Two database changes under the same variable - mysql

I have the code:
...SOME CODE HERE...
//inserting data order
$order = "UPDATE `database`.`table` SET `status_client` = 'PRELUAT' WHERE `flux_receptie`.`id` =$res";
$order = "UPDATE `database`.`table` SET `status_client` = 'PRELUAT' WHERE `flux_receptie`.`id` =$res";
//declare in the order variable
$result = mysql_query($order); //order executes
...SOME CODE HERE...
Ignore the DB command because it will be modified. My question is that if I can use $order for two database commands? Will $result = mysql_query($order); work properly?
Thanks friends! :)

No.
You are redefining $order in the second line, so the first time you set $order does not do anything. You will have to make two separate queries or combine them into a single MySQL statement.
By default, you are also simply not allowed to execute two queries at once for security purposes (as someone could inject a MySQL command in the middle of yours that does something nefarious). For example. setting $order to:
`UPDATE `table` SET `column`='value' WHERE (condition); UPDATE `table2` SET `column2`='value2' WHERE (condition2);
would not work either.

(following on from Nathans answer, and the comments to this)
To make two queries, simply structure:
//inserting data order
$order1 = "UPDATE `database`.`table` SET `status_client` = 'PRELUAT' WHERE `flux_receptie`.`id` =$res";
$order2 = "UPDATE `database`.`table` SET `status_client` = 'PRELUAT' WHERE `flux_receptie`.`id` =$res";
//declare in the order variable
$result = mysql_query($order1); //order executes
$resultTwo = mysql_query($order2);
This will execute both orders as defined in the variable string. I highly recommend exploring OOP MySQL with MySQLi or PDO methodology. Google it :)

Related

SQL COLUMN NAME [duplicate]

I'd like to get all of a mysql table's col names into an array in php?
Is there a query for this?
The best way is to use the INFORMATION_SCHEMA metadata virtual database. Specifically the INFORMATION_SCHEMA.COLUMNS table...
SELECT `COLUMN_NAME`
FROM `INFORMATION_SCHEMA`.`COLUMNS`
WHERE `TABLE_SCHEMA`='yourdatabasename'
AND `TABLE_NAME`='yourtablename';
It's VERY powerful, and can give you TONS of information without need to parse text (Such as column type, whether the column is nullable, max column size, character set, etc)...
Oh, and it's standard SQL (Whereas SHOW ... is a MySQL specific extension)...
For more information about the difference between SHOW... and using the INFORMATION_SCHEMA tables, check out the MySQL Documentation on INFORMATION_SCHEMA in general...
You can use the following query for MYSQL:
SHOW `columns` FROM `your-table`;
Below is the example code which shows How to implement above syntax in php to list the names of columns:
$sql = "SHOW COLUMNS FROM your-table";
$result = mysqli_query($conn,$sql);
while($row = mysqli_fetch_array($result)){
echo $row['Field']."<br>";
}
For Details about output of SHOW COLUMNS FROM TABLE visit: MySQL Refrence.
Seems there are 2 ways:
DESCRIBE `tablename`
or
SHOW COLUMNS FROM `tablename`
More on DESCRIBE here: http://dev.mysql.com/doc/refman/5.0/en/describe.html
I have done this in the past.
SELECT column_name
FROM information_schema.columns
WHERE table_name='insert table name here';
Edit: Today I learned the better way of doing this. Please see ircmaxell's answer.
Parse the output of SHOW COLUMNS FROM table;
Here's more about it here: http://dev.mysql.com/doc/refman/5.0/en/show-columns.html
Use mysql_fetch_field() to view all column data. See manual.
$query = 'select * from myfield';
$result = mysql_query($query);
$i = 0;
while ($i < mysql_num_fields($result))
{
$fld = mysql_fetch_field($result, $i);
$myarray[]=$fld->name;
$i = $i + 1;
}
"Warning
This extension is deprecated as of PHP 5.5.0, and will be removed in the future."
The simplest solution out of all Answers:
DESC `table name`
or
DESCRIBE `table name`
or
SHOW COLUMNS FROM `table name`
An old PHP function "mysql_list_fields()" is deprecated. So, today the best way to get names of fields is a query "SHOW COLUMNS FROM table_name [LIKE 'name']". So, here is a little example:
$fields = array();
$res=mysql_query("SHOW COLUMNS FROM mytable");
while ($x = mysql_fetch_assoc($res)){
$fields[] = $x['Field'];
}
foreach ($fields as $f) { echo "<br>Field name: ".$f; }
when you want to check your all table structure with some filed then use this code. In this query i select column_name,column_type and table_name for more details . I use order by column_type so i can see it easily.
SELECT `COLUMN_NAME`,COLUMN_TYPE,TABLE_NAME
FROM `INFORMATION_SCHEMA`.`COLUMNS`
WHERE `TABLE_SCHEMA`='yourdatabasename' order by DATA_TYPE;
If you want to check only double type filed then you can do it easily
SELECT `COLUMN_NAME`,COLUMN_TYPE,TABLE_NAME,DATA_TYPE
FROM `INFORMATION_SCHEMA`.`COLUMNS`
WHERE `TABLE_SCHEMA`='yourdatabasename' AND DATA_TYPE like '%bigint%' order by DATA_TYPE;
if you want to check which field allow null type etc then you can use this
SELECT `COLUMN_NAME`,COLUMN_TYPE,TABLE_NAME,IS_NULLABLE,DATA_TYPE
FROM `INFORMATION_SCHEMA`.`COLUMNS`
WHERE `TABLE_SCHEMA`='yourdatabasename' and DATA_TYPE like '%bigint%' and IS_NULLABLE ='NO' order by COLUMN_TYPE;
you want to check more then thik link also help you.
https://dev.mysql.com/doc/refman/5.7/en/columns-table.html
this generates a string of column names with a comma delimiter:
SELECT CONCAT('(',GROUP_CONCAT(`COLUMN_NAME`),')')
FROM `INFORMATION_SCHEMA`.`COLUMNS`
WHERE `TABLE_SCHEMA`='database_name'
AND `TABLE_NAME`='table_name';
function get_col_names(){
$sql = "SHOW COLUMNS FROM tableName";
$result = mysql_query($sql);
while($record = mysql_fetch_array($result)){
$fields[] = $record['0'];
}
foreach ($fields as $value){
echo 'column name is : '.$value.'-';
}
}
return get_col_names();
Not sure if this is what you were looking for, but this worked for me:
$query = query("DESC YourTable");
$col_names = array_column($query, 'Field');
That returns a simple array of the column names / variable names in your table or array as strings, which is what I needed to dynamically build MySQL queries. My frustration was that I simply don't know how to index arrays in PHP very well, so I wasn't sure what to do with the results from DESC or SHOW. Hope my answer is helpful to beginners like myself!
To check result: print_r($col_names);
SHOW COLUMNS in mysql 5.1 (not 5.5) uses a temporary disk table.
http://dev.mysql.com/doc/refman/5.1/en/internal-temporary-tables.html
http://dev.mysql.com/doc/refman/5.1/en/show-columns.html
So it can be considered slow for some cases. At least, it can bump up your created_tmp_disk_tables value. Imagine one temporary disk table per connection or per each page request.
SHOW COLUMNS is not really so slow, possibly because it uses file system cache. Phpmyadmin says ~0.5ms consistently. This is nothing compared to 500ms-1000ms of serving a wordpress page. But still, there are times it matters. There is a disk system involvement, you never know what happens when server is busy, cache is full, hdd is stalled etc.
Retrieving column names through SELECT * FROM ... LIMIT 1 was around ~0.1ms, and it can use query cache as well.
So here is my little optimized code to get column names from a table, without using show columns if possible:
function db_columns_ar($table)
{
//returns Array('col1name'=>'col1name','col2name'=>'col2name',...)
if(!$table) return Array();
if(!is_string($table)) return Array();
global $db_columns_ar_cache;
if(!empty($db_columns_ar_cache[$table]))
return $db_columns_ar_cache[$table];
//IMPORTANT show columns creates a temp disk table
$cols=Array();
$row=db_row_ar($q1="SELECT * FROM `$table` LIMIT 1");
if($row)
{
foreach($row as $name=>$val)
$cols[$name]=$name;
}
else
{
$coldata=db_rows($q2="SHOW COLUMNS FROM `$table`");
if($coldata)
foreach($coldata as $row)
$cols[$row->Field]=$row->Field;
}
$db_columns_ar_cache[$table]=$cols;
//debugexit($q1,$q2,$row,$coldata,$cols);
return $cols;
}
Notes:
As long as your tables first row does not contain megabyte range of data, it should work fine.
The function names db_rows and db_row_ar should be replaced with your specific database setup.
IN WORDPRESS:
global $wpdb; $table_name=$wpdb->prefix.'posts';
foreach ( $wpdb->get_col( "DESC " . $table_name, 0 ) as $column_name ) {
var_dump( $column_name );
}
Try this one out I personally use it:
SHOW COLUMNS FROM $table where field REGEXP 'stock_id|drug_name'
This question is old, but I got here looking for a way to find a given query its field names in a dynamic way (not necessarily only the fields of a table). And since people keep pointing this as the answer for that given task in other related questions, I'm sharing the way I found it can be done, using Gavin Simpson's tips:
//Function to generate a HTML table from a SQL query
function myTable($obConn,$sql)
{
$rsResult = mysqli_query($obConn, $sql) or die(mysqli_error($obConn));
if(mysqli_num_rows($rsResult)>0)
{
//We start with header. >>>Here we retrieve the field names<<<
echo "<table width=\"100%\" border=\"0\" cellspacing=\"2\" cellpadding=\"0\"><tr align=\"center\" bgcolor=\"#CCCCCC\">";
$i = 0;
while ($i < mysqli_num_fields($rsResult)){
$field = mysqli_fetch_field_direct($rsResult, $i);
$fieldName=$field->name;
echo "<td><strong>$fieldName</strong></td>";
$i = $i + 1;
}
echo "</tr>";
//>>>Field names retrieved<<<
//We dump info
$bolWhite=true;
while ($row = mysqli_fetch_assoc($rsResult)) {
echo $bolWhite ? "<tr bgcolor=\"#CCCCCC\">" : "<tr bgcolor=\"#FFF\">";
$bolWhite=!$bolWhite;
foreach($row as $data) {
echo "<td>$data</td>";
}
echo "</tr>";
}
echo "</table>";
}
}
This can be easily modded to insert the field names in an array.
Using a simple: $sql="SELECT * FROM myTable LIMIT 1" can give you the fields of any table, without needing to use SHOW COLUMNS or any extra php module, if needed (removing the data dump part).
Hopefully this helps someone else.
if you use php, use this gist.
it can get select fields full info with no result,and all custom fields such as:
SELECT a.name aname, b.name bname, b.*
FROM table1 a LEFT JOIN table2 b
ON a.id = b.pid;
if above sql return no data,will also get the field names aname, bname, b's other field name
just two line:
$query_info = mysqli_query($link, $data_source);
$fetch_fields_result = $query_info->fetch_fields();
This query fetches a list of all columns in a database without having to specify a table name. It returns a list of only column names:
SELECT COLUMN_NAME
FROM INFORMATION_SCHEMA.COLUMNS
WHERE table_schema = 'db_name'
However, when I ran this query in phpmyadmin, it displayed a series of errors. Nonetheless, it worked. So use it with caution.
if you only need the field names and types (perhaps for easy copy-pasting into Excel):
SELECT COLUMN_NAME, DATA_TYPE
FROM INFORMATION_SCHEMA.COLUMNS
WHERE TABLE_SCHEMA='databasenamegoeshere'
AND DATA_TYPE='decimal' and TABLE_NAME = 'tablenamegoeshere'
remove
DATA_TYPE='decimal'
if you want all data types
i no expert, but this works for me..
$sql = "desc MyTable";
$result = #mysql_query($sql);
while($row = #mysql_fetch_array($result)){
echo $row[0]."<br>"; // returns the first column of array. in this case Field
// the below code will return a full array-> Field,Type,Null,Key,Default,Extra
// for ($c=0;$c<sizeof($row);$c++){echo #$row[$c]."<br>";}
}
I have tried this query in SQL Server and this worked for me :
SELECT name FROM sys.columns WHERE OBJECT_ID = OBJECT_ID('table_name')
The call of DESCRIBE is working fine to get all columns of a table but if you need to filter on it, you need to use the SHOW COLUMNS FROM instead.
Example of PHP function to get all info of a table :
// get table columns (or return false if table not found)
function get_table_columns($db, $table) {
global $pdo;
if($cols = $pdo->query("DESCRIBE `$db`.`$table`")) {
if($cols = $cols->fetchAll(PDO::FETCH_ASSOC)) {
return $cols;
}
}
return false;
}
In my case, I had to find the primary key of a table. So, I used :
SHOW COLUMNS FROM `table` WHERE `Key`='PRI';
Here is my PHP function :
// get table Primary Key
function get_table_pk($db, $table) {
global $pdo;
$q = "SHOW COLUMNS FROM `$db`.`$table` WHERE `Key` = 'PRI'";
if($cols = $pdo->query($q)) {
if($cols = $cols->fetchAll(PDO::FETCH_ASSOC)) {
return $cols[0];
}
}
return false;
}

Do I need to fill all columns in an SQL Database to pass a variable

I am trying to pass variables to a sql database.
The database is set up as follows:
id, comment1, comment2, comment3, comment4
I am executing this by this code:
$comment1 = $_POST['comment1'];
$sql = "UPDATE comments SET comment1='$comment1' ";
mysqli_query($conn, $sql);
header("Location:index.php");
exit();
Is it possible to just add one variable at a time i.e. just comment 1? Or will I need to add all the variables to the database. The code is not working right now when I try to pass one variable.
Need to ensure it is set as null allowed and it will work

Select or Return "field" names from a query (not table) in MySQL

I have a Dynamic Pivot in MySQL (see this question: MySQL "Multi-Dimensional?" Dynamic Pivot)
I want to know the Column/As/Field names as if it were a table and I queried INFORMATION_SCHEMA (which if this was a REAL table, would be easy enough: MySQL query to get column names?).
But, I can find no question or reference to a function or SELECT option to get the Column/As/Field names from a query. Is this possible? If so, how?
Using Perl to access MySQL (http://dbi.perl.org/).
So, flipping this around... we know the fixed columns. So, if we use the same basic query that creates the Pivot to begin with, we can get a GROUP_CONCAT of the names.
SET #sql = NULL;
SELECT GROUP_CONCAT(qrv.req_name) INTO #sql
FROM (SELECT qrt.req_name FROM qual_requirment_values qrv JOIN qual_requirment_types qrt ON qrt.id = qrv.req_type_id) qrv;
SET #sql = CONCAT('r.rank,r.member_type,im.name,qrv.grouping,', #sql);
SELECT #sql;
This can then be split into an array and used.
Seems like the long way around, but in the absence of something else it will work for my application. Seems horribly inefficient! :)
The better answer, thanks to #OllieJones. The Data Base Interface used to access MySQL should provide a way.
In my case (Perl), the answer is here: http://www.perlmonks.org/?node_id=264623
my $sql = ... [some query];
my $sth = $dbh->prepare($sql);
$sth->execute();
my $field_name_arrayref = $sth->{NAME};
Further to the answer, this is the full method within my MySQL package. do() is our generic DBI method that returns queries in an AoA. Adapting that method to create do_fieldNames();
## Tested Method
sub do_fieldNames {
my ($self, $sql, $has_results) = #_;
my ($sth, $rv, #row, #query_results);
## Execute the SQL statement
$sth = $$self->prepare($sql);
$rv = $sth->execute or &error(3306, __LINE__, __FILE__, $sql, $$self->errstr);
return undef unless $rv > 0;
## SOLUTION >> Field Name arrayref, part of the standard included DBI Perl Module
my $field_name_arrayref = $sth->{NAME};
## Parse the results
if ($has_results || $sql =~ /^select/i) {
while (#row = $sth->fetchrow_array) {
push #query_results, [ #row ];
}
}
## Return results
return (\#query_results, $field_name_arrayref) ;
}

PHP update query with syntax error

Can anyone tell me why this doesnt work, and returns syntax error please?
$sql4 = "update apiStreetCheckGeneral
set (BBAverageSpeed, BBSuperFastBBAvailable, BBCommentary)
values ('$averagespeed', '$superfast', '$bbcommentary')
where PostCode='".$values['PostCode']."'";
CustomQuery($sql4);
This is your query:
update apiStreetCheckGeneral set (BBAverageSpeed, BBSuperFastBBAvailable, BBCommentary)
values ('$averagespeed', '$superfast', '$bbcommentary')
where PostCode='".$values['PostCode'].
I am not aware of update syntax that uses a column list or values. Set each one individually:
update apiStreetCheckGeneral
set BBAverageSpeed = '$averagespeed',
BBSuperFastBBAvailable = '$superfast',
BBCommentary = '$bbcommentary'
where PostCode='".$values['PostCode']."'"
You should learn, however, to use parameterized queries especially for update statements.
Use query like below
$sql4 = "update apiStreetCheckGeneral
set BBAverageSpeed = '$averagespeed',
BBSuperFastBBAvailable = '$superfast',
BBCommentary = '$bbcommentary'
where PostCode='".$values['PostCode']."' ";
CustomQuery($sql4);

How to use global variable in mysqli_query statement

I'm trying to create a function to count different table rows in my MySQL database. I have the following script, but when executing it, it will generate an error saying that the variable $con is not set, but it is. So my question is how can I use "global" in this statement?
function countrows($rows){
$sql = mysqli_query($con,"SELECT * FROM $rows");
$num_rows = mysqli_num_rows($sql);
echo $num_rows;
}
If $con is defined in the global scope (that is, it is not created inside any other functions), then make this call:
global $con;
as the first line in that function.
You might also pass it as a function parameter:
function countrows($rows, $con){
...
}
Here's how you do it:
function countrows($rows){
global $con;
$sql = mysqli_query($con,"SELECT * FROM $rows");
$num_rows = mysqli_num_rows($sql);
echo $num_rows;
}
BTW, if the table is large, I recommend using SELECT COUNT(*) instead of SELECT *. The latter requires downloading the entire contents of the table in order to count the rows, the former can usually be done efficiently in SQL.