I just ran into a problem.
I know these integers, $integers: 3,5,15,20.
I only want to select the rows from this following table where all comma separated INT's from the field NUMBERS are found.
TABLE: number_table
Uid Numbers
------------------------
1 3,5,15 OK, since all of NUMBERS are in $integers
2 5,15,20 OK, since all of NUMBERS are in $integers
3 3,4,5,15 NOT OK, since 4 is not found in $integers
4 2,15,20,25 NOT OK, since 2 and 25 is not found in $integers
Is it possible to do a "for-each" on a comma separated string or another way to do this SELECT?
UPDATE: It sounds like this is not possible. I will leave it here for little while. Just a hint. When searching for something in a comma separated string then MySQL provides the WHEERE something IN (comma separated string). What I What I look for is someway to traverse a comma separated string using MySQL but that might not be possible.
Something like this would do it (pseudocode):
SELECT * FROM number_table WHERE each_commaseparated_substring(Numbers , 'IN (3,5,15,20)')
It should NOT be comma separated fields.
It must be rows in the related table.
I haven't tried this, and it's a bit ugly and quite possibly slow but you can try the following.
3,5,15,20
SELECT * FROM number_table
WHERE Numbers (LIKE '%,3,%' OR LIKE '%3,%') AND Numbers LIKE '%,5,%' AND Numbers LIKE '%,15,%' AND Numbers (LIKE '%,20,%' OR LIKE '%,20%')
You may be able to do something with REGEX. But at the very least you could use a stored procedure.
Updated for correctness
Maybe try with concate code using PHP and the implode() function.
Correct the short answer is no, but despite being non-normal data there are solutions that are ugly so not recommended. Specifically make a split string function and loop through each value with a stored procedure.
Can MySQL split a column?
Mysql string split
You could check that the number of commas is one less than the number of search terms found:
SELECT * FROM number_table
WHERE CHAR_LENGTH(Numbers) - CHAR_LENGTH(REPLACE(Numbers, ',', '')) = -1
+ (FIND_IN_SET( 3, Numbers) > 0)
+ (FIND_IN_SET( 5, Numbers) > 0)
+ (FIND_IN_SET(15, Numbers) > 0)
+ (FIND_IN_SET(20, Numbers) > 0)
To create this from $integers using PHP:
$sql = "SELECT * FROM number_table
WHERE CHAR_LENGTH(Numbers) - CHAR_LENGTH(REPLACE(Numbers, ',', '')) = -1";
foreach ($integers as $i) $sql .= " + (FIND_IN_SET($i, Numbers) > 0)";
Related
I have this column in a table which is comma delimited to separate the values.
Here's the sample data:
2003,2004
2003,2005
2003,2006
2003,2004,2005
2003,2007
I want to get all data that contains only 1 comma.
I've been playing around with the '%' and '_' wildcards, but I can't seem to get the results I need.
SELECT column FROM table WHERE column like '%_,%'
Replace the , with '' empty set then take the original length less the replaced length. if 1 then only 1 comma if > 1 then more than 1 comma.
The length difference would represent the number of commas.
Length(column) - length(Replace(column,',','')) as NumOfCommas
or
where Length(column) - length(Replace(column,',','')) =1
While this may solve the problem, I agree with what others have indicated. Storing multiple values in a single column in a RDBMS is asking for more trouble. Better to normalize the data and get it to at least 3rd Normal form!
You can also use find_in_set() method which searches a value in comma separated list, by picking the last value of column using substring_index we can then check result of find_in_set should be 2 so that its the second and last value from list
select *
from demo
where find_in_set(substring_index(data,',',-1),data) = 2
Demo
Maybe another solution is to use regular expression in your case it can look like this ^[0-9]{4},[0-9]{4}$ :
SELECT * FROM MyTable WHERE ColName REGEXP '^[0-9]{4},[0-9]{4}$'
Or if you want all non comma one or more time :
SELECT * FROM MyTable WHERE ColName REGEXP '^[^,]*,[^,]*$'
My table contains some columns with ;-separated numbers like this :
1;2;43;22;20;12
and so on. It's also possible there's only 1 number in this column like 110, or 2 numbers like this 110;143
I want to select the rows that contain a certain number in this column. The number is in a variable $search_var.
Let's say I need to search for the number 1 in my column. If I use a select with like statement like so :
"SELECT * FROM Table WHERE ids LIKE '%".$search_var."%'"
I get all results containing '1' and not only '1', so I also get 11, 14, 110, 1999 etc.
I think I need to use some sort of regex-statement but I'm lost here... Who can help ?
You might not need regex for this
Set #YourNUmber := 110;
SELECT *
FROM Table
WHERE ';' + ids + ';' LIKE '%;'+ #yourNumber + ';%'
This guarantees there are always ; surrounding all the numbers.
This is formatted for SQL Server. The variable syntax and wildcards might be different if you are using something else.
EDIT:
Thanks #FélixGagnon-Grenier for the suggestions. I think either of these two will work. See here for a SQL Fiddle example
SELECT *
FROM T
WHERE concat(';',ids,';') LIKE concat('%;', #YourNumber , ';%');
SELECT *
FROM T
WHERE LOCATE(concat(';', #YourNumber , ';'),concat(';',ids,';'))>0
Try this solution if you're using SQL Server. This searches for the number where adjcent characters are not numbers:
SELECT * FROM Table WHERE ids LIKE '%[^0-9]".$search_var."[^0-9]%'
I have a field of comma-separated lists in MySQL:
id field1
1 aa,bb,cc
2 aa
I would like to count the total number of elements, with overlap. In this case that would be 4: aa appears twice and so should be double-counted.
It would suffice to count the number of commas in each field and add 1, since my lists do not have quotes or escaping.
Let's try that:
select count(field1) + sum(CHAR_LENGTH(field1) - CHAR_LENGTH(REPLACE(field1,',','')))
from Table1;
Why do you use comma separated string?
Databases aren't made for that.
You have 2 possibilities :
- make a loop in a stored procedure,
- count it into the code which call this MySQL query...
My table column has rows like this 1001, 1002, 1003 and so on separated by commas. There may be 1 or more comma separated values in each column. I need the total count of these comma separated values in the table. For example if my table has 2 rows one having 1001, 1002, 1003, 1004 and another with 1001, 1005 the output i should get is 6 i.e. 4+2. Kindly assist
there is no function in mysql to count char occurences. but you can replace every comma with nothing. and then you calculate the difference of lenghts which will give you the number of commas, which is one less than the number of values.
select
( LENGTH(col1) - LENGTH(REPLACE(col1, ',', '')) + 1 )
+ ( LENGTH(col2) - LENGTH(REPLACE(col2, ',', '')) + 1 )
AS valCount
from T;
(didn't test that explicitely but at least something very similar to that will do the job.)
replace()
length()
Try:
SELECT SUM(LEN(ColumnName) - LEN(REPLACE(ColumnName, ',', ''))) FROM TableName
This is one of those tasks that'd be much, much easier in the server-side script accessing your database than the database itself. Assuming you've already assigned the comma-separated strings to an array (where $array[1] is equal to the string from row 1:
$array = array("1001, 1002, 1003, 1004", "1001, 1005"); // assigned from database
foreach($array as $k => $v){
$numbersInString[$k] = count(explode(', ', $v));
}
echo implode(' + ',$numbersInString);
This is possible, with creative solutions (such as that from Raffael1984), in MySQL, but seems to much more easily, and concisely, implemented in PHP.
References:
count().
explode().
implode().
foreach().
Did you try using the count() function? You can specify which rows if you need to.
.row[COUNT(name)]
in your query. What does your table look like? I might be able to help more if I know what it looks like
I know it is not an appropriate technique to have a structure of MySQL table as such, but I have to work with such. The problem is, that the field in table has value with comma seperated integers, like "1,3,5,7,10" and I want the query to return rows, in which field has a to the query passed number in it, like:
SELECT * FROM `table` WHERE '5' IN (`field_in_table`)
However, it does not work, if, in this case, '5' is not the first number in the field.
Any advises, how to solve that?
Thanks in advance,
Regards,
Jonas
Have a look at
FIND_IN_SET
Returns a value in the range of 1 to N
if the string str is in the string
list strlist consisting of N
substrings. A string list is a string
composed of substrings separated by
“,” characters. If the first argument
is a constant string and the second is
a column of type SET, the
FIND_IN_SET() function is optimized to
use bit arithmetic. Returns 0 if str
is not in strlist or if strlist is the
empty string.
You could use WHERE field_in_table LIKE '%5%' instead.
Of course, the problem would be, '1,59,98' would return as wel.
SELECT * FROM table WHERE field_in_table LIKE '%5'");
should work
You could try
SELECT *
FROM table
WHERE '%,5,%' LIKE field_in_table OR
'%,5' LIKE field_in_table OR
'5,%' LIKE field_in_table;
A better approach might be to use regular expressions, a subject on which I am not an authority.
SELECT *
FROM table
WHERE FIELD LIKE '%,5,%' OR
FIELD LIKE '5,%' OR
FIELD LIKE '%,5'