I'm trying to split an HTML document into its head and body:
my #contentsArray = split( /<\/head>/is, $fileContents, 1);
if( scalar #contentsArray == 2 ){
$bodyContents = $dbh->quote(trim($contentsArray[1]));
$headContents = $dbh->quote(trim($contentsArray[0]) . "</head>");
}
is what i have. $fileContents contains the HTML code. When I run this, it doesn't split. Any one know why?
The third parameter to split is how many results to produce, so if you want to apply the expression only once, you would pass 2.
Note that this does actually limit the number of times the pattern is used to split the string (to one fewer than the number passed), not just limit the number of results returned, so this:
print join ":", split /,/, "a,b,c", 2;
outputs:
a:b,c
not:
a:b
sorry, figured it out. Thought the 1 was how many times it would find the expression not limit the results. Changed to 2 and works.
Related
I had the task to code the following:
Take a list of integers and returns the value of these numbers added up, but only if they are odd.
Example input: [1,5,3,2]
Output: 9
I did the code below and it worked perfectly.
numbers = [1,5,3,2]
print(numbers)
add_up_the_odds = []
for number in numbers:
if number % 2 == 1:
add_up_the_odds.append(number)
print(add_up_the_odds)
print(sum(add_up_the_odds))
Then I tried to re-code it using function definition / return:
def add_up_the_odds(numbers):
odds = []
for number in range(1,len(numbers)):
if number % 2 == 1:
odds.append(number)
return odds
numbers = [1,5,3,2]
print (sum(odds))
But I couldn’t make it working, anybody can help with that?
Note: I'm going to assume Python 3.x
It looks like you're defining your function, but never calling it.
When the interpreter finishes going through your function definition, the function is now there for you to use - but it never actually executes until you tell it to.
Between the last two lines in your code, you need to call add_up_the_odds() on your numbers array, and assign the result to the odds variable.
i.e. odds = add_up_the_odds(numbers)
I want to avoid importing different modules as that is mostly what I have found while looking online. I am stuck with this bit of code and I don't really know how to fix it or improve on it. Here's what I've got so far.
def avg(lst):
'''lst is a list that contains lists of numbers; the
function prints, one per line, the average of each list'''
for i[0:-1] in lst:
return (sum(i[0:-1]))//len(i)
Again, I'm quite new and this for loops jargon is quite confusing to me, so if someone could help me get it so the output of, say, a list of grades would be different lines containing the averages. So if for lst I inserted grades = [[95,92,86,87], [66,54], [89,72,100], [33,0,0]], it would have 4 lines that all had the averages of those sublists. I also am to assume in the function that the sublists could have any amount of grades, but I can assume that the lists have non-zero values.
Edit1: # jramirez, could you explain what that is doing differently than mine possible? I don't doubt that it is better or that it will work but I still don't really understand how to recreate this myself... regardless, thank you.
I think this is what you want:
def grade_average(grades):
for grade in grades:
avg = 0
for num in grade:
avg += num
avg = avg / len(grade)
print ("Average for " + str(grade) + " is = " + str(avg))
if __name__ == '__main__':
grades = [[95,92,86,87],[66,54],[89,72,100],[33,0,0]]
grade_average(grades)
Result:
Average for [95, 92, 86, 87] is = 90.0
Average for [66, 54] is = 60.0
Average for [89, 72, 100] is = 87.0
Average for [33, 0, 0] is = 11.0
Problems with your code: the extraneous indexing of i; the use of // to truncate he averate (use round if you want to round it); and the use of return in the loop, so it would stop after the first average. Your docstring says 'print' but you return instead. This is actually a good thing. Functions should not print the result they calculate, as that make the answer inaccessible to further calculation. Here is how I would write this, as a generator function.
def averages(gradelists):
'''Yield average for each gradelist.'''
for glist in gradelists:
yield sum(glist) /len(glist)
print(list(averages(
[[95,92,86,87], [66,54], [89,72,100], [33,0,0]])))
[90.0, 60.0, 87.0, 11.0]
To return a list, change the body of the function to (beginner version)
ret = []
for glist in gradelists:
ret.append(sum(glist) /len(glist))
return ret
or (more advanced, using list comprehension)
return [sum(glist) /len(glist) for glist in gradelists]
However, I really recommend learning about iterators, generators, and generator functions (defined with yield).
I have a MySQL database whose keys are of this type:
A_10
A_10A
A_10B
A_101
QAb801
QAc5
QAc25
QAd2993
I would like them to sort first by the alpha portion, then by the numeric portion, just like above. I would like this to be the default sorting of this column.
1) how can I sort as specified above, i.e. write a MySQL function?
2) how can I set this column to use the sorting routine by default?
some constraints that might be helpful: the numeric portion of my ID's never exceeds 100,000. I use this fact in some javascript code to convert my ID's to strings concatenating the non-numeric portion with the (number + 1,000,000). (At the time I had not noticed the variations/subparts as above such as A_10A, A_10B, so I'll have to revamp that part of my code.)
The best way to achieve what you want is to store each part in its own column, and I would strongly recommend to change table structure. If it's impossible, you can try the following:
Create 3 UDFs which returns prefix, numeric part, and postfix of your string. For a better performance they should be native (Mysql, as any other RDMS, is not really good in complex string parsing). Then you can call these functions in ORDER BY clause or in trigger body which validates your column. In any case, it will work slower than if you create 3 columns.
No simple answer that I know of. I had something similar a while back but had to use jQuery to sort it. So what I did was first get the output into an javascript array. Then you may want to insert a zero padding to your numbers. Separate the Alpha from Nummerics using a regex, then reassemble the array:
var zarr = new Array();
for(var i=0; i<val.length; i++){
var chunk = val[i].match(/(\d+|[^\d]+)/g).join(',');
var chunks = chunk.split(",");
for(var s=0; s<chunks.length; s++){
if(isNaN(chunks[s]) == true)
zarr.push(chunks[s]);
else
zarr.push(zeroPad(chunks[s], 5));
}
}
function zeroPad(num,count){
var numZeropad = num + '';
while(numZeropad.length < count) {
numZeropad = "0" + numZeropad;
}
return numZeropad;
}
You'll end up with an array like this:
A_00100
QAb00801
QAc00005
QAc00025
QAd02993
Then you can do a natural sort. I know you may want to do it through straight MySQL but I am not to sure if it does natural sorting.
Good luck!
I have found many calculations here and some php examples and most are just over my head.
I found this example:
SELECT b.zip_code, b.state,
(3956 * (2 * ASIN(SQRT(
POWER(SIN(((a.lat-b.lat)*0.017453293)/2),2) +
COS(a.lat*0.017453293) *
COS(b.lat*0.017453293) *
POWER(SIN(((a.lng-b.lng)*0.017453293)/2),2))))) AS distance
FROM zips a, zips b
WHERE
a.zip_code = '90210' ## I would use the users submitted value
GROUP BY distance
having distance <= 5; ## I would use the users submitted value
But, I am having trouble understanding how to implement the query with my database.
It looks like that query has all I need.
However, I cannot even find/understand what b.zip_code actually is! (whats the b. and zips a, zips b?)
I also do not need the state in the query.
My mySQL db structure is like this:
ZIP | LAT | LONG
33416 | 26.6654 | -80.0929
I wrote this in attempt to return some kind of results (not based on above query) but, it only kicks out one zip code.
## Just for a test BUT, in reality I desire to SELECT a zip code WHERE ZIP = the users submitted zip code
## not by a submitted lat lon. I left off the $connect var, assume it's there.
my $set1 = (26.6654 - 0.20);
my $set2 = (26.6654 + 0.20);
my $set3 = (-80.0929 - 0.143);
my $set4 = (-80.0929 + 0.143);
my $test123 = $connect->prepare(qq{SELECT `ZIP` FROM `POSTAL`
WHERE `LAT` >= ? AND `LAT` <= ?
AND `LONG` >= ? AND `LONG` <= ?}) or die "$DBI::errstr";
$test123->execute("$set1","$set2","$set3","$set4") or die "$DBI::errstr";
my $cntr;
while(#zip = $test123->fetchrow_array()) {
print qq~$zip[$cntr]~;
push(#zips,$zip[$cntr]);
$cntr++;
}
As you can see, I am quite the novice so, I need some hand holding here with verbose explanation.
So, in Perl, how can I push zip codes into an array from a USER SUBMITTED ZIP CODE and user submitted DISTANCE in miles. Can be a square instead of a circle, not really that critical of a feature. Faster is better.
I'll tackle the small but crucial part of the question:
However, I cannot even find/understand what b.zip_code actually is! (whats the "b." and "zips a, zips b"?)
Basically, the query joins two tables. BUT, both tables being joined are in fact the same table - "zips" (in other words, it joins "zips" table to itself"). Of course, since the rest of the query needs to understand when you are referring to the first copy of the "zips" table and when to the second copy of the "zips" table, you are giving a table alias to each copy - to wit, "a" and "b"'.
So, "b.xxx" means "column xxx from table zips, from the SECOND instance of that table being joined".
I don't see what's wrong with your first query. You have latitude and longitude in your database (if I'm understanding, you're comparing a single entry to all others). You don't need to submit or return the state that's just part of the example. Make the first query work like this:
my $query = "SELECT b.zip_code,
(3956 * (2 * ASIN(SQRT(
POWER(SIN(((a.lat-b.lat)*0.017453293)/2),2) +
COS(a.lat*0.017453293) *
COS(b.lat*0.017453293) *
POWER(SIN(((a.lng-b.lng)*0.017453293)/2),2))))) AS distance
FROM zips a, zips b WHERE
a.zip_code = ?
GROUP BY distance having distance <= ?";
my $sth = $dbh->prepare($query);
$sth->execute( $user_submitted_zip, $user_submitted_distance );
while( my ($zip, $distance) = $sth->fetchrow() ) ) {
# do something
}
This won't be that fast, but if you have a small record set ( less than 30k rows ) it should be fine. If you really want to go faster you should look into a search engine such as Sphinx which will do this for you.
fetchrow_array returns a list of list references, essentially a two-dimensional array, where each row represents a different result from the database query and each column represents a field from the query (in your case, there is only one field, or column, per row).
Calling while ($test123->fetchrow_array()) will cause an infinite loop as your program executes the query over and over again. If the query returns results, then the while condition will be satisfied and the loop will repeat. The usual idiom would be to say something more like for my $row ($test123->fetchrow_array()) { ..., which will only execute the query once and then iterate over the results.
Each result is a list reference, and the zip code you are interested in is in the first (and only) column, so you could accumulate the results in an array like this:
my #zips = (); # for final results
for my $row ($test123->fetchrow_array()) {
push #zips, $row->[0];
}
or even more concisely with Perl's map statement:
my #zips = map { $_->[0] } $test123->fetchrow_array()
which does the same thing.
SELECT ica.CORP_ID, ica.CORP_IDB, ica.ITEM_ID, ica.ITEM_IDB,
ica.EXP_ACCT_NO, ica.SUB_ACCT_NO, ica.PAT_CHRG_NO, ica.PAT_CHRG_PRICE,
ica.TAX_JUR_ID, ica.TAX_JUR_IDB, ITEM_PROFILE.COMDTY_NAME
FROM ITEM_CORP_ACCT ica
,ITEM_PROFILE
WHERE (ica.CORP_ID = 1000)
AND (ica.CORP_IDB = 4051)
AND (ica.ITEM_ID = 1000)
AND (ica.ITEM_IDB = 4051)
AND ica.EXP_ACCT_NO = ITEM_PROFILE.EXP_ACCT_NO
I'm trying basically say since the exp account code is '801500' then the Name should return "Miscellaneous Medic...".
It seems as if what you are showing is not possible. Have you edited the data in the editor??? You are joining using ica.EXP_ACCT_NO = ITEM_PROFILE.EXP_ACCT_NO . Therefore, every entry with EXP_ACCT_NO = 801500, should also have the same COMDTY_NAME.
However, it could be the case that your IDs are not actually numbers and that they are strings with whitespace (801500__ vs 801500 ). But since you are not performing a left-outer join, it would also mean you have an entry in ITEM_PROFILE with the same whitespace.
You also need to properly normalize your table data (unless this is a view) but it still means you have erroneous data.
Try to perform the same query, but using the TRIM function to remove whitespace: https://stackoverflow.com/a/6858168/1688441 .
Example:
SELECT ica.CORP_ID, ica.CORP_IDB, ica.ITEM_ID, ica.ITEM_IDB,
ica.EXP_ACCT_NO, ica.SUB_ACCT_NO, ica.PAT_CHRG_NO, ica.PAT_CHRG_PRICE,
ica.TAX_JUR_ID, ica.TAX_JUR_IDB, ITEM_PROFILE.COMDTY_NAME
FROM ITEM_CORP_ACCT ica
,ITEM_PROFILE
WHERE (ica.CORP_ID = 1000)
AND (ica.CORP_IDB = 4051)
AND (ica.ITEM_ID = 1000)
AND (ica.ITEM_IDB = 4051)
AND trim(ica.EXP_ACCT_NO) = trim(ITEM_PROFILE.EXP_ACCT_NO);