pivot tables in database with sqlalchemy - sqlalchemy

I need a database that support pivots to get pivot columns with sqlalchemy, something like that:
# find all possible values of the pivot
pivot_values = map(
operator.itemgetter(0),
select([pivot_on], from_obj=[report]).distinct().execute()
)
# build the new pivot columns
new_columns = [
pivot_func(case([(pivot_on == value, column)])).label("%s %s" % (value, column))
for value in pivot_values
for column in pivot_columns
]
return select(
non_pivot_columns + new_columns,
from_obj=[report],
group_by=group_by
)

I use the following recipe link text. I get the data and then pivot.

This is pretty old, but postgres now does pivoting: http://www.craigkerstiens.com/2013/06/27/Pivoting-in-Postgres
Presumably you would have to use sa.sql.func.crosstab etc in sqlalchemy. Guess you could map the crostabbed select to an object in the ORM and the pull the data out like that if you wanted.

Related

Django bulk update setting each to different values? [duplicate]

I'd like to update a table with Django - something like this in raw SQL:
update tbl_name set name = 'foo' where name = 'bar'
My first result is something like this - but that's nasty, isn't it?
list = ModelClass.objects.filter(name = 'bar')
for obj in list:
obj.name = 'foo'
obj.save()
Is there a more elegant way?
Update:
Django 2.2 version now has a bulk_update.
Old answer:
Refer to the following django documentation section
Updating multiple objects at once
In short you should be able to use:
ModelClass.objects.filter(name='bar').update(name="foo")
You can also use F objects to do things like incrementing rows:
from django.db.models import F
Entry.objects.all().update(n_pingbacks=F('n_pingbacks') + 1)
See the documentation.
However, note that:
This won't use ModelClass.save method (so if you have some logic inside it won't be triggered).
No django signals will be emitted.
You can't perform an .update() on a sliced QuerySet, it must be on an original QuerySet so you'll need to lean on the .filter() and .exclude() methods.
Consider using django-bulk-update found here on GitHub.
Install: pip install django-bulk-update
Implement: (code taken directly from projects ReadMe file)
from bulk_update.helper import bulk_update
random_names = ['Walter', 'The Dude', 'Donny', 'Jesus']
people = Person.objects.all()
for person in people:
r = random.randrange(4)
person.name = random_names[r]
bulk_update(people) # updates all columns using the default db
Update: As Marc points out in the comments this is not suitable for updating thousands of rows at once. Though it is suitable for smaller batches 10's to 100's. The size of the batch that is right for you depends on your CPU and query complexity. This tool is more like a wheel barrow than a dump truck.
Django 2.2 version now has a bulk_update method (release notes).
https://docs.djangoproject.com/en/stable/ref/models/querysets/#bulk-update
Example:
# get a pk: record dictionary of existing records
updates = YourModel.objects.filter(...).in_bulk()
....
# do something with the updates dict
....
if hasattr(YourModel.objects, 'bulk_update') and updates:
# Use the new method
YourModel.objects.bulk_update(updates.values(), [list the fields to update], batch_size=100)
else:
# The old & slow way
with transaction.atomic():
for obj in updates.values():
obj.save(update_fields=[list the fields to update])
If you want to set the same value on a collection of rows, you can use the update() method combined with any query term to update all rows in one query:
some_list = ModelClass.objects.filter(some condition).values('id')
ModelClass.objects.filter(pk__in=some_list).update(foo=bar)
If you want to update a collection of rows with different values depending on some condition, you can in best case batch the updates according to values. Let's say you have 1000 rows where you want to set a column to one of X values, then you could prepare the batches beforehand and then only run X update-queries (each essentially having the form of the first example above) + the initial SELECT-query.
If every row requires a unique value there is no way to avoid one query per update. Perhaps look into other architectures like CQRS/Event sourcing if you need performance in this latter case.
Here is a useful content which i found in internet regarding the above question
https://www.sankalpjonna.com/learn-django/running-a-bulk-update-with-django
The inefficient way
model_qs= ModelClass.objects.filter(name = 'bar')
for obj in model_qs:
obj.name = 'foo'
obj.save()
The efficient way
ModelClass.objects.filter(name = 'bar').update(name="foo") # for single value 'foo' or add loop
Using bulk_update
update_list = []
model_qs= ModelClass.objects.filter(name = 'bar')
for model_obj in model_qs:
model_obj.name = "foo" # Or what ever the value is for simplicty im providing foo only
update_list.append(model_obj)
ModelClass.objects.bulk_update(update_list,['name'])
Using an atomic transaction
from django.db import transaction
with transaction.atomic():
model_qs = ModelClass.objects.filter(name = 'bar')
for obj in model_qs:
ModelClass.objects.filter(name = 'bar').update(name="foo")
Any Up Votes ? Thanks in advance : Thank you for keep an attention ;)
To update with same value we can simply use this
ModelClass.objects.filter(name = 'bar').update(name='foo')
To update with different values
ob_list = ModelClass.objects.filter(name = 'bar')
obj_to_be_update = []
for obj in obj_list:
obj.name = "Dear "+obj.name
obj_to_be_update.append(obj)
ModelClass.objects.bulk_update(obj_to_be_update, ['name'], batch_size=1000)
It won't trigger save signal every time instead we keep all the objects to be updated on the list and trigger update signal at once.
IT returns number of objects are updated in table.
update_counts = ModelClass.objects.filter(name='bar').update(name="foo")
You can refer this link to get more information on bulk update and create.
Bulk update and Create

Rails SQL query on unknown (dynamic) number of queries using LIKE

I have a Rails search form that performs a dynamic query. That is, the user enters a search like:
(hobby="skiing") OR (gender="male" AND hobby="jogging")
So, I don't know how many queries I will be searching by until runtime.
I parse the search query by converting it into a valid SQL query, so the above search would be converted to the following format:
query = "hobby LIKE ? OR (gender LIKE ? AND hobby LIKE ?)"
queries = ["skiing", "male", "jogging"]
For the following query:
where(query, queries)
However, the general syntax of the Rails search query is very limiting:
where(query, query_1, query_2, query_3)
I cannot replace the 'query_n' arguments with an array like I want to, without Rails throwing an error.
NoMethodError (undefined method `where' for ["a", "b", "c"]:Array)
Attempting to splat the array yields the same error:
where(query, *queries)
Again:
NoMethodError (undefined method `where' for ["a", "b", "c"]:Array)
So what can I do?
EDIT:
The full search function looks like this:
def self.search(search)
query = "%#{search}%"
if search
includes(:games, :jobs)
strngs = ["hobby = ? OR name = ? OR gender = ?", "dsfgdsfg", "dsgsdfgsd", "sdfsfsdf"]
.where(strngs)
What you'll want to do is pass an array as a single argument to where which contains both the query AND the dynamic values. For example:
where(["att_1 LIKE ? OR att_2 LIKE ?", "value1", "value2"])
If an array is passed as the first and only argument, then the first element of the array is treated as a template. The following array values are treated as the dynamic values for the query template.
For your example, instead of having two separate variables queries and query, combine them into one query variable:
# A single array with the query AND values
query = ["hobby LIKE ? OR (gender LIKE ? AND hobby LIKE ?)", "skiing", "male", "jogging"]
# Run the `where` with a single array as the argument
YourModel.where(query)
This will allow you to query the DB with an unknown number of values using LIKE.
For reference: Rails where() docs

find row in ruby array

I have a mysql query that returns this type of data:
{"id"=>1, "serviceCode"=>"1D00", "price"=>9.19}
{"id"=>2, "serviceCode"=>"1D01", "price"=>9.65}
I need to return the id field based on a match of the serviceCode.
i.e. I need a method like this
def findID(serviceCode)
find the row that has the service code and return the ID
end
I was thinking of having a serviceCodes.each do |row| method and loop through and essentially go
if row == serviceCode
return row['id']
end
is there a faster / easier way?
You can use the method Enumerable#find:
service_codes = [
{"id"=>1, "serviceCode"=>"1D00", "price"=>9.19},
{"id"=>2, "serviceCode"=>"1D01", "price"=>9.65}
]
service_codes.find { |row| row['serviceCode'] == '1D00' }
# => {"id"=>1, "serviceCode"=>"1D00", "price"=>9.19}
If you use Rails Active Record as ORM and your Model named Product (only for example),
you can use something like this:
def findID(serviceCode)
Product.select(:id).where(serviceCode: serviceCode).first
end
If you have plain SQL Query in plain ruby class (not recommended), you should change this query to get only the id, as Luiggi mentioned. But aware of SQL Injections if your serviceCode coming from external Requests.

MySQL Dynamic Query Statement in Python with Dictionary

Very similar to this question MySQL Dynamic Query Statement in Python
However what I am looking to do instead of two lists is to use a dictionary
Let's say i have this dictionary
instance_insert = {
# sql column variable value
'instance_id' : 'instnace.id',
'customer_id' : 'customer.id',
'os' : 'instance.platform',
}
And I want to populate a mysql database with an insert statement using sql column as the sql column name and the variable name as the variable that will hold the value that is to be inserted into the mysql table.
Kind of lost because I don't understand exactly what this statement does, but was pulled from the question that I posted where he was using two lists to do what he wanted.
sql = "INSERT INTO instance_info_test VALUES (%s);" % ', '.join('?' for _ in instance_insert)
cur.execute (sql, instance_insert)
Also I would like it to be dynamic in the sense that I can add/remove columns to the dictionary
Before you post, you might want to try searching for something more specific to your question. For instance, when I Googled "python mysqldb insert dictionary", I found a good answer on the first page, at http://mail.python.org/pipermail/tutor/2010-December/080701.html. Relevant part:
Here's what I came up with when I tried to make a generalized version
of the above:
def add_row(cursor, tablename, rowdict):
# XXX tablename not sanitized
# XXX test for allowed keys is case-sensitive
# filter out keys that are not column names
cursor.execute("describe %s" % tablename)
allowed_keys = set(row[0] for row in cursor.fetchall())
keys = allowed_keys.intersection(rowdict)
if len(rowdict) > len(keys):
unknown_keys = set(rowdict) - allowed_keys
print >> sys.stderr, "skipping keys:", ", ".join(unknown_keys)
columns = ", ".join(keys)
values_template = ", ".join(["%s"] * len(keys))
sql = "insert into %s (%s) values (%s)" % (
tablename, columns, values_template)
values = tuple(rowdict[key] for key in keys)
cursor.execute(sql, values)
filename = ...
tablename = ...
db = MySQLdb.connect(...)
cursor = db.cursor()
with open(filename) as instream:
row = json.load(instream)
add_row(cursor, tablename, row)
Peter
If you know your inputs will always be valid (table name is valid, columns are present in the table), and you're not importing from a JSON file as the example is, you can simplify this function. But it'll accomplish what you want to accomplish. While it may initially seem like DictCursor would be helpful, it looks like DictCursor is useful for returning a dictionary of values, but it can't execute from a dict.

How to get Ruby MySQL returning PHP like DB SELECT result

So I use the PDO for a DB connection like this:
$this->dsn[$key] = array('mysql:host=' . $creds['SRVR'] . ';dbname=' . $db, $creds['USER'], $creds['PWD']);
$this->db[$key] = new PDO($this->dsn[$key]);
Using PDO I can then execute a MySQL SELECT using something like this:
$sql = "SELECT * FROM table WHERE id = ?";
$st = $db->prepare($sql);
$st->execute($id);
$result = $st->fetchAll();
The $result variable will then return an array of arrays where each row is given a incremental key - the first row having the array key 0. And then that data will have an array the DB data like this:
$result (array(2)
[0]=>[0=>1, "id"=>1, 1=>"stuff", "field1"=>"stuff", 2=>"more stuff", "field2"=>"more stuff" ...],
[1]=>[0=>2, "id"=>2, 1=>"yet more stuff", "field1"=>"yet more stuff", 2=>"even more stuff", "field2"=>"even more stuff"]);
In this example the DB table's field names would be id, field1 and field2. And the result allows you to spin through the array of data rows and then access the data using either a index (0, 1, 2) or the field name ("id", "field1", "field2"). Most of the time I prefer to access the data via the field names but access via both means is useful.
So I'm learning the ruby-mysql gem right now and I can retrieve the data from the DB. However, I cannot get the field names. I could probably extract it from the SQL statement given but that requires a fair bit of coding for error trapping and only works so long as I'm not using SELECT * FROM ... as my SELECT statement.
So I'm using a table full of State names and their abbreviations for my testing. When I use "SELECT State, Abbr FROM states" with the following code
st = #db.prepare(sql)
if empty(where)
st.execute()
else
st.execute(where)
end
rows = []
while row = st.fetch do
rows << row
end
st.close
return rows
I get a result like this:
[["Alabama", "AL"], ["Alaska", "AK"], ...]
And I'm wanting a result like this:
[[0=>"Alabama", "State"=>"Alabama", 1=>"AL", "Abbr"=>"AL"], ...]
I'm guessing I don't have the way inspect would display it quite right but I'm hoping you get the idea by now.
Anyway to do this? I've seen some reference to doing this type of thing but it appears to require the DBI module. I guess that isn't the end of the world but is that the only way? Or can I do it with ruby-mysql alone?
I've been digging into all the methods I can find without success. Hopefully you guys can help.
Thanks
Gabe
You can do this yourself without too much effort:
expanded_rows = rows.map do |r|
{ 0 => r[0], 'State' => r[0], 1 => r[1], 'Abbr' => r[1] }
end
Or a more general approach that you could wrap up in a method:
columns = ['State', 'Abbr']
expanded_rows = rows.map do |r|
0.upto(names.length - 1).each_with_object({}) do |i, h|
h[names[i]] = h[i] = r[i]
end
end
So you could collect up the rows as you are now and then pump that array of arrays through something like what's above and you should get the sort of data structure you're looking for out the other side.
There are other methods on the row you get from st.fetch as well:
http://rubydoc.info/gems/mysql/2.8.1/Mysql/Result
But you'll have to experiment a little to see what exactly they return as the documentation is, um, a little thin.
You should be able to get the column names out of row or st:
http://rubydoc.info/gems/mysql/2.8.1/Mysql/Stmt
but again, you'll have to experiment to figure out the API. Sorry, I don't have anything set up to play around with the MySQL API that you're using so I can't be more specific.
I realize that php programmers are all cowboys who think using a db layer is cheating, but you should really consider activerecord.