My teacher is pointing to oracle and debating that, but I have hopes of doing this with a pure injection in MySQL. I want to search the database in phpMyadmin and find exactly two K's. Is this possible?
The nearest thing I got is:
SELECT etunimi, sukunimi FROM nimet WHERE sukunimi LIKE '%k%k%n';
It is the last %k%k%n that needs to be solved. Can you help me prove my teacher wrong?
Use MySQL's REGEXP operator:
SELECT etunimi, sukunimi
FROM nimet
WHERE sukunimi REGEXP '^[^k]*k[^k]*k[^k]*n$'
I'm not sure what the n at the end is for, since you don't mention it in your question, but I left it, just in case.
Use this to find out strings with exactly 2 k's
SELECT etunimi, sukunimi FROM nimet WHERE LENGTH(sukunimi)-LENGTH(REPLACE(sukunimi, 'k', ''))=2;
Related
hope that you are doing fine
I am having very hard time writing a query
Here is my question explained
i have a database table say "jreviews_content" which has a field named "jr_produits"
In "jr_produits" the data is is the format *ryan-decosta*tom-gosling* so i want a search query that is exact word based i.e if the user type "rya" the mysql should not return anything
but if the user type ryan then it should return the row likewise if the user type "gos" the mysql should not return anything
but if the user type gosling then it should return the row where ryan and gosling are the exact words
the query that i am writing are
SELECT *
FROM `jreviews_content`
WHERE jr_produits LIKE '%*ryan-%' or jr_produits LIKE '%-ryan*%'
or jr_produits LIKE '%*ryan*%' or jr_produits LIKE '%-ryan-%';
I want that to be done in some other way that is more efficient(either by regular expression or any other method)
SELECT * FROM `jreviews_content` WHERE jr_produits REGEXP '^[*-]ryan[*-]$'
It doen't fetch anything
neither does
SELECT * FROM `jreviews_content` WHERE jr_produits like '%[*-]ryan[*-]%'
Please suggest something
Try the MySQL regex word boundary markers. They're documented about halfway down this page:
SELECT *
FROM jreviews_content
WHERE jr_produits REGEXP '[[:<:]]ryan[[:>:]]'
Note that I don't have MySQL access today, so this is untested.
Also heed what #user1032531 said. Records with values like *ryan-decosta*tom-gosling* almost always mean "bad design".
I am having issues with my MySQL syntax. I would like to run a select query where either one of two options are true. However the following code does not work.
SELECT * FROM games WHERE genre="indie" OR title="indie"
I have been fooling around and look at other threads and have found out how to use OR to check the same column for multiple entries but not a way to check different columns for the same entries. When I do:
SELECT * FROM games WHERE genre="indie"
The query works fine. Any help would be greatly appreciated.
The only way I see this really would't work, is if you've mistyped the name of the column 'title' (if the second query you wrote works)
The assumptions about the case sensitivity are wrong, since the second query returns something, the first should return at least the same rows as the second one
In MySQL " " works just as ' ', so this assuption was wrong too.
If you post more information, it would be easier to help you
Maybe you ignoring the upper/lower case? Also use like
You can use this:
SELECT * FROM games WHERE (LOWER(genre) like 'indie') OR (LOWER(title) like 'indie')
I am not very good with regexp so I really would like some help to achieve my goal.
When searching in my db I use an alias for specific keywords.
Here is an example
keyword tets alias test (someone have spell wrong then word test)
keyword b.m.w alias bmw (if someone write b.m.w instead of bmw)
etc.
So far if a user searches for "bmw 316" I use LIKE "%bmw%316%" to get the results.
Now if the user searches for "b.m.w 316" I must use
"%b.m.w%316%" OR
"%bmw%316%"
because b.m.w has alias bmw.
In the case of 6 words with 2-3 aliases there are too many combinations.
I am trying to achieve it with regexp.
In the scenario above it would be something like (bmw|b.m.w) 316.
How do I solve this problem?
You are not looking for REGEXP you are looking for a thing called levenshtein distance
MySQL does not (yet) have native support for this (wonderful) concept, but you can download a UDF here:
http://joshdrew.com/
And here's a list so you've got something to choose from:
http://blog.lolyco.com/sean/2008/08/27/damerau-levenshtein-algorithm-levenshtein-with-transpositions/
You can also write your own function in MySQL, so you don't have to install a UDF.
http://www.supermind.org/blog/927/working-mysql-5-1-levenshtein-stored-procedure
Finally this question might help you out as well:
Implementation of Levenshtein distance for mysql/fuzzy search?
A query for the closest match would look something like:
SELECT * FROM atable a ORDER BY levenshtein(a.field, '$search') ASC LIMIT 10
I have a query in mySQL that's meant to return search terms that are used on our site. Yes, this is for a tag cloud, and yes, I know it's a mullet :)
We've got an admin page where administrators can view search terms and choose to exclude them from showing up in the cloud. These words go into the "badWords" table. We've gotten some terms like "foo%2525252525252520bar", and we're having trouble getting those excluded.
In pseudocode, the query to get the search terms for the cloud is:
SELECT * FROM `searchTerms` WHERE `word` NOT IN ( SELECT `word` FROM `badWords` )
This works fine, unless one of the terms returned from the subquery has a % in it. Is there a way to escape the entire subquery? I've tried doing a
replace( SELECT `word` FROM `badWords`, '%', '\%' )
... but that's apparently not syntactically correct.
I can do two queries if need be, but wondered if there's a way to get it done as is.
Thanks!
==============================
UPDATE: closing this for now, as I think the error lies elsewhere. Will report back once I know for sure, but don't want folks wasting time answering the question here if it's not the correct question...
Upvoted both of the replies received so far. Thanks, guys.
==============================
UPDATE 2: sigh Nevermind... can't close it :\
==============================
FINAL UPDATE: Well, looks like escaping the value isn't the problem. The admin page passes the value in the URL before it's added to the badWords table. In passing the value via the URL, it changes. So what's added to badWords is actually "foo%25252525252520bar" (there's one less "25" sequence). If I manually update the value in badWords and add back the missing "25" it works as expected. So no need to replace or escape anything. I just need to fix those URL values properly.
==============================
I don't think the % is your problem here. I think that you're trying to use REPLACE() on the subquery itself (SELECT ...), and not on a column value (word). Try this instead:
SELECT * FROM `searchTerms`
WHERE `word` NOT IN (
SELECT REPLACE(`word`, '%', '\%') AS word FROM `badWords`
);
Good luck!
I'm not very good with MySQL syntax, but SQL Server let's you do it this way:
SELECT * FROM `searchTerms` WHERE `word` NOT IN ( SELECT REPLACE(`word`, '%', '\%') FROM `badWords` )
NOTE: Basically all I did was move your REPLACE over some =) Hope this helps.
I am having a problem with the following query(if this is a duplicate question then i'm terribly sorry, but i can't seem to find anything yet that can help me):
SELECT d.*, GROUP_CONCAT(g.name ORDER BY g.name SEPARATOR ", ") AS members
FROM table_d AS d LEFT OUTER JOIN table_g AS g ON (d.eventid = g.id)
WHERE members LIKE '%p%';
MySQL apparently can't handle a comparison of GROUP_CONCAT columns in a WHERE clause.
So my question is very simple. Is there a workaround for this, like using sub-query's or something similar? I really need this piece of code to work and there is not really any alternative to use other than handling this in the query itself.
EDIT 1:
I won't show the actual code as this might be confidential, I'll have to check with my peers. Anyway, I just wrote this code to give you an impression of how the statement looks like although I agree with you that it doesn't make a lot of sense. I'm going to check the answers below in a minute, i'll get back to you then. Again thnx for all the help already!
EDIT 2:
Tried using HAVING, but that only works when i'm not using GROUP BY. When I try it, it gives me a syntax error, but when I remove the GROUP BY the query works perfectly. The thing is, i need the GROUP BY otherwise the query would be meaningless to me.
EDIT 3:
Ok, so I made a stupid mistake and put HAVING before GROUP BY, which obviously doesn't work. Thanks for all the help, it works now!
Use HAVING instead of WHERE.
... HAVING members LIKE '%peter%'
WHERE applies the filter before the GROUP_CONCAT is evaluated; HAVING applies it later.
Edit: I find your query a bit confusing. It looks like it's going to get only one row with all of your names in a single string -- unless there's nobody in your database named Peter, it which case the query will return nothing.
Perhaps HAVING isn't really what you need here...
Try
SELECT ...
...
WHERE g.name = 'peter'
instead. Since you're just doing a simple name lookup, there's no need to search the derived field - just match on the underlying original field.
GROUP_CONCAT is an aggregate function. You have to GROUP BY something. If you just want all the rows that have %peter% in them try
SELECT d.*, g.name
FROM table_d AS d
LEFT OUTER JOIN table_g AS g
ON (d.eventid = g.id)
WHERE g.name LIKE '%peter%';