mysql converting multiple rows into columns in a single row - mysql

Question

i have a details table with columns:
user_id int
code int
value int
And i want to build a summary table that looks like:
user_id int
valueA int
valueB int
In the details table, valueA would correspond to say, code 5, and valueB would correspond to say, code 6, so i'm looking for something like:
insert into summary (user_id,valueA,valueB) VALUES ( SELECT ??? from details );
The problem of course is that i'm looking at multiple rows from the "details" table to populate one row in the "summary" table.
Eg, if i had the following rows in details:
1 5 100
1 6 200
2 5 1000
2 6 2000
I want to end up with the following in the summary table:
1 100 200
2 1000 2000
Any ideas?

Answer 1

MySQL doesn't have PIVOT/UNPIVOT syntax, which leaves you to use a combination of GROUP BY and CASE expressions:
INSERT INTO SUMMARY
(user_id,valueA,valueB)
SELECT d.user_id,
MAX(CASE WHEN d.code = 5 THEN d.value ELSE NULL END),
MAX(CASE WHEN d.code = 6 THEN d.value ELSE NULL END),
FROM DETAILS d
GROUP BY d.user_id

Answer 2

insert into summary (user_id,valueA,valueB)
SELECT a.user_id, a.value, b.value
from details a
join details b on a.user_id = b.user_id
WHERE a.code = 5 and b.code = 6;
beware: you will end up with multiple summary columns if user_id+code is not unique.
EDIT:
insert into summary (user_id,valueA,valueB)
select u.user_id, ifnull(a.value,0), ifnull(b.value,0)
from (select distinct user_id from details /* where code in (5,6) */) u
left join details a on a.user_id = u.user_id and a.code = 5
left join details b on b.user_id = u.user_id and b.code = 6

Answer 3

If you have a manageable set of codes (say just 5 and 6) you could do something like this:
SELECT details.user_id, code5.value, code6.value
FROM details JOIN
(SELECT user_id, value FROM details WHERE code = 5) AS code5 USING(user_id)
JOIN
(SELECT user_id, value FROM details WHERE code = 6) AS code6 USING(user_id);
You may need to modify your JOINs depending on if your codes are not required as 1 to 1 relationship (i.e. LEFT JOINs).
If you have a large set of codes, I would look into a cursor runs a similar query above over a result set of your codes or using a different technology, (i.e. PHP script).