Making csv from txt files - csv

Question

I have a lot of txt files like this:
Title 1
Text 1(more then 1 line)
And I would like to make one csv file from all of them that it will look like this:
Title 1,Text 1
Title 2,Text 2
Title 3,Text 3
etc
How could I do it? I think that awk is good for it but don't know how to realize it.

Answer 1

May I suggest:
paste -d, file1 file2 file3
To handle large numbers of files, max 40 per output file (untested, but close):
xargs -n40 files... echo >tempfile
num=1
for line in $(<tempfile)
do
paste -d, $line >outfile.$num
let num=num+1
done

Answer 2

This is approximately what you posted with some improvements.
for text in *
do
awk 'BEGIN {q="\""; print q}
NR==1 {
gsub(" "," ") # why?
gsub("Title: *","")
print
}
NR>1 {
gsub(" "," ") # why?
gsub("Content: *","")
gsub(q,q q)
print
}
END {print q}' "$text" >> ../final
done
Edit:
If you have a bunch of files that consist of only two lines, try this:
sed 'N;s/\n/,/' file*.txt
If the files contain more than two lines each then it will put each pair of lines on the same line separated by a comma.

Answer 3

Given 3 files containing the following data:
file1.txt
Heading 1
Text 1
Text 2
file2.txt
Heading 2
Text 1
file3.txt
Heading 3
Text 1
text 2
Text 3
The expected results are:
Heading 1,Text 1,Text 2
Heading 2,Text1
Heading 3,Text 1,text 2,Text 3
This is accomplished using the program createcsv.awk below invoked as
gawk -f createcsv.awk file1.txt file2.txt file3.txt
createcsv.awk
{
if (1 == FNR) {
# It is the first line of a new file
if (csvline != "") {
# First file or empty files we can ignore
print csvline;
}
csvline = "";
delimiter = "";
}
csvline = csvline delimiter $0;
if ("" == delimiter) { delimiter="," }
}
END{
print csvline;
}