If you have an array with six numbers, say:
public var check:Array = new Array[10,12,5,11,9,4];
or
public var check:Array = new Array[10,10,5,11,9,4];
How do you check for a match (of a pair?)
Array class has an indexOf method:
function indexOf(searchElement:*, fromIndex:int = 0):int
Searches for an item in an array by using strict equality (===) and returns the index position of the item.
Parameters
searchElement:* — The item to find in the array.
fromIndex:int (default = 0) — The location in the array from which to start searching for the item.
Returns
int — A zero-based index position of the item in the array. If the searchElement argument is not found, the return value is -1.
Got it (I think). Used the following:
public var match:Array = [10,12,5,10,9,4];
checkArray(match);
private function checkArray(check:Array) {
var i:int;
var j:int;
for (i= 0; i < check.length; i++) {
for (j= i+1; j < check.length; j++) {
if (check[i] === check[j]) {
trace(check[i] + " at " + i + " is a match with "+check[j] + " at " + j);
}
}
}
}
Related
Seeking a way to merge arrays by index like so:
var a1:Array = ["a", "b", "c"];
var a2:Array = ["1", "2", "3"];
var a3:Array = result: ["a", 1, "b", 2, "c", 3]
I've tried concat, push, splice... not getting close. Thanks.
function arrayMerge(arr1:Array, arr2:Array):Array {
var o:Array = new Array();
for (var i:int=0; i<Math.max(arr1.length, arr2.length); i++) {
if (i<arr1.length) o.push(arr1[i]);
if (i<arr2.length) o.push(arr2[i]);
}
return o;
}
Thanks Payam for answer and non-judgement. Here's how I applied your work:
var arr1:Array = ["question1", "question2", "question3"];
var arr2:Array = ["answer1", "answer2", "answer3"];
var o:Array = new Array();
for (var i:int=0; i<Math.max(arr1.length, arr2.length); i++) {
if (i<arr1.length) o.push(arr1[i]);
if (i<arr2.length) o.push(arr2[i]);
}
trace(o); //(question1,answer1,question2,answer2,question3,question3)
#AndyH :
payamsbr is right, but you may work with Vectors or Arrays
Perhaps tl; dr; but this is the principle.
If You want to understand something try those possibilities.
If you don't, just copy and paste some shorter code ;)
var v1:Vector.<String> = new <String>["a", "b", "c"];
var v2:Vector.<uint> = new <uint>[1, 2, 3]; // why do you use String here and not uint?
// if you want to convert a uint to a String, use myUint.toString();
function convertVectorToArray(v1:Vector.<String>,v2:Vector.<uint>):Array{
var mergedArray:Array = new Array();
if (v1.length != v2.length){
throw(new Error(" ***ERROR : the two Vectors or Arrays have not the same lenfgth!"));
}else{
for(var i:uint = 0; i <v1.length ; i++){
mergedArray.push(v1[i]);
mergedArray.push(v2[i]);
}
}
return(mergedArray);
}
function mergeVectors(v1:Vector.<String>,v2:Vector.<uint>):Vector.<Object>{
var mergedVector:Vector.<Object> = new Vector.<Object>();
if (v1.length != v2.length){
throw(new Error(" ***ERROR : the two Vectors or Arrays have not the same length!"));
}
for(var i:uint = 0; i <v1.length ; i++){
mergedVector.push(v1[i] as String);
mergedVector.push(v2[i] as uint);
}
return(mergedVector);
}
var mergedArray:Array = (convertVectorToArray(v1,v2));
var mergedVector:Vector.<Object> = (mergeVectors(v1,v2));
function listArray(arr:Array):String{
var str: String="";
if ((v1.length*2) != (v1.length + v2.length)){
throw(new Error(" ***ERROR : the two Vectors or Arrays have not the same length!"));
}else{
for (var i:uint = 0; i < arr.length ; i++){
str+="typeof(arr[" + i + "]) = " + (typeof(arr[i]) as String).toUpperCase() + ", value = " + arr[i] + "\n";
}
}
return str;
}
function listVector(vect:Vector.<Object>):String{
var str: String = "";
if ((v1.length*2) != (v1.length + v2.length)){
throw(new Error(" ***ERROR : the two Vectors or Arrays have not the same length!"));
}else{
for (var i:uint = 0; i < vect.length ; i++){
str+="typeof(vect[" + i + "]) = " + (typeof(vect[i]) as String).toUpperCase() + ", value = " + vect[i] + "\n";
}
}
return str;
}
trace(listArray(mergedArray));
trace(listVector(mergedVector));
You may add a sort() method if You need it (you didn't told about it)
And Always throw an Error if the 2 Arrays or Vectors don't have the same length!
Throwing an Error is the best way to understand if something goes wrong...
This will avoid You a lot of time if You need to debug Your code!!!
As You can see the output is the same, but if the Vector Class is used correctly, this is more efficient than an Array.
Output :
Since there's a Vector Class, I don't understand a lot of people who chose Arrays instead...
Of course Vector. is a nonsense, but I posted it anyway so You can figure You out the Vector Class.
Output is the same :
typeof(arr[0]) = STRING, value = a
typeof(arr[1]) = NUMBER, value = 1
typeof(arr[2]) = STRING, value = b
typeof(arr[3]) = NUMBER, value = 2
typeof(arr[4]) = STRING, value = c
typeof(arr[5]) = NUMBER, value = 3
typeof(vect[0]) = STRING, value = a
typeof(vect[1]) = NUMBER, value = 1
typeof(vect[2]) = STRING, value = b
typeof(vect[3]) = NUMBER, value = 2
typeof(vect[4]) = STRING, value = c
typeof(vect[5]) = NUMBER, value = 3
I forgot this easiest way if you really want an Array...
Quick done!
var ar1:Array = [1,2,3];
var ar2:Array = ["a","b","c"];
function merge(...arrays):Array {
var result:Array = [];
for(var i:int=0;i<arrays.length;i++){
result = result.concat(arrays[i]);
}
return result;
}
trace(merge(ar1, ar2));
// outputs : 1,2,3,a,b,c
Another possibility :
function populateObject(v1:Vector.<String>, v2:Vector.<uint>):Object{
var obj = new Object();
if ((v1.length*2) != (v1.length + v2.length)){
throw(new Error(" ***ERROR : the two Vectors or Arrays have not the same length!"));
}else{
for (var i:uint = 0; i < v1.length; i++){
obj[v2[i]] = v1[i];
}
}
return obj;
}
var o:Object = populateObject(v1,v2);
function listObject(someObj:Object):void{
var myObj:Object = someObj;
for (var i:String in someObj){
trace(someObj[i] + ": " + i);
}
}
listObject(o);
output =
a: 1
b: 2
c: 3
I think that You have a lot of possibilities to use here even it's my longer answer ;)
If You try those possibilities and understand them, this will certainty help You to think to find the best way to deal with Your issue.
But You may also copy and paste some shorter code.
I just wanted to show You that there's more than one answer.
If you understand this, You will be able to go further with coding.
Have fun ;)
Sincerely.
Nicolas
Best regards.
Nicolas.
This is more or less my first attempt at writing a Javascript function and I want to convert an array of column numbers to an array of column letters
If I run testFunction I get undefined
function testFunction() {
var ui = SpreadsheetApp.getUi();
aryCLTCN(["A","C","D"])
ui.alert(aryCLTCN[3]);
}
function aryCLTCN(array) {
var columnLet = array
var output = [];
for (var i = 0, length = columnLet.length; i < length; i++) {
output[i] = [];
output[i] = CLTCN(columnLet[(i)]);
}
}
function CLTCN(letter)
{
var column = 0, length = letter.length;
for (var i = 0; i < length; i++)
{
column += (letter.charCodeAt(i) - 64) * Math.pow(26, length - i - 1);
}
return column;
}
There are several problems with your code.
Within function testFunction() you call aryCLTCN(["A","C","D"]) but don't assign the result to a variable, then with aryCLTCN[3] you are trying to access a property "3" of the function itself. Which isn't a syntax error because functions can have properties, but the function has no such property so you get undefined. You need something like this:
var result = aryCLTCN(["A","C","D"]);
ui.alert(result[3]);
Except note that JavaScript arrays are zero-based, which means that [3] tries to access the fourth element, but your array only has three elements.
Within function aryCLTCN(array) you create an output array but don't return it. You need to add return output;.
Also with these two lines:
output[i] = [];
output[i] = CLTCN(columnLet[(i)]);
...the first line assigns output[i] to a new empty array, but the second line overwrites that with the return value from CLTCN(columnLet[(i)]);. You can remove output[i] = [];.
Putting all that together:
function testFunction() {
// var ui = SpreadsheetApp.getUi(); // commented out for demo in browser
var result = aryCLTCN(["A","C","D"])
// using alert() instead of ui.alert() for demo here in browser
alert(result[3]); // undefined because there's no 4th element
alert(result[2]); // shows third element
}
function aryCLTCN(array) {
var columnLet = array
var output = [];
for (var i = 0, length = columnLet.length; i < length; i++) {
output[i] = CLTCN(columnLet[(i)]);
}
return output;
}
function CLTCN(letter)
{
var column = 0, length = letter.length;
for (var i = 0; i < length; i++)
{
column += (letter.charCodeAt(i) - 64) * Math.pow(26, length - i - 1);
}
return column;
}
testFunction();
(Note that for the purposes of having a runnable code snippet in my answer I'm using alert() instead of ui.alert(), but in your real code you would stick with ui.alert().)
You get an undefined error because you are calling the trying to access an index on a function. aryCLTCN function needs to have a return the output array and you need to assign it to a variable in your testFunction to be able to access its elements.
Although there was nothing logically or effectively wrong with your functions, I have provided another working solution below.
function testFunction() {
var ui = SpreadsheetApp.getUi();
var colArr = ["A", "B", "Z", "AA", "AZ", "ZA", "AAA"];
var nColArr = colArr.map(function(col) {
var colNum = 0;
col.split('').forEach(function(l, i) { colNum += (l.charCodeAt() - 64) * Math.pow(26, col.length - 1 - i) });
return colNum;
});
ui.alert(nColArr); //Shows all elements inside the nColArr array.
ui.alert(nColArr[3]); //Shows the 4th element inside the nColArr array.
}
Try it out:
var colArr = ["A", "B", "Z", "AA", "AZ", "ZA", "AAA"];
var nColArr = colArr.map(function(col) {
var colNum = 0;
col.split('').forEach(function(l, i) {
colNum += (l.charCodeAt() - 64) * Math.pow(26, col.length - 1 - i)
});
return colNum;
});
console.log(nColArr);
I have a random number variable defined as below
var rannum:Number = Math.floor(Math.random()*50+1);
Then I have a trigger that calls for a new random number everytime a button is clicked
ranbtn.addEventListener(MouseEvent.CLICK, reran);
function reran (event:MouseEvent):void
{
rannum = Math.floor(Math.random()*50+1);
}
I would like to prevent the same random number from being selected until all the numbers have been selected and then possibly start over?
I found a few threads like this one but none of them were specifically what I needed
You need to create an array of the possible values and each time you retrieve a random index from the array to use one of the values, you remove it from the array.Here you have an easy example with javascript.
var uniqueRandoms = [];
var numRandoms = 50;
function makeUniqueRandom() {
// refill the array if needed
if (!uniqueRandoms.length) {
for (var i = 0; i < numRandoms; i++) {
uniqueRandoms.push(i);
}
}
var index = Math.floor(Math.random() * uniqueRandoms.length);
var val = uniqueRandoms[index];
// now remove that value from the array
uniqueRandoms.splice(index, 1);
return val;
}
I've found another option, You can declare an array of Integers:[1,2,3,4...50] and sort them randomly.
var sorted:Array = [];
for(var i:int = 0; i < 50; i++){
sorted.push(i);
}
//I'm making a copy of sorted in unsorted
var unsorted:Array = sorted.slice();
//Randomly sort
while(sorted.join() == unsorted.join()){
unsorted.sort(function (a:int, b:int):int { return Math.random() > .5 ? -1 : 1; });
}
If you get a selected num, you can add one until it is not selected.
Create a list of integers from 1 to 50.
Pick a random integer from the list and remove it.
When there are no more integers left (after 50 picks), repeat step 1.
Code:
function createRangeOfIntegers(from:int, to:int):Vector.<int> {
if (from >= to) throw new ArgumentError("Invalid arguments");
var integers:Vector.<int> = new <int>[];
for (var i:int = from; i <= to; i++) {
integers.push(i);
}
return integers;
}
function getRandomInteger(integers:Vector.<int>):int {
var index:int = Math.random() * integers.length;
var integer:int = integers.splice(index, 1)[0];
return integer;
}
Example:
// create all the possible integers
var integers:Vector.<int> = createRangeOfIntegers(1, 50);
// select a random integer
var random:int = getRandomInteger(integers);
// When you've selected all integers you can start over
if (integers.length == 0)
integers = createRangeOfIntegers(1, 50);
I'm not entirely sure if this is possible at all, but I'm trying to take a string in Flash and check to see if it is the same as the name of an already existing variable. Here is a piece of my code:
var randomNumber:int;
var randomNumberS:String;
var Mem1:String;
var Mem2:String;
randomNumber = Math.floor(Math.random()*3);
randomnumberS = ("Mem" + String(randomNumber));
TGiven.text = [the randomnumberS string, except as either the variable name Mem1 or Mem2]
Is this a possible task, and if not, is there a better way to perform this task? It would be very useful as I plan on making many more variables that start with Mem with higher and higher numbers.
It would be optimal if the variables were a member of a class or Object, to which you could evaluate whether they exist using hasOwnProperty().
For example:
var obj:Object = {
Mem1: "value1",
Mem2: "value2"
};
You could test whether obj has a property by name:
obj.hasOwnProperty("Mem1");
Applying your example using random numbers:
for (var i = 0; i < 100; i++) {
var randomNumber:int = Math.floor(Math.random() * 3);
if (obj.hasOwnProperty("Mem" + randomNumber))
trace("Mem" + randomNumber + " exists.");
else
trace("Mem" + randomNumber + " does not exist.");
}
You can also use the in keyword, such as:
"Mem1" in obj;
Using the same example:
for (var i = 0; i < 100; i++) {
var randomNumber:int = Math.floor(Math.random() * 3);
if (("Mem" + randomNumber) in obj)
trace("Mem" + randomNumber + " exists.");
else
trace("Mem" + randomNumber + " does not exist.");
}
Currently the way that I am taking a JSON string where I "Don't know the contents" and pulling the keys and the values is as follows:
var arr = [{"manager_first_name":"jim","manager_last_name":"gaffigan"}];
var arrLen = arr.length;
for(var i = 0; i < arrLen; i++){
var myKeys = Object.keys(arr[i]);
var keysLen = myKeys.length;
for(var x = 0; x < keysLen; x++){
keyName = myKeys[x];
keyValueStr = "arr[i]."+keyName;
keyValue = eval(keyValueStr);
console.log(keyName+':'+keyValue);
}
}
There has to be a cleaner and more efficient way of doing this. Any suggestion would be appreciated.
Using jQuery you can use http://api.jquery.com/jQuery.parseJSON/ & Object.keys - Than:
var obj = jQuery.parseJSON('{"manager_first_name":"jim","manager_last_name":"gaffigan"}');
var keys = Object.keys(obj);
jQuery.each(keys,function(k, v){
console.log(v);
console.log(obj[v]);
});
Create an object and initialize it with your JSON:
var arr = [{"manager_first_name":"jim","manager_last_name":"gaffigan"}];
var JSONObject = new MyJSONObject(arr);
in your constructor, set the object's properties.
You could use for-in loop which iterates over the enumerable properties of an object, in arbitrary order.
var arr = [{"manager_first_name":"jim","manager_last_name":"gaffigan"}];
for (var i = 0; i < arr.length; i++) {
var currentObj = arr[i];
for (var item in currentObj) {
console.log(item + " : " + currentObj[item]);
}
}
If your array always have only one item, you could omit the outermost for loop and just use arr[0]
var currentObj = arr[0];
for (var item in currentObj) {
console.log(item + " : " + currentObj[item]);
}