Is it possible to get the (first?) match of a regex and output it within a select? It looks like the REGEXP function only return whether there has been a match or not. I want to be able to extract information out of a varchar column without having to use complex SUBSTRING-LOCATION nestings.
Any ideas?
http://dev.mysql.com/doc/refman/5.1/en/regexp.html that's all there is. You can't do more than pattern comparison.
Related
I have an JSON string stored in the database and I need to SQL COUNT based on the WHERE condition that is in the JSON string. I need it to work on the MYSQL 5.5.
The only solution that I found and could work is to use the REGEXP function in the SQL query.
Here is my JSON string stored in the custom_data column:
{"language_display":["1","2","3"],"quantity":1500,"meta_display:":["1","2","3"]}
https://regex101.com/r/G8gfzj/1
I now need to create a SQL sentence:
SELECT COUNT(..) WHERE custom_data REGEXP '[HELP_HERE]'
The condition that I look for is that the language_display has to be either 1, 2 or 3... or whatever value I will define when I create the SQL sentence.
So far I came here with the REGEX expression, but it does not work:
(?:\"language_display\":\[(?:"1")\])
Where 1 is replaced with the value that I look for. I could in general look also for "1" (with quotes), but it will also be found in the meta_display array, that will have different values.
I am not good with REGEX! Any suggestions?
I used the following regex to get matches on your test string
\"language_display\":\[(:?\"[0-9]\"\,)*?\"3\"(:?\,\"[0-9]\")*?\]
https://regex101.com/ is a free online regex tester, it seems to work great. Start small and work big.
Sorry it doesn't work for you. It must be failing on the non greedy '*?' perhaps try without the '?'
Have a look at how to serialize this data, with an eye to serializing the language display fields.
How to store a list in a column of a database table
Even if you were to get your idea working it will be slow as fvck. Better off to process through each row once and generate something more easily searched via sql. Even a field containing the comma separated list would be better.
One column returns such values:
Something";s:5:"value";s:3:"900";s:11:"print_
I want to extract all numbers that are at least 3 digits long, in the above case thats 900. How can I do that in MySQL? Maybe using a regex? I cant use any index, the length of the string and the number in the string can be different.
Thanks!
Try unserialize() it if you are using PHP! And then var_dump it to see the strings and arrays
You can't extract them using MySQL, use any other language for that.
What you can do is include a Where Clause, that will make the work easier for your script.
Assuming your column is called "serialized" in the table "example"
SELECT serialized FROM example WHERE serialized REGEXP '[0-9]{3,}'
Please note that REGEXP is just outputting 1 or 0
After you did the query, use the regex functions of your language do extract the numbers like so:
([0-9]{3,})*
I have a table with tens of thousands of VIN numbers. Many of them look along the lines of this:
6MMTL#A423T######
WVWZZZ3BZ1?######
MPATFS27H??######
SCA2D680?7UH#####
SAJAC871?68H06###
The # represents a digit and the ? a letter (A-Z).
I want to search for the following: 6MMTL8A423T000000.
I am struggling to work out the logic. Should I use a function? Should I use mysql regex?
A regular expression match would be a good way to approach this problem. What you need to do is convert the vin expressions into valid regular expressions that represent the logic you've indicated. Here's a simple way to do that:
replace(replace(vin,'#','[0-9]'),'?','[A-Z]')
This would convert 6MMTL#A423T###### into 6MMTL[0-9]A423T[0-9][0-9][0-9][0-9][0-9][0-9]. Now using this converted format, do a regular expression match query:
select vin
from vins
where '6MMTL8A423T000000' regexp replace(replace(vin,'#','[0-9]'),'?','[A-Z]')
Sample Output: 6MMTL#A423T######
Demo: http://www.sqlfiddle.com/#!2/ee4de/4
In MySQL how to search a value in a field that contains value separated by commas?(I have to search for (5,6) and it should return the field that contains all possibilities {5,6,(5,6)}
Is it possible?
You can try this
MyModel.where("field LIKE (?)", "%5,6%")
MyModel.where("filed REGEXP '5,6'")
There are many methods in MySQL for pattern matching, such as like ,RLIKE, MATCH-AGAINST,FIND_IN_SET, etc. The exact one depends on your need. Explain your sample data and desired result; then I can say which function will best help you.
I have tried several regex patterns (designed for use with PHP because I couldn't find any for MySQL) for URL validation, but none of them are working. Probably MySQL has a slightly different syntax.
I've also tried to come up with one, but no success.
So does anyone know a fairly good regex to use with MySQL for URL validation?
According to article 11.5.2. Regular Expressions in MySQL's documentation, you can perform selections with a regular expression with the following syntax
SELECT field FROM table WHERE field REGEX pattern
In order to match simple URLS, you may use
SELECT field FROM table
WHERE field REGEXP "^(https?://|www\\.)[\.A-Za-z0-9\-]+\\.[a-zA-Z]{2,4}"
This will match most urls like
www.google.il
http://google.com/
http://ww.google.net/
www.google.com/index.php?test=data
https://yahoo.dk/as
http://goo.gle.com/
http://wt.a.x24-s.org/ye/
www.website.info
But not
htp://google.com
ww.google.com/
www-google.com
http://google.c
http://goo#.com
httpf://google.com
Although the answer KBA posted works, there are some inconstancies with the escaping.
The proper syntax should be, this syntax works in MySQL as well as in PHP for example.
SELECT field FROM table
WHERE field REGEXP "^(https?:\/\/|www\.)[\.A-Za-z0-9\-]+\.[a-zA-Z]{2,4}"
The above code will only match if the content of 'field' starts with a URL. If you would like to match all rows where the field contains a url (so for example surrounded by other text / content) just simply use:
SELECT field FROM table
WHERE field REGEXP "(https?:\/\/|www\.)[\.A-Za-z0-9\-]+\.[a-zA-Z]{2,4}"