I am using the historyclient of the googlefit. I am looking for the steps , calories and distance aggregated data per day for last 15 to 30 days .
However, I am getting inconsistent results every time I make a call to the historyclient which normally not matches to the googleFit dashboard . Any code snippet to get a reliable and consistent data.
Also, how reliable is the historyclient compare to the healthconnect apis newly launched
Thanks,
Nitin
Implementing the historyclient with aggregate_step_Delta. This is getting me the steps but always inconsisten with the googlefit dashboard;
Related
I'm currently using the JIRA REST API to retrieve the amount of time spent on a ticket in a project using the following route:
/rest/agile/1.0/board/{boardId}/sprint/{sprintId}/issue
Within one of the issues, I receive the following data relating to time:
"timetracking": {
"remainingEstimate": "9w 1d",
"timeSpent": "4d",
"remainingEstimateSeconds": 1324800,
"timeSpentSeconds": 115200
},
When converting the seconds to days, it results in 1.33333333 days, where as the timeSpent specifies 4 days.
Why does timeSpent and timeSpentSeconds not add up, and is there a way to resolve the issue to ensure that they do match?
I figured this out. As it turns out, it does not work on a 24 hour period, i.e. 1d does not equal 86400, but rather it works on hours spent on the project per day, in my case, 8h. Therefore the seconds is 4 * 8 which equals 1.33333... days.
In Jmeter v2.13, is there a way to capture Throughput via non-GUI/Command Line mode?
I have the jmeter.properties file configured to output via the Summariser and I'm also outputting another [more detailed] .csv results file.
call ..\..\binaries\apache-jmeter-2.13\bin\jmeter -n -t "API Performance.jmx" -l "performanceDetailedResults.csv"
The performanceDetailedResults.csv file provides:
timeStamp
elapsed time
responseCode
responseMessage
threadName
success
failureMessage
bytes sent
grpThreads
allThreads
Latency
However, no amount of tweaking the .properties file or the test itself seems to provide Throuput results like I get via the GUI's Summary Report's Save Table Data button.
All articles, postings, and blogs seem to indicate it wasn't possible without manual manipulation in a spreadsheet. But I'm hoping someone out there has figured out a way to do this with no, or minimal, manual manipulation as the client doesn't want to have to manually calculate the Throughput value each time.
It is calculated by JMeter Listeners so it isn't something you can enable via properties files. Same applies to other metrics which are calculated like:
Average response time
50, 90, 95, and 99 percentiles
Standard Deviation
Basically throughput is calculated as simple as dividing total number of requests by elapsed time.
Throughput is calculated as requests/unit of time. The time is calculated from the start of the first sample to the end of the last sample. This includes any intervals between samples, as it is supposed to represent the load on the server.
The formula is: Throughput = (number of requests) / (total time)
Hopefully it won't be too hard for you.
References:
Glossary #1
Glossary #2
Did you take a look at JMeter-Plugins?
This tool can generate aggregate report through commandline.
I'm writing tool to parse and extract some data from cpuprofile file (file produced when I save profile report) and I'm having some troubles with precision of Self & Total times calculations. So, time depends on the value from field hitCount, but. When hitCount is small (<300) the coefficient between hitCount and Self time ~1.033. But as hitCount grows, coefficient also grows.
So, when hitCount=3585, k is 1.057. When hitCount=7265: k=1.066.
Currently I'm using 1.035 as coefficient, I tried to minimize error on my sample data. But I'm not happy with approximation. I'm not familiar with Chromium code base to go and figure it out directly in the source code.
So how do I get Self time for function call having hitCount value?
Basically it's:
sampleDuration = totalRecordingDuration / totalHitCount
nodeSelfTime = nodeHitCount * sampleDuration
You can find it here:
https://code.google.com/p/chromium/codesearch#chromium/src/third_party/WebKit/Source/devtools/front_end/sdk/CPUProfileDataModel.js&sq=package:chromium&type=cs&l=31
I am developing a transit navigation app using the Google Directions API.
The API requires me to submit a departure time (departure_time) for transit queries.
Is it necessary to convert the local time to UTC time for this parameter?
I could not validate it through the API's response, as there is no accurate time returned in it.
That Doc Was In Error
Apparently the Google team writing that doc page made an error and later fixed it.
The number you report 1343605500 is no longer found on that page. Today the number on that page is 1343641500. I suspect you did indeed see that number on that page previously. Googling (ironically enough) for site:https://developers.google.com 1343605500 does list that page as a hit. Apparently the hit is based on a cached copy of the old erroneous page. Even Google cannot escape the reach of Google.
Work in UTC/GMT
Is it necessary to convert the local time to UTC time for this parameter?
Yes.
The API works with GMT/UTC (no time zone offset), which only makes sense when you think about it. Almost always, the best practice for handling date-time is to perform your business logic, serialization, database records, and so on in UTC, then convert to local time only for presentation to the user.
Just looking at the example URL itself suggests it is in UTC. The only possible reference to a local time zone would be the word "Brooklyn" which is certainly not a clear unique identifier for a time zone.
http://maps.googleapis.com/maps/api/directions/json?origin=Brooklyn&destination=Queens&sensor=false&departure_time=1343641500&mode=transit
And of course the doc says the API uses UTC/GMT:
the desired time of departure as seconds since midnight, January 1, 1970 UTC
Poor Writing
The confusion stems from the poor writing in that documentation page. They need to append a crucial "UTC" or "GMT" to that "9:45 am". Mentioning New York and 9:45 in the same breath implies local time, whereas that example is truly 5:45 in the morning local time in Brooklyn.
The below request searches for Transit Directions from Brooklyn, New York to Queens, New York. When requesting transit directions, be sure to specify either a departure_time or arrival_time.
Note that in this example the departure time is specified as July 30, 2012 at 09:45 am. Update the parameter to a point in the future before submitting the request.
Old Versus New Numbers
Old number: 1343605500 (reported in the answer by davidg, and by googling)
New number: 1343641500 (found 2013-12)
Number if they had actually meant 9:45 in New York: 1343655900.
Example Code
I don't do JavaScript. So instead, I present some Java code using the sophisticated Joda-Time 2.3 date-time handling library running in Java 7. I use both the old (erroneous) and new (correct) numbers to show the date-time in both UTC and New York time zones. Furthermore, I calculate the number of seconds since epoch would have been used to get to 9:45 am July 30 2012 in New York, to produce a third number of seconds.
The Google API uses seconds, while Joda-Time uses milliseconds, so I multiply or divide by a thousand.
// © 2013 Basil Bourque. This source code may be used freely forever by anyone taking full responsibility for doing so.
// import org.joda.time.*;
DateTimeZone timeZone_NewYork = DateTimeZone.forID( "America/New_York" );
// On this page:
// https://developers.google.com/maps/documentation/directions/#ExampleRequests
// …look for the following two paragraphs…
// --
// The below request searches for Transit Directions from Brooklyn, New York to Queens, New York. When requesting transit directions, be sure to specify either a departure_time or arrival_time.
// Note that in this example the departure time is specified as July 30, 2012 at 09:45 am. Update the parameter to a point in the future before submitting the request.
// --
// Below that text, find this URL:
// http://maps.googleapis.com/maps/api/directions/json?origin=Brooklyn&destination=Queens&sensor=false&departure_time=1343641500&mode=transit
// Extract that departure time of 1,343,641,500 seconds since the Unix Epoch of beginning of 1970 UTC.
// Apparently in the past that page erroneously used the number 1343605500 where today it uses 1343641500.
// Use the correct number found on that page today, 2013-12-25: 1343641500.
DateTime dateTimeInUtcWithNewNumber = new DateTime ( ( 1343641500L * 1000L ), DateTimeZone.UTC );
DateTime dateTimeInNewYorkWithNewNumber = dateTimeInUtcWithNewNumber.toDateTime( timeZone_NewYork );
System.out.println( "dateTimeInUtcWithNewNumber: " + dateTimeInUtcWithNewNumber );
System.out.println( "dateTimeInNewYorkWithNewNumber: " + dateTimeInNewYorkWithNewNumber );
// Use the old erroneous number previously found on that page: 1343605500.
DateTime dateTimeInUtcWithOldNumber = new DateTime ( ( 1343605500L * 1000L ), DateTimeZone.UTC );
DateTime dateTimeInNewYorkWithOldNumber = dateTimeInUtcWithOldNumber.toDateTime( timeZone_NewYork );
System.out.println( "dateTimeInUtcWithOldNumber: " + dateTimeInUtcWithOldNumber );
System.out.println( "dateTimeInNewYorkWithOldNumber: " + dateTimeInNewYorkWithOldNumber );
// Calculating the number that should have been used if the Google team had actually meant 9:45 AM local time in New York: 1343655900.
DateTime dateTimeInNewYork_2012_07_30_09_45 = new DateTime ( 2012, 7, 30, 9, 45, 0, timeZone_NewYork );
System.out.println( "dateTimeInNewYork_2012_07_30_09_45: " + dateTimeInNewYork_2012_07_30_09_45 );
System.out.println( "dateTimeInNewYork_2012_07_30_09_45 in seconds since Unix epoch: " + ( dateTimeInNewYork_2012_07_30_09_45.getMillis() / 1000L ) );
When run…
dateTimeInUtcWithNewNumber: 2012-07-30T09:45:00.000Z
dateTimeInNewYorkWithNewNumber: 2012-07-30T05:45:00.000-04:00
dateTimeInUtcWithOldNumber: 2012-07-29T23:45:00.000Z
dateTimeInNewYorkWithOldNumber: 2012-07-29T19:45:00.000-04:00
dateTimeInNewYork_2012_07_30_09_45: 2012-07-30T09:45:00.000-04:00
dateTimeInNewYork_2012_07_30_09_45 in seconds since Unix epoch: 1343655900
The number 71867806 represents the present day, with the smallest unit of days.
Sorry guy's, caching owned me, it's actually milliseconds!
How can I
calculate the currente date from it?
(or) convert it into an Unix timestamp?
Solution shouldn't use language depending features.
Thanks!
This depends on:
What unit this number represents (days, seconds, milliseconds, ticks?)
When the starting date was
In general I would discourage you from trying to reinvent the wheel here, since you will have to handle every single exception in regards to dates yourself.
If it's truly an integer number of days, and the number you've given is for today (April 21, 2010, for me as I'm reading this), then the "zero day" (the epoch) was obviously enough 71867806 days ago. I can't quite imagine why somebody would pick that though -- it works out to roughly 196,763 years ago (~194,753 BC, if you prefer). That seems like a strange enough time to pick that I'm going to guess that there's more to this than what you've told us (perhaps more than you know about).
It seems to me the first thing to do is verify that the number does increase by one every 24 hours. If at all possible keep track of the exact time when it does increment.
First, you have only one point, and that's not quite enough. Get the number for "tomorrow" and see if that's 71867806+1. If it is, then you can safely bet that +1 means +1 day. If it's something like tomorrow-today = 24, then odds are +1 means +1 hour, and the logic to display days only shows you the "day" part. If it's something else check to see if it's near (24*60, which would be minutes), (24*60*60, which would be seconds), or (24*60*60*1000, which would be milliseconds).
Once you have an idea of what kind of units you are using, you can estimate how many years ago the "start" date of 0 was. See if that aligns with any of the common calendar systems located at http://en.wikipedia.org/wiki/List_of_calendars. Odds are that the calendar you are using isn't a truly new creation, but a reimplementation of an existing calendar. If it seems very far back, it might be an Julian Date, which has day 0 equivalent to BCE 4713 January 01 12:00:00.0 UT Monday. Julian Dates and Modified Julian dates are often used in astronomy calculations.
The next major goal is to find Jan 1, 1970 00:00:00. If you can find the number that represents that date, then you simply subtract it from this foreign calendar system and convert the remainder from the discovered units to milliseconds. That will give you UNIX time which you can then use with the standard UNIX utilities to convert to a time in any time zone you like.
In the end, you might not be able to be 100% certain that your conversion is exactly the same as the hand implemented system, but if you can test your assumptions about the calendar by plugging in numbers and seeing if they display as you predicted. Use this technique to create a battery of tests which will help you determine how this system handles leap years, etc. Remember, it might not handle them at all!
What time is: 71,867,806 miliseconds from midnight?
There are:
- 86,400,000 ms/day
- 3,600,000 ms/hour
- 60,000 ms/minute
- 1,000 ms/second
Remove and tally these units until you have the time, as follows:
How many days? None because 71,867,806 is less than 86,400,000
How many hours? Maximum times 3,600,000 can be removed is 19 times
71,867,806 - (3,600,000 * 19) = 3,467,806 ms left.
How many minutes? Maximum times 60,000 can be removed is 57 times.
3,467,806 - (60,000 * 57) = 47,806 ms left
How many seconds? Maximum times 1,000 can be removed is 47 times.
47,806 - (1,000 * 47) = 806
So the time is: 19:57:47.806
It is indeed a fairly long time ago if the smallest number is in days. However, assuming you're sure about it I could suggest the following shell command which would be obviously not valid for dates before 1st Jan. 1970:
date -d "#$(echo '(71867806-71853086)*3600*24'|bc)" +%D
or without bc:
date -d "#$(((71867806 - 71853086) * 3600 * 24))" +%D
Sorry again for the messy question, i got the solution now. In js it looks like that:
var dayZero = new Date(new Date().getTime() - 71867806 * 1000);