MySQL grouping columns - mysql

is there any way i can group several of my columns together?
in one for my scripts i need to set several of my columns to the same value, is there a better way than typing out all the column names in my update query?
thanks

If these columns MUST always have the same value (that seems pointless) you could set an UPDATE TRIGGER on the column
delimiter |
CREATE TRIGGER somename BEFORE INSERT ON table1
FOR EACH ROW BEGIN
SET table1.col2=NEW.col1, table1.col3=NEW.col1;
END;
delimiter ;
But if that was the case, it would really make sense to just use ONE column instead of three.
Or, if its a Rights issue (this user shouldn't have the permission to make the columns different) you could build a Stored Procedure for doing the update
delimiter |
CREATE STORED PROCEDURE somename(IN val INT,IN whereval INT)
BEGIN
UPDATE table1 SET table1.col1=val, table1.col2=val, table1.col3=val
WHERE table1.id=whereval;
END;
delimiter ;

You'll need to type each column's name, there is no workaround.
UPDATE mytable
SET col1 = 1,
col2 = 1,
…

No, this is not possible.
See the syntax for update:
...
SET col_name1={expr1|DEFAULT} [, col_name2={expr2|DEFAULT}
...

Update syntax for MySQL requires each column to be named explicitly
update table set a = 'value', b = 'value'

Related

MySQL - Using SELECT for IF statement condition in stored procedure

I want to execute, in a stored procedure, a certain set of statements if, in table my_table there is exactly one row with value value in column column_name. I have tried the following, but I get a syntax error:
IF ((SELECT COUNT(*) FROM my_table WHERE column_name = value) = 1) THEN
BEGIN
END;
END IF;
For context: In my procedure I create a temporary table at some point, where I store a list of values. Then later on in the procedure, I want to check if a given value is present in that temporary table.
I think you might be better to structure it more like this
BEGIN
DECLARE myCOUNT INTEGER;
SELECT COUNT(*)
INTO myCount
FROM my_table
WHERE column_name=value;
IF (myCount = 1) THEN
-- do stuff
END IF;
END;
I'm not sure what you are trying to do, but I'll guess an "upsert" -- update a record if it exists, otherwise insert a new record.
In any case, if you are trying to ensure that name is unique in my_table, then this is not the right approach at all. Instead, declare a unique index/constraint so the database ensures the data integrity:
create unique index unq_my_table_name on my_table(name);
You can then use insert . . . on duplicate key update to modify the records in the database.

MySQL: Modify column based on column values in same table

I've got two columns in the same table for my users: name-displayed and short-name.
name-displayed is populated with the full name of the user, for example "John Doe". In short-name, there is the short value, e.g. "john-doe" (essentially de-capitalized and hyphenated).
How would I amend the data in short-name based on the data in name-displayed? I'm sure I could use a self-join based on UPDATE, but I'm not sure how to implement a change in data across the columns.
Any help would be hugely appreciated!
You need to use the Lower and Replace functions for this.
See: Lower and Replace in the docs.
Update <table_name>
set `short-name` = REPLACE(LOWER(`name-displayed`), ' ','-')
where <conditions>;
In case you want this done automatically, you'll need to write a trigger as Walter_Ritzel suggests.
delimiter //
CREATE TRIGGER auto_set_short_name BEFORE INSERT ON account
FOR EACH ROW
BEGIN
SET NEW.`short-name` = REPLACE(LOWER(`name-displayed`), ' ','-');
END;//
delimiter ;
You could use triggers: Triggers
A trigger Before Insert/Update could solve that easily.
delimiter //
CREATE TRIGGER ins_sum BEFORE INSERT OR UPDATE ON table
FOR EACH ROW
begin
SET New.`short-name` = REPLACE(LOWER(NEW.`name-displayed`), ' ','-') ;
end;
//
Use backticks or this char: ```, to make sure the - is not interpreted as a minus sign.
update table a join table b on a.id = b.id
set a.short-name = b.name-displayed;
I understand you need to set name-displayed same as short-name,
if that is not the case
care to explain.
what you want to amend ??

MySQL: Set to default value on update

Is it possible to set a column to its default value (or any specified value) on update when no value is specifically given in the statement? I was thinking that a trigger might accomplish this. Something like
IF ISNULL(NEW.column) THEN
NEW.column = value
END IF;
didn't work.
MySQL has function called DEFAULT(), which gets the default value from specified column.
UPDATE tbl SET col = DEFAULT(col);
MySQL Reference
UPDATE:
#JanTraenkner As far as I can tell, this is not possible. You can however make sure in your application code, that all columns are mentioned in your update statement and for those that do not have a value your use NULL as value. Then your trigger code is almost right, you just need to change it to
IF (NEW.column IS NULL) THEN
SET NEW.column = value
END IF;
Original answer:
I understood your question like, "set column to default value, if I don't specify the column in an update statement (which updates other columns from that table)".
To check with ISNULL() or col IS NULL doesn't work here, because when you don't specify it in the update statement it simply isn't there. There's nothing to check for.
I wrote this little example script which makes it work like I understood the question.
drop table if exists defvalue;
create table defvalue (id int auto_increment primary key, abc varchar(255) default 'default');
insert into defvalue (id) values (null);
insert into defvalue (id, abc) values (null, 'not_default_value');
insert into defvalue (id, abc) values (null, 'another_not_default_value');
drop trigger if exists t_defval;
delimiter $$
create trigger t_defval before update on defvalue
for each row
begin
set #my_def_value = (select default(abc) from defvalue limit 1);
if (new.abc = old.abc) then
set new.abc = #my_def_value;
end if;
end $$
delimiter ;
select * from defvalue;
update defvalue set id = 99 where id = 1;
select * from defvalue;
update defvalue set id = 98 where id = 2;
select * from defvalue;
I also had to save the default value of the column in a variable first because the function needs to know from which table. Unfortunately one can't specify that as parameter, not even as default(tablename.column).
All in all, please note, that this is rather a proof of concept. I'd recommend to solve this on application layer, not database layer. Having a trigger for this seems a bit dirty for me.

MySQL trigger after update on the same table

I have a MySQL trigger using the BEFORE INSERT ON table that calculates a value and updates the same table after a user inserts values in specific columns. This works as expected. But a user makes a mistake in their entry and fixes their error and I want to write a trigger that will update the calculated value after the error has been fixed. Is there a way to achieve this?
A BEFORE UPDATE ON table trigger has access to the existing values in the row as well as newly supplied values, and can set the value of any column in the table, based on whatever conditions and expressions we want.
For example, it's possible to test whether the value of one or more columns of concern has been modified, and then set some other column to some expression.
DELIMITER $$
CREATE TRIGGER my_before_update_trigger
BEFORE UPDATE ON my_table
FOR EACH ROW
BEGIN
IF NOT ((NEW.col1 <=> OLD.col1) AND (NEW.col2 <=> OLD.col2)) THEN
SET NEW.col3 = NEW.col1 * NEW.col2 ;
END IF;
END$$
DELIMITER ;

How to automatically update database fields with random values in MYSQL

I understand how to fill a field with random values, but I need my field to automatically update with a random value for each new column. For some reason, I'm having trouble figuring out how to do this.
By the way, as it says above, this is for a database in MySQL.
Thanks everyone
You can use a trigger to update a specific colum after insert like this:
DELIMITER |
CREATE TRIGGER randtrigger AFTER INSERT ON your_table
FOR EACH ROW BEGIN
UPDATE your_table SET some_column = rand()
WHERE id = NEW.id;
END;
|
DELIMITER ;