I'm working on a live server. I've updated to tip and it's caused problems: I need to revert back to a particular changeset (388) where things were OK.
I have no changes of any value on the server, the local changeset does not matter at all. In fact I actually want to kill any local accidental changes or merges so as not to confuse things.
How do I revert to a particular changeset and kill any local changes? Is it something to do with:
hg revert
---- UPDATE ---
To clarify, what I would like to do is first revert everything locally to changeset 388, and then ensure that my local repo is in such a state that when I do
hg status
I get no output. Otherwise I have a nasty feeling that when I next pull the tip, there will be conflicts to deal with - which I want to avoid, because the local changes are of no value.
---- UPDATE ---
For anyone else in this situation, what eventually fixed it for me was:
rm -rf <repo_dir>
hg clone http://repository
hg update -r 388
That will kill all your local changes, so proceed with caution (but that's what I wanted in this case).
Just use the command below, to get to a revision.
hg revert -r REV
It's conflicting with --all.
To kill all local changes, --all should work.
hg revert --all
Don't use rollback. It's a irreversible procedure, so should be used with care.
EDIT
You can update with --clean option. That will discard any uncommitted change.
And then update to some changeset.
server:
- ..
- rev 386
- rev 387
- rev 388
- rev 389
clone to production
-- testing stuff, it doesn't work!
-- panic!
-- rev 390 (in panic)
-- rev 391 (in panic)
-- cool down, thinking, need to go back to 388
-- one way: hg update -C -rev 388 (to keep 390, 391)
-- other way: rm -rf dir (to discard 390, 391)
-- hg clone http://server/hg
-- cd dir
-- hg update 388
-- testing, now works
There is also a wonderful Purge extension. Very solid stuff, it deletes all untracked files from working directory.
I don't think it is really clear what you want but my interpretation would be hg update -C -rev 388 but you could equally well be after revert, or possibly (unlikely) even rollback. my answer to this question gives a good difference between update and revert
you really need to work out what you want to see in the working copy AND what you want the state of the history to be like to choose between them
Related
Let's say I have the following commit history:
A - newest
B
C - oldest
I have changed a file foo in B, but I want to move the change from B to A.
How can I do that with hg?
There are several different ways that I can think of. Both have some moderate user requirements (please make sure you have backed up or pushed to a non-publishing repository first).
1 ) Use histedit and amend (requires that each extensions be enabled).
- copy file you wish to move to a safe location
- run hg histedit and edit changeset b and restore file to its original state
- run hg histedit --continue to commit changes.
- copy file from safe location to repository
- run hg amend to append file to changeset A
2 ) Use split and histedit.
- run hg split -r b
- split out all but the file you wish to move into a new changeset
- create a new changeset onto of that containing the fie (give it a temporary description)
- run hg histedit
- move the temp change above A
- roll the temp change into A
3 ) Use hg-evolve uncommit / amend. While this is a somewhat advanced method, I much prefer this one myself.
- run hg update B
- run hg uncommit and select the file you wish to move.
- run hg evolve to correct the stack
- run hg update A
Note: if you get a warning about needing to use --clean use hg shelve before
running the update followed by hg unshelve afterwords.
- run hg amend to add file to change A
4 ) Use hg uncommit all contents of changesets A and B and then recommit using hg commit -i to reassemble the changesets with the desired content.
There are likely a number of other ways, but this is what came to me.
Here's a simplistic but functional approach, maybe for people not very experienced with some of the more advanced HG commands:
Make sure your working directory is clean (no changes).
hg update -r C
hg revert -r B
hg commit ... as needed, but leave out the change destined for A. This creates B'.
hg shelve ... store away the uncommitted changes
hg revert -r A
hg unshelve ... restore uncommitted changes, merging them into the workding directory
hg commit ... creates C'.
hg strip -r B ... (optional!)
(where it says -r A that means use the revision # corresponding to A)
Explanation: we just create two (or more) entirely new changesets and then delete the originals (which is optional).
We're using revert basically to mean "copy from some changeset to the working directory" which I find is very handy in many circumstances.
After these operations -- but prior to using strip -- the history would look like:
*
|
A A'
| |
B B'
|/
C
and strip will just delete A, B.
I am working on BRANCH_A. I want to move the last 50 commits on this branch to a new branch BRANCH_B and revert BRANCH_A to the previous commit before these. What is the best method to achieve the same? Is it a good way?
Supposing that you just want BRANCH_A to be at the state of "HEAD - 50 commits" and you do not care if those commits appear in the history, then here is a simple solution:
For having all the commits on a new branch BRANCH_B you can simply create this branch while at the HEAD of BRANCH_A:
$ hg branch BRANCH_B
For restoring a previous state on BRANCH_A you can switch back to the HEAD of BRANCH_A, and commit a new changeset that will undo all the ones you do not want, this is done with hg backout:
$ hg update BRANCH_A
$ hg log -r 'branch(BRANCH_A) and head()~50 and not merge()'
$ hg backout -r 'branch(BRANCH_A) and head()~50 and not merge()'
$ hg commit -m"removed from .. to .."
You might have conflicts if changes happen in similar zones.
If you do want to rewrite history, you can either use the rebase or convert extensions to change names, remove commits etc. It all depends if you are working only locally or if you need to push to a server which is used by other people as well (in which case it is not advised to rewrite history).
Without editing history, simply:
Close the tip of BRANCH_A.
Create a named BRANCH_B off the closed tip of BRANCH_A.
Check in new commits to BRANCH_A starting from the node before the 50 commits.
I'm moving a build process to use mercurial and want to get the working directory back to the state of the tip revision. Earlier runs of the build process will have modified some files and added some files that I don't want to commit, so I have local changes and files that aren't added to the repository.
What's the easiest way to discard all that and get a clean working directory that has the latest revision?
Currently I'm doing this:
hg revert --all
<build command here to delete the contents of the working directory, except the .hg folder.>
hg pull
hg update -r MY_BRANCH
but it seems like there should be a simpler way.
I want to do the equivalent of deleting the repo, doing a fresh clone, and an update. But the repo is too big for that to be fast enough.
Those steps should be able to be shortened down to:
hg pull
hg update -r MY_BRANCH -C
The -C flag tells the update command to discard all local changes before updating.
However, this might still leave untracked files in your repository. It sounds like you want to get rid of those as well, so I would use the purge extension for that:
hg pull
hg update -r MY_BRANCH -C
hg purge
In any case, there is no single one command you can ask Mercurial to perform that will do everything you want here, except if you change the process to that "full clone" method that you say you can't do.
hg up -C
This will remove all the changes and update to the latest head in the current branch.
And you can turn on purge extension to be able to remove all unversioned files too.
To delete untracked on *nix without the purge extension you can use
hg pull
hg update -r MY_BRANCH -C
hg status -un|xargs rm
Which is using
update -r --rev REV revision
update -C --clean discard uncommitted changes (no backup)
status -u --unknown show only unknown (not tracked) files
status -n --no-status hide status prefix
hg status will show you all the new files, and then you can just rm them.
Normally I want to get rid of ignored and unversioned files, so:
hg status -iu # to show
hg status -iun0 | xargs -r0 rm # to destroy
And then follow that with:
hg update -C -r xxxxx
which puts all the versioned files in the right state for revision xxxx
To follow the Stack Overflow tradition of telling you that you don't want to do this, I often find that this "Nuclear Option" has destroyed stuff I care about.
The right way to do it is to have a 'make clean' option in your build process, and maybe a 'make reallyclean' and 'make distclean' too.
If you're looking for a method that's easy, then you might want to try this.
I for myself can hardly remember commandlines for all of my tools, so I tend to do it using the UI:
1. First, select "commit"
2. Then, display ignored files. If you have uncommitted changes, hide them.
3. Now, select all of them and click "Delete Unversioned".
Done. It's a procedure that is far easier to remember than commandline stuff.
There is a commit that just didn't work, so I want to abandon it without deleting it from history.
I have updated from an earlier revision and committed, thus creating a new head.
I don't have branches, I don't want branches, I just want to simply go on with the new head exactly as it is, nothing fancy, no merge, no worries, just go on forgetting the previous one.
I can't seem to find how to do that, and I'm starting to believe it can't be done. All I find is stuff about branches, or stuff about merging.
Update your repository to the head with the revision that you want to forget about, then use hg commit --close-branch to mark that (anonymous) branch as closed. Then update to the head of the branch that you do want, and continue working.
You can still see the closed branch if you use the -c option to hg heads, but it won't show up by default and hg merge will know not try to merge with the closed head.
You will need to use hg push --force the first time you push this closed head to another repository since you are actually create additional heads in the remote repository when you push. So tell Mercurial that this is okay with --force. People who pull the closed head wont be bothered by any warnings.
I know you don't want to work with branches at this stage, but that's exactly what you've done. When you went back to an earlier version and committed something that worked you created a branch - an unnamed branch, but a branch all the same.
There's no problem with just carrying on just as you are and not worrying about having multiple heads, but if you want to tidy things up so you don't accidentally pick the wrong head one time then you can kill off the old branch.
There's a good section in the Mercurial documentation that takes you through a number of options around Pruning Dead Branches.
I think the best option for you is to mark the old branch as "closed". If your old head is revision "123" then:
hg update -r 123
hg commit --close-branch -m 'Closing old branch'
hg update -C default
First of all, type:
hg heads
Imagine, you have three heads listed:
changeset: 223:d1c3deae6297
user: Your name <your#email.com>
date: Mon Jun 09 02:24:23 2014 +0200
summary: commit description #3
changeset: 123:91c5402959z3
user: Your name <your#email.com>
date: Sat Dec 23 16:05:38 2013 +0200
summary: commit description #2
changeset: 59:81b9804156a8
user: Your name <your#email.com>
date: Sat Sep 14 13:14:40 2013 +0200
summary: commit description #1
Let's say, you want to keep the last head active (223) and close the rest.
You would then do as follows:
Close head #59
hg up -r 59
hg ci --close-branch -m "clean up heads; approach abandoned"
Close head #123
hg up -r 123
hg ci --close-branch -m "clean up heads; approach abandoned"
Commit the changes
hg push
Don't forget to switch to the right head at the end
hg up -r 223
And you're done.
You want to use hg backout. This removes the changes made by the changeset from any child changeset.
Check this out for a good explanation.
Mercurial Backout
An alternative to closing or stripping the unwanted branch would be to merge it in a way that totally discards its effects, but leaves it in history. This approach will allow those unwanted changes to propagate in a push - so only use this if that is the intended effect.
Let's say the changeset history looks like this:
1-2-3-4-5-6
\
7-8-*
and it is 5 and 6 which are no longer wanted.
You can do this:
hg up 8
hg merge -r 6 -t :local
hg commit ...
which will create this:
1-2-3-4-5-6
\ \
7-8-9-*
The update to 8 ensures you are working at the desired head in history, which you want to keep.
The -t :local instructs hg to use the merge "tool" called local which tells it to ignore changes from the other branch, i.e., the one NOT represented by the current working folder state. More info.
Thus the unwanted changes in 5 and 6 are preserved in history but do not affect anything more recent.
Both Niall's and Nick's answers are straight on. Because I find myself creating lots of dangling heads, I ended up writing an alias to close heads more easily. By adding this to your .hgrc:
[alias]
behead = !REV=$($HG id -i); $HG update $# -q && $HG ci --close-branch -m "Closing dead head" && $HG update $REV -q
(if you already have an [alias] section, you can append to it instead)
You can now close a head in one single-command (and without having to update to a different changeset manually) like this:
$ hg behead 123
Note: the alias takes advantage of the fact that Mercurial aliases can be shell commands. This means that this will probably only work on UNIX, not on Windows.
This is a use case for the Evolve extension. It's currently not bundled with Mercurial, so it is technically a third party extension. But it's being used quite heavily by a bunch of people, including Mercurial developers, is being very actively developed, and isn't going anywhere.
With the Evolve extension, you simply do
hg prune -r revname
and get on with your life. The cset will still be there, but obsoleted. It won't be visible unless you pass the --hidden option to Mercurial commands, and by default won't be pushed to remote repositories. Though I think you can force it if you really want to.
If the cset you are pruning has ancestors you want to keep, then you'll have to run hg evolve to rebase those changesets. hg evolve will do so automatically. Otherwise, you don't have to do anything.
You may clone your corrupted repo to a new one without cloning that unwanted head. Then remove old repository, move newly created clone to the original place and continue working with it. This will take some time, but you'll get a perfectly clean repository without a sign of that unwanted revision.
hg clone --rev myGoodResition myDirtyRepo myCleanRepo
I have run into this issue many times when I want to behead a head that was created in error. I always want to see it disappear off the face of the Earth.
On your local copy, get the latest and then:
Find the beginning of a head you want to strip (where a new neck starts to branch off), get the revision number
Strip it.
Source: TipsAndTricks.
Source: PruningDeadBranches#Using_strip.
hg --config extensions.hgext.mq= strip -n <rev>
Make a trivial file update (add a whitespace to a file), commit and push.
Your repo should now have the head stripped. The last step is important as stripping doesn't create any changes you can push to your central repository. Without the last step you only have stripped the head locally.
So I keep making a silly mistake in Mercurial. Often times, I'll start work without doing an "hg pull" and an "hg update." When I try to push my changes, I get an error.
Is there any way to delete my local commits so I can avoid creating multiple heads, branches, etc? I just want to delete my local commits, merge my changes with the tip, and then re-commit. Sounds simple, right? I can't seem to find any way to easily delete local commits so I can cleanly merge with the tip.
Again, I'm only trying to delete local commits made with "hg ci". I don't want to modify files, revert, etc.
Enable the "strip" extension and type the following:
hg strip #changeset# --keep
Where #changeset# is the hash for the changeset you want to remove. This will remove the said changeset including changesets that descend from it and will leave your working directory untouched. If you wish to also revert your committed code changes remove the --keep option.
For more information, check the Strip Extension.
If you get "unkown command 'strip'" you may need to enable it. To do so find the .hgrc or Mercurial.ini file and add the following to it:
[extensions]
strip =
Note that (as Juozas mentioned in his comment) having multiple heads is normal workflow in Mercurial. You should not use the strip command to battle that. Instead, you should merge your head with the incoming head, resolve any conflicts, test, and then push.
The strip command is useful when you really want to get rid of changesets that pollute the branch. In fact, if you're in this question's situation and you want to completely remove all "draft" change sets permanently, check out the top answer, which basically suggests doing:
hg strip 'roots(outgoing())'
If you are using Hg Tortoise just activate the extension "strip" in:
File/Settings/Extensions/
Select strip
Then select the bottom revision from where you want to start striping, by doing right click on it, and selecting:
Modify history
Strip
Just like this:
In this example it will erase from the 19th revision to the last one commited(22).
Modern answer (only relevant after Mercurial 2.1):
Use Phases and mark the revision(s) that you don't want to share as secret (private). That way when you push they won't get sent.
In TortoiseHG you can right click on a commit to change its phase.
Also: You can also use the extension "rebase" to move your local commits to the head of the shared repository after you pull.
As everyone else is pointing out you should probably just pull and then merge the heads, but if you really want to get rid of your commits without any of the EditingHistory tools then you can just hg clone -r your repo to get all but those changes.
This doesn't delete them from the original repository, but it creates a new clone that doesn't have them. Then you can delete the repo you modified (if you'd like).
I came across this problem too. I made 2 commit and wanted to rollback and delete both commits.
$ hg rollback
But hg rollback just rolls back to the last commit, not the 2 commits. At that time I did not realize this and I changed the code.
When I found hg rollback had just rolled back one commit, I found I could use hg strip #changeset#. So, I used hg log -l 10 to find the latest 10 commits and get the right changeset I wanted to strip.
$ hg log -l 10
changeset: 2499:81a7a8f7a5cd
branch: component_engine
tag: tip
user: myname<myname#email.com>
date: Fri Aug 14 12:22:02 2015 +0800
summary: get runs from sandbox
changeset: 2498:9e3e1de76127
branch: component_engine
user: other_user_name<name#email.com>
date: Mon Aug 03 09:50:18 2015 +0800
summary: Set current destination to a copy incoming exchange
......
$ hg strip 2499
abort: local changes found
What does abort: local changes found mean? It means that hg found changes to the code that haven't been committed yet. So, to solve this, you should hg diff to save the code you have changed and hg revert and hg strip #changeset#. Just like this:
$ hg diff > /PATH/TO/SAVE/YOUR/DIFF/FILE/my.diff
$ hg revert file_you_have_changed
$ hg strip #changeset#
After you have done the above, you can patch the diff file and your code can be added back to your project.
$ patch -p1 < /PATH/TO/SAVE/YOUR/DIFF/FILE/my.diff
You can get around this even more easily with the Rebase extension, just use hg pull --rebase and your commits are automatically re-comitted to the pulled revision, avoiding the branching issue.
hg strip is what you are looking for. It's analogous of git reset if you familiar with git.
Use console:
You need to know the revision number. hg log -l 10. This command shows the last 10 commits. Find commit you are looking for. You need 4 digit number from changeset line changeset: 5888:ba6205914681
Then hg strip -r 5888 --keep. This removes the record of the commit but keeps all files modified and then you could recommit them.
(if you want to delete files to just remove --keep hg strip -r 5888
If you are familiar with git you'll be happy to use histedit that works like git rebase -i.
[Hg Tortoise 4.6.1]
If it's recent action, you can use "Rollback/Undo" action (Ctrl+U).
In addition to Samaursa's excelent answer, you can use the evolve extension's prune as a safe and recoverable version of strip that will allow you to go back in case you do anything wrong.
I have these alias on my .hgrc:
# Prunes all draft changesets on the current repository
reset-tree = prune -r "outgoing() and not obsolete()"
# *STRIPS* all draft changesets on current repository. This deletes history.
force-reset-tree = strip 'roots(outgoing())'
Note that prune also has --keep, just like strip, to keep the working directory intact allowing you to recommit the files.