all. I am working on a Scala/Lift web application that uses an iframe to display content from another web application hosted on the same domain. Is there a way to access the URL of the child frame's currently-displayed page? The suggested solutions found for the general problem typically use Javascript, but I would to like accomplish this with Scala if possible.
Thanks!
I don't believe this would be possible, presuming you are trying to read the current page that it is on rather than the page that is sent by default.
If you are trying to read the current page it is on then that would necessitate interaction between the server and the client, meaning you would have to use some javascript. If you are trying to find the page it was on originally then that should have been set earlier in your program so you will be able to just store that value in a variable and access it later.
If you clarified which you were trying to do you might get a more complete answer.
Related
I am using the ionic framework and would like to be able to read from the HTML from the current webpage and then send the selection back to my application.
I have the Theme-able Browser Plugin setup and can use it like any other web browser.
I have tried looking at ways to include my own script with the .executeScript() function but no luck.
I have also tried to read data from custom buttons that I have inserted into the tool/nav bar but that gives me the HTML of my application.
TL;DR: (Basically want access to the DOM of the current webpage and have the user use native selection to read the document.getSelection() and send that text back to my application.)
Any help would be highly appreciated.
After browsing the forums on Ionic I found the solution:
browser.executeScript({code:'window.getSelection().toString();'}).then((selection)=>{
packet.text = selection[0];});
This allows me to get the selection.
I read more in the Internet, but I didn't managed to find solution to this problem:
Is it possible to attach some external content in case of sending X-Frame-Option=SAMEORIGIN by server ?
I know that <iframe> can't be used, however maybe there exists some another way.
Thanks in advance
No, it's not possible to show another page's contents within your website if they are setting the HTTP header X-Frame-Options: SAMEORIGIN. That header says that the page can only be embedded on pages on the same domain name.
However, if you are running your own server-side application (i.e. using PHP, Node.js, etc), you can scrape the website on your server, and then display whatever info you needed from the other site that way. It will be more work this way, and you probably won't be able to perfectly replicate how everything appeared on the source site, but it's the only route you've got. I suggest googling "scraping" + the name of your server-side language/environment to learn how to do this.
I am planning to design a web application with multiple HTML and JSP pages. The first page of myapp (index.html) loads up with the url
localhost:8080/mywebapp
without an explicitly pointing it to
localhost:8080/mywebapp.index.html
because web-xml has index.html in its startup script. Thats perfectly fine!
But how to toggle between multiple JSPs and HTMLs that are in the web app keeping the URL constant
localhost:8080/mywebapp
The user should not be knowing the navigation pattern when he is using the web-app.
Ideas on any frameworks or implementations are highly appreciated.
Thanks
Leaving aside the fact that you shouldn't do this, essentially what you have to do is bypass the standard routing method of your application.
You can do this one of two ways.
1) Use Ajax to call all the different URLs you need from within a single page. This will give you the single URL you're looking for though it doesn't of course prevent anyone from trivially working out what the actual navigation URLs are and unless you build a single page app and do some really evil interdependencies finding your navigation is trivially easy.
2) Your second option would be to create a single servlet which takes parameters which identify which part of your application you want to use. If you really wanted to be horribly evil you could hash those arguments with some form of per user short duration cookie so that even if they identify the actual web calls you're making running them manually won't actually work.
I have a website that has a lot of data and that is sensitive to the website so I made a code that prevents right clicks but if you are using Safari it is easy to see the data I need to hide the info also so safari cant view it ether.
Client side, you cannot secure your code from view. Firebug will still show the code. You should have sensitive data on the Server.
You can't.
If the data is sufficiently sensitive that people shouldn't be able to view it, don't put it on a web site.
I m not sure if there is a completely safe solution.
if its images, use flash to load them dynamically.
yet people who knows swf-bin specs can decompile your swf files and find out the real image path.
if its data & text.
as much I can do is to
1: use pure js to render all views.
use XMLHttpRequest/ActiveXObject to load data and import these ajax js code # runtime.
compress your js/css code before deploy
here is one of my mockups
2: on the server side
check the request header to drop command line request.
exchange cookie/session key for each time.
BUT, this will make google-bots don't know how to inspect your site.
so DON'T do that on your landing page.
I have created a page in DNN 7 and added the standard feedback module available at Codeplex to it. Now I want to link to this page using a hyperlink in the middle of another page (not from a menu).
I am able to see the URL for the feedback page via the admin pages and it seems to be consistent. So the obvious way would be to use the HTML module and simply hardcode the URL. But something feels wrong about that. I thought of creating a simple module, encapsulate the hyperlink and surrounding text in a control and use NavigateURL to obtain the URL for the feedback page. Unfortunately, I have not been able to figure out how to do that. I have seen a lot of information about getting the URL for other controls within the same module and even using ModuleID but nothing that would help me implement the code for getting the URL for a particular page at my level of experience.
Sorry about the long intro but I was wondering if it is good practice to hardcode the URL and if not how to programmatically obtain the URL for the feedback page.
TIA
The first argument to NavigateURL is TabId (pages are called tabs in the DNN API). To get the ID of the Feedback tab/page, you'll want to call a method off of the DotNetNuke.Entities.Tabs.TabController class; I'd suggest the static method TabController.GetTabByTabPath(portalId, tabPath, cultureCode), so something like this:
Globals.NavigateURL(TabController.GetTabByTabPath(this.PortalId, "//Feedback", string.Empty))
You're still hard-coding the path to the page here; you could have a setting, which would let you pick the page, but that seems like a bit of overkill for a simple link. The main benefit that you would get by hard-coding the path, but still using NavigateURL is that any changes you make to how URLs are generated (e.g. upgrading to the Advanced URL Provider that comes in DNN 7.1) will happen automatically.
Most folks don't worry much about programatically generating links in HTML content.