I use similar queries (10) as following queries (modified) to find sum
SELECT sum(amount) AS amount
FROM `students`
WHERE sex='M'
&& name in ('salil', 'anil', 'gaikwad')
...and:
SELECT sum(amount) AS amount
FROM `students`
WHERE sex='M'
&& name in ('salil1', 'anil1', 'gaikwad1')
i want to make a single query of the above 10 queries. is it possible?
You can use UNION
SELECT 'subset1', sum(amount) AS amount FROM students WHERE sex='M' and name in ('salil', 'anil', 'gaikwad')
UNION
SELECT 'subset2', sum(amount) AS amount FROM students WHERE sex='M' and name in ('salil1', 'anil1', 'gaikwad1')
However, you probably query these sets of students for a reason, perhaps anil, salil and gaikwad are one group of students. If so, you should reflect this in the database structure, not in your code.
You could add a field 'SUbset' or 'Group' or whatever that is, to students table, so it looks like this:
name group_id
salil 1
anil 1
gaikwad 1
salil1 2
...
Then you can do
select group_id, sum(amount) from students group by group_id
Try something like this
SELECT sum(amount) AS amount
FROM students INNER JOIN
(SELECT 'salil%' Val UNION SELECT 'anil%' UNION SELECT 'gaikwad%') s ON students.NAME LIKE s.Val
WHERE sex='M'
This allows you to use the values in the second Table to join with LIKE.
Related
I am trying to merge two queries into one, but UNION is not working for me.
Here is the code:
SELECT
Customer_A,
Activity,
Customer_P,
Purchase
FROM (
SELECT
buyer_id as Customer_A,
COUNT(buyer_id) As Activity
FROM
customer_info_mxs
GROUP BY buyer_id
UNION ALL
SELECT
buyer_id as Customer_P,
SUM(purchase_amount) As Purchase
FROM
customer_info_mxs
GROUP BY buyer_id
)sub
I expect to have 4 columns as a result, but I get 2 instead (Customer_A) and(Activity).
If the query is supposed to return a list of customers, their number of purchases, and the total amount they’ve spent, then you can use a single query like this:
SELECT mxs.buyer_id as Customer,
COUNT(mxs.purchase_id) As Activity,
SUM(mxs.purchase_amount) As Purchases
FROM customer_info_mxs mxs
GROUP BY mxs.buyer_id;
Otherwise, your first subquery will always be a buyer_id and a value of 1.
Be sure to change purchase_id to whatever the unique id is for each purchase if you wish to see that number.
I think there is some confusion about the union statement. The union statement returns a row set that is the sum of all of the 'unioned' queries; since these queries have only 2 columns, the combined output only has two columns. The fact that the columns have different names is irrelevant. The column names in the output are being applied from the first query of the union.
One option is to just do
select buyer_id, count(buyer_id), sum(purchase_amount) from customer_info_mxs group by buyer_id
From your question, it looks like you are trying to do a pivot, turning some of the rows into additional columns. That could be done with ... some difficulty.
i read your comment,
'main goal is to creat a dataset in which returns 5 columns as: Customer_A, Activity (top 100), customer_P, Purchase(top 100), inner join of activity and purchase'
please try this query
SET #row_number = 0, #row_number2 = 0;
SELECT t1.Customer_A,t1.Activity, t2.Customer_P, t2.Purchase
from (
SELECT (#row_number:=#row_number + 1) AS n, t.Customer_a, t.Activity
from (
select buyer_id as Customer_A,COUNT(buyer_id) As Activity
FROM customer_info_mxs
GROUP BY buyer_id
order by Activity desc
Limit 100
)t
) t1
left join (
SELECT (#row_number2:=#row_number2 + 1) AS n,
FROM (
select buyer_id as Customer_P, SUM(purchase_amount) Purchase
FROM customer_info_mxs
GROUP BY buyer_id
order by Purchase desc
Limit 100
)t
) t2 on t2.n=t1.n
basic idea is, i just create some temporary number 0-99 to table 1 (t1) and join to temporary number on table 2 (t2)
i have two tables having following structure
Table A
itemId categoryId orderDate
==========================================
1 23 2016-11-08
1 23 2016-11-12
1 23 2016-11-16
Table B have the structure
categoryId stock price
==========================================
23 500 600
However mine desired output should be as like
Result C
price stock orderdate qty
600 500 2016-11-08 (first order date) 3 (3 time appearance in first table)
Here is what i have tried so far
select b.price,b.stock from B b, A a
where b.categoryId = (
select a.categoryId
from A
GROUP BY categoryId
HAVING COUNT(categoryId)>1
)
and (a.orderdate = (
select MIN(orderdate)
from A
where categoryId = b.categoryId)
)
i have following result
price stock orderdate
600 500 2016-11-08
i have no idea how do find qty as it is appeared 3 times in first table.
I think you want the records in table a grouped by item id and category id, so include these two in your group by statement. Then the other columns you have to aggregate using MIN, MAX, AVG, SUM, etc. I use MIN which will give you the smallest number in the group for that particular column, although it shouldn't matter in this case whether you use MIN or MAX or AVG - it's all the same. Then COUNT(*) will just count the number of recrods in the group.
Also, joins are generally preferred over listing tables with commas.
SELECT a.itemid, a.categoryid, MIN(b.price), MIN(b.stock), min(a.orderdate), count(*) as qty
FROM a
INNER JOIN b ON a.categoryid = b.categoryid
GROUP BY a.itemid, a.categoryid
You also need to select COUNT(*)
how about use following sql
select min(price), min(stock), min(orderDate), COUNT(categoryId)
from A,B where A.categoryId = B.categoryId
GROUP by A.categoryId
You could create views for your subqueries and give them meaningful names e.g. CategoriesUsedInMultipleOrders, MostRecentOrderByCategory. This would 'optimize' you query by abstracting away complexity and making it easier for the human reader to understand.
This is the Query with the appropriate join method see Result:
SELECT B.price, B.stock, MIN( A.orderDate ) AS orderdate, COUNT( * ) AS qty
FROM TableA A, TableB B
WHERE A.categoryId = B.CategoryId
GROUP BY A.categoryId, B.price, B.stock
This is my SQL table:
So this is my sql query:
SELECT sponsor_name, sub_name, sum(amount), count(id)
FROM sponsor
and the output is like this:
I want the output to show both Adidas and Dell Computers with their own sum and count. So it will show two rows like:
sponsor_name
sub_name
sum(amount)
count(id)
Adidas
Food Bank Kelowna
9000
4
Dell Computer
Food Bank Kelowna
1500
3
You should group by the columns you don't want to aggregate. In this case, sponsor_name and sub_name:
SELECT sponsor_name, sub_name, SUM(amount), COUNT(id)
FROM sponsor
GROUP BY sponsor_name, sub_name
COUNT and SUM (among others) are Aggregated Functions, that means they return a single value grouped somehow (by a column or a set of columns). You should do this by specifying a GROUP BY clause in your query.
So, try this:
SELECT sponsor_name, sub_name, sum(amount), count(1)
FROM SPONSOR
GROUP BY sponsor_name, sub_name;
I have a table in a MySQL database with an ID column. This is not a key of the table and several rows can have the same ID.
I don't really know SQL but I already figured out how to obtain the number of distinct IDs:
SELECT COUNT(DISTINCT ID) FROM mytable;
Now I want to count only those IDs which appear more than 2 times in the table.
So if the ID column contains the values
3 4 4 5 5 5 6 7 7 7
the query should return 2.
I have no idea how to do this. I hope someone can help me!
Btw, my table contains a huge number of rows. So if there are several possibilities I would also be happy to know which solution is the most efficient.
Try this:
SELECT COUNT(ID) FROM (
SELECT ID FROM mytable
GROUP BY ID
HAVING COUNT(ID) > 2) p
select count(*) from
(select count(id) as cnt,id from mytable group by id) da
where da.cnt>2
The inner query will give you how many elements does each id have. And the outer query will filter this.
SELECT
COUNT(ids)
FROM
(SELECT
COUNT(ID)AS ids
FROM
mytable
GROUP BY
ID
HAVING
ids>2
)AS tbl1
Updated :
SELECT count(ID)
FROM (
SELECT ID FROM mytable
GROUP BY ID
HAVING count(ID) > 2
) p
should do what you need
I have a database with the first five columns like this:
ID NAME QUANTITY PRICE KIND
1 Dog 2 5 A
2 Cat 1 6 B
3 Dog 2 5 C
4 Bird 5 5 C
(DOG QUANTITY and PRICE will always be the same)
What I want to do to is to something like
SELECT KIND, SUM(QUANTITY * PRICE) GROUP BY KIND WHERE DISTINCT NAME
So that I get something that looks like this:
A 10
B 6
C 25
(The duplicate DOG is eliminated.)
I know my syntax above is grossly wrong -- it's just seems to be the most eloquent way of explaining what sort of thing I'm looking for.
In other words, I want to get rid of non-distinct NAMES then SUM the rest. I seem to be able to do one or the other but not both.
Any ideas? If worse comes to worst I can do it as a loop in PHP rather than as a single MYSQL query.
I'm not really clear about either what the rules are or why your table is in that format (with repeated name, quantity,price) but here is one way of getting your expected output.
select kind, SUM(quantity*price)
from
(
SELECT name, quantity, price, min(kind) kind
FROM YourTable
group by name, quantity, price
) t
group by kind
Here I chose the item with the lowest ID as the one to keep:
Select T.Kind, Sum( T.Quantity * T.Price ) As Total
From Table As T
Where Id = (
Select Min(T2.Id)
From Table As T2
Where T2.Name = T.Name
)
Group By T.Kind
Assuming that your table is unique on Name and Kind, you can do:
Select T.Kind, Sum( T.Quantity * T.Price ) As Total
From Table As T
Where T.Kind = (
Select Min(T2.Kind)
From Table As T2
Where T2.Name = T.Name
)
Group By T.Kind