I would like to send a message and attachment via signal-cli.
I successfully set up docker a container by bbernhard/signal-cli-rest-api.
Normal message sending with curl-statement works fine and statement looks like:
curl -X POST -H "Content-Type: application/json" -d '{\"message\": \"Hello World!\", \"number\": \"+490000000\", \"recipients\": [\"+4900000000"]}' 'http://localhost:48080/v2/send'
The message will be sent to one recipient or many. Also working for a group by groupID.
Question: How to add an attachment like a JPG?
If I add \"base64_attachments\": [\"${ENCODED_IMAGE}")\"] to the statement, then i get the error message {"error":"Couldn't process request - invalid request"}
Full bash script looks like :
#!/bin/bash
INPUT_FILE="/path/to/file/IMG_5098.JPG"
TMPFILE=$(mktemp)
base64 "${INPUT_FILE}" --wrap=0 > "${TMPFILE}"
ENCODED_IMAGE=$(cat "${TMPFILE}")
curl -X POST -H "Content-Type: application/json" -d '{\"message\": \"Hello World!\", \"base64_attachments\": [\"${ENCODED_IMAGE}")\"], \"number\": \"+4900000\", \"recipients\": [\"+4900000000\"]}' 'http://localhost:48080/v2/send'
rm "${TMPFILE}"
I expected the image send as well as the message
Related
Sorry Pretty noob to json.
Basically I have a simple server where I can upload data in there.
E.g:
curl -vX PUT "http://IP:port/ABC" -H "Content-Type: application/json" -d #"Once Upon a time."
After when I do:
curl -vX GET "http://IP:port/ABC" -H "Content-Type: application/json"
I get:
{"reverse_shell":
{"aliases":{},"mappings":{},"settings":
{"index":{"creation_date":"1561863982371","number_of_shards":"5","number_of_replicas":"1","uuid":"IAWE83rYQqmtKW-9svkBVg","version":{"created":"6040299"},"provided_name":"ABC"}
}
}
}
As you can see there is no where mentioning Once Upon a time, so is there I am missing? or how do I get that data from json using curl?
I am in kali linux env.
It looks like you are trying to post a string as a file.
When you specify a "#" with -d this tells curl to send the data from a file called "Once Upon a time."
If you are trying to put a file then you should do:
my_text_file.txt
Once Upon a time.
curl -vX PUT "http://IP:port/ABC" -H "Content-Type: application/json" -d #./my_text_file.txt https://server/api/path
I want to execute a bash script after i make a POST request.So far i am using Postman for sending the request , but i was wondering if i can somehow do it from a bash script as well with a json file as parameter.
I have looked into curl so far but it does not work:
bash file
curl -X POST -d req.json http://localhost:9500
Json file (req.json)
{
"id":5,
"name":"Dan",
"age":33,
"cnp":33,
"children":100,
"isMarried":0
}
I just get the error :
HTTP/1.0 503 Service Unavailable
with the trailing HTML
curl should do the job. This will send a normal POST request using the data in req.json as the body:
curl -X POST -H "Content-Type: application/json" -d #req.json http://localhost:9500
The elements you were missing are -H "Content-Type: application/json" and the # in the data flag. Without the -H flag as above curl will send a content type of application/x-www-form-urlencoded, which most applications won't accept if they expect JSON. The # in the -d flag informs curl that you are passing a file name; otherwise it uses the text itself (i.e. "req.json") as the data.
I am trying to execute a CURL command to set a greeting message for a bot I am building. Guidance from Facebook here: https://developers.facebook.com/docs/messenger-platform/thread-settings/greeting-text
Example from Facebook:
curl -X POST -H "Content-Type: application/json" -d '{
"setting_type":"greeting",
"greeting":{
"text":"Timeless apparel for the masses."
}
}' "https://graph.facebook.com/v2.6/me/thread_settings?access_token=PAGE_ACCESS_TOKEN"
I am trying to run that from a SSH command prompt -- the only change I made was make it into 1 line, so that I can execute it from command line in one go.
curl -X POST -H "Content-Type: application/json" -d '{"setting_type":"greeting", "greeting":{"text":"Hi {{user_first_name}}! I am a bot. Simply say 'Hi' to start.. yes, it's as simple as that!"}}' "https://graph.facebook.com/v2.6/me/thread_settings?access_token=EAAFXmrm6M8cBAHF2TwfWMnQfksHnZBtQQIHYWjIFpmTffkG"
But, I get this error message from SSH when trying to execute above 1 liner.
-bash: !"}}': event not found
What am I doing wrong here? Any help is appreciated.
You have a problem with single quotes ', you can replace them with \u0027 :
curl -X POST -H "Content-Type: application/json" -d '{"setting_type":"greeting", "greeting":{"text":"Hi {{user_first_name}}! I am a bot. Simply say \u0027Hi\u0027 to start.. yes, it\u0027s as simple as that!"}}' "https://graph.facebook.com/v2.6/me/thread_settings?access_token=EAAFXmrm6M8cBAHF2TwfWMnQfksHnZBtQQIHYWjIFpmTffkG"
I want to use the pushbullet api (v2/push) for pushing messages, but if I include '%' character inside title or body the server gives me the following error:
{"error":{"type":"invalid_request","message":"Failed to decode urlencoded POST form body.","cat":"~(=^‥^)ノ"}}
How can I fix this problem?
request: curl https://api.pushbullet.com/v2/pushes -k -u token: -d type=note -d title="%test" -d body="%%test" -X POST
x-www-form-urlencoded is not the most straightforward of formats. You can probably use curl with the --data-urlencode option. You can also try encoding your values with this tool: http://meyerweb.com/eric/tools/dencoder/
That should produce urlencoded output, for instance your request would look more like:
curl -u token: https://api.pushbullet.com/v2/pushes --header "Content-Type: application/x-www-form-urlencoded" --data-binary 'type=note&title=TITLETEXT&body=%25BODYTEXT'
I am using curl in a bash script to fetch the response of a service as below,
response=$(curl -isb -H "Accept: application/json" "http://host:8080/some/resource")
Service response is of json type and on browser I could perfectly fine response.
However curl response has other unwanted things (such as set-cookie, content-length header in this case) and sometimes the actual response is eaten up.
Here is the output of echo $response >
Set-Cookie: rack.session=BAh7CEkiD3Nlc3Npb25faWQGOgZFVEkiRWJlY2JiOTE2M2Q1ZWI4NThjMDdi%0AYjRiOWRjMGMxMGEwYTBkMjE3NmJhZDVjYzY4YjY4ZTlmMTE2ZGVkYWE3MTMG%0AOwBGS
SIJY3NyZgY7AEZJIiVhZmQ2MmUyZGMxMzFmOGEwMjg3NDlhNWM3YmVm%0AN2FjNwY7AEZJIg10cmFja2luZwY7AEZ7B0kiFEhUVFBfVVNFUl9BR0VOVAY7%0AAFRJIi00MTc0OGM2MWNkMzljZTYxNzY3ZjU0
Y2I5OTdiYWRkN2MyNTBkYmU4%0ABjsARkkiGUhUVFBfQUNDRVBUX0xBTkdVQUdFBjsAVEkiLWRhMzlhM2VlNWU2%0AYjRiMGQzMjU1YmZlZjk1NjAxODkwYWZkODA3MDkGOwBG%0A--ee97a62095e7d42129
tontent-Length: 354c8; path=/; HttpOnly
This is breaking my response parsing logic.
I have seen this happening intermittently which is weird.
Is there a way to get "only" json response from cURL output?
I went through the curl documentation but could not see any thing/ or I could have missed it.
You are specifying the -i option:
-i, --include
(HTTP) Include the HTTP-header in the output. The HTTP-header includes things like server-name, date of the document, HTTP-version and more...
Simply remove that option from your command line:
response=$(curl -sb -H "Accept: application/json" "http://host:8080/some/resource")
I was executing a get request an also want to see just the response and nothing else, seems like magic is done with -silent,-s option.
From the curl man page:
-s, --silent
Silent or quiet mode. Don't show progress meter or error messages. Makes Curl mute. It will still output the data you ask for, potentially even to the terminal/stdout unless you redirect it.
Below the examples:
curl -s "http://host:8080/some/resource"
curl --silent "http://host:8080/some/resource"
Using custom headers
curl -s -H "Accept: application/json" "http://host:8080/some/resource"
Using POST method with a header
curl -s -X POST -H "Content-Type: application/json" "http://host:8080/some/resource" -d '{ "myBean": {"property": "value"}}'
You can also customize the output for specific values with -w, below the options I use to get just response codes of the curl:
curl -s -o /dev/null -w "%{http_code}" "http://host:8080/some/resource"