hey i need a way to get a formated number from my column decimal(23,2) NOT NULL DEFAULT '0.00'
in php i could use this function number_format('1111.00', 2, ',', '.');
it would return 1.111,00 (in Germany we use , to define decimal numbers)
how would i do this in mysql? with string replaces?
http://blogs.mysql.com/peterg/2009/04/
In Mysql 6.1 you will be able to do FORMAT(X,D [,locale_name] )
As in
SELECT format(1234567,2,’de_DE’);
For now this ability does not exist, though you MAY be able to set your locale in your database my.ini check it out.
With performance penalty and if you need todo it only in SQL you can use the FORMAT function and 3 REPLACE :
After the format replace the . with another char for example #, then replace the , with a . and then the chararacter you choose by a , which lead you for your example to 1.111,00
SELECT REPLACE(REPLACE(REPLACE(FORMAT("1111.00", 2), ".", "#"), ",", "."), "#", ",")
You can use
SELECT round(123.4566,2) -> 123.46
FORMAT(X,D) Formats the number X to a format like '#,###,###.##', rounded to D decimal places, and returns the result as a string. If D is 0, the result has no decimal point or fractional part.
SELECT FORMAT(12332.123456, 4);
-> '12,332.1235'
Antonio's answer
CONCAT(REPLACE(FORMAT(number,0),',','.'),',',SUBSTRING_INDEX(FORMAT(number,2),'.',-1))
is wrong; it may produce incorrect results!
For example, if "number" is 12345.67, the resulting string would be:
'12.346,67'
instead of
'12.345,67'
because FORMAT(number,0) rounds "number" up if fractional part is greater or equal than 0.5 (as it is in my example)!
What you COULD use is
CONCAT(REPLACE(FORMAT(FLOOR(number),0),',','.'),',',SUBSTRING_INDEX(FORMAT(number,2),'.',-1))
if your MySQL/MariaDB's FORMAT doesn't support "locale_name" (see MindStalker's post - Thx 4 that, pal). Note the FLOOR function I've added.
At least as far back as MySQL 5.5 you can use format:
SELECT FORMAT(123456789.123456789,2);
/* produces 123,456,789.12 */
SELECT FORMAT(123456789.123456789,2,'de_DE');
/*
produces 123.456.789,12
note the swapped . and , for the de_DE locale (German-Germany)
*/
From the MySQL docs:
https://dev.mysql.com/doc/refman/5.5/en/string-functions.html#function_format
Available locales are listed elsewhere in the docs:
https://dev.mysql.com/doc/refman/5.5/en/locale-support.html
CREATE DEFINER=`yourfunctionname`#`%` FUNCTION `money`(
`betrag` DECIMAL(10,2)
)
RETURNS varchar(128) CHARSET latin1
LANGUAGE SQL
NOT DETERMINISTIC
CONTAINS SQL
SQL SECURITY DEFINER
COMMENT ''
return(
select replace(format(cast(betrag as char),2),',',"'") as betrag
)
will creating a MySql-Function with this Code:
select replace(format(cast(amount as char),2),',',"'") as amount_formated
You need this:
CONCAT(REPLACE(FORMAT(number,0),',','.'),',',SUBSTRING_INDEX(FORMAT(number,2),'.',-1))
Related
I am trying to search for a string in a simple JSON Array e.g.
'["Accounting","Administration & Office Support","Advertising, Arts & Media"]'
SELECT classification
FROM Skills.skills
WHERE JSON_EXTRACT(classification, '$[0]') = "Accounting";
This work and returns all rows with "Accounting" in position 0.
My understanding is if I were to use as wildcard '$[*]' then this would search all positions. However, this does not return any rows.
What JSON function should I use in this case?
You can use JSON_SEARCH to search the array for the value:
SELECT *
FROM skills
WHERE JSON_SEARCH(classification, 'one', 'Accounting') IS NOT NULL
You can also use JSON_CONTAINS, but you need to be careful to add double quotes around the string to make it a valid JSON scalar:
SELECT *
FROM skills
WHERE JSON_CONTAINS(classification, '"Accounting"')
Demo on db-fiddle
I have a MySQL 8 table with a column called "coordinates" of type "polygon".
I am trying to insert a set of coordinates into it, like so:
INSERT INTO contract (coordinates)
VALUES (POLYGON(
(34.786166422784426, 32.162676265661624),
(34.720248454034426, 32.01024096292725),
(34.816378825128176, 31.973162105505374),
(34.86993717473755, 32.1338371543335),
(34.786166422784426, 32.162676265661624))
)
which is giving me a "column count doesn't match value count at row 1" error.
Why is this? How do I properly format this query? And how can I explicitly pass an ESRI with it?
This, by the way, works fine:
INSERT INTO contract (coordinates, smart_contract_version_id)
VALUES (ST_GeomFromText('POLYGON(( 34.786166422784426 32.162676265661624 , 34.720248454034426 32.01024096292725 , 34.816378825128176 31.973162105505374 , 34.86993717473755 32.1338371543335 , 34.786166422784426 32.162676265661624 ))', 4326), 1)
You are inserting wrong .. You don't need the sets of parens .. Note double parens are INTENTIONAL .. AND the X / Y is denoted by a space .. Not a comma. If it works without the "double parens" It's because you don't have any insets -- "holes" etc ..
POLYGON((
34.786166422784426 32.162676265661624,
34.720248454034426 32.01024096292725,
34.816378825128176 31.973162105505374,
34.86993717473755 32.1338371543335,
34.786166422784426 32.162676265661624
))
i have one question with regard to MYSQL. I want to create a function that is able to check whether an Input is given in a specific format.
The output should be in the following shape:
***x x (a) n (n) (n) (n)
with :
x = letters and numbers
n = numbers
a = letters
brackets = optional Values***
So my Solution until now is this (User 'Nick' helped me):
CREATE FUNCTION validate_number(testnumber VARCHAR(7))
RETURNS INT
DETERMINISTIC
RETURN testnumber REGEXP '^[[:alnum:]]{2}[[:alpha:]]?[[:digit:]]{1,4}$';
And this approach works for most cases.
But when i enter a value that exceeds the possible amount of elements (max elements = 7) i get no result.
example:
validate_number('00A00002345')
=> no result.
Do you guys have an idea what the problem is?
Thank you very much in advance.
you are actually pointing out the solution of the problem :)
just change VARCHAR(7) to something bigger VARCHAR(2000)
When I run your function, I get the error:
select validate_number('00A00002345')
Data too long for column 'testnumber' at row 1
You can add a length to the varchar.
CREATE FUNCTION validate_number (
in_testnumber VARCHAR(32000)
)
Or, use text:
CREATE FUNCTION validate_number (
in_testnumber text
)
RETURNS INT
DETERMINISTIC
BEGIN
RETURN (in_testnumber REGEXP '^[[:alnum:]]{2}[[:alpha:]]?[[:digit:]]{1,4}$');
END;
Could someone please help me with this one?
So I need to write a user input function in which I need to concatenate two strings. When outputted, there must be a space between the two strings, note there is not a space in the two strings when inputting them. Test functions with the following, String 1: Spring, String 2: Break!
This is my solution:
create function concatenate(X CHAR,Y CHAR)
Returns CHAR(50)
Return concat(X, ' ', Y);
select concatenate('Spring','Break')
However, the problem is that sql only returns the first letter of each word, which is "S B". But I want it to be "Spring Break"
Any ideas on this one? Helps are very appreciated
Supply a length for the input parameters as well:
create function concatenate(X CHAR(24),Y CHAR(24))
Returns CHAR(50)
Return concat(X, ' ', Y);
select concatenate('Spring','Break')
You need to define the size when you declare the argument.
create function con(X char(50), Y char(50))
returns char(100)
You have to specify the size of CHAR(), otherwise it will use the default CHAR(1), and you can't get want you want.
eg:
create function hello(x char(10),y char(10))
returns char(30) deterministic
return concat(x,' ',y)`
select hello('Hello','World');
Hello World
On a new project I work on I have data in CSV format to import into a mysql table. One of the columns is a price field which stores currency in the european format ie. 345,83.
The isssue I have is storing this decimal seperator. In most European currencies the decimal seperator is "," but when I try to insert a decimal number into a field (ex. 345,83), I get the following error: "Data truncated for column 'column_name' at row 'row #'". If I use '.' instead of ',' it works fine. Could you please help me with, how to store this format in mysql?
you can store it as a regular decimal field in the database, and format the number european style when you display it
edit: just added an example of how it might be achieved
$european_numbers = array('123.345,78', '123 456,78', ',78');
foreach($european_numbers as $number) {
echo "$number was converted to ".convert_european_to_decimal($number)."\n";
// save in database now
}
function convert_european_to_decimal($number) {
// i am sure there are better was of doing this, but this is nice and simple example
$number = str_replace('.', '', $number); // remove fullstop
$number = str_replace(' ', '', $number); // remove spaces
$number = str_replace(',', '.', $number); // change comma to fullstop
return $number;
}
Use number_format or money_format, it's pretty much what you preffer.
It's worse than you think. The number 1234.56 may be written in Europe as:
1234,56
1 234,56 (space as a group separator)
1.234,56 (dot as a group separator)
In .net the number parser can works according to a given culture, so if you know the format it does the hard work for you. I'm sure you can find a PHP equivalent, it'd save you a lot of trouble.
You could import the currency field into a VARCHAR column and then copy this column into a DECIMAL column while replacing the , by a . in all rows using MySQL string-manipulation-functions.
UPDATE <<table>>
SET <<decimal-currency-col>> = REPLACE(<<varchar-currency-col>>, ',', '.');
Some data types do not have a direct
correlation between SQL Server or
Access and MySQL. One example would be
the CURRENCY data type: MySQL does not
(yet) have a CURRENCY data type, but
creating a column with the definition
DECIMAL(19,4) serves the same purpose.
While MSSQL defaults to Unicode
character types such as nCHAR and
nVARCHAR, MySQL does not so tightly
bind character sets to field types,
instead allowing for one set of
character types which can be bound to
any number of character sets,
including Unicode.
from http://dev.mysql.com/tech-resources/articles/migrating-from-microsoft.html
You could also consider multiplying it by 100 and storing it as INT.
Before inserting the price to the DB:
$price = (int)$price*100;
After receiving price from the DB:
$price = number_format($price, 2, ',', ' ');
Try replacing the "," with "."?
$price = str_replace(",", ".", $price);