I'd like to conditionally hide a tab in a TabNavigator. It seems that setting visible doesn't work properly (presumably because this is how the TabNavigator hides the tabs that aren't currently selected).
What's the right way to do this?
You can do this by making use of TabNavigator's getTabAt() method which returns the Button that makes up the visual tab. You can then set that Button's visible property. It's a little tricky to get this setup with a bindings, but it's doable.
You could also consider just disabling the tab instead, which you can do by setting enabled on the corresponding TabNavigator child (for which visible didn't work).
What do you mean by hide? If you actually mean remove, then just take your array that's bound to the data in the TabNavigator, and remove the applicable element from it.
If you want to just have them removed temporarily, create a component of your own that encapsulates the TabNavigator and has an array of removed tabs and an array of actual tabs. Then handle this as you see fit.
You might want to check out the flexlib project. They have a component called SuperTabNavigator that adds a lot of functionality to the base Flex TabNavigator, including hiding tabs (I think).
If you do have to create your own component, though, it's a bit more tricky. The thing to know is that "tabs" are actually specially styled buttons, contained within a TabBar component (the TabBar is then contained within the TabNavigator). What you'll have to do then, is subclass TabNavigator and have some property on your views (i.e. the canvases, etc. that are added to the TabNavigator) that is bound to the visible and includeInLayout properties of the TabBar buttons.
In essence, what you'll have is something like:
BindingUtils.bindProperty( tabButton, "visible", view, "someProperty" );
BindingUtils.bindProperty( tabButton, "includeInLayout", view, "someProperty" );
I don't know about TabNavigator, but in other containers, you can set the includeInLayout property to false and it will be ignored. You probably still need to combine it with visible.
var secondTab = tabNavigator.removeChildAt(0);
Related
I must adapt to application to wcag focus requirements.
My application works on jsf/primefaces and I have problem with focus on many elements.
For example unexpanded filters contains ui-helper-hidden-accessible class (which is invisible until I click filter to expand) and I cant focus on unexpanded filter name to expand it by keyboard because (I think) ui-helper-hidden-accessible which size is 1x1px receive focus.
I want to span element inside filter div or div with ui-selectcheckboxmenu-trigger class will receive focus instead of unexpanded ui-helper-hidden-accessible.
Do You know how to do it?
Second example is primeface's menuItems - they also not receive focus. The only solution I know is to replace the elements to elements without ui-helper-hidden-accessible class, but unfortunately I can't use this soultion
<nf:author id="filter-selected-authors"
value="#{applicationsBean.dataModel.filter.selectedAuthors}"
converter="#{userConverter}"
completeMethod="#{applicationsBean.usersAutoComplete}"
componentsToUpdate=":datatableForm:applicationTable"
dataTableModel="#{applicationsBean.dataModel}"
oncompleteJs="dynamicScroll()"/>
How can I go about creating a form which pops up when the user clicks a button on a Jade template? I tried the following in HTML, which works:
http://www.formget.com/how-to-create-pop-up-contact-form-using-javascript/
Now to use this in my Node.js project would I need to create a separate Jade file for the form itself? That is what I tried and then I tried to display the form like this:
function div_show() {
alert("Test");
document.getElementById('abc').style.display = "block";
}
Unfortunately that does not work. What is the recommended approach for creating a pop up form in Jade? I am really confused with Jade and I can't seem to find a good tutorial for this, there are loads for HTML...
Thanks for the help!
Normally for this you would use:document.getElementById('abc').style.visibility="visible";
To hide your table use:document.getElementById('abc').style.visibility="hidden";
When using the 'style' attribute you are using plain css commands. Make sure your default div style settings have it 'hidden', if that is what you want.This display:block;visibility:hidden;' must exist in your default settings for that div style so the DOM has a clear path to what it is controlling. By itself 'display:block;' does not hide or make objects visible, it is mostly about the shape the div creates as a container for objects.
As an option you can use:
document.getElementById('abc').style.display="block";
To hide your table use:document.getElementById('abc').style.display="none";
For this you would set your div style settings to 'display:none;visibility:visible;.
In this case 'display="none"' removes the object from all display layers and could allow other objects to fill in it's space. When it is visible it will push other objects on the same z-index out of the way. If it has a higher z-index, say +100 higher, it will pop-up above the other objects on the page. The 'visibility' attribute only controls the objects visibility, it does not remove it from the display memory. It can still take up space even though it is not visible. The 'opacity' attribute does about the same thing, except it allows you to also make an object as transparent as you like.
is there any way to either set a flex 4 list component to selectable "false" or disable/hide its selectioncolor? I've tried to change it designview, but it doesn't allow me change it that way. I've also tried tweaking it via the list component or the scroller/viewport control via as3, but I really can't seem to fin a way.
If you have a list that doesn't have selection, you can quickly change it into DataGroup. Sometimes I even prefer using DataGroup instead of the List and if I need to manage a selection I add the selection state to the items in the data provider, thus each item would know whether it is selected. This solution allows me to perform filtering, sorting, reordering on the list and still keep the selected state of the items.
try to put this on
ItemRenderer property
autoDrawBackground="false"
You could use an item renderer for the List, and set the selection color in the item renderer. Here are some examples of this:
Styling both foreground and background selection color in a Flex list/datagrid
Hopefully a quick question here. I have setup a "LayoutPage" custom class (based on MovieClip) and I am attemptimg to create a "selected" behaviour.
When I assign my "addEventListener(MouseEvent.CLICK,toggleSelection)" from within my custom class, everything works as expected, clicking any object of that class does display the correct behaviour.
Now, I would like to extend the functionality by adding keyboard modifyer to either extend the selection or replace it.
For this, I thought of moving the "addEventListener" out of the class and put it inside the parent instead (my "PageLayout" class where all the "LayoutPage" live). But by doing so, the click event no longer register on the "LayoutPage" class but rather on its individual children (Page icon, Page number text field, Page Highlight shape, etc.)
Can anybody explain why this is happening and how I can circumvent it?
TIA
This should be happening no matter where you put your addEventListener. It is because mouseChildren is switched on by default. It is probably best to turn it off inside your LayoutPage class like so:
myLayoutPage.mouseChildren = false;
The actual issue is that use are probably using currentTarget to reference the item that was clicked on in your event handler method. Take a look at the descriptions for currentTarget and target to get a good idea of how they differ.
A good option would be to add your listener at the PageLayout level, but add it specifically to each LayoutPage child like so:
myLayoutPage.addEventListener(MouseEvent.CLICK, toggleSelection);
This way you can just use target in your handlers. But it would probably be best to still switch mouseChildren to false on each of your LayoutPage instances.
I have a DataGrid populated via an Array. The last column in the DataGrid uses an ItemRenderer (Button). I want to show the Button in certain rows but not in others (leave those empty). I've looked everywhere for an example or even a clue how to do this (tried labelFunction on DG, etc.) but can't find anything about it. Any help would be appreciated. Thanks!
Okay... with (lots of) help, figured it out.
First off, I'm not sure why the itemRenderer requires a container but it does. The array must also be checked from the itemRenderer and not from the main application... again, I don't know why since the debugger shows it going through the exact same loop/events, etc.).
If interested here's the relevant parts of the code:
Main App:---
{col1:'', col2:'', col3:'', col4:'', col5:'', col6:'', col7: '', col8:'', col9:'', col10:'', col11:'yo'}];
public function initData():void
{ xferSchedule.dataProvider = schedArray; }
]]>
an item renderer does not have to be a container, it has to implement IDataRenderer (a Button does not). One could extend Button and implement this interface to get a simple button renderer. If you want it to display conditionally, you will accomplish this by handling those conditions within the renderer based on the data.
Now this might get slightly complex. I would recommend you to define you an XML instead of Array of Objects. If the node has the type property button, then it would create button at that cell whose value type is button.
How to create a button dynamically inside a grid which is yet again dynamic?
This might end into the whole component being dynamic.