Does the Google Directions API use UTC or Local Time? - google-maps

I am developing a transit navigation app using the Google Directions API.
The API requires me to submit a departure time (departure_time) for transit queries.
Is it necessary to convert the local time to UTC time for this parameter?
I could not validate it through the API's response, as there is no accurate time returned in it.

That Doc Was In Error
Apparently the Google team writing that doc page made an error and later fixed it.
The number you report 1343605500 is no longer found on that page. Today the number on that page is 1343641500. I suspect you did indeed see that number on that page previously. Googling (ironically enough) for site:https://developers.google.com 1343605500 does list that page as a hit. Apparently the hit is based on a cached copy of the old erroneous page. Even Google cannot escape the reach of Google.
Work in UTC/GMT
Is it necessary to convert the local time to UTC time for this parameter?
Yes.
The API works with GMT/UTC (no time zone offset), which only makes sense when you think about it. Almost always, the best practice for handling date-time is to perform your business logic, serialization, database records, and so on in UTC, then convert to local time only for presentation to the user.
Just looking at the example URL itself suggests it is in UTC. The only possible reference to a local time zone would be the word "Brooklyn" which is certainly not a clear unique identifier for a time zone.
http://maps.googleapis.com/maps/api/directions/json?origin=Brooklyn&destination=Queens&sensor=false&departure_time=1343641500&mode=transit
And of course the doc says the API uses UTC/GMT:
the desired time of departure as seconds since midnight, January 1, 1970 UTC
Poor Writing
The confusion stems from the poor writing in that documentation page. They need to append a crucial "UTC" or "GMT" to that "9:45 am". Mentioning New York and 9:45 in the same breath implies local time, whereas that example is truly 5:45 in the morning local time in Brooklyn.
The below request searches for Transit Directions from Brooklyn, New York to Queens, New York. When requesting transit directions, be sure to specify either a departure_time or arrival_time.
Note that in this example the departure time is specified as July 30, 2012 at 09:45 am. Update the parameter to a point in the future before submitting the request.
Old Versus New Numbers
Old number: 1343605500 (reported in the answer by davidg, and by googling)
New number: 1343641500 (found 2013-12)
Number if they had actually meant 9:45 in New York: 1343655900.
Example Code
I don't do JavaScript. So instead, I present some Java code using the sophisticated Joda-Time 2.3 date-time handling library running in Java 7. I use both the old (erroneous) and new (correct) numbers to show the date-time in both UTC and New York time zones. Furthermore, I calculate the number of seconds since epoch would have been used to get to 9:45 am July 30 2012 in New York, to produce a third number of seconds.
The Google API uses seconds, while Joda-Time uses milliseconds, so I multiply or divide by a thousand.
// © 2013 Basil Bourque. This source code may be used freely forever by anyone taking full responsibility for doing so.
// import org.joda.time.*;
DateTimeZone timeZone_NewYork = DateTimeZone.forID( "America/New_York" );
// On this page:
// https://developers.google.com/maps/documentation/directions/#ExampleRequests
// …look for the following two paragraphs…
// --
// The below request searches for Transit Directions from Brooklyn, New York to Queens, New York. When requesting transit directions, be sure to specify either a departure_time or arrival_time.
// Note that in this example the departure time is specified as July 30, 2012 at 09:45 am. Update the parameter to a point in the future before submitting the request.
// --
// Below that text, find this URL:
// http://maps.googleapis.com/maps/api/directions/json?origin=Brooklyn&destination=Queens&sensor=false&departure_time=1343641500&mode=transit
// Extract that departure time of 1,343,641,500 seconds since the Unix Epoch of beginning of 1970 UTC.
// Apparently in the past that page erroneously used the number 1343605500 where today it uses 1343641500.
// Use the correct number found on that page today, 2013-12-25: 1343641500.
DateTime dateTimeInUtcWithNewNumber = new DateTime ( ( 1343641500L * 1000L ), DateTimeZone.UTC );
DateTime dateTimeInNewYorkWithNewNumber = dateTimeInUtcWithNewNumber.toDateTime( timeZone_NewYork );
System.out.println( "dateTimeInUtcWithNewNumber: " + dateTimeInUtcWithNewNumber );
System.out.println( "dateTimeInNewYorkWithNewNumber: " + dateTimeInNewYorkWithNewNumber );
// Use the old erroneous number previously found on that page: 1343605500.
DateTime dateTimeInUtcWithOldNumber = new DateTime ( ( 1343605500L * 1000L ), DateTimeZone.UTC );
DateTime dateTimeInNewYorkWithOldNumber = dateTimeInUtcWithOldNumber.toDateTime( timeZone_NewYork );
System.out.println( "dateTimeInUtcWithOldNumber: " + dateTimeInUtcWithOldNumber );
System.out.println( "dateTimeInNewYorkWithOldNumber: " + dateTimeInNewYorkWithOldNumber );
// Calculating the number that should have been used if the Google team had actually meant 9:45 AM local time in New York: 1343655900.
DateTime dateTimeInNewYork_2012_07_30_09_45 = new DateTime ( 2012, 7, 30, 9, 45, 0, timeZone_NewYork );
System.out.println( "dateTimeInNewYork_2012_07_30_09_45: " + dateTimeInNewYork_2012_07_30_09_45 );
System.out.println( "dateTimeInNewYork_2012_07_30_09_45 in seconds since Unix epoch: " + ( dateTimeInNewYork_2012_07_30_09_45.getMillis() / 1000L ) );
When run…
dateTimeInUtcWithNewNumber: 2012-07-30T09:45:00.000Z
dateTimeInNewYorkWithNewNumber: 2012-07-30T05:45:00.000-04:00
dateTimeInUtcWithOldNumber: 2012-07-29T23:45:00.000Z
dateTimeInNewYorkWithOldNumber: 2012-07-29T19:45:00.000-04:00
dateTimeInNewYork_2012_07_30_09_45: 2012-07-30T09:45:00.000-04:00
dateTimeInNewYork_2012_07_30_09_45 in seconds since Unix epoch: 1343655900

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I have a Python script using Brownie that occasionally triggers a swap on Uniswap by sending a transaction to Optimism Network.
It worked well for a few days (did multiple transactions successfully), but now each time it triggers a transaction, I get an error message:
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I had the same problem, and I managed to sort it out by adding
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Unable to get correct ETA using Google Maps API

I am collecting ETA for few locations for some project work. I get different time duration during different point of time, but there is one case which returns same results
Origin: Acres Club, 411-B, Hemu Kalani Marg, Sindhi Society, Chembur, Mumbai, Maharashtra
Destination: Chhatrapati Shivaji Terminus, Chhatrapati Shivaji Terminus Area, Mumbai, Maharashtra
This always returns 1702 seconds.
Below is the API call I am making:
https://maps.googleapis.com/maps/api/distancematrix/json?origins=Acres%20Club,%20411-B,%20Hemu%20Kalani%20Marg,%20Sindhi%20Society,%20Chembur,%20Mumbai,%20Maharashtra&destinations=Chhatrapati%20Shivaji%20Terminus,%20Chhatrapati%20Shivaji%20Terminus%20Area,%20Mumbai,%20Maharashtra&key=
Let me know if I am missing anything. Thanks in Aadvance.
If I understand correctly you are interested in getting a duration taking into account current traffic conditions. Please note that duration with traffic conditions requires a departure time to be specified in your request.
Have a look at the documentation that reads:
departure_time — The desired time of departure. You can specify the time as an integer in seconds since midnight, January 1, 1970 UTC. Alternatively, you can specify a value of now, which sets the departure time to the current time (correct to the nearest second).
For requests where the travel mode is driving: You can specify the departure_time to receive a route and trip duration (response field: duration_in_traffic) that take traffic conditions into account. This option is only available if the request contains a valid API key, or a valid Google Maps APIs Premium Plan client ID and signature. The departure_time must be set to the current time or some time in the future. It cannot be in the past.
https://developers.google.com/maps/documentation/distance-matrix/intro#DistanceMatrixRequests
I would suggest changing you request to
https://maps.googleapis.com/maps/api/distancematrix/json?origins=Acres%20Club%2C%20411-B%2C%20Hemu%20Kalani%20Marg%2C%20Sindhi%20Society%2C%20Chembur%2C%20Mumbai%2C%20Maharashtra&destinations=Chhatrapati%20Shivaji%20Terminus%2C%20Chhatrapati%20Shivaji%20Terminus%20Area%2C%20Mumbai&departure_time=now&traffic_model=best_guess&key=YOUR_API_KEY
In this case you will see something similar to
"rows":[
{
"elements":[
{
"distance":{
"text":"16.2 km",
"value":16206
},
"duration":{
"text":"28 mins",
"value":1702
},
"duration_in_traffic":{
"text":"45 mins",
"value":2715
},
"status":"OK"
}
]
}
],
in your response. Where duration_in_traffic shows duration taking into account current traffic conditions and duration is a typical average duration.
Hope this helps!

How to interpret Timelien for HighStock

I am using the HighStock API of HighChart.
The demo:
http://jsfiddle.net/gh/get/jquery/1.9.1/highslide-software/highcharts.com/tree/master/samples/stock/demo/compare/
Makes a timeline on the x-Axis.
But the data JSON data for the graph has the following keys:
E.g. for AAPL:
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How do all the 1229.... values relate to Date/Time?? I mean how does
1232582400000
relate to 22. January 2009???
And I have data int he following format in Java:
2015-12-10 15:27
How should I use them in the HighChart API?
The numeric time stamps you see as "1232582400000" is the javascript time stamp. I believe it is UNIX epoch time in milliseconds (multiply epoch time by 1000). You can convert your human-readable time values into javascript time in any number of ways. The basic example if you have year, month, day, hour, and second would be to make your data series use Date.UTC():
[Date.UTC(year, month, day, hour, minute), yValue]
"Unix time (also known as POSIX time or Epoch time) is a system for
describing instants in time, defined as the number of seconds that
have elapsed since 00:00:00 Coordinated Universal Time (UTC),
Thursday, 1 January 1970, not counting leap seconds."
(source)

Calculate date from numeric value

The number 71867806 represents the present day, with the smallest unit of days.
Sorry guy's, caching owned me, it's actually milliseconds!
How can I
calculate the currente date from it?
(or) convert it into an Unix timestamp?
Solution shouldn't use language depending features.
Thanks!
This depends on:
What unit this number represents (days, seconds, milliseconds, ticks?)
When the starting date was
In general I would discourage you from trying to reinvent the wheel here, since you will have to handle every single exception in regards to dates yourself.
If it's truly an integer number of days, and the number you've given is for today (April 21, 2010, for me as I'm reading this), then the "zero day" (the epoch) was obviously enough 71867806 days ago. I can't quite imagine why somebody would pick that though -- it works out to roughly 196,763 years ago (~194,753 BC, if you prefer). That seems like a strange enough time to pick that I'm going to guess that there's more to this than what you've told us (perhaps more than you know about).
It seems to me the first thing to do is verify that the number does increase by one every 24 hours. If at all possible keep track of the exact time when it does increment.
First, you have only one point, and that's not quite enough. Get the number for "tomorrow" and see if that's 71867806+1. If it is, then you can safely bet that +1 means +1 day. If it's something like tomorrow-today = 24, then odds are +1 means +1 hour, and the logic to display days only shows you the "day" part. If it's something else check to see if it's near (24*60, which would be minutes), (24*60*60, which would be seconds), or (24*60*60*1000, which would be milliseconds).
Once you have an idea of what kind of units you are using, you can estimate how many years ago the "start" date of 0 was. See if that aligns with any of the common calendar systems located at http://en.wikipedia.org/wiki/List_of_calendars. Odds are that the calendar you are using isn't a truly new creation, but a reimplementation of an existing calendar. If it seems very far back, it might be an Julian Date, which has day 0 equivalent to BCE 4713 January 01 12:00:00.0 UT Monday. Julian Dates and Modified Julian dates are often used in astronomy calculations.
The next major goal is to find Jan 1, 1970 00:00:00. If you can find the number that represents that date, then you simply subtract it from this foreign calendar system and convert the remainder from the discovered units to milliseconds. That will give you UNIX time which you can then use with the standard UNIX utilities to convert to a time in any time zone you like.
In the end, you might not be able to be 100% certain that your conversion is exactly the same as the hand implemented system, but if you can test your assumptions about the calendar by plugging in numbers and seeing if they display as you predicted. Use this technique to create a battery of tests which will help you determine how this system handles leap years, etc. Remember, it might not handle them at all!
What time is: 71,867,806 miliseconds from midnight?
There are:
- 86,400,000 ms/day
- 3,600,000 ms/hour
- 60,000 ms/minute
- 1,000 ms/second
Remove and tally these units until you have the time, as follows:
How many days? None because 71,867,806 is less than 86,400,000
How many hours? Maximum times 3,600,000 can be removed is 19 times
71,867,806 - (3,600,000 * 19) = 3,467,806 ms left.
How many minutes? Maximum times 60,000 can be removed is 57 times.
3,467,806 - (60,000 * 57) = 47,806 ms left
How many seconds? Maximum times 1,000 can be removed is 47 times.
47,806 - (1,000 * 47) = 806
So the time is: 19:57:47.806
It is indeed a fairly long time ago if the smallest number is in days. However, assuming you're sure about it I could suggest the following shell command which would be obviously not valid for dates before 1st Jan. 1970:
date -d "#$(echo '(71867806-71853086)*3600*24'|bc)" +%D
or without bc:
date -d "#$(((71867806 - 71853086) * 3600 * 24))" +%D
Sorry again for the messy question, i got the solution now. In js it looks like that:
var dayZero = new Date(new Date().getTime() - 71867806 * 1000);