price
ON grocery_price.item_id = grocery_item.id
LEFT JOIN grocery_store
ON grocery_store.id=grocery_price.store_id
WHERE grocery_price.selection='no'
AND buy='yes'
GROUP BY grocery_price.item_id
ORDER BY store_id, grocery_item.category, grocery_item.name
Returns this:
ID category cat itemName price store_id storeName
92 3 Bread/Bakery Arnold Bread 2.14 1 Food Lion
But the grocery_price table holds this info:
item_id price_base price_special store_id
92 4.29 2.14 9
92 3.99 0.00 1
so the store_id I need to be returned is 9 (the storeName returned would NOT then be Food Lion)
EDIT: WORKING QUERY based on Uueerdo's comments (thank you!)
SELECT minP.item_id, gi.category, gc.name AS cat,
gi.name as itemName, gp.store_id,
gs.name AS storeName, minP.price
FROM
(SELECT p.item_id, MIN(IF(p.price_special >0,
p.price_special,p.price_base)) AS price
FROM grocery_item AS i
INNER JOIN grocery_price AS p ON (i.id = p.item_id)
WHERE i.buy = 'yes'
GROUP BY p.item_id) AS minP
INNER JOIN grocery_item AS gi ON minP.item_id = gi.id
INNER JOIN grocery_category AS gc on gi.category = gc.id
LEFT JOIN grocery_price AS gp
ON minP.price = IF(gp.price_special > 0,
gp.price_special,gp.price_base)
AND gp.item_id = gi.id
INNER JOIN grocery_store AS gs ON gp.store_id = gs.id
GROUP BY gi.id
ORDER BY gs.id, gi.category,gi.name
The values returned for non-grouped, non-aggregated fields are an (effectively) random selection from the values encountered with the grouped fields' values. Most RDBMS do not even consider such a query valid, and even newer versions of MySQL default to disallowing such queries.
In cases like yours, where you need the non-grouped value(s) associated with the aggregate result (min in this case); the aggregating query must be converted into a subquery, that can be joined back to the aggregated tables to find the source row(s) that correspond to the aggregated value.
Edit: Basically, you need to look at the problem slightly differently. You're currently finding the lowest price for an item and a store that item is listed for; you need to find the lowest price for an item, and use that to find the store(s) that have the item at that price.
This gets you the lowest price for item's marked "buy":
SELECT p.item_id, MIN(IF(p.price_special > 0,p.price_special,p.price_base)) AS price
FROM grocery_item AS i
INNER JOIN grocery_price AS p ON (i.id = p.item_id)
WHERE i.buy = 'yes'
GROUP BY p.item_id
You can then take that to get the rest of the results:
SELECT minP.item_id
, gi.name
, gi.category, gc.category_name AS cat, gi.Name as itemName, gi.buy
, gp.store_id, gp.name AS storeName
, minP.price
FROM ([the query above]) AS minP
INNER JOIN grocery_item AS gi ON minP.item_id = gi.id
INNER JOIN grocery_category AS gc on gi.category = gc.grocery_category_id
/* Guessing on this join since grocery_category_id
was not qualified with it's table name */
INNER JOIN grocery_price AS gp
ON minP.price = IF(gp.price_special > 0,gp.price_special,gp.price_base)
/* Alternatively: ON minP.price IN (gp.price_special, gp.price_base)
... though this could cause false positives if the minP.price is 0
from one store's base price being "free"
*/
INNER JOIN grocery_store AS gs ON gp.store_id = gs.id
;
I'm trying to output the top x items in my database based on a value of linked 'tags'
http://sqlfiddle.com/#!9/f23ad2
The function I'm currently using (note: :userId is the id from the user table):
SELECT
item.id,
item.name
FROM
item
LEFT JOIN
item_tag
ON
item.id = item_tag.item
LEFT JOIN
tag
ON
item_tag.tag = tag.id
LEFT JOIN
user_tag
ON
user_tag.user = :userId
AND
item_tag.tag = user_tag.tag
LEFT JOIN
item_tag_rating
ON
item_tag.tag = item_tag_rating.tag
AND
TRUNCATE(user_tag.val,0) = item_tag_rating.user_tag
ORDER BY
tag_rating DESC
LIMIT 10
The idea is that the user_tags table will tell you the user's tag_level (1-5) or if they don't currently have one use a default of 3 and based on that you get the value for that level in the item_tags table.
If there are 3 tags for instance you end up with 3 decimal numbers (percentage rating converted to decimal) which is then combined to get an overall percentage rating for the item. I then want to use that overall percentage number to output the top x items.
Any suggestions on how I could do this?
I need a modification of my previous post regarding
how to combine tables with 1 to many relationship into 1 line of record
how to combine tables with 1 to many relationship into 1 line of record
now my problem is my record has now 1 to many relationship. What I need to show is the last record only and combine it in a single line
tables tbl_equipment and tbl_warranty
and here is the desired output
here is the code I'm trying to implement
SELECT
a.equipmentid,
a.codename,
a.name,
a.labelid,
a.ACQUISITIONDATE,
a.description,
a.partofid,
w1.warrantyid as serviceidwarranty,
w1.startdate,
w1.enddate,
w2.warrantyid as productidwarranty,
w2.startdate,
w2.enddate,
s.equipstatusid,
l.equiplocationid FROM TBL_EQUIPMENTMST a
left JOIN tbl_equipwarranty w1
ON w1.equipmentid=a.equipmentid and w1.serviceproduct = 'service'
left JOIN tbl_equipwarranty w2
ON w2.equipmentid=a.equipmentid and w2.serviceproduct = 'product'
left join tbl_equipstatus s
on a.equipmentid = s.equipmentid
left join tbl_equiplocation l
on a.equipmentid = l.equipmentid WHERE a.equipmentid = '112'
I only want to show 1 record with the last value of warranty product and warranty service in the output. Can anyone guide me how to modify my code so that when I try join all the tables listed above can produce 1 record only with the last record of warranty as an output.
I am using firebird as a database. If you have a solution in mysql kindly tell me and ill try to find the counterpart in firebird.
with summary as(
select e.equipmentid ,e.Codename,e.Name,w.warrantyid ,w.Satartdate ,w.Enddate,w.warrantytype
from Eqp e
join Warranty w
on(w.equipmentid =e.equipmentid )
where w.warrantyid =3)
select *,w.warrantyid,w.Satartdate ,w.Enddate,w.warrantytype
from summary s
join Warranty w
on s.Satartdate =w.Satartdate and s.Enddate =w.Enddate
where w.warrantyid =4
after reading the comment of Barmar at the question for solution. I Figured out subquery can solve my problem. Subquery is a new word for me. I research on how to use subquery and came out with a solution below. you can correct me if my code is wrong or how to improve the performance of the query
SELECT
a.equipmentid,a.codename,a.name,a.labelid,a.ACQUISITIONDATE,a.description,a.partofid,
w1.warrantyid as serviceidwarranty,w1.startdate,w1.enddate,
w2.warrantyid as productidwarranty,w2.startdate,w2.enddate,
s.equipstatusid,
l.equiplocationid
FROM
TBL_EQUIPMENTMST a
left JOIN
(select first 1 *
from tbl_equipwarranty
where equipmentid='112' and serviceproduct = 'service'
order by warrantyid desc) w1 ON w1.equipmentid = a.equipmentid
and w1.serviceproduct = 'service'
left JOIN
(select first 1 *
from tbl_equipwarranty
where equipmentid = '112' and serviceproduct = 'product'
order by warrantyid desc) w2 ON w2.equipmentid = a.equipmentid
and w2.serviceproduct = 'product'
left join
(select first 1 *
from tbl_equipstatus
where equipmentid = '112'
order by equipstatusid desc) s on a.equipmentid = s.equipmentid
left join
(select first 1 *
from tbl_equiplocation
where equipmentid = '112'
order by equiplocationid desc) l on a.equipmentid = l.equipmentid
WHERE
a.equipmentid = '112'
i have 5 tables called personal,dailypay,bonuses,iou and loans am trying to write a query that will generate payroll from this table's...my code is
select personal.name as NAME,
(sum(dailypay.pay) + bonuses) - (iou.amount + loans.monthly_due)) as SALARY
from personal
join dailypay on personal.eid = dailypay.eid
left join bonuses on personal.eid = bonuses.eid
left join iou on personal.eid = iou.eid
left join where dailypay.date = 'specified_date'
and bonuses.date_approved = 'specified_date'
and iou.date_approved = 'specified_date'
and loans.date = month(now()
It returns the name and null salary values for staffs that does have records for either bonuses,iou and loans. But i want to sum their dailypay, deduct/add deductions or additions return the values, in the event of no record it should proceed with the summation without any deduction or subtraction.
You missed something when pasting the code, as there is no join for the loans table. Also, you are using the table bonuses as a value, you need a field name also. I added some code for the join and for the field, but used ??? for names that are unknown to me.
When you add or subtract a null value to something else, the result is null, that's why you get null as result when any of the values from the left-joined tables are missing. You can use ifnull(..., 0) to turn a null value into zero.
You need a group by clause, otherwise it would sum up the salary for all persons.
If I get you right, you have several records in the dailypay table for each user, but only one record per user in the other tables? In that case you have the problem that you will be joining the other tables against each row in the dailypay, so if you have 20 payment records for a user, it will count the bonus 20 times. You can use an aggregate like max to get the value only once.
You have put conditions for the left.joined tables in the where clause, but this will turn the joins into inner joins. You should have those conditions in each join clause.
select
personal.name as NAME,
(sum(dailypay.pay) + ifnull(max(bonuses.???), 0)) - (ifnull(max(iou.amount), 0) + ifnull(max(loans.monthly_due), 0)) as SALARY
from
personal
inner join dailypay on personal.eid = dailypay.eid
left join bonuses on personal.eid = bonuses.eid and bonuses.date_approved = 'specified_date'
left join iou on personal.eid = iou.eid and iou.date_approved = 'specified_date'
left join loans on personal.??? = loans.??? and loans.date = month(now())
where
dailypay.date = 'specified_date'
group by
personal.name
There seems to be an extranous left join before the where and a missing closing bracket ) in month(now()
so it should look like:
select personal.name as NAME,
(sum(dailypay.pay) + bonuses) - (iou.amount + loans.monthly_due)) as SALARY
from personal
join dailypay on personal.eid = dailypay.eid
left join bonuses on personal.eid = bonuses.eid
left join iou on personal.eid = iou.eid
where dailypay.date = 'specified_date'
and bonuses.date_approved = 'specified_date'
and iou.date_approved = 'specified_date'
and loans.date = month(now())
I have 3 tables
person (id, name)
area (id, number)
history (id, person_id, area_id, type, datetime)
In this tables I store the info which person had which area at a specific time. It is like a salesman travels in an area for a while and then he gets another area. He can also have multiple areas at a time.
history type = 'I' for CheckIn or 'O' for Checkout.
Example:
id person_id area_id type datetime
1 2 5 'O' '2011-12-01'
2 2 5 'I' '2011-12-31'
A person started traveling in area 5 at 2011-12-01 and gave it back on 2011-12-31.
Now I want to have a list of all the areas all persons have right now.
person1.name, area1.number, area2.number, area6.name
person2.name, area5.number, area9.number
....
The output could be like this too (it doesn't matter):
person1.name, area1.number
person1.name, area2.number
person1.name, area6.number
person2.name, area5.number
....
How can I do that?
This question is, indeed, quite tricky. You need a list of the entries in history where, for a given user and area, there is an 'O' record with no subsequent 'I' record. Working with just the history table, that translates to:
SELECT ho.person_id, ho.area_id, ho.type, MAX(ho.datetime)
FROM History AS ho
WHERE ho.type = 'O'
AND NOT EXISTS(SELECT *
FROM History AS hi
WHERE hi.person_id = ho.person_id
AND hi.area_id = ho.area_id
AND hi.type = 'I'
AND hi.datetime > ho.datetime
)
GROUP BY ho.person_id, ho.area_id, ho.type;
Then, since you're really only after the person's name and the area's number (though why the area number can't be the same as its ID I am not sure), you need to adapt slightly, joining with the extra two tables:
SELECT p.name, a.number
FROM History AS ho
JOIN Person AS p ON ho.person_id = p.id
JOIN Area AS a ON ho.area_id = a.id
WHERE ho.type = 'O'
AND NOT EXISTS(SELECT *
FROM History AS hi
WHERE hi.person_id = ho.person_id
AND hi.area_id = ho.area_id
AND hi.type = 'I'
AND hi.datetime > ho.datetime
);
The NOT EXISTS clause is a correlated sub-query; that tends to be inefficient. You might be able to recast it as a LEFT OUTER JOIN with appropriate join and filter conditions:
SELECT p.name, a.number
FROM History AS ho
JOIN Person AS p ON ho.person_id = p.id
JOIN Area AS a ON ho.area_id = a.id
LEFT OUTER JOIN History AS hi
ON hi.person_id = ho.person_id
AND hi.area_id = ho.area_id
AND hi.type = 'I'
AND hi.datetime > ho.datetime
WHERE ho.type = 'O'
AND hi.person_id IS NULL;
All SQL unverified.
You're looking for results where each row may have a different number of columns? I think you may want to look into GROUP_CONCAT()
SELECT p.`id`, GROUP_CONCAT(a.`number`, ',') AS `areas` FROM `person` a LEFT JOIN `history` h ON h.`person_id` = p.`id` LEFT JOIN `area` a ON a.`id` = h.`area_id`
I haven't tested this query, but I have used group concat in similar ways before. Naturally, you will want to tailor this to fit your needs. Of course, group concat will return a string so it will require post processing to use the data.
EDIT I thikn your question has been edited since I began responding. My query does not really fit your request anymore...
Try this:
select *
from person p
inner join history h on h.person_id = p.id
left outer join history h2 on h2.person_id = p.id and h2.area_id = h.area_id and h2.type = 'O'
inner join areas on a.id = h.area_id
where h2.person_id is null and h.type = 'I'