std::vector of std::function - function

Question

I have the following:
typedef std::function<void(const EventArgs&)> event_type;
class Event : boost::noncopyable
{
private:
typedef std::vector<event_type> EventVector;
typedef EventVector::const_iterator EventVector_cit;
EventVector m_Events;
public:
Event()
{
}; // eo ctor
Event(Event&& _rhs) : m_Events(std::move(_rhs.m_Events))
{
}; // eo mtor
// operators
Event& operator += (const event_type& _ev)
{
assert(std::find(m_Events.begin(), m_Events.end(), _ev) == m_Events.end());
m_Events.push_back(_ev);
return *this;
}; // eo +=
Event& operator -= (const event_type& _ev)
{
EventVector_cit cit(std::find(m_Events.begin(), m_Events.end(), _ev));
assert(cit != m_Events.end());
m_Events.erase(cit);
return *this;
}; // eo -=
}; // eo class Event
And during compilation:
1>c:\program files (x86)\microsoft visual studio 10.0\vc\include\algorithm(41): error C2451: conditional expression of type 'void' is illegal
1> Expressions of type void cannot be converted to other types
Now, I understand this is because of what is being stored in the vector and the operator ==. Is there another way to store std::function in an STL container? Do I need to wrap it up in something else?

Answer 1

You can store boost::function in the vector, provided you don't use std::find. Since you seem to need this, wrapping the function in its own class with equality would be probably the best.
class EventFun
{
int id_;
boost::function<...> f_;
public:
...
bool operator==(const EventFun& o) const { return id_==o.id_; } // you get it...
};
Note that this requires you maintain the id_ in a sane way (eg. two different EventFuns will have different id_s, etc.).
Another possibility would be to store boost::functions with a tag the client would remember and use to identify the particular function on deleting it.